• Home

  • Documents

  • Typepad · Math 2 Test Review Fall 2011 Evaluate. 2 1-7, f(x) -2 3x — 4, 2. 5. 8. 11. Name Date...
3

Typepad · Math 2 Test Review Fall 2011 Evaluate. 2 1-7, f(x) -2 3x — 4, 2. 5. 8. 11. Name Date h(x) = f(x) = period 110 3. 6 9. 1. 4. 7. 3x+1, x > 5 —10

  • Upload
    others

  • View
    1

  • Download
    0

Embed Size (px)

Citation preview

Page 1: Typepad · Math 2 Test Review Fall 2011 Evaluate. 2 1-7, f(x) -2 3x — 4, 2. 5. 8. 11. Name Date h(x) = f(x) = period 110 3. 6 9. 1. 4. 7. 3x+1, x > 5 —10
Page 2: Typepad · Math 2 Test Review Fall 2011 Evaluate. 2 1-7, f(x) -2 3x — 4, 2. 5. 8. 11. Name Date h(x) = f(x) = period 110 3. 6 9. 1. 4. 7. 3x+1, x > 5 —10
Page 3: Typepad · Math 2 Test Review Fall 2011 Evaluate. 2 1-7, f(x) -2 3x — 4, 2. 5. 8. 11. Name Date h(x) = f(x) = period 110 3. 6 9. 1. 4. 7. 3x+1, x > 5 —10

Batxilergo Zientifiko-Teknikoa MATEMATIKA II · eta 1d=x2−3x+ r zeren 2x 2 + 5x = (x 2 + 3) + 2 (x 2 + x – 1) – (x 2 – 3x + 1) 3.- M3,4 multzoan, eman dezagun = 5 3 3 9 2

Batxilergo Zientifiko-Teknikoa MATEMATIKA II · eta 1d=x2−3x+ r zeren 2x 2 + 5x = (x 2 + 3) + 2 (x 2 + x – 1) – (x 2 – 3x + 1) 3.- M3,4 multzoan, eman dezagun = 5 3 3 9 2

Documents
ABSOLUTE VALUE INEQUALITIES. Just like absolute value equations, inequalities will have two solutions: |3x - 2| ≤ 7 3x – 2 ≤ 7 +2 +2 3x ≤ 9 x ≤ 3 -5/3

ABSOLUTE VALUE INEQUALITIES. Just like absolute value equations, inequalities will have two solutions: |3x - 2| ≤ 7 3x – 2 ≤ 7 +2 +2 3x ≤ 9 x ≤ 3 -5/3

Documents
2 6 5 15 x 3x f(x) = 3x 1. Addition 2. Subtraction 3. Multiplication 4. Division

2 6 5 15 x 3x f(x) = 3x 1. Addition 2. Subtraction 3. Multiplication 4. Division

Documents
Chapter 19 Technology … · Chapter 19 Technology. ... Perfect-Substitution Technologies 9 3 18 6 24 8 x 1 x 2 x 1 + 3x 2 = 18 x 1 + 3x 2 = 36 x 1 + 3x 2 = 48 All are linear and

Chapter 19 Technology … · Chapter 19 Technology. ... Perfect-Substitution Technologies 9 3 18 6 24 8 x 1 x 2 x 1 + 3x 2 = 18 x 1 + 3x 2 = 36 x 1 + 3x 2 = 48 All are linear and

Documents
3 3 4 4 3 3 4 4 = = 3 3 x 3x 3 x 3x 3 x 3x 3 x 3x 3 x 3x 3 x 3x 3

3 3 4 4 3 3 4 4 = = 3 3 x 3x 3 x 3x 3 x 3x 3 x 3x 3 x 3x 3 x 3x 3

Documents
Ejercicios de Matemáticas II 2º Bachillerato INTEGRALES III 1. · b) c) u 011,' clx — - clx e-x - du = 3 3x cos x clx u = 3X cit,' = cos x clx — sen x 3x cos x clx = 3x x —

Ejercicios de Matemáticas II 2º Bachillerato INTEGRALES III 1. · b) c) u 011,' clx — - clx e-x - du = 3 3x cos x clx u = 3X cit,' = cos x clx — sen x 3x cos x clx = 3x x —

