1
Student Learning of Calorimetry Concepts Ngoc-Loan P. Nguyen and David E. Meltzer Iowa State University Supported by NSF DUE-#9981140 Project Description: Student volunteers (N=8) from a calculus- based physics course were interviewed on their understanding of calorimetry concepts in audio-taped sessions lasting 45-60 minutes. Based on their responses, a series of worksheet questions were developed. During the next offering of the same course (Summer 2002), a pretest on calorimetry concepts was administered to the entire class. The worksheets were then used in one of the recitation sections of the class, and later a related exam question was administered to the entire class. Summary of Interview Questions: • A piece of hot metal is placed in colder water (mass of metal = mass of water) and left in thermal isolation. Describe the transfer of energy between the metal and the water, and their relative amounts of temperature change. • Draw a graph of temperature vs. time for the metal and water when the mass of the metal is (1) the same as the water, and (2) twice that of the water. • Draw a temperature vs time graph for two different liquids heated at the same rate, when the liquids have the same mass but different specific heats. Observation from the Interviews: The requirement for the students to draw and justify temperature-time graphs was very helpful in getting them to thoroughly explain their reasoning. Example interview item A 3. A calorimeter is made of very good insulating material and it has a lid. We can assume that no energy transfer occurs between the walls of the calorimeter and any material contained within it, and also that there is no energy transfer between the calorimeter and the room where it is located. A piece of copper metal is put into a calorimeter which is partly filled with water. The mass of the copper is the same as the mass of the water, but the temperature of the copper is higher than the temperature of the water. The calorimeter is left alone for several hours. a) Does energy transfer occur? If yes, please explain and compare the quantities or amounts of energy that are transferred and where they are transferred to. b) Is there a temperature change in either the copper or the water? If so compare the amount of temperature change or lack of such in the copper and water. If one changes temperature more, then which one changes temperature more and why? Example interview item C 6. Suppose that a mass of copper is heated to a high initial temperature. Suppose then that is placed in a insulated container of water that is at a lower initial temperature. a) Graph the temperature of the copper and water if they both have the same mass. b) Graph the temperature of the copper and water if the mass of the copper is double that of the water. Tem perature (degrees) Tim e Tem perature (degrees) Tim e Example interview item B 5. Suppose we have two separate containers each containing different liquids with different specific heats but with the same mass and initial temperature. Each container is placed on an heating plate that delivers the same rate of heating in joules per second to each liquid. i) Below please graph the temperature of each liquid as a function of time. ii) Please explain the reasoning that you used to determine how you chose to draw the graph as you did. Tem perature (degrees) Tim e (seconds) Major findings from interviews: • Students were able to use the concept of thermal equilibrium in their explanations. • Students were often unable to distinguish among heat, internal energy, and work. • In the case of copper and water of equal mass, some students (3 out of 8) incorrectly stated that the copper would have the smaller temperature change. Their reasons were (1) higher thermal conductivity of the copper; (2) higher melting point of the copper, and (3) the idea that water could change temperature “more easily” than the copper. • Almost all students (7 out of 8) were able to state correctly that doubling the mass of the copper would lead to a smaller net temperature change for the copper. Pretest: Items similar to the interview questions were administered as in-class quizzes during the summer-session course. Sample pretest item: 2. Suppose we have two separate containers: One container holds Liquid A, and another contains Liquid B. The mass and initial temperature