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Đề thi thử đại học chuyên Vinh -2013
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TRNG I HC VINH TRNG THPT CHUYN
KHO ST CHT LNG LP 12, LN 3 - NM 2013 Mn: TON; Khi: A v A1; Thi gian lm bi: 180 pht
I. PHN CHUNG CHO TT C TH SINH (7,0 im)
Cu 1 (2,0 im). Cho hm s 2231 24 += mxxy (1), vi m l tham s.
a) Kho st s bin thin v v th ca hm s (1) khi .34=m
b) Tm m th ca hm s (1) c ba im cc tr to thnh mt tam gic c tm ng trn ngoi tip trng gc ta O. Cu 2 (1,0 im). Gii phng trnh .2sin)cos2(sin2cos)cos1(3sin xxxxxx +=+ Cu 3 (1,0 im). Gii phng trnh ).5(212)2(3)12(4 322 xxxxxx +=++ Cu 4 (1,0 im). Tnh th tch khi trn xoay to thnh khi quay hnh phng gii hn bi cc ng
3,0,3
12
==++= xy
xxy xung quanh trc honh.
Cu 5 (1,0 im). Cho hnh lng tr '''. CBAABC c cc y l tam gic u cnh 3a. Hnh chiu vung gc ca 'C ln mt phng )(ABC l im D tha mn iu kin DBDC 2= . Gc gia ng thng 'AC v mt phng )'''( CBA bng .450 Tnh theo a th tch khi lng tr '''. CBAABC v tnh csin gc gia hai ng thng 'BB v AD. Cu 6 (1,0 im). Cho cc s thc khng m x, y, z tha mn 521211 2 =+++++ zyx . Tm gi tr ln nht ca biu thc .2 333 zyxP ++=
II. PHN RING (3,0 im) Th sinh ch c lm mt trong hai phn (phn a hoc phn b) a. Theo chng trnh Chun Cu 7.a (1,0 im). Trong mt phng vi h ta ,Oxy cho tam gic ABC c ),5;4( B phng trnh cc ng thng cha ng cao k t A v trung tuyn k t B ln lt l 073 = yx v .01 =++ yx Tm ta cc im A v C bit din tch tam gic ABC bng 16.
Cu 8.a (1,0 im). Trong khng gian vi h ta ,Oxyz cho cc ng thng ;2
311
1:1== zyxd
;1
12
21
:2== zyxd .
112
23:3
zyxd =+= Tm ta im P thuc 1d v im Q thuc 2d sao cho ng
thng PQ vung gc vi 3d v di PQ nh nht. Cu 9.a (1,0 im). Trong mt phng ta Oxy, tm tp hp im biu din cc s phc z tha mn
11 ++++
+z
izz
iz l s thun o.
b. Theo chng trnh Nng cao
Cu 7.b (1,0 im). Trong mt phng vi h ta ,Oxy cho im ).2;32(M Vit phng trnh chnh tc ca elp (E) i qua M bit rng M nhn hai tiu im ca (E) di mt gc vung.
Cu 8.b (1,0 im). Trong khng gian vi h ta ,Oxyz cho im )2;3;1(K v mt phng .03:)( =++ zyxP Vit phng trnh ng thng d i qua K, song song vi mt phng )(Oyz v to vi
(P) mt gc c .2tan = Cu 9.b (1,0 im). Gii h phng trnh ).,(
)log1(2)22(log)1(log)36(333.2
222
2
R
+=+++= +
yxyxyx
yxxyx
---------------------------- Ht --------------------------
Ghi ch: 1. BTC s tr bi vo cc ngy 18, 19/5/2013. nhn c bi thi, th sinh phi np li phiu d thi cho BTC.
2. K kho st cht lng ln cui nm 2013 s c t chc vo chiu ngy 15 v ngy 16/6/2013. ng k d thi ti vn phng trng THPT Chuyn t ngy 18/5/2013.