Documents
HCDC: A Top-Down Perspective - Yipeng Huangyipenghuang.com/wp-content/uploads/2013/08/2014_05_02...1 – 3x 2 + 3x 2 Subject to constraints x 1 + 2x 2 - 2x 3 =< 4 x 1 + x 2 - x

HCDC: A Top-Down Perspective - Yipeng Huangyipenghuang.com/wp-content/uploads/2013/08/2014_05_02...1 – 3x 2 + 3x 2 Subject to constraints x 1 + 2x 2 - 2x 3 =< 4 x 1 + x 2 - x

Documents
Chapter 7 Answers - Welcome to CaltechAUTHORS - … · (x + ])sin x + cos x + C 3. x sin 5x/5 + cos 5x/25 + C 5. (x2 ... (x - 2)(x + 3l3l2 + C 33. x sin 3x/3 + cos 3x/9 + C 35. 3x

Chapter 7 Answers - Welcome to CaltechAUTHORS - … · (x + ])sin x + cos x + C 3. x sin 5x/5 + cos 5x/25 + C 5. (x2 ... (x - 2)(x + 3l3l2 + C 33. x sin 3x/3 + cos 3x/9 + C 35. 3x

Documents
matemática - emdombosco.files.wordpress.com · a) f(x) = x2 — 3x — x2 — 3x — 10 = 9x — x — 2x — I > O (concavidade para cima) f(x) > O para x < —2 ou x >

matemática - emdombosco.files.wordpress.com · a) f(x) = x2 — 3x — x2 — 3x — 10 = 9x — x — 2x — I > O (concavidade para cima) f(x) > O para x < —2 ou x >

Documents
MULTIPLYING BINOMIALS. Solve the following problems using the distributive property. x ( 3 + 7 ) = ( 2x + 3 ) x = 3x + 7x 10x 3x + 7x 10x 2x 2 + 3x

MULTIPLYING BINOMIALS. Solve the following problems using the distributive property. x ( 3 + 7 ) = ( 2x + 3 ) x = 3x + 7x 10x 3x + 7x 10x 2x 2 + 3x

Documents
1 Warm-up Factor the following x 3 – 3x 2 – 28x 3x 2 – x – 4 16x 4 – 9y 2 x 3 + x 2 – 9x - 9

1 Warm-up Factor the following x 3 – 3x 2 – 28x 3x 2 – x – 4 16x 4 – 9y 2 x 3 + x 2 – 9x - 9

Documents
Maths EXERCISE NO: 2 - seo-manager.s3.amazonaws.com · x 0.x 3x 6x 2x 10x 5 3 3x 0.x 5x _____ 6x 3x 10x 5 6x 0x 10x _____ 3x 0x 5 3x 0x 5 _____ 0 _____ 3x 6x 2x 10x 5 x 3x 6x 3

Maths EXERCISE NO: 2 - seo-manager.s3.amazonaws.com · x 0.x 3x 6x 2x 10x 5 3 3x 0.x 5x _____ 6x 3x 10x 5 6x 0x 10x _____ 3x 0x 5 3x 0x 5 _____ 0 _____ 3x 6x 2x 10x 5 x 3x 6x 3

Documents
ESPRESSIONI CON I POLINOMI - liceoeinsteinmilano.gov.it · bergamini_equazioni X filedivisione polinomi, 2di3 x 2 x (3x - filedivisione polino....pd x 1 x 3x-1 1 (x (2 x x 1 x) x

ESPRESSIONI CON I POLINOMI - liceoeinsteinmilano.gov.it · bergamini_equazioni X filedivisione polinomi, 2di3 x 2 x (3x - filedivisione polino....pd x 1 x 3x-1 1 (x (2 x x 1 x) x

Documents
ENGM 631 Optimization Using Solver. Sec. 3.1Alt. Model Max Z = 3X 1 + 5X 2 s.t. X 1 < 8,000 X 2 < 6,000 3X 1 + 4X 2 < 36,000 X 1 > 0 X 2 > 0

ENGM 631 Optimization Using Solver. Sec. 3.1Alt. Model Max Z = 3X 1 + 5X 2 s.t. X 1 < 8,000 X 2 < 6,000 3X 1 + 4X 2 < 36,000 X 1 > 0 X 2 > 0

