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Applied Mathematics, 2014, 5, 2602-2611 Published Online September 2014 in SciRes. http://www.scirp.org/journal/am http://dx.doi.org/10.4236/am.2014.516248
How to cite this paper: Aiyub, M. (2014) Some Lacunary Sequence Spaces of Invariant Means Defined by Musielak-Orlicz Functions on 2-Norm Space. Applied Mathematics, 5, 2602-2611. http://dx.doi.org/10.4236/am.2014.516248
Some Lacunary Sequence Spaces of Invariant Means Defined by Musielak-Orlicz Functions on 2-Norm Space Mohammad Aiyub Department of Mathematics, University of Bahrain, Sakhir, Bahrain Email: [email protected] Received 11 July 2014; revised 15 August 2014; accepted 25 August 2014
Copyright © 2014 by author and Scientific Research Publishing Inc. This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
Abstract The purpose of this paper is to introduce and study some sequence spaces which are defined by combining the concepts of sequences of Musielak-Orlicz functions, invariant means and lacunary convergence on 2-norm space. We establish some inclusion relations between these spaces under some conditions.
Keywords Invariant Means, Musielak-Orlicz Functions, 2-Norm Space, Lacunary Sequence
1. Introduction Let ω be the set of all sequences of real numbers ,c∞ and 0c be respectively the Banach spaces of bounded, convergent and null sequences ( )kx x= with ( )kx ∈ or the usual norm sup kkx x= , where 1,2,3,k ∈ = , the positive integers.
The idea of difference sequence spaces was first introduced by Kizmaz [1] and then the concept was gene- ralized by Et and Çolak [2]. Later on Et and Esi [3] extended the difference sequence spaces to the sequence spaces:
( ) ( ) ( ){ }: ,m mv k vX x x x X∆ = = ∆ ∈
for , X c∞= and 0c , where ( )kv v= be any fixed sequence of non zero complex numbers and ( ) ( )1 1
1 .m m mv k v k v kx x x− −
+∆ = ∆ − ∆
The generalized difference operator has the following binomial representation,
M. Aiyub
2603
( )0
1 , for all .m im
v k k i k ii
mx v x k
i + +=
∆ = − ∈
∑
The sequence spaces ( )mv ∞∆ , ( )m
v c∆ and ( )0mv c∆ are Banach spaces normed by
1.
mm
i i vi
x v x x∆ ∞
=
= + ∆∑
The concept of 2-normed space was initially introduces by Gahler [4] as an interesting linear generalization of normed linear space which was subsequently studied by many others [5] [6]). Recently a lot of activities have started to study summability, sequence spaces and related topics in these linear spaces [7] [8]).
Let X be a real vector space of dimension d , where 2 d≤ < ∞ . A 2-norme on X is a function .,. : X X× → which satisfies:
1) , 0x y = if and only if x and y are linearly dependent, 2) , ,x y y x= ,
3) , , ,x y x yα α α= ∈ ,
4) , , ,x y z x y x z+ ≤ + . The pair ( ), .,.X is called a 2-normed space. As an example of a 2-normed space we may take 2X =
being equiped with the 2-norm ,x y = the area os paralelogram spaned by the vectors x and y , which may be given explicitly by the formula
11 221 2
21 22
, E
x xx x abs
x x
=
.
Then clearly ( ), .,.X is 2-normed space. Recall that ( ), .,.X is a 2-Banach space if every cauchy sequence in X is convergent to some x X∈ .
Let σ be a mapping of the positive integers into itself. A continuous linear functional φ on ∞ is said to be an invariant mean or σ -mean if and only if
1) ( ) 0xφ ≥ , when the sequence ( )nx x= has, 0nx ≥ for all n , 2) ( ) ( )1, 1,1,1,e eφ = = , 3) ( )( ) ( )nx xσφ φ= for all .x ∞∈
If ( )kx x= , where ( ) ( )( )k kTx Tx xσ= = . It can be shown that
( ){ }: lim , uniformly inknkV x t x l nσ ∞= ∈ =
lim ,l xσ= − where
( ) ( ) ( ) ( )1 2
1n k nn n
kn
x x x xt x
kσ σ σ
+ + + +=
+
[9].
In the case σ is the translation mapping 1n n→ + , σ -mean is often called a Banach limit and Vσ the set of bounded sequences of all whose invariant means are equal is the set of almost convergent sequence [10].