of the two liquids are the same, but the specific heat of Liquid A is greater than Liquid B. Each container is placed on a heating plate that delivers the same rate of heating in joules per second to each liquid beginning at initial time t 0 . a) On the grid below, graph the temperature as a function of time for each liquid, A and B. Use a separate line for each liquid, even if they overlap. Make sure to clearly label your lines, and use proper graphing techniques. b) Please explain the reasoning that you used in drawing your graph. (Please continue on the back of the page.) Tem perature Tim e t 0 Liquid A Liquid B H eating Plate The specific heatofA is greaterthan the specific heatofB . Pretest Results: For the most part, students were able to correctly draw two lines with the line representing liquid B having the greater slope. However, a significant minority (22%) drew the liquid-A line as having the greater slope, and many were unable to give acceptable explanations. 9% of students showed the lines sloping down (i.e., cooling). Post-test: A post-test question was given to the class as part of their next exam, after using the worksheets. Analysis of these results is not yet complete. Exam Question 2. Suppose that a mass of aluminum (Al) is heated to a high initial temperature. At time t 0 it is placed in an insulated container of water that is at a lower initial temperature. The mass of the aluminum is the same as the mass of the water. (Note: The specific heat of water is higher than that of aluminum.) a) On the grid below, graph the temperature as a function of time of the aluminum and water separately. (Don’t worry about precise quantitative accuracy.) Make sure to clearly label your graphs. (Note: t 1 represents a time shortly after the initial time, before equilibrium is reached.) b) Please explain the reasoning that you used in drawing your graph. Tem perature Time W ater Al Insulation t 1 t 0 Exam Question Answer Tem perature Time W ater Al Insulation t 1 t 0 W ater Al Common errors in exam responses: • Slope of water line having greater absolute value than that of the aluminum line. • Indicating that the net temperature change of the aluminum was less than that of the water, or that water’s temperature change would be “faster.” • Stating that the time until equilibrium was reached for one material or the other would be “longer,” or would require “more time” or “less time.” • Saying that temperature changes occur “more easily” or “less easily” for one of the materials. • Stating that for aluminum, “heat absorption/change/increase is faster Example worksheet page B Energy T ransfer to Sam ple: A B + 2 kJ -4 kJ -2 kJ 0 kJ + 4 kJ 0 InternalEnergy B B A A Tim e Zero Long A fter 10 kJ 8 kJ 2 kJ 4 kJ 6 kJ A bsolute Tem perature B B A A Tim e Zero Long A fter 0 Example worksheet page D 6. Suppose we have two samples, A and B, of different materials, placed in a partitioned insulated container of negligible heat capacity. Sample A has 1.5 times the mass of sample B. Energy but no material can pass through the conducting partition. The atmosphere in the container can transfer energy but has a negligible heat capacity. Assume specific heat is independent of temperature. The specific heat of material B is twice that of material A. a. If the temperature of sample A changes by T A , what would be the corresponding change in sample B? T B = _________? b. Complete the bar charts below for temperature and energy transfer. If any quantity is zero, label that quantity as zero. Explain your reasoning below. A B A bsolute Tem perature B B A A Tim e Zero Long A fter 0 Energy Transfer to Sam ple: A B + 2 kJ -4 kJ -2 kJ 0 kJ + 4 kJ Student Response to Worksheets: Appropriate Difficulty Level: Students took the entire time given to them (forty minutes) to work on the sheets. No students finished the entire 8-page worksheet. Accessibility: Most students were able to go through the worksheets based on discussions among themselves, but instructor intervention was required for some students on several questions. Supplements standard instruction: By the time the students had been given the worksheets they had already had a traditional lecture and completed a homework assignment on calorimetry. However, this did not seem to make the worksheets redundant. Even the more advanced students needed to pause, think, and