Urea Kamal

Embed Size (px)

Citation preview

  • 8/10/2019 Urea Kamal

    1/92

    1

    MANUFACTURE OF UREA

    ( Capacity : 1500 MTD )

    PROJECT REPORT

    Submitted to Panjab University,Chandigarh

    In Partial Fulfillment of the requirements

    For the Degree ofBACHELOR OF CHEMICAL ENGINEERING

    2011

    Submitted By:

    KAMAL BHARTI

    Univ Roll no:CH7228Univ. Institute of Chemical Engineering & Tech.

    Panjab University,Chandigarh

  • 8/10/2019 Urea Kamal

    2/92

    2

    ACKNOWLEDGEMENT

    I would like to thank my Department authorities for giving me this

    opportunity to work on this project which helped me in increasing my

    knowledge as well as in giving me an opportunity to put my theoretical

    knowledge to practical use.

    I would also like to offer my sincere thanks to my project supervisor

    Dr. Shantanu Basu for providing inspiration and encouragement throughout

    my work. I have enjoyed free and informal discussion with him and his

    valuable suggestions have gone a long way in the completion of my work.

    Thanks to all the teachers and staff of University Institute Of

    Chemical Engineering And Technology for their time to time guidance.

    Kamal Bharti

  • 8/10/2019 Urea Kamal

    3/92

    3

    CERTIFICATE

    This is to certify that Mr Kamal Bharti, Roll No.-CH-7228, a finalyear student of the University Institute of chemical Engineeringand Technology, Panjab University, Chandigarh has completed hisproject entitled MANUFACTURE OF UREA BY MITSUITOATSU PROCESS under my supervision.This report of theproject may be accepted for the evaluation as a part of therequirement of B.E. CHEMICAL degree.

    DR. SHANTANUBASU

    UICET,PU

    TEACHER SIGNATURE

  • 8/10/2019 Urea Kamal

    4/92

    4

    TABLE OF CONTENTS

    1. INTRODUCTION 5

    2. MANUFACTURING OF UREA 6

    3. IMPORTANCE OF UREA..6

    4. PROPERTIES OF UREA 7

    5. VARIOUS UREA SYNTHESIS PROCESS8

    6. PROCESS SELECTION.9

    7. PROCESS FLOW DIAGRAM10

    8.

    PROCESS DESCRIPTION11

    9. MATERIAL BALANCE..15

    10.ENERGY BALANCE..30

    11.DESIGN38

    (a)REACTOR DESIGN..42(b)HIGH PRESSURE DECOMPOSER DESIGN..54

    12.

    COST ESTIMATION61

    13.GENERAL SITE CONSIDERATIONS..69

    14.UTILITIES ...74

    15.INSTRUMENT & CONTROL.77

    16.INSTRUCTIONS FOR OPERATION.........82

    17.STARTUP OF PLANT .83

    18.SAFETY84

    19.

    ENVIRONMENTALCONSIDERATIONS..91

    20.REFERENCES.92

  • 8/10/2019 Urea Kamal

    5/92

    5

    Introduction

    Urea is synthetic origined nitrogenous material, NH2CO NH2. Its nitrogen content is 46.6

    %( when pure). At room temperature urea is colorless, odorless and tasteless.

    When it is dissolved in water it hydrolyzes very slowly to ammonia and carbon dioxide.

    Urea today occupies the key position amongst the various solid nitrogenous fertilizers by

    virtue of its highest content which allow a consumption saving in transportation and

    distribution cost.

    The process of urea synthesis is of immense importance as it was the first organic

    compound to be synthesized from inorganic compound in laboratory. Wholer obtained

    urea from ammonium cyanide in 1828. Today various manufacturing process use the

    reaction between liquid ammonia and carbon dioxide gas to give ammonia carbonate

    which on the sub sequent dehydration yield urea and water.

    The technology and engineering if urea production has therefore undergone rapid

    development in the last two decades so with the result that stream plants of 1500 MTPD

    capacity and even higher have been designed and engineered.

    The chemical fertilizer manufacturing in India started during the early 40s with only two

    small plants, today it is the fourth producer of fertilizer and occupies the third position in

    the fertilizer consumption in world.

  • 8/10/2019 Urea Kamal

    6/92

    6

    Manufacture of Urea

    Urea is commercially produced by the direct dehydration of ammonium carbonate

    (NH2COONH4) at elevated temperature and pressure. NH2COONH4is obtained by direct

    reaction of NH4and CO2. The two reactions are usually carried out simultaneously in a

    high pressure reactor.

    H = -38000 cal/gmol

    H = +7500 cal/gmol

    Importance of Urea

    1. Fertilizer grade urea is mainly used as fertilizer in the form of prills. 90% of urea

    produced in India is used as fertilizer.

    2. Technical grade urea is used in the manufacture of thermosetting resins.

    3. Used in pharmaceutical industry. It promotes healing of wounds.

    4. Feed grade urea is used for the purpose of animal feed as a protein supplement.

    5. Used in manufacture of explosives

  • 8/10/2019 Urea Kamal

    7/92

    7

    Properties of Urea

    S.No. Property Assigned value

    1.

    Formula weight 60.06

    2. Melting point 132.7C

    3. Boiling point Decomposes at atmospheric

    pressure(< boiling)

    4. Index of refraction 1.484 - 1.602

    5. Crystalline form Tetragonal

    6. Specific gravity 1.335

    7. Bulk density 0.74 g/cm

    Specific Heat of Urea:

    Temperature (C) Specific Heat (cal/g C)

    0 0.344

    50 0.397

    100 0.451

    150 0.504

  • 8/10/2019 Urea Kamal

    8/92

    8

    Various urea synthesis processes

    The basic reactions that are involved for the production of urea are same for all the

    processes. The difference between the different processes is the way in which the

    unconverted reactants are treated:

    1. Once through process

    In this process, the unconverted reactants after the decomposition are released

    and are used for making other nitrogenous fertilizers like ammonium sulphate

    and ammonium nitrate. One of the drawback of this type of urea process is

    that, relatively large amount of ammonium salts accompany the production of

    urea.2.

    Partial recycle process

    In this process, a part of unconverted reactant is recycled and the remaining

    off gases NH3, CO2and H2O are used for making other nitrogenous fertilizers.

    Since the demand for urea is more as compared to other nitrogenous fertilizers

    because of its high nitrogen content, this process is obsolete these days.

    3. Total recycle process

    This is the most widely used process. It is sub divided into three types:

    a)

    Hot gas recycle Here the hot decomposed NH3 and CO2gases are

    compressed and recycled. Since the corrosion problems are more in

    this case it is also obsolete.

    b) Gas separationIn this process, the off gases after the decomposition

    of the carbonate are scrubbed with selective solvent. Then, the

    separated NH3and CO2are mixed with made up reactants entering the

    reactor. The advantage of this process is no water is recycled and the

    conversion efficiency is high.

    c) Solution recycle In this method, the decomposed gases NH3, CO2

    and H2O are condensed to form aqueous ammonium carbamate which

    is recycled to the reactor. This method is most widely used.

  • 8/10/2019 Urea Kamal

    9/92

    9

    Various advanced technologies

    1. Mitsui Toatsu process

    2. Stamicarbon process

    3.

    chemical process

    4. Snam Progetti process

    5. Inventa process

    6. Montedison total recycle process

    Process Selection

    I am selecting MITSUI TOATSU total recycle process for urea manufacture.

    In this greatly improved process, the various advanced techniques from research and

    development are incorporated into the commercially proven total recycle improved

    process.

    This process is widely used because of certain advantages:

    1.

    Temperature in the reactor is controlled by the recycle stream which is recycled

    back to the autoclave. Part of the heat evolved (reaction being exothermic) is used

    for heating the recycle stream to bring its temperature to reactor temperature and

    the rest is dissipated to the atmosphere.

    2. The consumption of raw materials i.e. NH3and CO2per mega tonne (MT) of urea

    is less compared to other process.

    3. Biuret content in the final product is around 0.6% and the moisture content is

    0.4%.

    4. Simple operations.

    5. Easier maintenance.

    6. Efficiency is good.

  • 8/10/2019 Urea Kamal

    10/92

    10

    PROCESS FLOW DIAGRAM

  • 8/10/2019 Urea Kamal

    11/92

    11

    PROCESS DESCRIPTION

    The raw material required for urea manufacture is NH3and CO2. NH3reacts with CO2to

    form ammonium carbamate, which decomposes urea. The reactions which take place are:

    (1)

    . (2)

    The reaction 1 can be easily carried to completion but reaction 2 usually has conversion

    of only 50-70 %. Since both the reactions are reversible, therefore, the equilibrium

    depends on temperature, pressure and concentration of various components.

    Since removal of water favors the formation of urea in reaction 2, therefore, the molarratio of NH3to CO2is 4 and the molar ratio of H2O to CO2is 0.8.

  • 8/10/2019 Urea Kamal

    12/92

    12

    Synthesis section:

    The suction temperature of CO2 is maintained at 35-37C and it is compressed to 230

    kg/cm2in a four stage compressor and is injected to the reactor. NH 3is pressurized to a

    pressure of 230 kg/cm2and is injected to the reactor through NH3preheated with which

    maintains its temperature at 75-80C. The stream of ammonium carbonate solution

    having temperature of about 95C from high pressure absorber is recycled to the reactor.