1
TRNG I HC VINH TRNG THPT CHUYN
P N KHO ST CHT LNG LP 12, LN 3 - NM 2013 Mn: TON Khi A, A1; Thi gian lm bi: 180 pht
Cu p n im
a) (1,0 im)
Khi 34=m hm s tr thnh .2
38
31 24 += xxy
1o. Tp xc nh: R=D , y l hm s chn. 2o. S bin thin:
* Gii hn ti v cc: .)238
31(limlim 42
4 +=+= xxxy xx
* Chiu bin thin: Ta c .,3
1634' 3 R= xxxy
===
20
0'xx
y ; >
m Khi th hm s c 3 im cc tr l )32;3(),2;0( 2mmBA v ).32;3( 2mmC
0,5
Cu 1.
(2,0 im)
Tam gic ABC c tm ng trn ngoi tip trng gc ta O khi v ch khi OCOBOA ==
0)133)(1()32(32 222 =++= mmmmmm
===
.
6213
0,1
m
mm
Kt hp iu kin 0>m ta c gi tr ca m l .6
213,1 +== mm
0,5
Phng trnh cho tng ng vi xxxxxxxx cos2sin2sin2sin2coscos2cos3sin +=+
.0)1sin)(cossin(cos
sincos2cossin3sin)sin2sincos2(cos2cos3sin
=++=
+++=+
xxxxxxx
xxxxxxxx
0,5
Cu 2.
(1,0 im)
* .4
1tan0sincos kxxxx +===+
xO 2
y
2
310
2
x +0 0 0 0 +'y
y 3
10
+
2
2
2+
+
310
2
*
+=
=
+=+
+=+=
+=
.22
2
244
244
21
4cos1sincos
kx
kx
kx
kxxxx
Vy nghim ca phng trnh l kx +=4
, .,22
,2 Z+== kkxkx
0,5
iu kin: .21x
Phng trnh cho tng ng vi )254(212)2(3 23 += xxxxxx v
+==
+=
)1()12(2123
2)12)(2(212)2(3
2
2
xxxx
xxxxxxx
0,5
Cu 3.
(1,0 im)
Phng trnh (1) tng ng vi
02123)12(2 2 =+ xxxx .0212.312.2 2 =+ xx
xx (2)
t .0,12 = txxt Khi phng trnh (2) tr thnh
,210)2)(12(0232 2 ==+=+ ttttt .0t
Suy ra ,3240482 ==+ xxx tha mn iu kin. Vy nghim ca phng trnh l .324,324,2 =+== xxx
0,5
Ta c .103
12
==++ x
xx
Th tch V cn tnh l th tch khi trn xoay to thnh khi quay hnh thang cong gii hn bi
cc ng 3,1,0,3
12
===++= xxy
xxy xung quanh Ox.
Suy ra
+++=+
+=3
122
3
12
2
d3
23
21d3)1( x
xxxx
xxV
( ) .3
d2)3ln4(3
d2|3|ln3
12
3
12
1
32
++=+++= x
xx
xxx (1)
0,5
Cu 4.
(1,0 im)
Tnh .3
d3
12
+=
xxI t .tan3 tx = Khi 1=x th ,
6=t khi 3=x th
3=t v
.cos
d3d 2 ttx = Suy ra .
63d
31
cosd3.
)tan1(31
3d 3
6
3
6
22
3
12
==+=+=
t
tt
txxI
Thay vo (1) ta c .33)3ln4(
2 +=V
0,5
T gi thit ).(' ABCDC V )'''//()( CBAABC nn .45'))'''(,'())(,'( 0=== ADCCBAACABCAC
S dng nh l cosin cho 7aADABD = 745tan' 0 aADDC == .
Suy ra th tch lng tr
.4219
43)3(.7.' 3
2
aaaSDCV ABC ===
Cu 5.
