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Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF 3 c) HCl + CaCO 3 H 2 O + CO 2 + CaCl 2 Agenda -Turn in Lab -Notes Unit 5-3 -One-on-One grade check -WS Practice Unit 5-3 Homework Dec 9 - Deadline for quiz retake

Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

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Page 1: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Warm up 11-10-151. Why do we have to balance chemical equations?2. Balance these chemical equations:a) Sb + O2 → Sb4O6

b) FeCl3 + KF → KCl + FeF3

c) HCl + CaCO3 → H2O + CO2 + CaCl2

Agenda-Turn in Lab -Notes Unit 5-3-One-on-One grade check-WS Practice Unit 5-3

HomeworkDec 9 - Deadline for quiz retake

Page 2: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

a) Sb + O2 → Sb4O6

b) FeCl3 + KF → KCl + FeF3

c) HCl + CaCO3 → H2O + CO2 + CaCl2

Page 3: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Unit 5-3

Types of Chemical Reactions

Page 4: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Types of Chemical Reactions

• Synthesis or CombinationA + B → AB

Ex: 2Na(s) + Cl2 (g) → 2NaCl (s)

The love story

Page 5: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Types of Chemical Reactions

• DecompositionAB → A + B

Ex: 2H2O → 2H2 + O2

The break-up

Page 6: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Types of Chemical Reactions

• Single Replacement or Single DisplacementAX + B → BX + A

Ex: CuSO4 + Zn(s) → ZnSO4 + Cu(s)

The complication

Page 7: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Types of Chemical Reactions

• Double Replacement or Double DisplacementAB + CD → CB + AD

Ex: Pb(NO3)2 + 2KI → PbI2 + 2KNO3

Page 8: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Types of Chemical Reactions

• CombustionCarbon compound + O2 → CO2 + H2O

Ex: CH4 + 2O2 → CO2 + 2H2O

Page 9: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Check In

• Name the reaction type for the following equations:

• NH3+ H2SO4 → (NH4)2SO4

• HgO → Hg + O2

• CH4 + O2 → H2O + CO2

• CuCl2 + H2S → CuS + HCl

• BaCl2 + Na2SO4 → NaCl + BaSO4

SynthesisDecompositionCombustionDouble Replace.Double Replace.

Page 10: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Percent Yield

• Analysis of the efficiency for chemical reaction• Percent Yield calculation

Page 11: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Percent Yield• Theoretical yield – The maximum amount of products that can be

formed in a reaction based on calculation

Page 12: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Percent Yield

• The actual yield – Real amount produced in a reaction (usually less

than the expected theoretical yield).

Page 13: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Percent YieldExample• A reaction should have produced 1.44g of

MgO. After the experiment, only 1.23g of magnesium oxide was present. What is the percent yield?

Page 14: Warm up 11-10-15 1. Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF

Assignments

• Summary• Practice Worksheet due next class• One-on-One grade check