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56 Example A4.19 Given: Consider the bending beam shown below with a concentrated harmonic force acting at the mid-length point C on the beam. Find: For this problem: a) Use the modal uncoupling approach to determine the particular solution w P (t)= W (x)sint of the beam‘s EOM. b) Make a hand sketch of |W (x = L/2)| vs. for a range of values of covering up through the first four resonances of the response. Provide details on how you arrived at this hand sketch. w(x,t) x = 0 x = L EI , ρ A

w(x,t) x = 0 x = L...or, p j+ω j 2p j=fˆ jsinΩt The particular solutions for these modally-uncoupled EOMs are given by: p jP(t)= ˆf j ω j 2−Ω2 sinΩt Therefore, the beam response

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  • 56

    Example A4.19

    Given: Consider the bending beam shown below with a concentrated harmonic force acting at themid-length point C on the beam.

    Find: For this problem:a) Use the modal uncoupling approach to determine the particular solution wP (t) = W (x)sin⌦t

    of the beam‘s EOM.b) Make a hand sketch of |W (x = L/2)| vs. ⌦ for a range of values of ⌦ covering up through the

    first four resonances of the response. Provide details on how you arrived at this hand sketch.

    w(x,t)

    x = 0 x = L

    EI , ρA

  • ME 563 – Fall 2014

    Hom

    ework Problem

    8.4 C

    onsider the bending beam show

    n below w

    ith a concentrated harmonic force acting at

    the mid-length point C

    on the beam.

    a) U

    se the modal uncoupling approach to determ

    ine the particular solution wP (x,t)=

    W(x)sinΩ

    t of the beam’s EO

    M. Feel free to use natural frequency and

    modal function results from

    a previous homew

    ork assignment in arriving at your

    solution here.

    b) M

    ake a hand sketch of W(x

    =L/2) vs. Ω

    for a range of values of Ω covering

    up through the first four resonances of the response. Provide details on how you

    arrived at this hand sketch.

    c) R

    epeat b) above for W(x

    =L)

    .

  • or,

    pj +ω j2pj = f̂ j sinΩt

    The particular solutions for these modally-uncoupled EOMs are given by:

    pjP (t) =f̂ j

    ω j2 −Ω2

    sinΩt

    Therefore, the beam response is:

    wP (x, t) = Wj( )(x)pjP (t)

    j=1

    = W j( )(x)f̂ j

    ω j2 −Ω2

    ⎝⎜

    ⎠⎟

    j=1

    ∑⎧⎨⎪

    ⎩⎪

    ⎫⎬⎪

    ⎭⎪sinΩt

    =W (x)sinΩt

    From this, we have:

    W L2

    ⎛⎝⎜

    ⎞⎠⎟ = W

    j( ) L2

    ⎛⎝⎜

    ⎞⎠⎟

    f̂ jω j2 −Ω2

    ⎝⎜

    ⎠⎟

    j=1

    = f0W j( ) L

    2⎛⎝⎜

    ⎞⎠⎟

    ⎡⎣⎢

    ⎤⎦⎥2

    ρA W ( j)2 dx0

    L

    ∫⎛

    ⎝⎜

    ⎠⎟

    1ω j2 −Ω2

    ⎝⎜

    ⎠⎟

    j=1

    Comments:

    • Resonances will occur for the jth mode when Ω =ω j , unless W( j)(L / 2) = 0 .

    • Anti-resonances will occur between every pair of resonances since the coefficient of 1/ ω j

    2 −Ω2( ) in the above sum is positive for all modes.