    The maintained temperature in the reactor is 200C. The percent conversion is 60%.

    Decomposition Section:

    1. High pressure decomposer:

    The effluents from the reactor which are at 120C flows to high pressure

    decomposer which operates at 155C and 16 kg/cm2 pressure. The reactor

    effluents flow down in high pressure decomposer which is conventional 1-1

    exchanger which is heated by steam at a pressure of 13 kg/cm2. As a result,

    ammonium carbamate is decomposed and NH3and CO

    2are released. The vapors

    from the high pressure decomposer are fed to the high pressure absorber and the

    liquid from high pressure decomposer is fed to low pressure decomposer.

    2. Low pressure decomposer:

    The liquid from high process decomposer which operates at a temperature of

    155C flows down in low pressure decomposer which operates at a temperature

    of 130C and a pressure of 1.5 kg/cm2. As in case of high pressure decomposer,

    steam is also used here but a pressure of 6 kg/cm 2. Most of the remaining

    ammonium carbamate gets decomposed here along with the liberation of NH3.

    The vapors from low pressure decomposer is fed to high pressure absorber

    whereas the liquid (urea solution) to the separator.

  • 8/10/2019 Urea Kamal

    13/92

  • 8/10/2019 Urea Kamal

    14/92

    14

    crystallizer where the urea solution containing 35-40% urea crystals are taken out

    from the bottom. It is further fed to centrifuge (i.e. crystals and mother liquor).

    Biuret in feed urea solution remains in mother liquor because of the difference of

    solubility and so a part of mother liquor is returned to reactor (via recovery

    section) for preventing accumulation of biuret in mother liquor. Biuret in reactor

    is decomposed to urea again.

    Drying and Prilling:

    Urea crystals obtained from centrifuge is sent to drier where the crystals are dried upto

    0.3% moisture by passing hot air of about 120C. It is then conveyed pneumatically to

    prilling tower. At the top of prilling tower, urea is separated from air with the help of

    cyclone separator. Urea is then fed to remelter. The molten urea coming out of the melter

    is fed to prilling bucket. The mother urea coming out of the prilling tower and encounters

    a cold air flow which causes its solidification and subsequent cooling. The urea prills thus

    obtained are fed to the rotary screen where oversize products are removed. After this the

    urea prills are sent to product storage silos with the help of belt conveyors.

    Selection of feed stock:

    The basic raw materials needed for the production of urea is NH3 and CO2 which are

    obtained from NH3 plant which is situated adjacent to urea plant. The feed stock for

    manufacture of NH3and CO2can be naphtha, natural gas, heavy fuel oil, etc.

  • 8/10/2019 Urea Kamal

    15/92

    15

    MATERIAL BALANCE

  • 8/10/2019 Urea Kamal

    16/92

    16

    OVERALL MATERIAL BALANCE:

    BASIS: 1500 MT of urea per day

    1 day operation

    The final composition of prilled urea is:

    Urea = 99.1%

    Water = 0.3%

    Biuret = 0.6%

    So the final product per day is:

    Urea = 1486.50 MT

    Water = 4.50MT

    Biuret = 9.00MT

    Biuret is formed according to the reaction:

    Urea Biuret

    (Mol. Wt: 60) (Mol. Wt.: 103)

    Now Biuret in final product = 9.00MT

    9.00MT of Biuret will be formed from = 60 x 2 x9.00/ 103

    =10.48MT of Urea

  • 8/10/2019 Urea Kamal

    17/92

    17

    Therefore, total urea in the final product = 1486.50 + 10.48

    =1497.00MT

    Raw material used for manufacture of urea is NH3 and CO2. The reaction is:

    Ammonia Carbon dioxide Ammonium Carbamate

    (Mol.Wt. =70) (Mol. Wt. =44) (Mol.Wt. =78)

    (Ammonium Carbamate) (Urea)

    (Mol. Wt. = 78) (Mol.Wt. = 60)

    Reaction 2 is spontaneous so it gets converted or completed very fast. While reaction 3 isslow and its conversion depends on the synthesis conditions which are 195C and 230

    kg/cm2.

    We take CO2to be the LIMITING COMPONENT

    Molar feed ratio of NH3to CO2 = 4.0

    Assuming conversion of ammonium carbamate to urea by reaction (3) be 60%.

    Now, for 1497.00MT of urea, ammonium carbamate required will be

    78 x 1497.00/ 60 x 100/60 = 3243.50MT

  • 8/10/2019 Urea Kamal

    18/92

    18

    For 3243.50MT ammonium carbamate CO2required is = 44 x 3243.50 / 78

    = 1829.65MT

    Since, molar ratio of NH3to CO2in feed is = 4.0

    Therefore, NH3required is = 4 x1829.65 x 17 /44

    = 2827.64MT

    The composition weight percentage of input to autoclave is

    CO2= 32.02 %

    Urea = 8.01 %

    NH3= 49.49 %

    H2O = 10.48 %

    Since, CO2in the input =1829.65MT

    Therefore, total input is =1829.65/0.3202 =5714.08MT

    So, in the input

    CO2= 1829.65 MT

    NH3= 5714.08 x .4949 = 2827.90 MT

    Urea = 5714.08 x .0801 = 457.70 MT

    H2O = 5714.08 x .1048 = 598.83 MT

    Ammonium Carbamate leaving the reactor =3243.50 x 0.4

    =1297.40 MT

  • 8/10/2019 Urea Kamal

    19/92

    19

    By reaction (3) H2O produced in reactor = 18 x 1497.00/60

    = 449.10 MT

    Total water coming out of the reactor = 598.83 + 449.10 MT

    = 1047.93 MT

    As CO2is the limiting component in the reactor, therefore NH3required for 1829.65 MT

    of CO2 = 2 x 17 x1829.65/ 44

    = 1415.82 MT

    NH3coming out of the reactor = (2827.901413.82) MT

    = 1414.08 MT

    Urea coming out of the reactor = (Urea in input) + (Urea formed in the reactor)

    = 457.70 + 1497.00

    = 1954.70 MT

    Therefore, composition of outlet from the reactor is:

    Urea = 1954.70 MT

    NH3 = 1414.08 MT

    H2O = 1047.93 MT

    Ammonium Carbamate = 1297.40 MT

  • 8/10/2019 Urea Kamal

    20/92

    20

    High Pressure Decomposer:

    Assumption :90% of ammonium carbamate reverts back to give NH3and CO2and also

    90% NH3and 15% of water goes out in the vapor stream to high pressure absorber.

    Amount of ammonium carbamate decomposed = 1297.40 x .90

    = 1167.66 MT

    Amount of ammonium carbamate going to low pressure = 1297.40 x .10

    Decomposer = 129.74 MT

    1167.66 MT of ammonium carbamate decomposed will give NH3 = 2 x 17 x 1167.6/ 78

    = 508.98 MT

    Total weight of NH3in high pressure decomposer = 508.98 + 1414.08

    = 1923.06 MT

    NH3going out in vapor stream =1923.06 x 0.9

    = 1730.75 MT

    NH2in low pressure decomposer = 1923.06 x .10

    = 192.30 MT

    Also, ammonium carbamate decomposed will give CO2 = 44 x 1167.66 / 78

    = 658.68 MT

    All the CO2goes back to the vapor stream

    CO2in the vapor stream = 658.68 MT

  • 8/10/2019 Urea Kamal

    21/92

    21

    Amount of water leaving in the vapor stream = 0.15 x 1047.93

    = 157.19 MT

    Amount of water in low pressure decomposer = 1047.93 x .85

    = 890.74 MT

    Low Pressure Decomposer

    Assumption :Assuming that 85% of ammonium carbamate reverts back to NH3 and

    CO2and 90% of NH3 and 15% H2O goes out in the vapor stream i.e. to high pressure

    absorber.

    Amount of ammonium carbamate decomposed = 129.74 x 0.85

    =110.28 MT

    Amount of ammonium carbamate going to separator = 129.74 x .15

    = 19.46 MT

  • 8/10/2019 Urea Kamal

    22/92

    22

    Ammonium carbamate decomposed will give NH3 = 2 x 17 x 110.28/ 78

    = 48.07 MT

    Total amount of NH3in low pressure decomposer = 48.07 + 192.31

    = 240.38 MT

    Amount of NH3going in vapor stream = 240.38 x 0.90

    = 216.34 MT

    Amount of NH3going in gas separator = 240.38 x .10

    = 24.04 MT

    Also ammonium carbamate decomposed will give CO2 = 44 x 110.28 / 78

    =62.21 MT of CO2

    Amount of Water in vapor stream = 890.74 x .15

    = 133.61 MT

    Amount of Water going to gas separator = 890.74 x .85

    = 757.13 MT

  • 8/10/2019 Urea Kamal

    23/92

    23

    GAS SEPERATOR

    Assuming all the ammonium carbamate decomposed to give NH3and CO2. All the NH3

    and CO2produced goes o the gas condenser and 15% of water goes to gas condenser.