reason out several of the problems. Ideas for curriculum development: Increased precision: Many times student explanations were vague or imprecise. We developed questions that required more exact understanding or manipulation of specific quantities. Proportional reasoning: By using ratios or other tasks that required students to compare specific numbers, they would be led to develop more precise judgments and descriptions. Guided development: The poor explanations given by many students suggested that it would be helpful to guide them through the concepts in a step-by-step manner. Targeting confusion among fundamental quantities: The worksheets were designed to focus students’ thinking on the distinctions among basic thermodynamic quantities such as temperature, heat, and internal energy. Sample worksheet page A The internal energy [s y m bol: U ] o f a n id e a l g a s is e q u a l to th e to tal k in e tic e n e rg y o f a ll o f th e m o lecu le s in th e g a s. A cco rd in g to th e k in e tic th e o ry o f g a s e s, th e a b s o lu te temperature o f a n id e a l g a s is p ro p o rtio n a l to th e a v e ra g e k in e tic e n e rg y o f th e m o le cu les co n ta in ed w ith in th e gas. 1 . S u p p o se w e h a v e tw o sam p le s, A and B , o f a n id eal g as p laced in a p a rtitio n ed in su la ted co n ta in e r o f n eg lig ib le h ea t c a p a city . S am ple A h a s th e sam e m ass a s sa m ple B a n d ea c h s id e o f th e p a rtitio n h a s th e sa m e v olum e . E n erg y b u t n o m a te ria l ca n p a ss th ro u g h th e c o n d u c tin g p a rtitio n ; th e p a rtitio n is rig id a n d ca n n o t m ove. O n th e b a r c h a rt o n th e n ex t p a g e, th e v a lu es o f th e sa m p le s' in te r n a l en erg y a re sh o w n a t s o m e in itia l tim e (“ T im e Z ero ” ); " L o n g A fter" refers to a tim e lo n g a fte r th a t in itia l tim e . R e f e r to th e s e t o f th re e b a r c h a rts to a n sw e r th e fo llo w in g q u e s tio n s. a. F in d th e a b so lu te te m p era tu re o f s a m p le A a t tim e z ero (th e in itia l tim e ), a n d p lo t it o n th e c h a rt. H int: If tw o eq u a l m a sses o f id ea l g a s h a v e th e sa m e in te r n a l e n erg y , w ill th e ir te m p era tu re b e th e sa m e , o r d iffe r e n t? If th e ra tio o f in te rn a l en erg ie s is B A U U , w h a t c a n y o u sa y about B A T T ? b. A fte r th e in itia l tim e , w o u ld y o u ex p e c t to se e a n y c h a n g es in th e tem p era tu res o f s a m p les A a n d B ? If y e s, d e s c rib e th e c h a n g e s (i.e ., in creases o r d ec re a se s ). If y o u d o n ’t e x p e c t to o b s erv e a n y c h a n g e s , e x p la in w hy. c. A lo n g tim e a fte r tim e z ero , w h a t ra tio d o y o u ex p e c t fo r th e te m p e ra tu re s o f th e tw o sam p les? _____? B A T T d. A lo n g tim e a fte r tim e z ero , w h a t ra tio d o y o u ex p e c t fo r th e in te rn a l e n erg ies o f th e tw o sam p les? _____? B A U U E x p lain . e. C o m p le te th e b a r c h a rts b y fin d in g th e “ L o n g A fter” v alu es fo r te m p erature an d in te rn a l en erg y , an d also th e am o u n ts o f e n erg y transferred to th e tw o sa m p le s . (T h is is th e n e t tra n s fe r th a t o ccu rs b e tw een tim e z ero a n d th e tim e “ lo n g a fte r.” ) If a n y q u a n tity is z ero , la b el th a t q u a n tity as z ero . E x p la in y o u r re a so n in g b elo w . B A in s u la tio n Example worksheet page C 5. Suppose we have two samples, A and B, of different materials, placed in a partitioned insulated container of negligible heat capacity. Sample A has the same mass as sample B. Energy but no material can pass through the conducting partition. The atmosphere in the container can transfer energy but has a negligible heat capacity. Assume specific heat is independent of temperature. The specific heat of material A is twice that of material B. a. If the temperature of sample A changes by T A , what would be the corresponding change in the temperature of sample B? T B = _________? b. Complete the bar charts below for temperature and energy transfer. If any quantity is zero, label that quantity as zero. Explain your reasoning below. B A A bsolute Tem perature B B A A Tim e Zero Long A fter 0 Energy T ransfer to Sam ple: A B + 2 kJ -4 kJ -2 kJ 0 kJ + 4 kJ

