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Lecture 7 : Refs : D . Arovas notes ch
.
5 z . ,
kinetic theory& the Boltzmann equation
Reit ch . 12-14Kardar
,Stat . phys of particles .
Kinetic theory : Study of macroscopic properties of many- particle
Systems using microscopic equation , of motion.
Imagine we have a systemof N particles described by
the Hamiltonian
H = EYL'¥m + ukil ) + ,§ ucxix ;)
The probability of finding particlei at x ; within dei and
with momentum p ; within dpi is
g( × , , ... ,×n ; P , , ... ,pn ) dxidp , . . . . dxwdpnat
Remebr from the first lecture that if (there denoted by f )
satisfies the Lionville 's theorem ,which States
that g
behaves like an incompressible fluid , that is
dg dg- =o or a =
- { 9. H }dt
where the Poisson bracket { A ,B } isdefined by
{ A B}=§(°Fga9±pa - ftp.ofa )= . { Bint
This results in the continuity equation
0g with x=( 7. P )
of+ 17×194=0
v = 1 if ,p.
)
7-2
For macroscopic observables , g contains wayto much
information. often it will be sufficient to know only
one or few body densities . we are now particularlyinterested in the one . body
distribution
f trip ;t ) = § ( 8( Iiltl-FISIF ,.lt ' - F ) )
= N f,
.tt#ddxiddPiglr,xr....xn;F.Fu...Fn;t )
The one - body distributionfunction satisfies
) d3p fliip , E) = n( t.tl densityof particles
fd3r nc Fit ) = Ntotal number of particles
and
f ( F , F ; t ) dridp
is the number of particles in a volumeDF around
F and with momentum range d§ around I
If there is no potential v ( 51 , suchthat
translation symmetry is preserved ,the equilibrium
distribution is
f°lF .FI = pthfmksphe- %mkBT
with n=F
7-3
If we know f we can compute expectation values ofobservables that only depend
on F and F,
such as
particle current
%it) = Sdf
fliip;t )
IM
and energycurrentjdritl
= fdf flip ;tl Elp )Em
etc . we now want to obtain an equation that
allows us to calculate f systematically .
The Boltzmann equation
Consider the flow of phase space volume in the
absence of collisions between particles
- ttdtt ^
+ n Q"% drtdp
'
DFDF>
,
Lionville 's theorem States the flow in phase spaceis
Incompressible , i.e. , that dFdF=dF' df'
,
or
f ( Ftidt , ftp.dt , ttdt )dF' df'
= f( i. Fit ) didp
Taylor expandingwe then obtain
¥+o±÷+ :÷i=o
7-4
Keeping in mind that we are assuming there are no
collisions,
that is H = EIP ) + Ue×+( F ),
we have
E= dat = 9¥ = off
=icp)
is = -9¥ = . off = text
Therefore
I+
t.SI+ E. ftp. = 0
at
This onlydescribes the eftet of the motion without
ay
collision . To descnipe themotion realistically we need
to take into account theeffects of collisions .
This Is written in terms of acollision integral , which
at this point we simply write as
÷+o . :÷+÷o¥=l¥t . "Note : sometimes people write
tooth.
= - t.IE . E. of
for a streaming term ,and then
o¥=l¥hwH¥h. "
making explicit that there aretwo distinct contributions
to
the time evolution of f , streamingmotion and collisions .
7-5
Collisions
We assume collisions are elastic Naturally , there will be-
Some observables that are invariants ofthe motion and
need to be conserved by the collisions( such as energy ,
Momentum,
particle number ) .Consider an observable
given by the functionAir , F)
,
such that its expectation
value is
AH ) = fdidp Ali , F) f IF , F)
Taking thetime derivative
date = fdidf Air.FI#=sa=aeairiFlfiooota-EfIttEh
. ")=saiap[o÷. # f+F÷IIf +
Aloft. " ]
where we use thatit is independent of F
and E= jo .
Now
oo÷oE+o÷¥t=f÷9¥io÷. :# =Landwhere Ho is the Hamiltonian
without collisions . Since
{ A. Ho } = It gires the timeevolution between
collisions,
It
and we assumeA to be conserved by
that motion,
the
first two terms above must give zero
.
That rs
day = Sdidpaeriplfott). . "
7-6
Quantities that are conserved by the collisions have £¥←=o .
Examples : A=1 particle number
A =pmomentum
A= Elf ) energy.
Scatteringprocesses
What processescontribute to the collison integral ?
i ) single particle scattering #}Define the rate w(P→P
'
) such that
w( Pip'
)f( F,
F. E) df 'dF
is the rate at which particles within df of ( F.F) scatter
into within df'
of IF'ir ) at time t .
The differential cross section is then
do = w(Pi'P# delnivl
- 1
ii ) Two . particle scattering PIXXP'
x ×/ F
'
PT i
In similar way asin
the single particle scattering we definethe rate
WCPTI -7 PYFZ'
)fz( F. F, ;i ,Fa ;t1dEdF2
at which two particles within df , of P ,and dpzot Fz
scatter within DF ,'
ot F,' and dfz ' of Fz
'
at time t .
7-7
Here fz is the two . particle distribution function
fzlip ; F 'F'
;t)=§ <81 Iiltl - F) SIPIHI - F) SIXTH - FYJIPTHI - F
'
) >
and the differential cross section
do = ¥521152'
) IF 'dpi'
IT , - Jzl
Note that we have assumed the scattering Occurs locally .
This essentially amountsto treating each scattering process
independently and that the scatteringtakes place on length
scale small compared with meandistance between particles .