    Ammonium carbamate decomposed to give NH3 = 2 x 17 19.46 / 78

    = 8.48 MT

    Total ammonia in gas separator = 8.48 + 24.04

    = 32.52 MT

    Ammonium carbamate decomposed to give CO2 = 44 x 19.46 / 76

    = 10.98 MT

  • 8/10/2019 Urea Kamal

    24/92

    24

    Crystallizer

    In the crystallizer 80% of water is evaporator or vaporized

    Amount of H2O vaporized = 0.8 x 643.56

    = 514.85 MT

    Amount of H2O left in urea solution = 0.2 x 643.56

    = 128.71 MT

  • 8/10/2019 Urea Kamal

    25/92

  • 8/10/2019 Urea Kamal

    26/92

    26

    Drier

    Assuming that 80% of water is removed. Also 0.6% of urea gets converted to biuret by

    reaction (1)Water removed from the solution = 0.80 x 25.74

    = 20.58 MT

    Water left in the solution = 0.20 x 25.4

    = 5.15 MT

    Biuret formed = 0.006 x 1497.00

    = 9.00 MT

    Total feed to reactor is:

    Urea = 457.70 MT

    CO2 = 1829.65 MT

    NH3 = 2827.90 MT

    H2O = 598.83 MT

    Recycle to reactor is:

    Urea = 457.70 MT

    CO2 = 731.87 MT

    NH3 = 593.88 MT

    H2O = 587.34 MT

  • 8/10/2019 Urea Kamal

    27/92

    27

    Gas Condenser

    Assuming we add 80 MT of water to gas condenser.

  • 8/10/2019 Urea Kamal

    28/92

    28

    High pressure absorber

    Assuming 30% of total NH3in high pressure absorber gets recycled to the reactor.

  • 8/10/2019 Urea Kamal

    29/92

    29

  • 8/10/2019 Urea Kamal

    30/92

    30

    ENERGY BALANCE

  • 8/10/2019 Urea Kamal

    31/92

    31

    Basis:One day operation

    In the reactor, the fresh NH3enters at 80C and 230 kg/cm2while CO2enters at 35 C

    and 230 kg/cm2. The recycle stream returning from high pressure absorber enters the

    reactor at 95C and 230 kg/cm2.

    The effect of pressure is very significant in case of gases but is not appreciable in solids

    and liquids and can be assumed to be negligible.

    Mean specific heat of liquid NH3between 25 to 200C:

    = ( Cpof liquid NH3at 25C + Cpof liquid NH3at 200C ) / 2

    = (1.147 + 1.341) / 2

    = 1.244 cal/gmC

    = 1.244 x 17

    = 21.148 cal/gm mol C

    Mean specific heat of gaseous NH3is = Cpmean between 25 to 200C

    T

    = Cp dT / (T-To)

    To

    473

    = (6.70 + 0.00630) T dT/ (473-298)298

    = 11.56 cal/gmolC

    Mean specific heat of H2O is = Cpmean between 25 and 200C

    = (1.0 + 1.2) / 2

    = 1.1 cal/gmC

    = 1.1 x 18

    = 19.80 cal/gmolC

  • 8/10/2019 Urea Kamal

    32/92

    32

    Mean specific heat of urea = Cpmean between 25 and 200C

    = (0.370 + 0.555) / 2

    = 0.4625 cal/gmC

    = 0.4625 x 60

    = 27.75 cal/gmolC

    Mean specific heat of ammonium carbamate = Cpmean between 25 and 200C

    = ( 0.410 + 0.62) / 2

    = 0.515 cal/gmC

    = 0.515 x 78

    = 40.17 cal/gmolC

    Mean specific heat of CO2 = Cpmean between 25 and 200C

    = T

    = (+T-/T2) dT / (T-To)

    To

    = {10.34(473-298) + (0.00274/2) (4732-2982) + 195500 (1/4731/298)}/ (473-298)

    = 10.009 cal/gmolC

    Cpmean of H2O vapor between 25 and 200C

    T

    = Cp dT / (T-To)To

    = [8.22(473-298) + (0.00015/2) (47322982)] / (473298)

    = 0.456 cal/g mol C

  • 8/10/2019 Urea Kamal

    33/92

    33

    Reactor

    From material balance

    In stream (1),

    NH3 = 2827.90593.88

    = 2234.02 MT

    Also,

    T1 = 80C

    Therefore,

    H1 = 2234.02 x 103x 1.244 x (80-25)

    = 152.85 x 106Kcal

    In stream (2),

    CO2 = 1829.65731.87

    = 1097.78 MT

    Also,

    T2 = 35C

    Therefore,

    H2 = 1097.78 x 103x 10.009 x (35-25) / 44

    = 2.52 x 106Kcal

  • 8/10/2019 Urea Kamal

    34/92

    34

    In stream (3),

    Urea = 457.70 MT

    NH3 = 593.88 MT

    CO2 = 731.87 MT

    H2O = 587.34 MT

    Also,

    T3 = 95C

    Therefore,

    H3 = [(457.70 x 0.4625) + (593.88 x 11.56/17) + (731.87 x 10.01/44)

    + (587.34 x 1.1)] x 103x (95-25)

    =99.97 x 106Kcal

    In stream (4),

    Urea = 1954.70 MT

    NH3

    = 1414.08 MT

    H2O = 1047.93 MT

    Amm.carbamate = 1297.40 MT

    Also,

    T4 = 120C

    Therefore,

    H4 = [(1954.70 x 0.4625) + (1414.08 x 11.56 / 17) + (1297.4 x 0.515)

    + (1047.93 x 1.1)] x 103x (120-25)

    =251.70 x 106Kcal

  • 8/10/2019 Urea Kamal

    35/92

    35

    In the reactor two reactions progress,

    Hr1= -38000 cal/gmol

    Hr2= +7500 cal/gmol

    Amount of Urea formed in reactor = 1954.70457.70= 1497.00 MT

    = 24.95 ton mol

    So Hr2 = 24.95 x 103x 7500

    = 187.125 x 106 Kcal

    Total amount of ammonium carbamate before it decomposes to urea:

    = 24.95 + 1297.4/78

    = 41.583 ton mol

    Total heat of reaction (1) at 25C = 41.583 x (-38000) x 103

    Hr1 = -1580.154 x 106Kcal

    Total heat of reaction (2) at 25C

    Htotal = Hr1+Hr2+ (H4- H1 - H2- H3)

    = [-1580.154 + 187.125 + 251.70152.852.5299.97] x 106

    = -1396.67 x 106Kcal/day

    Since it came negative i.e. heat is released.

  • 8/10/2019 Urea Kamal

    36/92

    36

    High pressure decomposer

    Now,

    For stream (1)

    H1 = 251.70 x 106Kcal ( from reactor energy balance)

    T1 = 120C

    For stream (2)NH3 = 1730.75 MT

    CO2 = 658.68 MT

    H2O = 157.19 MT

    Also, T2 = 55C

    H2 = [(658.68 x 10.01/44) + (157.19 x 0.456) + (1730.75 x 11.56/17)] x 103x (55-25)

    = 39.92 x 106Kcal

    For stream (3)

  • 8/10/2019 Urea Kamal

    37/92

    37

    NH3 = 192.31 MT

    Urea = 1954.70 MT

    H2O = 890.74 MT

    Amm. Carbamate = 129.74 MT

    T3 = 130C

    H3 = [(1954.70 x 0.4625) + (890.74 x 1.1) + (192.31 x 11.56/17) + (129.74 x 0.515)] x 103x

    (13025)

    = 218.55 x 106Kcal

    Now,

    The reaction in progress in high pressure decomposer is

    H = 38000 cal/gmol

    Ammonium carbamate decomposed at 25 C = 1297.40129.74

    = 1167.66 MT

    = 14.97 ton mol

    So,

    Hr = 14.97 x 38000 x 103

    = 568.86 x 106Kcal

    Htotal = Hr+ H2+ H3- H1

    = [568.86 + 39.92 + 218.55251.70] x 106

    = 575.63 x 106Kcal/day

    Therefore, total heat requirement in high pressure decomposer = 575.63 x 106Kcal/day

  • 8/10/2019 Urea Kamal

    38/92

    38

    REACTOR PROCESS

    DESIGN

  • 8/10/2019 Urea Kamal

    39/92

    39

    The rate expression for urea formation is found from different mechanism involved. The

    mechanism is as follows:

    The formation of urea takes place according to reaction (5).

    Hence its rate expression is:

    Therefore,

  • 8/10/2019 Urea Kamal

    40/92

    40

    Similarly,

    Also,

    So,

    Putting the value of CHO CNfrom (7) in (8), we get

    Assuming k6to be very small and hence neglecting it, we have

    From (6) and (9), we get

  • 8/10/2019 Urea Kamal

    41/92

    41

    Also,

    NH2 COO NH4is an intermediate.

    So,

    Substituting in (10), we get

    Substituting in the main rate expression, we have

    Putting

    Since the rate expression corresponds to stoichiometric equation the reaction iselementary.

  • 8/10/2019 Urea Kamal

    42/92

    42

    DESIGN OF REACTOR

  • 8/10/2019 Urea Kamal

    43/92

    43

    Where,

    A represents CO2

    B represents NH3

    C represents Urea

    D represents H2O

    So,

    CA= CAO(1-XA) / (1+AXA)

    CB= CBO(1-XB) / (1+ BXB)

    But,

    CBOXB = 2 CAOXA

    AndAXA BXB

    = (2-3) / 3

    = - 1/3

    So, putting these conditions in general rate equation

  • 8/10/2019 Urea Kamal

    44/92

    44

    Where,

    Feed to the reactor is on one day basis.