Student Learning of Calorimetry Concepts Ngoc-Loan P. Nguyen and David E. Meltzer Iowa State University Supported by NSF DUE-#9981140 Project Description:

Embed Size (px)

Citation preview

Page 1: Student Learning of Calorimetry Concepts Ngoc-Loan P. Nguyen and David E. Meltzer Iowa State University Supported by NSF DUE-#9981140 Project Description:

Student Learning of Calorimetry Concepts

Ngoc-Loan P. Nguyen and David E. Meltzer

Iowa State University

Supported by NSF DUE-#9981140

Project Description: Student volunteers (N=8) from a calculus-based physics course were interviewed on their understanding of calorimetry concepts in audio-taped sessions lasting 45-60 minutes. Based on their responses, a series of worksheet questions were developed. During the next offering of the same course (Summer 2002), a pretest on calorimetry concepts was administered to the entire class. The worksheets were then used in one of the recitation sections of the class, and later a related exam question was administered to the entire class.

Summary of Interview Questions:

• A piece of hot metal is placed in colder water (mass of metal = mass of water) and left in thermal isolation. Describe the transfer of energy between the metal and the water, and their relative amounts of temperature change.

• Draw a graph of temperature vs. time for the metal and water when the mass of the metal is (1) the same as the water, and (2) twice that of the water.

• Draw a temperature vs time graph for two different liquids heated at the same rate, when the liquids have the same mass but different specific heats.

Observation from the Interviews: The requirement for the students to draw and justify temperature-time graphs was very helpful in getting them to thoroughly explain their reasoning.

Example interview item A

3. A calorimeter is made of very good insulating material and it has a lid. We can assume that no energy transfer occurs between the walls of the calorimeter and any material contained within it, and also that there is no energy transfer between the calorimeter and the room where it is located.

A piece of copper metal is put into a calorimeter which is partly filled with water. The mass of the copper is the same as the mass of the water, but the temperature of the copper is higher than the temperature of the water. The calorimeter is left alone for several hours.

a) Does energy transfer occur? If yes, please explain and compare the quantities or amounts of energy that are transferred and where they are transferred to.

b) Is there a temperature change in either the copper or the water? If so compare the amount of temperature change or lack of such in the copper and water. If one changes temperature more, then which one changes temperature more and why?

Example interview item C

6. Suppose that a mass of copper is heated to a high initial temperature. Suppose then that is placed in a insulated container of water that is at a lower initial temperature.

a) Graph the temperature of the copper and water if they both have the same mass.

b) Graph the temperature of the copper and water if the mass of the copper is double that of the water.

Temperature(degrees)

Time

Temperature(degrees)

Time

Example interview item B

5. Suppose we have two separate containers each containing different liquids with different specific heats but with the same mass and initial temperature. Each container is placed on an heating plate that delivers the same rate of heating in joules per second to each liquid.

i) Below please graph the temperature of each liquid as a function of time.

ii) Please explain the reasoning that you used to determine how you chose to draw the graph as you did.

Temperature(degrees)

Time(seconds)

Major findings from interviews:

• Students were able to use the concept of thermal equilibrium in their explanations.

• Students were often unable to distinguish among heat, internal energy, and work.

• In the case of copper and water of equal mass, some students (3 out of 8) incorrectly stated that the copper would have the smaller temperature change. Their reasons were (1) higher thermal conductivity of the copper; (2) higher melting point of the copper, and (3) the idea that water could change temperature “more easily” than the copper.

• Almost all students (7 out of 8) were able to state correctly that doubling the mass of the copper would lead to a smaller net temperature change for the copper.

Pretest: Items similar to the interview questions were administered as in-class quizzes during the summer-session course.

Sample pretest item:

2. Suppose we have two separate containers: One container holds Liquid A, and another contains Liquid B. The mass and initial temperature of the two liquids are the same, but the specific heat of Liquid A is greater than Liquid B. Each container is placed on a heating plate that delivers the same rate of heating in joules per second to each liquid beginning at initial time t0.

a) On the grid below, graph the temperature as a function of time for each liquid, A and B. Use a separate line for each liquid, even if they overlap. Make sure to clearly label your lines, and use proper graphing techniques.

b) Please explain the reasoning that you used in drawing your graph. (Please continue on the back of the page.)

Temperature

Timet0

Liquid A Liquid B

Heating Plate

The specific heat of A is greater than the

specific heat of B.

Pretest Results: For the most part, students were able to correctly draw two lines with the line representing liquid B having the greater slope. However, a significant minority (22%) drew the liquid-A line as having the greater slope, and many were unable to give acceptable explanations. 9% of students showed the lines sloping down (i.e., cooling).

Post-test: A post-test question was given to the class as part of their next exam, after using the worksheets. Analysis of these results is not yet complete.

