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We are Group - A, now ready to present our Presentation.

We request, to be patient and Hope to stay with us.

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Assignment on:

Statistical Analysis of Sales of QUBEE Communication Ltd.

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Statistics???

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Statistics is the science of collecting, organizing, presenting, analyzing, and interpreting numerical data for the purpose of assisting in making a more effective decision.

Statistical techniques are used to make decisions that effect our daily lives

Insurance companies use statistics to set rates for different insurance

City corporation may want to examine the contamination level of different lake water

Medical professional assess the performance of a new drug over the existing one

No matter what is your future line of work, you will make decisions that will involve data

Data Set collected from Qubee Communications Ltd.

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This data set contains last Twelve months Sales volume against Advertisement cost.

Months Sales (million) Advertisement Cost (million)

January, 13 32.24 4

February,13 37.6 4.8

March,13 38.4 4.8

April,13 40.4 5.2

May,13 39.8 4.6

June,13 41.2 5.6

July,13 40 5.4

August,13 45.6 6

September,13 48 5.8

October, 2013 40.2 5.5

November, 2013 42.8 6.1

December, 2013 50.35 8.3

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Data presentation

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Data presentation

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Data presentation

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Months

Sales (Y) Advertisement Cost

(X)Jan, 13 32.24 4 (9.1425) 9.1425 -1.51 1.51

Feb,13 37.6 4.8 (3.7825) 3.7825 -0.71 0.71

Mar,13 38.4 4.8 (2.9825) 2.9825 -0.71 0.71

Apr,13 40.4 5.2 (0.9825) 0.9825 -0.31 0.31

May,13 39.8 4.6 (1.5825) 1.5825 -0.91 0.91

Jun,13 41.2 5.6 (0.1825) 0.1825 0.09 0.09

Jul,13 40 5.4 (1.3825) 1.3825 -0.11 0.11

Aug,13 45.6 6 4.2175 4.2175 0.49 0.49

Sep,13 48 5.8 6.6175 6.6175 0.29 0.29

Oct, 13 40.2 5.5 (1.1825) 1.1825 -0.01 0.01

Nov, 13 42.8 6.1 1.4175 1.4175 0.59 0.59

Dec, 13 50.35 8.3 8.9675 8.9675 2.79 2.79

  = 496.59 = 66.1 42.44

8.52

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Range: Highest value for sales is 50.35 and lowest value is 32.24.So, Range for sales = 50.35 – 32.24 = 18.11

Highest value for advertisement cost is 8.3 and lowest value is 4.So, Range for advertisement cost = 8.3 – 4 = 4.3

Mean deviation: For sales,

= 3.54

For advertisement cost, MD = ∑| X − X |/n = .71

MD = ∑( Y − Y )/n

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Months

Sales (Y)

Advertisement Cost (X)

Jan, 13

32.24 4 -9.14 -1.49 83.59 2.22

Feb,13 37.6 4.8 -3.78 -0.71 14.31 0.50Mar,1

338.4 4.8 -2.98 -0.71 8.90 0.50

Apr,13 40.4 5.2 -0.98 -0.31 0.97 0.10May,1

339.8 4.6 -1.58 -0.91 2.50 0.83

Jun,13 41.2 5.6 -0.18 0.09 0.03 0.01Jul,13 40 5.4 -1.38 -0.11 1.91 0.01Aug,1

345.6 6 4.22 0.49 17.79 0.24

Sep,13 48 5.8 6.62 0.29 43.79 0.08Oct, 13

40.2 5.5 -1.18 -0.01 1.40 0.00

Nov, 13

42.8 6.1 1.42 0.59 2.01 0.35

Dec, 13

50.35 8.3 8.97 2.79 80.42 7.78

Total 908.1 115.5 0.00 0.00 257.60 12.63

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Variance for sales:

∑(Y − Y)2 / n = 21.47

For advertisement cost:

∑(X − X)2 /n = 1.05

Standard deviation for sales=

Variance 47.21 4.6

advertisement cost =

Variance 05.1 1.03

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The CV is the ratio of the standard deviation to the arithmetic mean, expressed as a percentage:

100X

sCV

sales

10038.41

6.4CV =11.1

2%

advertisement cost 10051.5

03.1CV =

18.69%

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Correlation and regression are the most commonly used techniques for investigating the relationship between two quantitative variables.

Comments for Scatter diagram: We observe from the above scatter diagram that, the points are going upwards from left side to right side and it is strong positive correlation. It means when company increased their advertisement cost; sales have been increased.

Thank You

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