    So,

    = 1.1540 m3/min

    Similarly,

  • 8/10/2019 Urea Kamal

    45/92

    45

    = 3.3859 m3/min

    = 0.2464 m3/min

    = 0.4301 m3/min

    Therefore,

    Total volumetric flow rate = 1.1540 + 3.3859 + 0.2464 + 0.4301

    = 5.2164 m3/min

    Now,

    ()

    = 28.877 kmol/min

    Therefore,

    = 5.5358 Kmol/m3

    Similarly,

    ()

    = 115.519 kmol/min

    Therefore,

    = 22.1453 Kmol/m3

  • 8/10/2019 Urea Kamal

    46/92

    46

    Also,

    = 4

    The value of rate constant k for this reaction is k = 2.71 x 10-4(m3/Kmol)2min-1

    Substituting these

    values in equation

    (1)

    Now,

    CSTR with recycle

    For CSTR with recycle we have,

  • 8/10/2019 Urea Kamal

    47/92

    47

    Also,

    Therefore,

    Putting the value of rate equation in this equation, we get

    Here CAO = 5.5358

    So, Volumetric flow rate of Outlet

    = 0.6984 m3/min

    = 1.6931 m3/min

  • 8/10/2019 Urea Kamal

    48/92

    48

    = 1.0523 m3/min

    = 0.7527 m3/min

    Therefore,

    Total volumetric flow rate in outlet = 0.6984 + 1.6931 + 1.0523 + 0.7527

    =4.1965m3/min

    Again,

    Volumetric flow rate of recycle

    = 0.4616 m3/min

    = 0.7111 m3/min

    = 0.2464 m3/min

    = 0.4266 m3/min

    Therefore,

    Total volumetric flow rate in recycle = 0.4616 + 0.7111 + 0.2464 + 0.4266

    = 1.8457 m3/mi

  • 8/10/2019 Urea Kamal

    49/92

    49

    The reactor used for manufacture of urea has recycle stream as well. The recycle ratio R

    may be defined as:

    Volumetric flow rate of product leaving the system after recycle = 4.19651.8457

    = 2.3508 m3/min

    Therefore,

    = 0.7851

    Also,

    And

    XAf= 0.6

    Therefore,

    ( )

    = 0.2639

    Now putting these values in the equation we get

  • 8/10/2019 Urea Kamal

    50/92

    50

    where

    Now, lets plot the graph between f(XA) and XA

    XA 0 0.1 0.2 0.3 0.4 0.5 0.6

    f(XA) 0.0625 0.0695 0.0784 0.090 0.106 0.1286 0.1633

  • 8/10/2019 Urea Kamal

    51/92

    51

    Therefore,

    t = 214.82 x (Area of the rectangle shown)

    = 214.82 x (0.6-0.2639)x0.16

    = 11.55 min

    But,

    So,

    V = t x V0

    = 11.55 x 5.2164

    = 60.25 m

    3

    Dimensions : any convenient L/D ratio can be chosen.

    Let L/D = 4

    Volume of reactor,

    60.25 = D2x 4D / 4

    D = 2.68 m

    Length, L = 4D

    =10.71m

    Design and Selection of Head:

    The heads may be ellipsoidal, dished conical, hemispherical, flat. Standard ellipsoidal

    heads are somewhat stronger than dished heads of the same gage. Hemispherical heads

    are also stronger than formed heads but they are costlier. So taking cost into

  • 8/10/2019 Urea Kamal

    52/92

    52

    consideration I have selected the ellipsoidal head for the autoclave. The thickness of

    standard ellipsoidal head is given by thickness of standard ellipsoidal head is given by

    where,

    P = design pressure

    D = average diameter of shell

    S = allowable unit stress

    e = efficiency of joint (say 80%)

    therefore,

    = 0.1743 m

    Therefore,

    Thickness of ellipsoidal head = 174.3 + 6 mm = 180.3 mm

    For ellipsoidal head the inside depth is equal of inside dia of the shell. Therefore,

    ( )

    So, the inside depth of ellipsoidal head is 39.9 cm.

  • 8/10/2019 Urea Kamal

    53/92

    53

    SPECIF ICATION SHEET

    Equipment : Urea Autoclave

    Plant : Urea Plant

    Type : Plug Flow

    Position : Vertical

    No. of uni ts : 1

    Service : synthesis of Urea from NH3and CO2

    Operation : Continuous

    DESIGN DATA

    Operati on temperature : 200C

    Operating Pressur e : 230 kg/cm2

    Design Temperatur e : 200C

    Capacity : 43.703 m3

    Volumetri c F low rate : 4.1965 m3/min

    I nternal Diameter : 2.68 m

    Shell thickness : 0.1803 m

    Height : 10.71 m

    Types of top & bottom heads : Ellipsoidal

    Materi al of construction : Carbon Steel 1020

    Li ning Material : Titanium

  • 8/10/2019 Urea Kamal

    54/92

    54

    HIGH PRESSURE DECOMPOSER DESIGN

    High pressure decomposer is employed for decomposing ammonium carbonate to liberate

    NH3and CO2. In high pressure decomposer ammonium carbonate is heated by stream at

    13 kgf/cm2 pressure. The effluents from the reactor which are at 120C flows to high

    pressure decomposer which operates at 155C and 16 kgf/cm2 pressure, high pressure

    decomposer is a reboiler which is conventional 1-1 heat exchanger, vertical thermosiphon

    type.

    Total heat duty = 575.63 x 106kcal/day (from energy balance)

    = 23.984 x106kcal/hr

    Amount of stream required can be calculated as:

    Pressure of stream entering = 13 kgf.cm2

    Temperature of stream entering = 187C

    Latent heat of stream at this pressure = 470.743 kcal/kg

    But,

    Q = m x Latent Heat

    Therefore,

    23.984 x 106 = m x 470.743

    m = 50.95 x 103kg/hr

    = 849.15 kg/min

    Therefore, steam requirement is 849.15 kg/min.

    Selection of shell side and tube side fluids:The effluents from reactor can be passed on tube side whereas stream can be passed on

    shell side. The advantage of passing stream on shell side is that the steam that condensing

    can easily be removed by using a stream rap connected o shell. Secondly, the non

    condensable gases in stream can be vented easily by providing a vent value in shell.

  • 8/10/2019 Urea Kamal

    55/92

    55

    Tube side => Effluents from reactor

    Shell side => Stream

    Stream Effluents from reactor

    Temp in 187C 120C

    Temp out 187C 155C

    T1 = 187155

    = 32C

    T2 = 187120

    = 67C

    Evaluation of properties:

    Average temp of effluents from reactor = (120+155)/2

    = 137.5 C

    1.Specific Heat:

    Cpof NH3at 137.5C = 0.546 Kcal/kgC

    Cpof H2O at 137.5C = 1.10 Kcal/kgC

    Cpof Urea at 137.5C = 0.492 Kcal/kgC

    Cpof Amm. Carbamate at 137.5C = 0.576 Kcal/kgC

    Average value of specific heat of effluents = 0.594 Kcal/kgC

    2. Viscosity:

    Viscosity of urea = 3.25 cp

    Viscosity of NH3 = 0.014 cp

    Viscosity of H2O = 0.207 cp

    Since, the viscosity of urea is more, the average viscosity can be taken as that of

    urea.

    Therefore,

  • 8/10/2019 Urea Kamal

    56/92

    56

    average viscosity of effluents = 3.25 cp

    3. Density:

    Density of water = 928.12 kg/cm3

    Density of Urea = 1226 kg/cm3

    Density of NH3 = 580 kg/cm3

    Heat duty of reboiler = 23.984 x 106 Kcal/ hr

    Assume overall heat transfer coefficient = 600 W/m2 oC

    According

    Q = U x A x LMTD

    A = 984.6 m2

    Assuming

    Tube outer diameter = 20 mm

    Inside diameter = 16 mm

    Length = 4.83 mm

    So surface area = 3.14 x D x L

    = 0.303 m2

    No. of tubes = (984.6 / 0.303)

    = 3250 tubes

    Assuming no. of passes = 4

    So no. of tube/ passes = 3250 / 4

    = 812

    Cross section area of tubes = 3.14 x (16x10-2)2/4

    = 2.1x10-4

    So total flow area = 812 x 2.1x10-4

    = 0.170 m2

    Mass velocity of effluent

    = (1414.08 + 1954.70 + 1047.93 +1297.40) x 103 / (24x3600)

  • 8/10/2019 Urea Kamal

    57/92

    57

    = 66.135 Kg/sec

    Average density of effluent

    = 911.37 Kg/m3

    Mass velocity of effluent

    = 66.135 / 0.170

    = 389.03 Kg/m2/sec

    So velocity = 389.03 / 911.37

    = 0.4268 < 1 m/sec

    So consider 8 tube passes

    No. of tube/pass = 3250/8

    = 406 tubes

    So flow area = 406 x 2.1x10-4

    = 0.0853 m2

    Mass velocity = (66.135 / 0.0853)

    = 775.32 kg/m2sec

    Velocity = 775.32 / 911.37

    = 0.851 m/sec

    Finding Reynolds no.

    avg = 3.25x10-3poise

    = 3818.22

    L/D = 302

    So using graph Re v/s jHfor different L/D

  • 8/10/2019 Urea Kamal

    58/92

    58

    jH = 6.0x 10-3

    To calculate Pr

    Kcarb.= 0.138 w/moc Xcarb. = 0.22

    Kwater= 0.68 w/moc Xwater = 0.18

    Kurea = 0.28 w/moc Xurea = 0.26

    Kammonia= 0.032 w/moc Xammonia = 0.24

    So Kmix = KiXi

    = 0.23 w/moc

    Similarly

    Cpmix = CpiXi

    =2.4x103KJ/KgoC

    Pr no. = Cp/K

    = 34.64

    So tube side coefficient

    h D / k = jH*Re*Pr0.33

    By putting all values, we get

    h = 1269/10 w/m2 oc

    Assuming shell side coefficient = 1600 w/m2 oc

    Therefore ,

    Overall heat transfer coefficient

    (1/Uo) = (1/ho) + (do/dixhi) + (doln(do/di)/2kcu)

    = 604.38 >600

    so satisfactory.