Documents
1. Reglas de integración √3x 3 dx √3x 1 2 1 2 x dx x2 + 9 2–4x 4 L 2 dx x – 1 3x 2 2 3 3x 1 4(x – 1)4 dx (x – 1)5 (4x – 1)6 6 112. ∫ Solución: arc sen x + k 113

1. Reglas de integración √3x 3 dx √3x 1 2 1 2 x dx x2 + 9 2–4x 4 L 2 dx x – 1 3x 2 2 3 3x 1 4(x – 1)4 dx (x – 1)5 (4x – 1)6 6 112. ∫ Solución: arc sen x + k 113

Documents
Multiply. (x+3)(x+2) x x + x 2 + 3 x + 3 2 Bellringer part two FOIL = x 2 + 2x + 3x + 6 = x 2 + 5x + 6

Multiply. (x+3)(x+2) x x + x 2 + 3 x + 3 2 Bellringer part two FOIL = x 2 + 2x + 3x + 6 = x 2 + 5x + 6

Documents
EXATA.GG – GESTÃO GOVERNAMENTAL LTDA CNPJ - … · [A] 3x + x/8 = 4x. [B] 3x + x/2 = 4x. [C] 3x + 2x/8 = 4x. [D] 3x + 4x/2 = 4x. ESPAÇO PARA RASCUNHO CONHECIMENTOS GERAIS 16 –

EXATA.GG – GESTÃO GOVERNAMENTAL LTDA CNPJ - … · [A] 3x + x/8 = 4x. [B] 3x + x/2 = 4x. [C] 3x + 2x/8 = 4x. [D] 3x + 4x/2 = 4x. ESPAÇO PARA RASCUNHO CONHECIMENTOS GERAIS 16 –

Documents
1.00 Lecture 22 Systems of Linear Equations. 3x 0 + x 1 -2x 2 =5 2x 0 + 4x 1 + 3x 2 = 35 x 0 -3x 1 = - 5 31 -2x 0 5 243x 1 = 35 1 -30x 2 -5 A x =b 3 x

1.00 Lecture 22 Systems of Linear Equations. 3x 0 + x 1 -2x 2 =5 2x 0 + 4x 1 + 3x 2 = 35 x 0 -3x 1 = - 5 31 -2x 0 5 243x 1 = 35 1 -30x 2 -5 A x =b 3 x

Documents
EXAMPLE 5 Solve quadratic equations Solve (a) 3x 2 + 10x – 8 = 0 and (b) 5p 2 – 16p + 15 = 4p – 5. a. 3x 2 + 10x – 8 = 0 (3x – 2)(x + 4) = 0 3x – 2 = 0

EXAMPLE 5 Solve quadratic equations Solve (a) 3x 2 + 10x – 8 = 0 and (b) 5p 2 – 16p + 15 = 4p – 5. a. 3x 2 + 10x – 8 = 0 (3x – 2)(x + 4) = 0 3x – 2 = 0

Documents
Quadratic Formula. Solve x 2 + 3x – 4 = 0 This quadratic happens to factor: x 2 + 3x – 4 = (x + 4)(x – 1) = 0 This quadratic happens to factor: x 2

Quadratic Formula. Solve x 2 + 3x – 4 = 0 This quadratic happens to factor: x 2 + 3x – 4 = (x + 4)(x – 1) = 0 This quadratic happens to factor: x 2

Documents
DifferentiationDerefter skrives 3x^2,x), så der kommer til at stå: d(3x^2,x) (x til sidst betyder, at den uafhængige variable er x). F6 Enter Enter F3 1 3 x ^ 2 , x ) Enter Der

DifferentiationDerefter skrives 3x^2,x), så der kommer til at stå: d(3x^2,x) (x til sidst betyder, at den uafhængige variable er x). F6 Enter Enter F3 1 3 x ^ 2 , x ) Enter Der

Documents
Name:__________ warm-up 6-2 Using f(x) = 3x + 2 and g(x) = 2x 2 – 1, find (f – g)(x), if it exists. Using f(x) = 3x + 2 and g(x) = 2x 2 – 1, find (f ●