(1,0 im)
0,5
'B
A C
B
D
'C
a3 045
'A
3
V '//' BBAA nn ADAADAAADBB '),'(),'( == (1) V )(' ABCDC nn ,16''''''')'''(' 2222 aACDCDAACDCCBADC =+=
.11''' 22 aDCDCCCAA =+== Suy ra .771
'.2'''cos222
=+=ADAA
DAADAAADA (2)
T (1) v (2) suy ra .771|'cos|),'cos( == ADAADBB
0,5
Vi hai s khng m a, b ta c .1111 baba ++++++ (1) Tht vy, babababa ++++++++++ 122)1)(1(22)1( ,11 baabba +++++ lun ng. Du ng thc xy ra khi 0=a hoc .0=b p dng (1) ta c zyxzyx 21211212115 22 ++++++++++= .2212 2 zyx ++++ Suy ra ,8222 ++ zyx hay .
24
2xzy + (2)
0,5
Cu 6.
(1,0 im)
Khi .2
42)(232
333
+++ xxzyxP (3)
Ch rng, t (2) v x, y, z khng m ta c .220 x Xt hm s
323
242)(
+= xxxf trn ].22;0[ Ta c
[ ].)16(2)12()2(43
2436)(' 22
222 xxxxxxxxxf +=
=
Vi ]22;0[x ta c ===
.20
0)('xx
xf
T 232)22(,24)2(,64)0( === fff suy ra ].22;0[,64)( xxf (4) T (3) v (4) ta c ,64P du ng thc xy ra khi 4,0 === zyx hoc .4,0 === yzx Vy gi tr ln nht ca P l 64, t c khi 4,0 === zyx hoc .4,0 === yzx
0,5
.073:pt =+ yxBCAHBC ),37;( ccCBCC ).;73( aaAAHA +
Suy ra trung im AC l .2
73;2
73
+++ cacaM
Do .082012
732
7301: =+=+++++=++ cacacayxBMM (1)
0,5
Cu 7.a (1,0 im)
Ta c10
|1410|),(,410)312()4( 22 +===+= aBCAdAHcccBC
.16|)75)(4(|.21 =+== acAHBCSABC (2)
T (1) v (2) suy ra
====
.573;
536,
52;
529
)1;2(),3;2(
536,
52
2,3
CA
CA
ca
ca
0,5
Cu 8.a (1,0 im)
)1;22;(),32,,1( 21 ++++ qqqQdQpppPdP . Suy ra ).22;22;1( ++++= qpqpqpPQ
0)22(1)22(1)1(20.33 =++++++= qpqpqpPQudPQ 02 =++ qp hay .2+= qp
0,5
A
B H C
M
4
Suy ra .2727)3(245122)6(9 22222 ++=++=+++= qqqqqPQ Suy ra 33min =PQ khi 3,1 == qp hay ).2;4;3(),1;1;0( QP 0,5 Gi s yixz += v im biu din s phc z l ).;( yxM Ta c .
)1()1(22)(2
1||2)(||2
11 2222
2
2
yxixxyx
zzzizzizzz
ziz
ziz
++++++=+++
+++++=++++
+ 0,5
Cu 9.a (1,0 im)
11 ++++
+z
izz
iz l s thun o
=+
+
++=++
).0;1();(41
21
0)1(
02)(2 22
22
22
yx
yxyx
xyx
Vy tp hp im M l ng trn 41
21 2
2
=+
+ yx b i im ).0;1( 0,5
Phng trnh chnh tc ca ).0(1:)( 22
2
2
>>=+ baby
axE
.1412)( 22 =+ baEM (1)
.1642190 2221
021 ===== baccFFMOMFF (2)
0,5
Cu 7.b (1,0 im)
T (1) v (2) suy ra .1824
:)(8
24 222
2
=+ =
= yxEba
0,5
Phng trnh .0:)( =xOyz Gi s d c vtcp ).0(),;;( 222 ++ cbacbaud Ta c 0.1
0.
