Standard Deviation and Variance

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it shaows standard deviation process

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  • 4/7/2015 StandardDeviationandVariance

    http://www.mathsisfun.com/data/standarddeviation.html 1/7

    StandardDeviationandVariance

    Deviationjustmeanshowfarfromthenormal

    Standard DeviationTheStandardDeviationisameasureofhowspreadoutnumbersare.

    Itssymbolis(thegreeklettersigma)

    Theformulaiseasy:itisthesquarerootoftheVariance.Sonowyouask,"WhatistheVariance?"

    VarianceTheVarianceisdefinedas:

    TheaverageofthesquareddifferencesfromtheMean.

    Tocalculatethevariancefollowthesesteps:

    WorkouttheMean(thesimpleaverageofthenumbers)

    Thenforeachnumber:subtracttheMeanandsquaretheresult(thesquareddifference).

    Thenworkouttheaverageofthosesquareddifferences.(WhySquare?)

    ExampleYouandyourfriendshavejustmeasuredtheheightsofyourdogs(inmillimeters):

  • 4/7/2015 StandardDeviationandVariance

    http://www.mathsisfun.com/data/standarddeviation.html 2/7

    Theheights(attheshoulders)are:600mm,470mm,170mm,430mmand300mm.

    FindouttheMean,theVariance,andtheStandardDeviation.

    YourfirststepistofindtheMean:

    Answer:

    Mean=600+470+170+430+300

    =1970

    =3945 5

    sothemean(average)heightis394mm.Let'splotthisonthechart:

    Nowwecalculateeachdog'sdifferencefromtheMean:

  • 4/7/2015 StandardDeviationandVariance

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    TocalculatetheVariance,takeeachdifference,squareit,andthenaveragetheresult:

    So,theVarianceis21,704.

    AndtheStandardDeviationisjustthesquarerootofVariance,so:

    StandardDeviation:=21,704=147.32...=147(tothenearestmm)

    AndthegoodthingabouttheStandardDeviationisthatitisuseful.NowwecanshowwhichheightsarewithinoneStandardDeviation(147mm)oftheMean:

  • 4/7/2015 StandardDeviationandVariance

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    So,usingtheStandardDeviationwehavea"standard"wayofknowingwhatisnormal,andwhatisextralargeorextrasmall.

    Rottweilersaretalldogs.AndDachshundsareabitshort...butdon'ttellthem!

    Nowtrythe StandardDeviationCalculator .

    But ... there is a small change with Sample DataOurexamplewasforaPopulation(the5dogsweretheonlydogswewereinterestedin).

    ButifthedataisaSample(aselectiontakenfromabiggerPopulation),thenthecalculationchanges!

    Whenyouhave"N"datavaluesthatare:

    ThePopulation:dividebyNwhencalculatingVariance(likewedid)

    ASample:dividebyN1whencalculatingVariance

    Allothercalculationsstaythesame,includinghowwecalculatedthemean.

    Example:ifour5dogswerejustasampleofabiggerpopulationofdogs,wewoulddivideby4insteadof5likethis:

    SampleVariance=108,520/4 =27,130

    SampleStandardDeviation=27,130=164(tothenearestmm)

    Thinkofitasa"correction"whenyourdataisonlyasample.

    Formulas

  • 4/7/2015 StandardDeviationandVariance

    http://www.mathsisfun.com/data/standarddeviation.html 5/7

    Herearethetwoformulas,explainedat StandardDeviationFormulas ifyouwanttoknowmore:

    The"PopulationStandardDeviation":

    The"SampleStandardDeviation":

    Lookscomplicated,buttheimportantchangeistodividebyN1(insteadofN)whencalculatingaSampleVariance.

    *Footnote:Whysquarethedifferences?

    Ifwejustaddedupthedifferencesfromthemean...thenegativeswouldcancelthepositives:

    4+444

    =04

    Sothatwon'twork.Howaboutweuse absolutevalues ?

    |4|+|4|+|4|+|4|

    =4+4+4+4

    =44 4

    Thatlooksgood(andisthe MeanDeviation ),butwhataboutthiscase:

  • 4/7/2015 StandardDeviationandVariance

    http://www.mathsisfun.com/data/standarddeviation.html 6/7

    |7|+|1|+|6|+|2|

    =7+1+6+2

    =44 4

    OhNo!Italsogivesavalueof4,Eventhoughthedifferencesaremorespreadout!

    Soletustrysquaringeachdifference(andtakingthesquarerootattheend):

    42+42+42+42

    =64

    =44 4

    72+12+62+22

    =90

    =4.74...4 4

    Thatisnice!TheStandardDeviationisbiggerwhenthedifferencesaremorespreadout...justwhatwewant!

    Infactthismethodisasimilarideato distancebetweenpoints ,justappliedinadifferentway.

    Anditiseasiertousealgebraonsquaresandsquarerootsthanabsolutevalues,whichmakesthestandarddeviationeasytouseinotherareasofmathematics.

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