By Lacunary sequence ( ) , 0,1, 2,rk rθ = = where 0 0k = we mean an increasing sequence of non neg- ative integers ( ) ( )1 r r rh k k r−= − → ∞ →∞ . The intervals determined by θ are denoted by [ ]1r r rI k k−= −
and the ratio 1
r
r
kk −
will be denoted by rq . The space of lacunary strongly convergent sequence Nθ was de-
fined by Freedman et al. [11] as follows:
( ) 1: lim 0 for some .r
i kr k Ir
N x x x lhθ →∞ =
= = − =
∑
An Orlicz function is a function [ ) [ ): 0, 0,M ∞ → ∞ which is continuous, non-decreasing and convex with ( ) ( )0 0, 0M M x= > for 0x > and ( )M x →∞ as .x →∞
M. Aiyub
2604
It is well known that if M is convex function and ( )0 0M = then ( ) ( )M x M xλ λ≤ , for all λ with 0 1.λ≤ ≤
Lindenstrauss and Tzafriri [12] used the idea of Orlicz function and defined the sequence space which was called an Orlicz sequence space M such as
( )1
: , for some 0kM k
k
xx x M ρ
ρ
∞
=
= = < ∞ >
∑
which was a Banach space with the norm
1inf 0 : 1k
k
xx Mρ
ρ
∞
=
= > ≤
∑
which was called an Orlicz sequence space. The M was closely related to the space p which was an Orlicz sequence space with ( ) ,pM t t= for 1 p≤ < ∞ . Later the Orlicz sequence spaces were investigated by Prashar and Choudhry [13], Maddox [14], Tripathy et al. [15]-[17] and many others.
A sequence of function ( )kM M= of Orlicz function is called a Musielak-Orlicz function [18] [19]. Also a Musielak-Orlicz function ( )kΦ = Φ is called complementary function of a Musielak-Orlicz function M if
( ) ( ){ }sup : 0 , for 1, 2,3, .k kt t s M s s kΦ = − ≥ =
For a given Musielak-Orlicz function M , the Musielak-Orlicz sequence space Ml and its subspaces M are defined as follow:
( ){ }: , for some 0M k Ml x x I cx cω= = ∈ < ∞ >
( ){ }: , for all 0M k Mx x I cx cω= = ∈ < ∞ >
where MI is a convex modular defined by
( ) ( ) ( )1
, .M k k k Mk
I x M x x x l∞
=
= = ∈∑
We consider Ml equipped with the Luxemburg norm
inf 0 : 1Mxx k Ik
= > ≤
or equipped with the Orlicz norm
( )( )0 1inf 1 : 0 .Mx I kx kk
= + >
The main purpose of this paper is to introduce the following sequence spaces and examine some properties of the resulting sequence spaces. Let ( )kM M= be a Musielak-Orlicz function, ( ), .,.X is called a 2-normed space. Let ( )kp p= be any sequences of positive real numbers, for all k ∈ and ( )ku u= such that
( )0 1, 2,3,ku k≠ = . Let s be any real number such that 0s ≥ . By ( )2 Xω − we denote the space of all sequences defined over ( ), .,.X . Then we define the following sequence spaces:
( )
( ) ( )( )
,
, , , , , .,.
12 : , 0, 0sup
k
r
mv
pm
kn v ksk k k
r n k Ir
M p u s
t xx x X k u M z s
h
θ
σω
ω ρρ
∞
−
∈
∆
∆ = = ∈ − < ∞ > ≥
∑
M. Aiyub
2605
( )
( ) ( )( )
, , , , , .,.
12 :: , 0 for some , 0, 0lim
k
r
mv
pm
kn v ksk k k
r k Ir
M p u s
t xx x X k u M z l s
h
θ
σω
ω ρρ
−
∈
∆
∆ = = ∈ − = > ≥
∑
( )
( ) ( )( )
0, , , , , .,.
12 :: , 0 0, 0lim
k
r
mv
pm
kn v ksk k k
r k Ir
M p u s
t xx x X k u M z s
h
θ
σω
ω ρρ
−
∈
∆
∆ = = ∈ − = > ≥
∑
Definition 1. A sequence space E is said to be solid or normal if ( )k kx Eα ∈ whenever ( )kx E∈ and for all sequences of scalar ( )kα with 1kα ≤ [20].