)()2;3;1()//( =
= a
nu
OyzKOyzd
Oyzd
hay .0=a Suy ra );;0( cbud v ).1;1;1(Pn 0,5
Cu 8.b (1,0 im)
Do 00 900 nn t .32sin2tan == M
22.3||))(,sin(cb
cbPd+
+=
.00)(32
.3|| 2
22===
++ cbcb
cbcb
Chn ).1;1;0(1 === ducb Suy ra phng trnh
+=+=
=
.231
:tzty
xd
0,5
iu kin:
>+>>.01
0,1xy
yx
Phng trnh th nht ca h tng ng vi xxyyx 6.3333.2 21 +=+ ++ .1333)32(3)32( 11 +==+=+ ++ xyxyxxyx
Phng trnh th hai ca h tng ng vi .2)1)(1(2log)1)(1(log 2222 yxyxyxyx =++=++
0,5
Cu 9.b (1,0 im)
T ta c
=>+=
=+>+=
=++>+=
01
0121
012)1)(1(
0122 xx
xyyxy
xyyxyx
xy
==
+=+=
.2
53,2
512
53,2
51
yx
yx
0,5
TRNG I HC VINH TRNG THPT CHUYN
KHO ST CHT LNG LP 12, LN 3 - NM 2013 Mn: TON; Khi: D; Thi gian lm bi: 180 pht
I. PHN CHUNG CHO TT C TH SINH (7,0 im)
Cu 1 (2,0 im). Cho hm s 2231 24 += mxxy (1), vi m l tham s.
a) Kho st s bin thin v v th ca hm s (1) khi 34=m .
b) Tm m th ca hm s (1) c ba im cc tr to thnh mt tam gic c tm ng trn ngoi tip trng gc ta O. Cu 2 (1,0 im). Gii phng trnh .2sin)cos2(sin2cos)cos1(3sin xxxxxx +=+ Cu 3 (1,0 im). Gii bt phng trnh ( ) ( )422 12323 xxxx
1
TRNG I HC VINH TRNG THPT CHUYN
P N KHO ST CHT LNG LP 12, LN 3 - NM 2013 Mn: TON Khi D; Thi gian lm bi: 180 pht
Cu p n im
a) (1,0 im)
Khi 34=m hm s tr thnh .2
38
31 24 += xxy
1o. Tp xc nh: R=D , y l hm s chn. 2o. S bin thin:
* Gii hn ti v cc: .)238
31(limlim 42
4 +=+= xxxy xx
* Chiu bin thin: Ta c .,3
1634' 3 R= xxxy
===
20
0'xx
y ; >
m Khi th hm s c 3 im cc tr l )32;3(),2;0( 2mmBA v ).32;3( 2mmC
0,5
Cu 1.
(2,0 im)
Tam gic ABC c tm ng trn ngoi tip trng gc ta O khi v ch khi OCOBOA ==
0)133)(1()32(32 222 =++= mmmmmm
===
.
6213
0,1
m
mm
Kt hp iu kin 0>m ta c gi tr ca m l .6
213,1 +== mm
0,5
Phng trnh cho tng ng vi xxxxxxxx cos2sin2sin2sin2coscos2cos3sin +=+
.0)1sin)(cossin(cos
sincos2cossin3sin)sin2sincos2(cos2cos3sin
=++=
+++=+
xxxxxxx
xxxxxxxx
0,5
Cu 2.
(1,0 im)
* .4
1tan0sincos kxxxx +===+
xO 2
y
2
310
2
x +0 0 0 0 +'y
y 3
10
+
2
2
2 +
+
310
2
*
+=
=
+=+
+=+=
+=
.22
2
244
244
21
4cos1sincos
kx
kx
kx
kxxxx
Vy nghim ca phng trnh l kx +=4
, .,22
,2 Z+== kkxkx
0,5
Bt phng trnh cho tng ng vi .0233)3(2 224
3
V '//' BBCC nn '.),'(),'( ACCACCCACBB == (1) Ta c 222222 14'',11'' aADDCACaDCDCCC =+==+=
.111
'.2'''cos222
=+=CCCA
ACCCCAACC (2)
T (1) v (2) suy ra .111'cos),'cos( == ACCACBB
0,5
T gi thit ta c )21)(1(22216 22 yxyx +++++= .21222221222 22222 yxyxyxyxyx +++++++++++= T ta c ,321 2 ++ yx hay .822 + yx Suy ra .220,
24
2
xxy
Khi 2++ x
yxP .2
22
12
22
222
42
+++=+++=+
+
xxx
xx
x
x
x (1)
0,5
Cu 6.