Exam Question

2. Suppose that a mass of aluminum (Al) is heated to a high initial temperature. At time t0 it is placed in an insulated container of water that is at a lower initial temperature. The mass of the aluminum is the same as the mass of the water. (Note: The specific heat of water is higher than that of aluminum.)

a) On the grid below, graph the temperature as a function of time of the aluminum and water separately. (Don’t worry about precise quantitative accuracy.) Make sure to clearly label your graphs. (Note: t1 represents a time shortly after the initial time, before equilibrium is reached.)

b) Please explain the reasoning that you used in drawing your graph.

Temperature

Time

Water

Al

Insulation

t1t0

Exam Question Answer

Temperature

Time

Water

Al

Insulation

t1t0

Water

Al

Common errors in exam responses:

• Slope of water line having greater absolute value than that of the aluminum line.

• Indicating that the net temperature change of the aluminum was less than that of the water, or that water’s temperature change would be “faster.”

• Stating that the time until equilibrium was reached for one material or the other would be “longer,” or would require “more time” or “less time.”

• Saying that temperature changes occur “more easily” or “less easily” for one of the materials.

• Stating that for aluminum, “heat” absorption/change/increase is faster

• Explaining that the faster temperature change of aluminum was due to its higher initial temperature.

Example worksheet page B

Energy Transfer to Sample:

A B

+ 2 kJ

- 4 kJ

- 2 kJ

0 kJ

+ 4 kJ

0

Internal Energy

B BA A

Time Zero Long After

10 kJ

8 kJ

2 kJ

4 kJ

6 kJ

Absolute Temperature

B BA A

Time Zero Long After

0

Example worksheet page D

6. Suppose we have two samples, A and B, of different materials, placed in a partitioned insulated container of negligible heat capacity. Sample A has 1.5 times the mass of sample B. Energy but no material can pass through the conducting partition. The atmosphere in the container can transfer energy but has a negligible heat capacity. Assume specific heat is independent of temperature. The specific heat of material B is twice that of material A.

a. If the temperature of sample A changes by TA, what would be the corresponding change in sample B? TB = _________?

b. Complete the bar charts below for temperature and energy transfer. If any quantity is zero, label that quantity as zero.

Explain your reasoning below.

A B

Absolute Temperature

B BA A

Time Zero Long After

0

Energy Transfer to Sample:

A B

+ 2 kJ

- 4 kJ

- 2 kJ

0 kJ

+ 4 kJ

Student Response to Worksheets:

•Appropriate Difficulty Level: Students took the entire time given to them (forty minutes) to work on the sheets. No students finished the entire 8-page worksheet.

•Accessibility: Most students were able to go through the worksheets based on discussions among themselves, but instructor intervention was required for some students on several questions.

•Supplements standard instruction: By the time the students had been given the worksheets they had already had a traditional lecture and completed a homework assignment on calorimetry. However, this did not seem to make the worksheets redundant. Even the more advanced students needed to pause, think, and reason out several of the problems.

Ideas for curriculum development:

• Increased precision: Many times student explanations were vague or imprecise. We developed questions that required more exact understanding or manipulation of specific quantities.

• Proportional reasoning: By using ratios or other tasks that required students to compare specific numbers, they would be led to develop more precise judgments and descriptions.

• Guided development: The poor explanations given by many students suggested that it would be helpful to guide them through the concepts in a step-by-step manner.

•Targeting confusion among fundamental quantities: The worksheets were designed to focus students’ thinking on the distinctions among basic thermodynamic quantities such as temperature, heat, and internal energy.

Sample worksheet page A

T h e i n t e r n a l e n e r g y [ s y m b o l : U ] o f a n i d e a l g a s i s e q u a l t o t h e t o t a l k i n e t i c e n e r g y o f a l l o f t h e m o l e c u l e s i n t h e g a s . A c c o r d i n g t o t h ek i n e t i c t h e o r y o f g a s e s , t h e a b s o l u t e t e m p e r a t u r e o f a n i d e a l g a s i s p r o p o r t i o n a l t o t h e a v e r a g e k i n e t i c e n e r g y o f t h e m o l e c u l e s c o n t a i n e dw i t h i n t h e g a s .