    So this is 1-8 type shell and tube heat exchanger having U = 605 w/m2 oc

    To find tube side Pressure Drop:

    Pt= NP{8 Jf(L/di)(/w)-m+2.5}ut

    2/2

    Where ut=tube side fluid velocity

    NP=no of tube side passes

  • 8/10/2019 Urea Kamal

    59/92

    59

    Putting values,

    Pt=8*{8*6.81*10-3(4.83/16*10-3)+2.5}911.37*0.851*0.851/2

    Pt=50018.977Pa =50.018kPa or kN/m2

    Shell Diameter:-

    Bundle Diameter, Db=20(3250/0.0365)1/2.675

    =1.1469m

    Shell diameter from graph12.1=80+1.1469=81.1469m

    Assume baffle cut=25%

    Baffle spacing=Ds/5=1.469/5=0.299m

    Tube Pitch=1.25do=1.25*20*10-3

    =25mm

    Shell Side area=As=(Pt-do/Pt)*Ds*Bs

    =0.894m2

    Mass velocity Gs=849.15/0.0894=9498.322kg/m2

    Velocity=9498.322/s=21.93m/s

    De=1.27/d

    o(P

    t2-0.785d

    o2)

    De=19.7485mm

    Re=DeGs/ =179024

    J f=3.2*10-2(from Graph)

    Again For pressure drop,

    Ps=8J f(Ds/De)(L/Bs) sus2/2(/w)

    -0.14

    =31234Pa=312.34kPa

    Which is too high, it can be reduced by increasing baffle pitch .Doubling the pitch values,

    reduces Pressure Drop by

    Ps =312/4=78kPa.

  • 8/10/2019 Urea Kamal

    60/92

    60

    SPECIF ICATION SHEET

    Equipment : High Pressure Decomposer

    Plant : Urea Plant

    Type : Fixed, Head

    Position : Vertical

    No. of uni ts : 1

    DESIGN DATA

    UNIT DATA SHELL SIDE TUBE SIDE

    Fluid Steam Effluents from reactor

    Temp. Inlet C 187 120

    Temp. Outlet C 187 155

    Operating pressure kg/cm2 13 16

    No. of passes 1 1

    Fouling factor

    Pressure drop kPa 78 50.018

    Density kg/m3 1226

    Viscosity Cp 3.25

    Specific heat kcal/kg C 0.594

    Latent heat kcal/kg 470.743

    CONTRUCTION:

    Type of unit = Decomposer

    Tube pitch = 1 triangular

    Shell material = Carbon Steel

    Diameter = 35 inch

    Tube Material = Stainless Steel

    No. of tubes = 3250

    Outside Diameter = 1

  • 8/10/2019 Urea Kamal

    61/92

    61

    COST ESTIMATION

  • 8/10/2019 Urea Kamal

    62/92

    62

    Marshall & Swift index

    For the capacity of 60000 ton/yr

    Fixed capital investment in the year 1990 = 8 mn $

    But we have a capacity of 1500 tonn/day

    =360*1500 tonn/year

    Marshall & Swift index in the year 1990 = 904

    Marshall &Swift installment equipment index in the year 2008 = 1384

    So Fixed capital investment in urea production plant of capacity 360000 tonn/yr

    = C (Fe) Rx

    Where ,

    R = capacity of plant divided by the capacity of reference

    X = power factor for plant capacity ratio

    = 0.7

    Fe = ratio of index

    C = 8 mn$ *(1384/904)*(547500/60000)0.7

    = 57.573 mn$

    Estimation of capital investment cost(I) Direct Costs:

    1. Installation costs = 10% of fixed capital

    = $ 57.573 x 106x 0.10

    = $ 5.757 x 106

    2. Piping and instrumentation = 10 % of F.C.I.

    = $ 57.573 x 10

    6

    x 0.10= $ 5.757 x 106

    3. Electrical cost = 5 % of F.C.I.

    = $ 57.573 x 106x 0.05

    = $ 2.878 x 106

  • 8/10/2019 Urea Kamal

    63/92

    63

    4. Building cost = 10 % of F.C.I.

    = $ 57.573 x 106x 0.10

    = $ 5.757 x 106

    5. Service facility = 5 % of F.C.I.

    = $ 57.573 x 106x 0.05

    = $ 2.878 x 106

    6. Land cost = 5 % of F.C.I.

    = $ 57.573 x 106x 0.05

    = $ 2.878 x 106

    Total direct cost = 1 + 2 + 3 + 4 + 5 + 6

    = $ 25.906 x 106

    (II) Indirect Costs:

    1.

    Design and Engg. Cost = 25 % of Direct cost

    = $ 25.906 x 106x 0.25

    = $ 6.476 x 106

    2. Contractors feeCost = 10% of Direct cost.

    = $ 25.906 x 106x 0.10

    = $ 2.59 x 106

    3. Contingency allowance = 10% of Direct cost.

    = $ 25.906 x 106

    x 0.10= $ 2.59 x 106

    Total Indirect cost = 1 + 2 + 3

    = $ 11.656 x 106

  • 8/10/2019 Urea Kamal

    64/92

    64

    Working Capital

    Working Capital is the additional investment needed, over and above the fixed capital, to

    start the plant and operate it to the point when income is earned.

    It includes the cost of

    1. Start up

    2. Initial catalyst charges

    3. Raw material and intermediates in the process.

    4. Finished product inventories

    5. Funds to cover outstanding accounts from customers.

    Most of the working capital is recovered at the end of the project. The total investment

    needed for a project is the sum total of the fixed and working capital.

    Working Capital = 15 % of Total Capital Investment

    = 0.15 x TCI

    Now,

    Total Capital Investment = total F.C.I. + W.C.I.

    = F.C.I. + 0.15T.C.I.

    Total Capital Investment = F.C.I. / 0.85

    = 57.573 / 0.85

    = $ 67.733 x 106

    = Rs 338.66 x 107

    Estimation of Total Product Cost

    It includes direct cost, fixed charges and plant overhead cost.

    Manufacturing cost = Direct cost + Fixed charges + plant overhead cost

    (1.) Direct product cost

  • 8/10/2019 Urea Kamal

    65/92

    65

    (a) Raw material cost

    Cost of ammonia = 280$/unit

    Cost of carbon dioxide = 100$/ unit

    Cost of ammonia used = 2827.90*280*360

    = 285.05 mn$

    Cost of carbon dioxide = 1829.65*100*360$

    = 65.86mn$

    So ,

    Raw material cost = 285.05+65.86

    = 350.91mn$

    (b) Fixed charges:

    Life span for plant = 50 years

    (1.) Depreciation = Fixed capital investment/ life span

    = 57.573/ 50

    = 1.15mn$/yr

    (2.) local taxes

    Taking 1% of FCI = 0.5757 mn$

    Insurance = 0.2878 mn$

    So ,

    Total fixed cost = 2.0135mn $

    (c) Plant overhead cost:

    = 5%of FCI

    = 0.05*57.573 mn$

    = 2.8786 mn$

    So manufacturing cost

  • 8/10/2019 Urea Kamal

    66/92

    66

    = 355.80 mn$

    General expenses = 15% of FCI

    = 0.15*57.573

    = 8.636 mn$

    So ,

    Total production cost = 364.436mn$

    Cost of urea = 800 $/ton

    Urea produced from reactor = 1954.70MT/day

    = 360*1954.70MT/yr

    Total income = 1954.70*360*800

    = 562.95mn$

    So ,

    Profit = 562.95- 364.436

    = 198.51 mn$

    Taxes = 30% of gross earning

    = 0.30*198.51

    = 59.55mn$

    So ,

    Net profit = 138.95 mn$

    And

    Annual rate of return = 41.03%

  • 8/10/2019 Urea Kamal

    67/92

    67

    COST OF MAJOR EQUIPMENT

    (1.) Cost of reactor (Plug flow with recycle)

    Diameter = 2.68m

    Height = 10.71m

    From the graph

    Equipment purchase cost = 80,000 $

    For carbon steel,

    Material factor (MF) = 1

    Pressure factor (PF) = 2.2 (for pressure >60 bar)

    So,

    Purchase equipment cost for the year 2004

    = 80000 $ *(MF * PF)

    = 80000$ *(1*2.2)

    = 176000$

    So, purchase equipment cost for the year 2008

    = 176000* 1384/ 1277.33

    = 190697.28 $

    (2.) Cost of heat exchanger

    Type of heat exchanger: shell & tube type

    No. of tube passes = 8

    No. of shell passes = 1

    From log-log graph,Cost = 98000 $

    And,

    For carbon steel,

    Material factor = 1

    Pressure factor = 1.3(for pressure up to 65 bar)

