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Differential Amplifiers
Differential amps take two input signals and amplify the differences (good signal) while rejecting their common levels (noise)Normal-mode input: differential changes in the input signalsCommon-mode input: both inputs change levels togetherA good differential amp has a high common-mode rejection ratio (CMRR) of about 106 (120 dB)Ratio of response for normal-mode signal to response for common-mode signal of the same amplitudeDifferential amps help us to understand operational amplifiers (coming in Lab 8)Differential Amplifiers in Electrocardiography
Differential Amplifier Construction
(+ or non-inverting input)
( or inverting input)
(single-ended output)
Differential Amplifier Construction
Long-tailed pair configuration:(The Art of Electronics, Horowitz and Hill, 2nd Ed.)
Differential Amplifier of Lab 61
+ input
input
output
Q1
Q2
Differential Amplifier Performance
Differential Amplifier Performance
(Student Manual for The Art of Electronics, Hayes and Horowitz, 2nd Ed.)
Differential Amplifier Performance:
Improving CMRR
(Lab 61)
Single-Ended Input Differential Amplifier
output (not inverted)
(Lab 61)
+ input
Example Problem 2.13
Solution details given in class.
Verify that and
. Then design a differential amplifier to your own specifications.
Bootstrapping
Standard emitter follower biasing scheme:Bootstrapping
Bootstrapping increases Zin at signal frequencies without disturbing the DC bias:(Lab 62)
Bootstrap Design
Want Thvenin resistance of bootstrap network at DC to be same as Thvenin resistance of bias voltage divider in original circuit (10k)Choose R3 = 4.7kThen R3 + R1R2 = 10k R1R2 = 5.3k 5kChoose R1 / R2 = 1 (same as original circuit)Solve for R1 and R2 from the above R1 = R2 = 10kChoose f3dB and calculate C2 or choose C2 and calculate f3dB using C2 = 10 mF, f3dB = 3.2 HzWe do the latter since we dont know choice of f3dBSimilarly, choose C1 and calculate f3dB,inFor C1 = 0.1 mF, f3dB,in = 16.9 HzTransistor Junction and Circuit Capacitance
Miller Effect
Consider the following amplifier with voltage gain G, with a capacitor connected between input and output:The effective input capacitance becomes Ceff = C(1 + G)According to the Miller model, the equivalent input circuit is:Ceff
Miller Effect
Source impedance (Rsource) and Ceff form a low-pass filter with an f3dB smaller than without Miller Effect(CMiller = Ceff)
Defeating Miller Effect
Reduce Rsource (Rsource = 0 eliminates Miller Effect)Arrange things so that base and collector of any one transistor do not head in opposite directions at the same timeDefeating Miller Effect
Cascode circuit(Lab 63)
Beating Miler Effect
Single-ended input differential amplifierDarlington Connection
VC
VE = 0 V
VB 1.2 V
0.6 V
(Lab 64)
IC
IB
Superbeta Transistor
Superbeta transistor used in Lab 65
(Lab 65)
(
)
E
e
C
R
r
R
G
+
=
2
diff
tail
CM
2
R
R
r
R
G
E
e
C
+
+
-
=
e
E
r
R
R
G
G
+
=
tail
CM
diff
CMRR
C
R
V
G
20
max
diff,
=
1
20
CMRR
max
R
V
=
B
C
Q
Q
I
I
=
=
2
1
Darlington
b
b
b
V
6
.
0
sat
,
CE
V