Name:__________ warm-up 6-2 Using f(x) = 3x + 2 and g(x) = 2x 2 – 1, find (f – g)(x), if it exists. Using f(x) = 3x + 2 and g(x) = 2x 2 – 1, find (f ●

Documents
o 2x+2 = 8 x 3x+3 = 9 x

o 2x+2 = 8 x 3x+3 = 9 x

Documents
 · 2020. 10. 3. · 2y + 4 2x - 3 x + 1 6y - 2 3x 5y -1 4y 5x + 5y 6y - 1 7x 7 - y 3x + 1 2x + 5 5B 6B ME E=A 7 x + 1 + x 4x + x 3x + 4x 4 x + x + 3 3x + 2x + 5x 2 + 10x - 2 4y +

 · 2020. 10. 3. · 2y + 4 2x - 3 x + 1 6y - 2 3x 5y -1 4y 5x + 5y 6y - 1 7x 7 - y 3x + 1 2x + 5 5B 6B ME E=A 7 x + 1 + x 4x + x 3x + 4x 4 x + x + 3 3x + 2x + 5x 2 + 10x - 2 4y +

Documents
Warm up Use Synthetic Division: 1. 3x 2 – 11x + 5 x – 4 2. 5x 5 + 3x 3 +1 x + 2

Warm up Use Synthetic Division: 1. 3x 2 – 11x + 5 x – 4 2. 5x 5 + 3x 3 +1 x + 2

Documents
upload.exam24h.com thi thu mon...22 2 xx2 2 2 x x x22 2 4x 3x 1 2x 4x 3x 1 2x lim 4x 3x 1 2x lim 4x 3x 1 2x 1 4x 3x 1 2x 3x 1 3 3 3 x lim lim lim 4x 3x 1 2x 4x 3x 1 2x 3 1 4 2 4 42

upload.exam24h.com thi thu mon...22 2 xx2 2 2 x x x22 2 4x 3x 1 2x 4x 3x 1 2x lim 4x 3x 1 2x lim 4x 3x 1 2x 1 4x 3x 1 2x 3x 1 3 3 3 x lim lim lim 4x 3x 1 2x 4x 3x 1 2x 3 1 4 2 4 42

Documents
 · 2 cot 4x 2 tan x + sec x x2 cos 2x 1 + sin x cos x tan 4 3x cos 2x f'(x) = (x + cos x)2 — + COS — (it) — 2 — + COS 2. 8. 11. 14. 20. 1 — sin — cos 3x y — —cosec

 · 2 cot 4x 2 tan x + sec x x2 cos 2x 1 + sin x cos x tan 4 3x cos 2x f'(x) = (x + cos x)2 — + COS — (it) — 2 — + COS 2. 8. 11. 14. 20. 1 — sin — cos 3x y — —cosec

Documents
FACTORING REVIEW EXAMPLES 1. Factor x 2 + 3x – 4Solve x 2 + 3x – 4 = 0 Graph Y 1 = x 2 + 3x – 4 Find x-intercepts What _____× _____ = – 4 and _____+ _____

FACTORING REVIEW EXAMPLES 1. Factor x 2 + 3x – 4Solve x 2 + 3x – 4 = 0 Graph Y 1 = x 2 + 3x – 4 Find x-intercepts What _____× _____ = – 4 and _____+ _____

Documents
WU #19 1.Simplify: 4x 2 – 2x + 4 + 3x 2 + 4x – 1 2.Multiply: (x + 7)(x – 2) 3.Multiply: (3x + 9)(7x – 1) 4.Multiply: (x + 1)(x – 1) 5.Multiply: (2x -

WU #19 1.Simplify: 4x 2 – 2x + 4 + 3x 2 + 4x – 1 2.Multiply: (x + 7)(x – 2) 3.Multiply: (3x + 9)(7x – 1) 4.Multiply: (x + 1)(x – 1) 5.Multiply: (2x -

Documents
Algebraic long division Divide 2x³ + 3x² - x + 1 by x + 2 x + 2 is the divisor The quotient will be here. 2x³ + 3x² - x + 1 is the dividend

Algebraic long division Divide 2x³ + 3x² - x + 1 by x + 2 x + 2 is the divisor The quotient will be here. 2x³ + 3x² - x + 1 is the dividend

Documents