(1,0 im)
Xt hm s 2
22
1)( +++= xxxf trn ].22;0[ Ta c
].22;0[,0)2(2
4)(' 22
++= x
xxxxf
Suy ra .22)22()( = fxf (2) T (1) v (2) ta c ,22P du ng thc xy ra khi .0,22 == yx Vy gi tr ln nht ca P l ,22 t khi .0,22 == yx
0,5
.073:pt =+ yxBCAHBC ),37;( ccCBCC ).;73( aaAAHA +
Suy ra trung im AC l .2
73;2
73
+++ cacaM
Do .082012
732
7301: =+=+++++=++ cacacayxBMM (1)
0,5
Cu 7.a (1,0 im)
Ta c 10
|1410|),(,410)312()4( 22 +===+= aBCAdAHcccBC
.16|)75)(4(|.21 =+== acAHBCSABC (2)
T (1) v (2) suy ra
====
.573;
536,
52;
529
)1;2(),3;2(
536,
52
2,3
CA
CA
ca
ca
0,5
)1;22;(),32,,1( 21 ++++ qqqQdQpppPdP . Suy ra ).22;22;1( ++++= qpqpqpPQ
0)22(1)22(1)1(20.33 =++++++= qpqpqpPQudPQ 02 =++ qp hay .2+= qp
0,5
Cu 8.a (1,0 im)
Suy ra .2727)3(245122)6(9 22222 ++=++=+++= qqqqqPQ Suy ra 33min =PQ khi 3,1 == qp hay ).2;4;3(),1;1;0( QP
0,5
Cu 9.a
Gi s yixz += v im biu din s phc z l ).;( yxM Ta c .
)1()1(22)(2
1||2)(||2
11 2222
2
2
yxixxyx
zzzizzizzz
ziz
ziz
++++++=+++
+++++=++++
+ 0,5
A
B H C
M
4
(1,0 im)
11 ++++
+z
izz
iz l s thun o
=+
+
++=++
).0;1();(41
21
0)1(
02)(2 22
22
22
yx
yxyx
xyx
Vy tp hp im M l ng trn 41
21 2
2
=+
+ yx b i im ).0;1( 0,5
Phng trnh chnh tc ca ).0(1:)( 22
2
2
>>=+ baby
axE
.1412)( 22 =+ baEM (1)
.1642190 2221
021 ===== baccFFMOMFF (2)
0,5
Cu 7.b (1,0 im)
T (1) v (2) suy ra .1824
:)(824 22
2
2
=+ =
= yxEba
0,5
Phng trnh .0:)( =xOyz Gi s d c vtcp ).0(),;;( 222 ++ cbacbaud Ta c 0.1
0.
)()2;3;1()//( =
= a
nu
OyzKOyzd
Oyzd
hay .0=a Suy ra );;0( cbud v ).1;1;1(Pn 0,5
Cu 8.b (1,0 im)
Do 00 900 nn t .32sin2tan == M
22.3||))(,sin(cb
cbPd ++=
.00)(32
.3|| 2
22===+
+ cbcbcb
cb
Chn ).1;1;0(1 === ducb Suy ra phng trnh
+=+=
=
.231
:tzty
xd
0,5
iu kin:
>+>>.01
0,1xy
yx
Phng trnh th nht ca h tng ng vi xxyyx 6.3333.2 21 +=+ ++ .1333)32(3)32( 11 +==+=+ ++ xyxyxxyx
Phng trnh th hai ca h tng ng vi .2)1)(1(2log)1)(1(log 2222 yxyxyxyx =++=++
0,5
Cu 9.b (1,0 im)
T ta c
=>+=
=+>+=
=++>+=
01
0121
012)1)(1(
0122 xx
xyyxy
xyyxyx
xy
==
+=+=
.2
53,2
512
53,2
51
yx
yx
0,5