diket:p = 10 Tl = 1.5 m
Mu = 3.75 Tm37500000 Nmm
1,6 Mu = 60000000 Nmmfy = 400 Mpafc' = 25 Mpa
h = 400 mm
m =
m = 18.8235294118 mmb = 200 mm b = 200 mm
h = 400 mmd' = 30 mmd = 370 mm
Rn
Rn = 2.7392257122
ρ =
= 0.00735755748
=
= 0.0035
ρ 0.00735755748 > 0.0035
ok
= ρ . B . D= 544.459253216
perhitungan tulangan:n =
2 D 19
== 567.057473973
567.057473973 > 544.4593
=
ρ min
ρ min
As perlu
As perlu mm²
As coba n . 1/4 .π D² As coba mm²
As coba As perlu
ok
a =
a = 53.3701151975
Mn = As . Fy (d - a/2)= 77871721.6061 Nmm
Mn MuMn = 77871721.6061 > 60000000
ok
a Cc = 0.85 . Fc' . a . b
d - a/2
MnTs = As . Fy
diket:p = 10 Tl = 1.8 m
Mu = 4.5 Tm45000000 Nmm
1,6 Mu = 72000000 Nmmfy = 400 Mpafc' = 25 Mpa
m =
m = 18.82352941176 mmb = 1000 mmh = 200 mmd' = 30 mmd = 170 mm
Rn
Rn = 3.114186851211
ρ =
= 0.008458908357
=
= 0.0035
ρ 0.008458908357 > 0.0035
ok
= ρ . B . D= 1438.014420716
== 1610
1610 > 1438.014ok
a =
a = 30.30588235294
=
ρ min
ρ min
As perlu
As perlu mm²
As coba
As coba mm²
As coba As perlu
Mn = As . Fy (d - a/2)= 99721505.88235 Nmm
As bagi =Mn Mu =
Mn = 99721505.88235 > 72000000 =ok
pakai tulangan pakai tulangan
Jd = Jd =
= 124.8831862297 mm =
D 16 125 D 10
As terpasang
0,002 . b . h400450
174.5329252
175
diket:= 3728 kg/m
l = 8 mVu = 1/2 . q . L
= 14912 kg149120 N
fy = 240 Mpafc' = 15 Mpab = 200 mmh = 500 mmd' = 30 mmd = 470 mm
Vc =
= 60676.7390906 N
Vc < Vu60676.74 < 149120PERLU TULANGAN GESER
=
=
= 168738.645525 N
= 10 mmAv =
= 157.079632679
s =
= 105.006073215 mmpakai tulangan
Ø 10 - 106
untuk mempermudah pemasangan tulangan :
Ø 10 - 100
qult
Ø Vs Vu - Ø Vc
Vs perlu
Ø tuln . 1/4 . π . D²
mm²
Mu = 300,000,000 Nmmfy = 400 Mpafc' = 25 Mpab = 300 mmh = 700 mmd' = 40 mmd = 660 mm
As1 = 1000
a =
= 62.74509803922
= As . Fy
= 201160784.3137 Nmm
= or Mn2 = As2 . Fy . (d-d')= 123549019.6078
= 123549019.6078 Nmm
=
= 498.1815306768
= As1 + As2= 1498.181530677
perhitungan tulangan:
n =
jadi pakai4 D 22
jadi pakaiAs2=As' = 498.1815306768
2 D 22
201160784.3137 123549019.608
Mu324709803.9216 > 300,000,000
ok
mm²
φMn1
Mn2 perlu
As2 = As'
mm²
As1 totalmm²
φMn1 φMn2
φMn total
Nmm
Mu = 300,000,000 Nmmfy = 400 Mpafc' = 15 Mpabw = 200 mmh = 600 mmhf = 120 mmd' = 30 mmd = 570 mmAs = 1700L = 6000 mm
1/4 L = 1500 mmbw + 16.hf = 2120 mm = 1500 mm
jb = 1800 mm
misal, a = hfCc 1 = 0,85 . Fc' . a . b
= 2295000 N
Ts = As . Fy= 680000 N
Cc 1 Ts2295000 > 680000
maka a < hf, termasuk balok T-persegi, balok tekan tidak perlu seluruhnya, hanya sebagian
maka,
a =
= 35.55555555556
Cc 2 = 0,85 . fc' . a . b= 680000 N
Cc 2 Ts680000 = 680000
ok
= As . Fy
= 300408888.8889 Nmm
Mu300408888.89 > 300,000,000
ok
mm²
b eff
φMn
φMn
perhitungan tulangan:
n =
jadi pakai penulangan4 D 25
maka a < hf, termasuk balok T-persegi, balok tekan tidak perlu seluruhnya, hanya sebagian
Mu = 300,000,000 Nmmfy = 400 Mpafc' = 15 Mpabw = 300 mmh = 500 mmhf = 120 mmd' = 40 mmd = 460 mmAs = 4000L = 5000 mm
1/4 L = 1250 mmbw + 16.hf = 2220 mm = 750 mm
jb = 750 mm
misal, a = hfCc 1 = 0,85 . Fc' . a . b
= 1147500 N
Ts = As . Fy= 1600000 N
Cc 1 Ts1147500 < 1600000
maka a > hf, termasuk balok T-murni, balok tekan masuk sampai di bawah pelat
maka,
a T.murni =
= 238.30065359 mm
Cc 2 = Ts - Cc1= 452500
Cc1 + Cc 2 Ts1600000 = 1600000
ok
=
= 468867581.7 Nmm
Mu468867581.7 > 300,000,000
ok
mm²
b eff
φMn
φMn
perhitungan tulangan:
n =
jadi pakai penulangan5 D 32
maka a > hf, termasuk balok T-murni, balok tekan masuk sampai di bawah pelat