  • 8/10/2019 Urea Kamal

    68/92

    68

    So,

    Purchased equipment cost of heat exchanger in 2004

    = 98000$ * 1*1.3

    = 127400 $

    So in 2008,

    = 127400*1384/ 1277.33

    138039.19 $

  • 8/10/2019 Urea Kamal

    69/92

    69

    GENERAL SITE CONSIDERATIONS

    PLANT LOCATION AND SITE SELECTION

    The location of the plant can have a crucial effect on the profitability of a project, and the

    scope for future expansion. Many factors must be considered when selecting a suitable

    site. The principal factors to consider are:

    1. Location, with respect to the marketing area.

    2. Raw material supply.

    3. Transport facilities.

    4. Availability of labor.

    5. Availability of utilities: water, fuel, power.

    6. Availability of suitable land.

    7. Environmental impact and effluent disposal.

    8. Local community considerations.

    9. Climate.

    10. Political and strategic considerations.

    Marketing areaFor materials that are produced in bulk quantities; such as cement, mineral acids, and

    fertilizers, where the cost of the product per tone is relatively low and the cost of

    transport a significant fraction of the sales price, the plant should be located close to the

    primary market. This consideration will be less important for low volume production,

    high-priced products; such as Pharmaceuticals. In an international market, there may be

    an advantage to be gained by locating the plant within an area with preferential tariff

    agreements; such as the European Community (EC).

    Raw materialsThe availability and price of suitable raw materials will often determine the site location.

    Plants producing bulk chemicals are best located close to the source of the major raw

    material; where this is also close to the marketing area.

  • 8/10/2019 Urea Kamal

    70/92

    70

    Transport

    The transport of materials and products to and from the plant will be an overriding

    consideration in site selection. If practicable, a site should be selected that is close to at

    least two major forms of transport: road, rail, waterway (canal or river), or a sea port.

    Road transport is being increasingly used, and is suitable for local distribution from a

    central warehouse. Rail transport will be cheaper for the long-distance transport of bulk

    chemicals. Air transport is convenient and efficient for the movement of personnel and

    essential equipment and supplies, and the proximity of the site to a major airport should

    be considered.

    Availability of labor

    Labor will be needed for construction of the plant and its operation. Skilled construction

    workers will usually be brought in from outside the site area, but there should be an

    adequate pool of unskilled labor available locally; and labor suitable for training to

    operate the plant. Skilled tradesmen will be needed for plant maintenance. Local trade

    union customs and restrictive practices will have to be considered when assessing the

    availability and suitability of the local labor for recruitment and training.

    Utilities (services)Chemical processes invariably require large quantities of water for cooling and general

    process use, and the plant must be located near a source of water of suitable quality.

    Process water may be drawn from a river, from wells, or purchased from a local

    authority. At some sites, the cooling water required can be taken from a river or lake, or

    from the sea; at other locations cooling towers will be needed. Electrical power will be

    needed at all sites. A competitively priced fuel must be available on site for steam and

    power generation.

    Environmental impact, and effluent disposalAll industrial processes produce waste products, and full consideration must be given to

    the difficulties and cost of their disposal. The disposal of toxic and harmful effluents will

    be covered by local regulations, and the appropriate authorities must be consulted during

  • 8/10/2019 Urea Kamal

    71/92

    71

    the initial site survey to determine the standards that must be met. An environmental

    impact assessment should be made for each new project, or major modification or

    addition to an existing process.

    Local community considerationsThe proposed plant must fit in with and be acceptable to the local community. Full

    consideration must be given to the safe location of the plant so that it does not impose a

    significant additional risk to the community. On a new site, the local community must be

    able to provide adequate facilities for the plant personnel: schools, banks, housing, and

    recreational and cultural facilities.

    Land (site considerations)Sufficient suitable land must be available for the proposed plant and for future expansion.

    The land should ideally be flat, well drained and have suitable load-bearing

    characteristics. A full site evaluation should be made to determine the need for piling or

    other special foundations.

    ClimateAdverse climatic conditions at a site will increase costs. Abnormally low temperatures

    will require the provision of additional insulation and special heating for equipment and

    pipe runs. Stronger structures will be needed at locations subject to high winds

    (cyclone/hurricane areas) or earthquakes.

    Political and strategic considerations

    Capital grants, tax concessions, and other inducements are often given by governments to

    direct new investment to preferred locations; such as areas of high unemployment. The

    availability of such grants can be the overriding consideration in site selection.

  • 8/10/2019 Urea Kamal

    72/92

    72

    SITE LAYOUT

    The process units and ancillary buildings should be laid out to give the most economical

    flow of materials and personnel around the site. Hazardous processes must be located at a

    safe distance from other buildings. Consideration must also be given to the future

    expansion of the site. The ancillary buildings and services required on a site, in addition

    to the main processing units (buildings), will include:

    1. Storages for raw materials and products: tank farms and warehouses.

    2. Maintenance workshops.

    3. Stores, for maintenance and operating supplies.

    4. Laboratories for process control.

    5. Fire stations and other emergency services.6. Utilities: steam boilers, compressed air, power generation, refrigeration, transformer

    stations.

    7. Effluent disposal plant.

    8. Offices for general administration.

    9. Canteens and other amenity buildings, such as medical centres.

    10. Car parks.

    When roughing out the preliminary site layout, the process units will normally be sited

    first and arranged to give a smooth flow of materials through the various processing

    steps, from raw material to final product storage. Process units are normally spaced at

    least 30 mapart; greater spacing may be needed for hazardous processes. The location of

    the principal ancillary buildings should then be decided. They should be arranged so as to

    minimize the time spent by personnel in travelling between buildings. Administration

    offices and laboratories, in which a relatively large number of people will be working,

    should be located well away from potentially hazardous processes. Control rooms will

    normally be located adjacent to the processing units, but with potentially hazardous

    processes may have to be sited at a safer distance. The sitting of the main process units

    will determine the layout of the plant roads, pipe alleys and drains. Access roads will be

    needed to each building for construction, and for operation and maintenance.

  • 8/10/2019 Urea Kamal

    73/92

    73

    Utility buildings should be sited to give the most economical run of pipes to and from the

    process units. Cooling towers should be sited so that under the prevailing wind the plume

    of condensate spray drifts away from the plant area and adjacent properties. The main

    storage areas should be placed between the loading and unloading facilities and the

    process units they serve. Storage tanks containing hazardous materials should be sited at

    least 70 m (200 ft) from the site boundary.

    A TYPICAL PALNT LAYOUT

  • 8/10/2019 Urea Kamal

    74/92

    74

    UTILITIES

    The word "Utilities" is now generally used for the ancillary services needed in the

    operation of any production process. These services will normally be supplied from acentral site facility; and will include:

    1. Electricity.

    2. Steam, for process heating.

    3. Cooling water.

    4. Water for general use.

    5. Demineralised water.

    6. Compressed air.

    7. Inert-gas supplies.

    8. Refrigeration.

    9. Effluent disposal facilities

    ELECTRICITYPower is required for chemical process, motor, lightening, pumps, compressor, & other

    general & mechanical purposes. It may be purchased from local supply authority or

    generated at plant by steam turbine, generator.

    STEAMThe steam for process heating is usually generated in water tube boilers; using the most

    economical fuel available. The process temperatures required can usually be obtained

    with low-pressure steam, typically 2.5 bar (25 psig), and steam is distributed at a

    relatively low mains pressure, typically around 8 bar (100 psig).

  • 8/10/2019 Urea Kamal

    75/92

    75

    COMBINED HEAT AND POWER (CO-GENERATION)The energy costs on a large site can be reduced if the electrical power required is

    generated on site and the exhaust steam from the turbines used for process heating. The

    overall thermal efficiency of such systems can be in the range 70 to 80 per cent;

    compared with the 30 to 40 per cent obtained from a conventional power station, where

    the heat in the exhaust steam is wasted in the condenser. Whether a combined heat and

    power system scheme is worth considering for a particular site will depend on the size of

    the site, the cost of fuel, the balance between the power and heating demands; and

    particularly on the availability of, and cost of, standby supplies and the price paid for any

    surplus power electricity generated.

    COOLING WATERNatural and forced-draft cooling towers are generally used to provide the cooling water

    required on a site; unless water can be drawn from a convenient river or lake in sufficient

    quantity. Sea water, or brackish water, can be used at coastal sites, but if used directly

    will necessitate the use of more expensive materials of construction for heat exchangers.

    WATER FOR GENERAL USE

    The water required for general purposes on a site will usually be taken from the local

    mains supply, unless a cheaper source of suitable quality water is available from a river,

    lake or well.

    DEMINERALISED WATER

    Demineralised water, from which all the minerals have been removed by ion-exchange, is

    used where pure water is needed for process use, and as boiler feed-water. Mixed and

    multiple-bed ion-exchange units are used; one resin converting the cations to hydrogen

    and the other removing the acid radicals. Water with less than 1 part per million of

    dissolved solids can be produced.

  • 8/10/2019 Urea Kamal

    76/92

    76

    REFRIGERATION

    Refrigeration will be needed for processes that require temperatures below those that can

    be economically obtained with cooling water. For temperatures down to around 10C

    chilled water can be used. For lower temperatures, down to30C, salt brines (NaCl andCaCl2) are used to distribute the "refrigeration" round the site from a central refrigeration

    machine. Vapor compression machines are normally used.

