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ACTL3002 Life Insurance and Superannuation Models Model Solutions to Tutorial 6 - held in Week 7 See Dickson, et al. Solutions Manual for assigned problems. In class exercises and presentations. 1. The only work required here is writing out the APV of future expenses which is given by APVFE = e 0 +(e 1 + e 2 · P x ) · ¨ a x + e 3 · A x . By the principle of equivalence, we have APVFP = APVFB + APVFE G · ¨ a x = A x + e 0 +(e 1 + e 2 · P x ) · ¨ a x + e 3 · A x = e 0 +(e 1 + e 2 · P x ) · ¨ a x + (1 + e 3 ) · A x which implies the expense-loaded premium is G = e 0 +(e 1 + e 2 · P x ) · ¨ a x + (1 + e 3 ) · A x ¨ a x = e 0 · (P x + d)+(e 1 + e 2 · P x ) + (1 + e 3 ) · P x = (1 + e 0 + e 2 + e 3 ) · P x +(e 1 + de 0 ) so that clearly, a = (1 + e 0 + e 2 + e 3 ) and c =(e 1 + de 0 ). 2. It is not stated in the problem whether this is fully-discrete, fully continuous, or otherwise. So, we make the assumption that this is a fully-discrete 10-year endowment policy. Note that for issue age x = 40, we have under De Moivre’s law, that k p 40 = 40+k 40 = 60 - k 60 . (a) Let G be the expense-loaded (or gross) annual premium. Thus, we have, by equating APVFP with APVFB+APVFE, G · ¨ a 40: 10 = 1000A 40: 10 + 50 where ¨ a 40: 10 = 9 X k=0 v k · k p 40 = 1 60 9 X k=0 v k · (60 - k) = ¨ a 10 - 1 60 (Ia) 9 =7.848055 and A 40: 10 =1 - d¨ a 40: 10 =0.6981517 so that G = 1000A 40: 10 + 50 ¨ a 40: 10 = 1000 (0.6981517) + 50 7.848055 = 95.329576. 1

Tutorial Solutions Week 6

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  • ACTL3002 Life Insurance and Superannuation ModelsModel Solutions to Tutorial 6 - held in Week 7

    See Dickson, et al. Solutions Manual for assigned problems.

    In class exercises and presentations.

    1. The only work required here is writing out the APV of future expenses which is given by

    APVFE = e0 + (e1 + e2 Px) ax + e3 Ax.

    By the principle of equivalence, we have

    APVFP = APVFB + APVFE

    G ax = Ax + e0 + (e1 + e2 Px) ax + e3 Ax= e0 + (e1 + e2 Px) ax + (1 + e3) Ax

    which implies the expense-loaded premium is

    G =e0 + (e1 + e2 Px) ax + (1 + e3) Ax

    ax= e0 (Px + d) + (e1 + e2 Px) + (1 + e3) Px= (1 + e0 + e2 + e3) Px + (e1 + de0)

    so that clearly, a = (1 + e0 + e2 + e3) and c = (e1 + de0).

    2. It is not stated in the problem whether this is fully-discrete, fully continuous, or otherwise. So, wemake the assumption that this is a fully-discrete 10-year endowment policy. Note that for issue agex = 40, we have under De Moivres law, that

    kp40 =`40+k`40

    =60 k

    60.

    (a) Let G be the expense-loaded (or gross) annual premium. Thus, we have, by equating APVFPwith APVFB+APVFE,

    G a40:10 = 1000A40:10 + 50where

    a40:10 =

    9k=0

    vk k p40 = 160

    9k=0

    vk (60 k)

    = a10 1

    60(Ia)9 = 7.848055

    andA40:10 = 1 da40:10 = 0.6981517

    so that

    G =1000A40:10 + 50

    a40:10=

    1000 (0.6981517) + 50

    7.848055= 95.329576.

    1

  • For year k = 1, 2, ..., 9, the gross premium reserve is given by

    kV = 1000A40+k:10k G a40+k:10k= 1000A40+k:10k 95.329576 a40+k:10k= 1000

    (1 da40+k:10k

    ) 95.329576 a40+k:10k= 1000 (1000(0.04/1.04) + 95.329576) a40+k:10k= 1000 133.791114a40+k:10k

    = 1000 133.791114(9ks=0

    vs s p40+k)

    = 1000 133.791114(9ks=0

    vs (

    1 s60 k

    ))

    = 1000 133.791114(a10k

    1

    60 k (Ia)9k).

    The values are summarized below:

    k 1 2 3 4 5 6 7 8 9

    kV 30.99 116.40 206.52 301.67 402.20 508.50 620.96 740.04 866.21

    (b) If we let a be the acquisition expense, in general, the gross annual premium will be

    Ga =1000A40:10 + a

    a40:10=

    1000 (0.6981517) + a

    7.848055= 88.9585702 +

    a

    a40:10

    and the gross premium reserve will be

    kV = 1000A40+k:10k Ga a40+k:10k= 1000A40+k:10k 88.9585702 a40+k:10k a

    (a40+k:10ka40:10

    )= 1000

    (1 da40+k:10k

    ) 88.9585702 a40+k:10k a( a40+k:10ka40:10)

    = 1000 (1000(0.04/1.04) + 88.9585702) a40+k:10k a(a40+k:10ka40:10

    )= 1000 127.420109a40+k:10k a

    (a40+k:10ka40:10

    ).

    Reserves will be negative if it ever hits negative at the end of the first year. This is because reserveis increasing obviously (because of the nature of the endowment insurance - not all reserves doincrease over time) with time and if it ever hits negative, it must be in the first year. Therefore,we must have

    1000 127.420109a41:9 a(a41:9a40:10

    )> 0

    or equivalently,

    a the prospective reserve at 4% = the retrospective reserveat 4%> the retrospective reserve at 3%

    - End of Tutorial 6 model solutions -

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