Equivalently , the scatteringtime to is the smallest time
scale in the problem andin particular is
much smaller
Mean free time T , i.e. tea< < I
.
This assumption
requires low density ,such as is
obtained in gases
but not in dense liquids.
If 5 is the totalcross section
,the mean free time is
defined such thatin the Volume
orx ✓ E there
#-) trotmeanehr,
• has units
c- ve -
should be on average one particle ,i. a.
,
or t =
nvooven= 1
E
For single particle scattering v is the average velocity ,while
7-8
for two particle scattering it 's the average relative velocity .
V = < Iv , - ✓ 217.
Let's focus on the two particle scattering from now on .
N±oe: The one particle scattering requiresa potential that
breaks translation invariance . This can for example happen
if there is disorderin the system . In a gas this might
be dust particles . In a relatively clean environmentthe
two particle processes maydominate . This is not
necessarily always true .
With the definition of the rates , weknow how to
wrote
down the collision integral :
#t )a , ,
= |dFsdIidPi WCP , 'Pz'
-7 Fizlfzlioir; Pir ;t )[
e. , ; # it ')- w( Fit → Bi Fi )fzlPNote that this depends on fz and not only f .
The differential
equation for f therefore doesnot close
.
we wouldin
Principle nowneed to write
down a differential equation
for fz but wewould find that it depends
on
fz the three - bodydistribution
,which In turn depends
on
f , etc . ( seeKardw for details ) . To close the set of
equation we new to makean approximation .
7- 9We therefore make the assumption of Molecular
chaos
( or Stoss Zal - Ausatz ) that
fz( F. R,
;F. Fz ) = f ( i ,E) FIF , PI ) .
Note that when we use this approximation in the
expression for ( ft ). , ,
it is used for the two particles
just betorc the collisiontakes place . If the motion
of
all the particles in the long finebetween the
collision
is chaotic ( hence the name ) we can safely
assume
that the particles are not correlatedbefore the
collision.
To make further progress , we usetime - reversal
invariance and parity symmetry ofthe microscopic
motion which together imply
wlpi ,I→ PYE'
) Iwl - Fi , - Fi - ' - Fi, -E) I wtpipz'
-7 I. E)
Using this weobtain ( surpassing
F in the notation )
( 0¥ ). , ,
=|dFzdpYdPi' WIFPI 'PYFil[ftp.lflpi ) - ftp.lflp . ) ]
7-10
The transition probability wlpipz- s PYPI' ) is highly constrained
by conservationlaws :
B. tpz = F.'
+ Ez'
conservation of momentum
¥L+ Man = HE + If'
conservation at energy
This means that the length of the relativemomentum
191=1152-In = pit P ,'
- zi , .E = (Pip + IPi )'
- 2,5,
!Fi= lpi'
- Fil
is conserved . It can however be rotated by a solid angle£
i. c .
Pz'
- PY = II. . Fire where bil=1 .
Thus, Knowing F, ,F, and a gives F,
'and PI via
15,'
=I Iftp.lpipili )Fi = ±( PT + In + lpi - Pilr )
Taken together this meansthat
Sdi, 'fdF .' wlpipi → F.
' PI ) ( ftp.ilflpil-ftplffpz ) ]
2 O_0 oo
= fdr or w -KI[ ftp.llflpil - ftp.lflpz ) ]where we used the definition of the differential Cross section .Altogether we get the Boltzmann equation ;
Get + ii. ftp.E.fpf-fdpzdpidpi' WIFPI ' ' PYPI 'l[ftp.lflpi ) - ftp.lflp . ) ]do
= fdfzfd's
Jr 15 -521 [ ftp.llflpil - ftp.lflpz ) ]
7-11
Boltzmann 's H - theorem
DefineHIT ) = fdidpflr.pt ) ln f C F. F. t )
If f satisfies the Boltzmann equation , then
¥I 0
dt
-Proof :
daft = fdidp ¥ ( lnfti ) = fdrtdp ¥lnf[
since fdoidpf = N independentof time .
f F, =f( By)
= Said ,i{[ i. of' - E. 0¥' ]enfI , I+
ftp.dhdfelfuillfifziff
, ] lnf,
}£
fz=f( Fz ) etc .
The first part with the streaming terms is Zero , ascan be
Checked by repeated partial integration( check ! )
since we are integrating over F , and iz we can change thelabels without changing the integral . Using ( schematically )
I = t(fdPTdPz( IIP , ,Pr ) + IIPZ , P , ) ) and lufitlnfi = lnlf.fr )
we then get
dzft =
tzfdr,dF ,
dpidrffrhi
- oil [ fifzi - f. fz ] lufifz )
Finally , using the symmetryof the cross section under time reversal
and parity we cantale I, pit ) I,
' PI without changing
7-12
the value of the integral . Again averaging overthe two we get
dk I-
= gfdridp , dpidrffrlv- oil [ fifz ' - fifz ][lufifz ) .hn/f,ify )]
dt
I 0
since ( y- × ) ( lug
- lnx ) 20
-
In equilibrium S = - KBH gives thermal entropy . H is a generalized -
to non equilibrium and reflects irreversibility .
Q : At which point in our derivation did irreversibility sneak in?
A : when we tool fz ( F,§, ;I. Fz ) . - f ( F. F.) f ( FiP2 )
Note that dtt= o if f( F.) fc Fz ) = ftp.llflpz
'
) which is a
dt
version of detailed balance which is satisfied in equilibrium .
One can in fact use this necessaryconation to derive a
functional form for the equilibriumdistribution feq .