    COMPRESSED AIR

    Compressed air will be needed for general use, and for the pneumatic controllers that are

    usually used for chemical process plant control. Air is normally distributed at a mainspressure of 6 bar (100 psig). Rotary and reciprocating single-stage or two-stage

    compressors are used. Instrument air must be dry and clean (free from oil).

    INERT GASES

    Where large quantities of inert gas are required for the inert blanketing of tanks and for

    purging this will usually be supplied from a central facility. Nitrogen is normally used,

    and is manufactured on site in an air liquefaction plant, or purchased as liquid in tankers.

    EFFLUENT DISPOSAL

    Facilities will be required at all sites for the disposal of waste materials without creating a

    public nuisance.

  • 8/10/2019 Urea Kamal

    77/92

    77

    INSTRUMENT AND PROCESS CONTROL

    Instrumentation is the most important factor in ensuring safety and smooth working of

    the plant. A separate control room is provided in modern plants where on panels

    indicators and recorders are present.

    Instruments are used in the industry to measure process variables such as temperature,

    pressure, density, level specific heat, conductivity, humidity, flow rate, chemical

    composition etc.

    The primary objectives of the designer when specifying instrumentation and control

    schemes are:

    1. Safe plant operation:(a) To keep the process variables within known safe operating limits.

    (b) To detect dangerous situations as they develop and to provide alarms and

    automatic shut-down systems.

    (c) To provide interlocks and alarms to prevent dangerous operating

    procedures.

    2. Production rate:To achieve the design product output.

    3. Product quality:To maintain the product composition within the specified quality standards.

    4. Cost:To operate at the lowest production cost, commensurate with the other objectives.

    These are not separate objectives and must be considered together.

  • 8/10/2019 Urea Kamal

    78/92

    78

    TEMPERATURE CONTROL / MEASUREMENTS

    Various instruments are used for e.g.

    1. Thermocouple

    2. Resistance Thermometers

    3. Thermistors

    4. Mercury in Glass Thermometers.

    Controllers are used to maintain temperature within specified limits. Every temperature

    control problems is essential one. The temperature lay involved in the measurement of

    this variable is an important factor. Thermal element is usually placed in a well to protect

    it and allow servicing of element without interrupting the process. The location of the

    temperature element often has as much to do with the efficiency element often as other

    parts of the control loops. Temperature bulb should always be located at point where the

    coefficient of heat transfer will be as large as possible e.g. if vapors and liquid are at

    same temperature, then bulb should be kept in liquid because of high heat transfer

    coefficients.

    PRESSURE CONTROL / MEASUREMENTS

    It is quite necessary for most system handling vapours of gas. It can be measured by

    using pressure gauges.

    Self operated pressure regulation is often used in pressure control. It is installed directly

    in the line the control sensing apparatus is paced about 10 diameters from the unit. This

    location eliminates erroneous pressure caused by turbulence. Sudden change in velocity,

    shock and vibrations difficulties often occur when self operated regulation are used with

    liquids.

  • 8/10/2019 Urea Kamal

    79/92

    79

    LEVEL CONTROL / MEASUREMENT

    The measurement of level can be defined as the determination of location of interface

    with respect to a fixed plane. The main objective of a level control system is to maintain

    the level of the liquid in a tank at the Act point value. The different is pressure transmitter

    senses the pressure difference / a function of liquid level in the tank) and gives out an

    electrical signal, which after signal conditioning is given to the P.I.D. controller. The

    controller compares the measured variables with the set point and depending upon the

    error, gives an output to the control valve. The control value, in turn controls the flow.

    Due to the control of flow, the level is controlled to its set point.

    FLOW CONTROL / MEASUREMENTS

    It is defined as volume per unit time at specific temperature and pressure conditions. It is

    generally measured by positive displacement of rate meters.

    The process flow-sheet shows the arrangement of the major pieces of equipment and their

    interconnection. It is a description of the nature of the process. The Piping and Instrument

    diagram (P and I diagram) shows the engineering details of the equipment, instruments,

    piping, valves and fittings; and their arrangement. It is often called the Engineering Flow-

    sheet or Engineering Line Diagram.

    The P and I diagram shows the arrangement of the process equipment, piping, pumps,

    instruments, valves and other fittings. It should include:

    1. All process equipment identified by an equipment number. The equipment should be

    drawn roughly in proportion, and the location of nozzles shown.

    2. All pipes, identified by a line number. The pipe size and material of construction

    should be shown. The material may be included as part of the line identification number.

    3. All valves control and block valves, with an identification number. The type and size

    should be shown. The type may be shown by the symbol used for the valve or included in

    the code used for the valve number.

    4. Ancillary fittings that are part of the piping system, such as inline sight-glasses,

    strainers and steam traps; with an identification number.

  • 8/10/2019 Urea Kamal

    80/92

    80

    5. Pumps, identified by a suitable code number.

    6. All control loops and instruments, with an identification number.

    REACTOR CONTROL

    The schemes used for reactor control depend on the process and the type of reactor. If a

    reliable online analyzers is available, and the reactor dynamics is suitable, the product

    composition can be monitored and the reactor conditions and feed flows controlled

    automatically to maintain the desired product compositions and yield. More often, the

    operator is the final link in the control loop, adjusting the controller set points. Reactor

    temperature will normally be controlled by regulating the flow of heating and cooling

    medium. Pressure is usually held constant.

  • 8/10/2019 Urea Kamal

    81/92

    81

  • 8/10/2019 Urea Kamal

    82/92

    82

    INSTRUCTIONS FOR OPERATION

    Before starting, always make sure that the followings:

    No visible damage is evident in the system.

    All electrical switches are turned off.

    All water valves are closed.

    All valves are tightly closed.

    Start up procedure.

    Check the level in the tank.

    Switch on the main supply.

    Turn on the main pump.

    Open valve for pump.

    Start mechanical pump.

    Open the steam valve.

    Check the flow, temperature& pressure during the operation.

    System shut down.

    Reduce the flow of the feed & steam.

    Reduce all flow rates & wait for pasture to drop.

    Turn off the pump.

    When the flow slow down close the valve tightly to avoid cavitations.

    Disconnect the packing line.

  • 8/10/2019 Urea Kamal

    83/92

    83

    N START UP OF PLANT

    The testing phase of the start up requires about 10 days. First of all the utility systemconsisting of high and low pressure steam, process and instrument air, cooling water and

    electric power have to be tested. Pumps are greased and checked for absence of kindage.

    After all utilities and moving systems are ready, water is introduced in the system instead

    of feed and tightness of the plant is established on water testing. Instruments are checked

    for response and accuracy. The feed is then introduced in place of water and is allowed

    gradually to displace the water in the system.

    After the process has been fairly well stabilized on hand control, it is then placed on

    instrument control, and then the entire operation is brought under automatic process

    control. Each step is so adjusted that it gives most efficient performance.

    The first consideration must be given to the quality of products. The conversion of

    carbamate to urea in the reactor is greatly affected by temperature and pressure in the

    reactor. Hence skilled persons are required to maintain these constants at the required

    conditions.

  • 8/10/2019 Urea Kamal

    84/92

    84

    SAFETY

    General rules for the protection of personnel from moving machinery, hot equipment are

    to be observed, pipes and large equipments containing steam at high temperature and

    pressure and installed in the plant. Protection of the personnel from burns where blowing

    out of these materials can occur should be provided.

    Since the plant is an open air installation, hence the risks of poisoning and unnecessary

    housing should be avoided. Storage of combustible material at the site should be avoided.

    In the case of unconsciousness due to poisoning, artificial respiration should be applied.

    Hand operated fire extinguishers, fire carpets and emergency showers should be placed

    where ever possible. The extinguishers should be used against small fires and the firecarpets and the showers should be used when clothing has caught fire. The showers

    should also be used against burns from chemicals. Eye washers should be installed

    wherever necessary. Smoking should be forbidden in the plant.

    In case of fire it is normal to use water to keep the surrounding cool, until the leak

    resulting in the fire is shut off. All sparks should be avoided and welding should be

    exercised keeping in view that no combustible material is in close vicinity.

    For the protection of the personnel the following equipments should be available:

    1.

    Safety helmets and shoes which should be worn by persons when they are

    working.

    2. Goggles for protection against liquid and gases.

    3. Gloves for protection against heat.

    4. Respiration masks with filters for dust for protection against poisonous gases like

    NH3, etc.

    5. Ear stuffers or other devices for protection against noise.

    Ammonia vapours have pungent smell and they are alkaline. Even a small concentration

    of NH3 vapour or liquid may cause fatal damages. Persons employed in handling of

    gaseous and liquid NH3should wear gloves and respiratory masks with special filters.

  • 8/10/2019 Urea Kamal

    85/92

  • 8/10/2019 Urea Kamal

    86/92

    86

    manufacturing processes are, to a greater or lesser extent, inherently unsafe, and

    dangerous situations can develop if the process conditions deviate from the design values.

    The safe operation of such processes depends on the design and provision of engineered

    safety devices, and on good operating practices, to prevent a dangerous situation

    developing, and to minimize the consequences of any incident that arises from the failure

    of these safeguards.