1 . S u p p o s e w e h a v e t w o s a m p l e s , A a n d B , o f a n i d e a l g a s p l a c e d i n a p a r t i t i o n e d i n s u l a t e d c o n t a i n e r o f n e g l i g i b l e h e a t c a p a c i t y . S a m p l e A h a s t h e s a m em a s s a s s a m p l e B a n d e a c h s i d e o f t h e p a r t i t i o n h a s t h e s a m e v o l u m e . E n e r g y b u t n o m a t e r i a l c a n p a s s t h r o u g h t h e c o n d u c t i n g p a r t i t i o n ; t h e p a r t i t i o n i sr i g i d a n d c a n n o t m o v e .

O n t h e b a r c h a r t o n t h e n e x t p a g e , t h e v a l u e s o f t h e s a m p l e s ' i n t e r n a l e n e r g y a r e s h o w n a t s o m e i n i t i a l t i m e ( “ T i m e Z e r o ” ) ; " L o n g A f t e r " r e f e r s t o at i m e l o n g a f t e r t h a t i n i t i a l t i m e . R e f e r t o t h e s e t o f t h r e e b a r c h a r t s t o a n s w e r t h e f o l l o w i n g q u e s t i o n s .

a . F i n d t h e a b s o l u t e t e m p e r a t u r e o f s a m p l e A a t t i m e z e r o ( t h e i n i t i a l t i m e ) , a n d p l o t i t o n t h e c h a r t . H i n t : I f t w o e q u a l m a s s e s o f i d e a l g a s h a v e t h e

s a m e i n t e r n a l e n e r g y , w i l l t h e i r t e m p e r a t u r e b e t h e s a m e , o r d i f f e r e n t ? I f t h e r a t i o o f i n t e r n a l e n e r g i e s i s B

A

U

U , w h a t c a n y o u s a y a b o u t

B

A

T

T ?

b . A f t e r t h e i n i t i a l t i m e , w o u l d y o u e x p e c t t o s e e a n y c h a n g e s i n t h e t e m p e r a t u r e s o f s a m p l e s A a n d B ? I f y e s , d e s c r i b e t h e c h a n g e s ( i . e . , i n c r e a s e so r d e c r e a s e s ) . I f y o u d o n ’ t e x p e c t t o o b s e r v e a n y c h a n g e s , e x p l a i n w h y .

c . A l o n g t i m e a f t e r t i m e z e r o , w h a t r a t i o d o y o u e x p e c t f o r t h e t e m p e r a t u r e s o f t h e t w o s a m p l e s ? _____?B

A

T

T

d . A l o n g t i m e a f t e r t i m e z e r o , w h a t r a t i o d o y o u e x p e c t f o r t h e i n t e r n a l e n e r g i e s o f t h e t w o s a m p l e s ? _____?B

A

U

U E x p l a i n .

e . C o m p l e t e t h e b a r c h a r t s b y f i n d i n g t h e “ L o n g A f t e r ” v a l u e s f o r t e m p e r a t u r e a n d i n t e r n a l e n e r g y , a n d a l s o t h e a m o u n t s o f e n e r g y t r a n s f e r r e d t ot h e t w o s a m p l e s . ( T h i s i s t h e n e t t r a n s f e r t h a t o c c u r s b e t w e e n t i m e z e r o a n d t h e t i m e “ l o n g a f t e r . ” ) I f a n y q u a n t i t y i s z e r o , l a b e l t h a t q u a n t i t y a sz e r o . E x p l a i n y o u r r e a s o n i n g b e l o w .

B A

i n s u l a t i o n

Example worksheet page C

5. Suppose we have two samples, A and B, of different materials, placed in a partitioned insulated container of negligible heat capacity. Sample A has the same mass as sample B. Energy but no material can pass through the conducting partition. The atmosphere in the container can transfer energy but has a negligible heat capacity. Assume specific heat is independent of temperature. The specific heat of material A is twice that of material B.

a. If the temperature of sample A changes by TA, what would be the corresponding change in the temperature of sample B? TB = _________?

b. Complete the bar charts below for temperature and energy transfer. If any quantity is zero, label that quantity as zero. Explain your reasoning below.

BA

Absolute Temperature

B BA A

Time Zero Long After

0

Energy Transfer to Sample:

A B

+ 2 kJ

- 4 kJ

- 2 kJ

0 kJ

+ 4 kJ