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- Tate and Anna are selling pies for a school fundraiser. Customers can buy apple pies and blackberry pies. Tate sold 7 apple pies and 8 blackberry pies

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- Slide 1
- Tate and Anna are selling pies for a school fundraiser. Customers can buy apple pies and blackberry pies. Tate sold 7 apple pies and 8 blackberry pies for a total of $155. Anna sold 2 apple pies and 4 blackberry pies for a total of $70. Write a system of equations to represent this situation (do not need to solve). Write down this problem on your READY RECALL SHEET Be prepared to explain your answer if you are called on. prepare for my Unit 11 Test by making a 3x5 card and completing my Practice Test.
- Slide 2
- ITEMS of BUSINESS Test is on Monday/Tuesday. Also, its the last Day to turn in any absent/missing work. SAGE test is May 7-12. BE HERE.
- Slide 3
- Questions on Homework? then Trade-n-Grade
- Slide 4
- SYSTEMS OF EQUATIONS Unit 11 Review
- Slide 5
- Write them down on your 3x5 card. UNIT 11 REVIEW CONCEPTS Remember Its worth An extra 1% on your test!
- Slide 6
- POSSIBLE SOLUTIONS FOR 2 EQUATIONS (1,3) Intersecting Lines Different Slope, y-int. can be different or the same Solve Algebraically: You will get one solution (X,Y) Parallel Lines Same slope, different y-int. Solve Algebraically: Variables drop out FALSE Statement ex. 12 = 9 Coincidental Lines Same line, same slope, same y-int. Solve Algebraically: Variables drop out TRUE Statement ex. 22 = 22
- Slide 7
- LETS TRY A FEW PROBLEMS Given the following systems, can You determine how many solutions (One, None, or Infinite) w/o graphing? C. y = 9x - 1 y = -1 + 9x Infinite One None
- Slide 8
- HOW MANY SOLUTIONS?
- Slide 9
- SOLVE BY GRAPHING { Solution: (3, 2)
- Slide 10
- SOLVING BY GRAPHING y = 3x 1 -3x + y = 1 { { No Solution Infinite Solutions y = 3x -1
- Slide 11
- SOLVING BY SUBSTITUTION x + y = 12 x = 2 + y 2 + y x is equal to 2 + y { 2 + y can replace x It is of equal value. 2 + y + y = 12 We can solve this!
- Slide 12
- A. Solve by Substitution: -5x + 5y = -5 x = -y + 5 { -5(-y + 5) + 5y = -5 5y 25+ 5y 10y 25 = -5 +25 10y = 20 10 y = 2 = -5 x = -y + 5 x = -(2) + 5 x = 3 Solution: (3, 2) x, y x = -2 + 5 SUBSTITUTION -5(3) + 5(2) = -5 3 = -2 + 5 Check: Are these statements TRUE?
- Slide 13
- B. Solve by Substitution: 2(2y + 3) 4y = 1 2x 4y = 1 x = 2y + 3 { 4y+ 6 4y 0y + 6 = 1 6 = 1 Is this true? = 1 NO SUBSTITUTION NO SOLUTION
- Slide 14
- C. Solve by Substitution: 4x 2(2x + 5) = -10 4x 2y = -10 y = 2x + 5 { 4x 4x 10 0x 10 = -10 -10 = -10 Is this true? = -10 YES SUBSTITUTION INFINITE SOLUTIONS
- Slide 15
- x + y = 30 x y = 6 ADD THE TWO EQUATIONS TOGETHER & SOLVE 2x = 36 2 x = 18 REPLACE x WITH 18 IN ONE OF THE ORIGINAL EQUATIONS & SOLVE FOR Y 18 + y = 30 y = 30 - 18 y = 12 x = 18, y = 12 (18,12) MATHICAL MATT/MAGGIE WE ARE USING THE ELIMINATION METHOD!!
- Slide 16
- A. Solve by Elimination: { 5x + 2y = 12 -5x + 4y = -66 + 6y= -54 6 6 y = -9 5x + 2y = 12 5x + 2(-9) = 12 5x - 18 = 12 +18 5x= 30 5 5 x = 6 Solution: (6, -9) x, y ELIMINATION
- Slide 17
- I WISH
- Slide 18
- LETS PRACTICE WITH OUR COMMUNICATORS Example: Multiply both sides with 3 x + 2y = 7 3x + 6y = 21 A. Multiply both sides with 2 3x - y = 4 6x - 2y = 8 B. Multiply both sides with -4 x - 4y = 2 -4x + 16y = -8 C. Oppositize both sides x - 3y = -5 -x + 3y = 5
- Slide 19
- C. Solve by Elimination: Is this true? Yes! 12y { 2x 4y = 6 -3x + 6y = -9 6x -6x + 0 = 0 ( )3 = 18 ( )2 + 12y= -18 Infinite Solutions ELIMINATION
- Slide 20
- Solve by Elimination: 15y { 3x 5y = -6 -9x + 15y = 13 9x -9x + 15y = 13 + 0 = -5 Is this true? ( ) 3 = -18 No! ELIMINATION NO SOLUTION
- Slide 21
- What does it Look Like? ONE SOLUTION: (X,Y) FALSE STATEMENT TRUE STATEMENT
- Slide 22
- WHICH METHOD SHOULD I USE? 5x + 8y = 3 -5x 7 y = -2 y = 2x - 4 -5x +2 y = -2 y = 3/4x -5 y = 5x - 8 2x 4y = 10 x = -6y + 12 -3x + 4y = 1 15x + 3y = -2 y = 6/7x +3 y = x - 12 SUB ELIM GRAPH 5 y = mx + b
- Slide 23
- STORY PROBLEM The cost of making apple pies includes the booth rental of $180 and $4 per pie. We are charging $10 per pie. Write two equations, one representing the Production Cost and the other representing the Income. Assign y (dependent variable) to the Production Cost/Income and x (independent variable) to the number of pies sold. Production Cost: Income from Sales: Solve the above system. What does the solution represent? The graph of the equations is to the right. The point of intersection is called the Break-Even Point. At least ______ apple pies must be sold to make a profit. Y = 180 + 4x Y = 10x Using Substitution: 10x 10x = 180 + 4x -4x 6x = 180 6 x = 30 y = 10x y = 10(30) y = 300 Solution: (30, $300) Break-Even Point 31
- Slide 24
- prepare for my Unit 11 Test by making a 3x5 card and completing my Practice Test. Unit 11 Review
- Slide 25
- Do the CIRCLED PROBLEMS on the PRACTICE TEST. When you finish, you can work on the rest of the problems. Practice Test
- Slide 26
- Answers 2 3 4 7 8 12 14 15 17 19C 20 22 Y = 10 X 4C Y = 5C (10,50) 11 CARS FALSE, VARIABLES DROP OUT, NO SOLUTION
- Slide 27
- 21 possible Now, rework the ones you missed AND finish the rest of the practice test. -1 = 95% -2 = 90% -3 = 86% -4 = 81% -5 = 76% -6= 71% -7= 67% -8= 62% -9 or more: F Whats your score?
- Slide 28
- SHOW YOUR WORK Write down todays homework on your CALENDAR CARD. WHITE Worksheet UNIT 11 PRACTICE TEST