    The term "engineered safety" covers the provision in the design of control systems,

    alarms, trips, pressure-relief devices, automatic shut-down systems, duplication of key

    equipment services; and fire-fighting equipment, sprinkler systems and blast walls, to

    contain any fire or explosion.

    THE HAZARDS

    Toxicity

    Most of the materials used in the manufacture of chemicals are poisonous, to some

    extent. The potential hazard will depend on the inherent toxicity of the material and the

    frequency and duration of any exposure. It is usual to distinguish between the short-term

    effects (acute) and the long-term effects (chronic). A highly toxic material that causes

    immediate injury, such as phosgene or chlorine, would be classified as a safety hazard.

    Whereas a material whose effect was only apparent after long Exposure at low

    concentrations, for instance, carcinogenic materials, such as vinyl chloride, would be

    classified as industrial health and hygiene hazards. The permissible limits and the

    precautions to be taken to ensure the limits are met will be very different for these two

    classes of toxic materials. Industrial hygiene is as much a matter of good operating

    practice and control as of good design.

    Control of substanceshazardous to health

    The employer is required to carry out an assessment the flanged joints (liable to leak),

    Ventilation: use open structures, or provide adequate to evaluate the risk to health, and

    establish what precautions are needed to protect employees. A written record of the

    assessment would be kept, and details made available to employees. The designer will be

  • 8/10/2019 Urea Kamal

    87/92

    87

    concerned more with the preventative aspects of the use of hazardous substances. Points

    to consider are:

    1. Substitution: of the processing route with one using less hazardous material or,

    substitution of toxic process materials with non-toxic, or less toxic materials.

    2. Containment: sound design of equipment and piping, to avoid leaks. For example,

    specifying welded joints in preference to gasket

    ventilation systems.

    4. Disposal: provision of effective vent stacks to disperse material vented from pressure

    relief devices; or use vent scrubbers.

    5. Emergency equipment: escape routes, rescue equipment, respirators, safety showers,

    eye baths,

    In addition, good plant operating practice would include:

    1. Written instruction in the use of the hazardous substances and the risks involved,

    2. Adequate training of personnel.

    3. Provision of protective clothing.

    4. Good housekeeping and personal hygiene.

    5. Monitoring of the environment to check exposure levels. Consider the installation

    of permanent instruments fitted with alarms.

    6. Regular medical check-ups on employees, to check for the chronic effects of toxic

    materials.

    Flammability

    The term "flammable" is now more commonly used in the technical literature than

    "inflammable" to describe materials that will burn, and will be used in this book. The

    hazard caused by a flammable material depends on a number of factors:

    1. The flash-point of the material.

    2. The auto ignition temperature of the material.

    3. The flammability limits of the material.

    4. The energy released in combustion.

    Explosions

  • 8/10/2019 Urea Kamal

    88/92

    88

    An explosion is the sudden, catastrophic, release of energy, causing a pressure wave

    (blast wave). An explosion can occur without fire, such as the failure through over-

    pressure of a steam boiler or an air receiver. When discussing the explosion of a

    flammable mixture it is necessary to distinguish between detonation and deflagration. If a

    mixture detonates the reaction zone propagates at supersonic velocity (approximately 300

    m/s) and the principal heating mechanism in the mixture is shock compression. In a

    deflagration the combustion process is the same as in the normal burning of a gas

    mixture; the combustion zone propagates at subsonic velocity, and the pressure build-up

    is slow. Whether detonation or deflagration occurs in a gas-air mixture depends on a

    number of factors; including the concentration of the mixture and the source of ignition.

    Unless confined or ignited by a high-intensity source (a detonator) most materials will

    not detonate. However, the pressure wave (blast wave) caused by a deflagration can still

    cause considerable damage. Certain materials, for example, acetylene, can decompose

    explosively in the absence of oxygen; such materials are particularly hazardous.

    Sources of ignition

    Though precautions are normally taken to eliminate sources of ignition on chemical

    plants, it is best to work on the principle that a leak of flammable material will ultimately

    find an ignition source.

    Electrical equipment

    The sparking of electrical equipment, such as motors, is a major potential source of

    ignition, and flame proof equipment is normally specified. Electrically operated

    instruments, controllers and computer systems are also potential sources of ignition of

    flammable mixtures.

    Static electricity

    The movement of any non-conducting material, powder, liquid or gas, can generate static

    electricity, producing sparks. Precautions must be taken to ensure that all piping is

    properly earthed (grounded) and that electrical continuity is maintained around flanges.

  • 8/10/2019 Urea Kamal

    89/92

    89

    Escaping steam, or other vapors and gases, can generate a static charge. Gases escaping

    from a ruptured vessel can self-ignite from a static spark.

    Process flames

    Open flames from process furnaces and incinerators are obvious sources of ignition and

    must be sited well away from plant containing flammable materials.

    Miscellaneous sources

    It is the usual practice on plants handling flammable materials to control the entry on to

    the site of obvious sources of ignition; such as matches, cigarette lighters and battery-

    operated equipment. The use of portable electrical equipment, welding, spark-producing

    tools and the movement of petrol-driven vehicles would also be subject to strict control

    Exhaust gases from diesel engines are also a potential source of ignition.

    Pressure

    Over-pressure, a pressure exceeding the system design pressure, is one of the most

    serious hazards in chemical plant operation. Failure of a vessel, or the associated piping,

    can precipitate a sequence of events that culminate in a disaster. Pressure vessels are

    invariably fitted with some form of pressure-relief device, set at the design pressure, so

    that (in theory) potential over-pressure is relieved in a controlled manner.

    Temperature deviations

    Excessively high temperature, over and above that for which the equipment was

    designed, can cause structural failure and initiate a disaster. High temperatures can arise

    from loss of control of reactors and heaters; and, externally, from open fires. In the design

    of processes where high temperatures are a hazard, protection against high temperatures

    is provided by:

    1. Provision of high-temperature alarms and interlocks to shut down reactor feeds, or

    heating systems, if the temperature exceeds critical limits.

    2. Provision of emergency cooling systems for reactors, where heat continues to be

    generated after shut-down; for instance, in some polymerization systems,

  • 8/10/2019 Urea Kamal

    90/92

    90

    3. Structural design of equipment to withstand the worst possible temperature excursion.

    4. The selection of intrinsically safe heating systems for hazardous materials.

    Steam, and other vapour heating systems, is intrinsically safe; as the temperature cannot

    exceed the saturation temperature at the supply pressure. Other heating systems rely on

    control of the heating rate to limit the maximum process temperature. Electrical heating

    systems can be particularly hazardous.

    Fire protection

    To protect against structural failure, water-deluge systems are usually installed to keep

    vessels and structural steelwork cool in a fire. The lower section of structural steel

    columns are also often lagged with concrete or other suitable materials.

    Noise

    Excessive noise is a hazard to health and safety. Long exposure to high noise levels can

    cause permanent damage to hearing. At lower levels, noise is a distraction and causes

    fatigue.

    The basic safety and fire protective measures that should be included in all chemical

    process designs are listed below:-

    1. Adequate, and secure, water supplies for fire fighting.

    2. Correct structural design of vessels, piping, steel work.

    3. Pressure-relief devices.

    4. Corrosion-resistant materials, and/or adequate corrosion allowances.

    5. Segregation of reactive materials.

    6. Earthing of electrical equipment.

    7. Safe location of auxiliary electrical equipment, transformers, switch gear.

    8. Provision of back-up utility supplies and services.

    9. Compliance with national codes and standards.

    10. Fail-safe instrumentation.

    11. Provision for access of emergency vehicles and the evacuation of personnel.

    12. Adequate drainage for spills and fire-fighting water.

  • 8/10/2019 Urea Kamal

    91/92

    91

    ENVIRONMENTAL CONSIDERATIONS

    All individuals and companies have a duty of care to their neighbors, and to the

    environment in general. In the United Kingdom this is embodied in the Common Law. In

    addition to this moral duty, stringent controls over the environment are being introduced

    in the United Kingdom, the European Community, the United States, and in other

    industrialized countries and developing countries. Vigilance is required in both the design

    and operation of process plant to ensure that legal standards are met and that no harm is

    done to the environment.

    Consideration must be given to:

    1. All emissions to land, air, water.

    2. Waste management.

    3. Smells.

    4. Noise.

    5. The visual impact.

    6. Any other nuisances.

  • 8/10/2019 Urea Kamal

    92/92

    REFERENCES

    1. Sinnot, R.K, Coulson and Richardsons Chemical Engineering, vol-6, Fourth

    edition, 2005

    2. Perry, Robert H, Green, Don W., Chemical Engineers Handbook, 1999

    3. McCabe, Warren L, Smith, Julian C, Harriott Peter Unit Operations of

    Chemical Engineering, Sixth edition, 2001

    4.

    Eckman, Donald P., Industrial Instrumentation, 1991

    5. Hesse, Herman C., Rushton, J.Henry, Process Equipment Design

    6. Peters, Max S.,Timmerhaus,Klaus D. Process Design and Economics for

    Chemical Engineers, Fourth edition , 1958

    7. Levenspiel, O., Chemical Reaction Engineering., 2ndEd., John Wiley.

    8. Hesse, H.C. and Rushton, J.H., Process Equipment Design, Niki D Van

    Nostrand Company Inc.

    9. Chapmon, Alan, J, Heat Transfer, 4thEd., Mc Millan.