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TUTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: [email protected]

T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: [email protected]

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Page 1: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

TUTORIAL 4 SOLUTIONSLecturer: Miss Anis Atikah Ahmad

Tel: +604 976 3245

Email: [email protected]

Page 2: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

The liquid phase reaction

A + B C

follows an elementary rate law and is carried out isothermally in a flow system. The concentrations of A & B feed streams are 2 M before mixing. The volumetric flow rate of each stream is 5 dm3/min, and the entering temperature is 300 K. The streams are mixed immediately before entering. Two reactors are available. One is gray 200 dm3 CSTR that can be heated to 77°C or cooled to 0°C, and the other is a white 800 dm3 PFR operated at 300 K that cannot be heated or cooled but can be painted red or black. Note k = 0.07 dm3/mol.min at 300 K and E = 20 kcal/mol.

(a) Select type of reactor that could be used by showing appropriate calculations.

(b) Calculate time taken to achieve 90% conversion in a 200 dm3 batch reactor with CA0 = CB0 = 1 M after mixing at a temperature of 77°C.

(c) Repeat part (b) if the reactor were cooled to 0°C

(d) Calculate the conversion if the CSTR and PFR were operated at 300 K and connected in series. The entering volumetric flow rate is 10 dm3/h.

(e) Repeat part (d) if CSTR and PFR are connected in parallel with an entering flow rate of 5 mol/min to each of the reactor.

QUESTIONS

Page 3: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

A

A

r

XFV

0

(a)Select type of reactor that could be used by showing appropriate calculations.

1. Design equation:

2. Rate Law:

3. Stoichiometry:

4. Combine:

CSTR

BAA CkCr

XCC AOA 1 XCC AOB 1

220

0

1 XkC

XFV

A

A

min/10min5min5/1 333000 moldmdmdmmolvCF AA

3200dmVCSTR 30 1 dmmolCA

?350 KTk

Page 4: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

Using Arrhenius eq, find k at T=350K

Solving for X,

350

1

300

1

987.1

20000exp07.0)350( Kk

min45.8)350( 3 moldmKk

(a)Select type of reactor that could be used by showing appropriate calculations.

CSTR

220

0

1 XkC

XFV

A

A

2233

2

11min45.8

min10200

Xdmmolmoldm

Xmoldm

925.0X

Page 5: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

X

AA r

dXFV

0

0

(a)Select type of reactor that could be used by showing appropriate calculations.

1. Design equation:

2. Rate Law:

3. Stoichiometry:

4. Combine:

5. Solving for X: X= 0.85

PFR

BAA CkCr

XCC AOA 1 XCC AOB 1

X

A

A

X

dX

kC

FV

022

0

0

1min/100 molFA

3800dmVPFR 3

0 1 dmmolCA

min07.0 3 moldmk

XX

F

VkC

A

A

10

20

Page 6: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

200dm3 CSTR gives higher conversion than 800dm3 PFR

Thus, CSTR is chosen.

(a)Select type of reactor that could be used by showing appropriate calculations.

Page 7: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

(b) Calculate time taken to achieve 90% conversion in a 200 dm3 batch reactor with CA0 = CB0 = 1 M after mixing at a temperature of 77°C.

1. Design equation:

2. Rate Law:

3. Stoichiometry:

4. Combine:

5. Solving for t:

Batch

Vrdt

dXN A

RA 0

BAA CkCr

XCC AOA 1 XCC AOB 1

VXkCdt

dXN AO

RA

220 1 22

0 1 XkCdt

dXC AO

RA

21 XkCdt

dXAO

R

Rt

RAO

X

dtkCX

dX

0021

Page 8: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

(b) Calculate time taken to achieve 90% conversion in a 200 dm3 batch reactor with CA0 = CB0 = 1 M after mixing at a temperature of 77°C.

5. Solving for t:

21 XkCdt

dXAO

R

Rt

RAO

X

dtkCX

dX

0021

AOR kCX

Xt

1

33 1min45.89.01

9.0

dmmolmoldm

min065.1

Page 9: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

Using the same equation in part (b), except the value of k is used at T= 273K.

From Arrhenius eq,

Thus,

(c) Repeat part (b) if the reactor were cooled to 0°C

dayskCX

Xt

AOR 5.2min3543

1

273

1

350

1

987.1

20000exp45.8)273( Kk

min1054.2 33 moldm

AOR kCX

Xt

1

Page 10: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

(d) Calculate the conversion if the CSTR and PFR were operated at 300 K and connected in series. The entering volumetric flow rate is 10 dm3/h.

v0=10 dm3/h.

220

0

1 XkC

XFV

A

ACSTR

00

220

0

220 11

vC

XkCV

F

XkCVX

A

ACSTR

A

ACSTR

min10

11min07.02003

2333

dm

XdmmolmoldmdmX

44.0X

?X

Page 11: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

(d) Calculate the conversion if the CSTR and PFR were operated at 300 K and connected in series. The entering volumetric flow rate is 10 dm3/h.

v0=10 dm3/h.

44.0X?X

X

A

A

X

dX

kC

FV

44.022

0

0

1

44.01

1

1

120

0

XkC

FV

A

A

7857.1

1

1800

20

003

XkC

vCdm

A

A

7857.1

1

1

1min07.0

min10800

33

33

Xdmmolmoldm

dmdm

865.0X

Page 12: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

(e) Repeat part (d) if CSTR and PFR are connected in parallel with an entering flow rate of 5 dm3/h to each of the reactor.

5 dm3/h.

5 dm3/h.

10 dm3/h.

00

220

0

220 11

vC

XkCV

F

XkCVX

A

ACSTR

A

ACSTR

min5

11min07.02003

2333

dm

XdmmolmoldmdmX

56.0X

?X

Page 13: T UTORIAL 4 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my

(e) Repeat part (d) if CSTR and PFR are connected in parallel with an entering flow rate of 5 dm3/h to each of the reactor.

5 dm3/h.

5 dm3/h.

10 dm3/h. 56.0X

?X

X

A

A

X

dX

kC

FV

022

0

0

1

XX

F

VkC

A

A

10

20

XX

dm

dmmolmoldmdm

1min5

1min07.08003

333

91.0X