Definition 2. A sequence space E is said to be monotone if it contains the canonical pre-images of all its steps spaces, [20].
Definition 3. If X is a Banach space normed by . , then ( )m X∆ is also Banach space normed by
( )1
.m
mk
kx x f x
∆=
= + ∆∑
Remark 1. The following inequality will be used throughout the paper. Let ( )kp p= be a positive sequence of real numbers with 0 supk kp p G< ≤ = , ( )1max 1,2GD −= . Then for all ,k ka b ∈ for all k ∈ . We have
( ).k k kp p pk k k ka b D a b+ ≤ + (1)
2. Main Results Theorem 1. Let ( )kM M= be a Musielak-Orlicz function, ( )kp p= be a bounded sequence of positive real number and ( )rkθ = be a lacunary sequence. Then ( ), , , , , .,. ,m
vM p u sθ
σω
∞ ∆ ( ), , , , , .,. m
vM p u sθ
σω ∆
and ( )0, , , , , .,. m
vM p u sθ
σω ∆ are linear spaces over the field of complex numbers.
Proof 1. Let ( ) ( ) ( )0, , , , , , .,. m
k k vx x y y M p u sθ
σω = = ∈ ∆ and ,α β ∈C . In order to prove the result we
need to find some 3ρ such that,
( )( )3
1lim , 0, uniformly in .
k
r
pm
nk v k ksk kr k Ir
t x yu k M z n
h
α β
ρ−
→∞ ∈
∆ + = ∑
Since ( ) ( ) ( )0, , , , , , .,. m
k k vx y M p u sθ
σω ∈ ∆ , there exist positive 1 2,ρ ρ such that
( )1lim , 0 uniformly in
k
r
pm
kn v ksk kr k Ir
t xu k M z n
h ρ−
→∞ ∈
∆ =
∑
and
( )1lim , 0 uniformly in .
k
r
pm
kn v ksk kr k Ir
t xu k M z n
h ρ−
→∞ ∈
∆ =
∑
Define ( )3 1 2max 2 ,2 .ρ α ρ β ρ= Since ( )kM is non decreasing and convex
M. Aiyub
2606
( )( )
( )( ) ( )( )
( ) ( )
( )
3
3 3
1 2
1 ,
1 , ,
1 , ,
,
k
r
k
r
k
r
r
pm
nk v k ksk k
k Ir
pm m
nk v k nk v ksk k
k Ir
pm m
nk v k nk v ksk k
k Ir
mnk v ks
k kk Ir
t x yu k M z
h
t x t yu k M z z
h
t x t yu k M z z
h
t xD u k M zh
α β
ρ
α β
ρ ρ
ρ ρ
ρ
−
∈
−
∈
−
∈
−
∈
∆ +
∆ ∆ ≤ +
∆ ∆ ≤ +
∆≤
∑
∑
∑
∑( )
,
0, as , uniformly in .
k k
r
p pm
nk v ksk k
k Ir
t yD u k M zh
r n
ρ−
∈
∆ +
→ →∞
∑
So that ( ) ( ) ( )0, , , , , .,. .m
k k vx y M p u sθ
σα β ω + ∈ ∆ This completes the proof. Similarly, we can prove that
( ), , , , , .,. mvM p u sθ
σω ∆ and ( ), , , , , .,. m
vM p u sθ
σω
∞ ∆ are linear spaces.
Theorem 2. Let ( )kM M= be a Musielak-Orlicz function, ( )kp p= be a bounded sequence of positive real number and ( )rkθ = be a lacunary sequence. Then ( )0
, , , , , .,. mvM p u sθ
σω ∆ is a topological linear
space totalparanormed by
( )( )
1
1
1inf : , 1 for some , 1, 2,
k
r
r
Hpmm nk v kp H s
k k kk k Ir
t xg x x u k M z r
hρ ρ
ρ−
∆= ∈
∆ = + ≤ =
∑ ∑
Proof 2. Clearly ( ) ( )g x g x∆ ∆= − . Since ( )0 0kM = , for all k ∈ . we get ( ) 0g θ∆ = , for .x θ= Let
( )kx x= , ( ) ( )0, , , , , .,. m
k vy y M p u sθ
σω = ∈ ∆ and let us choose 1 0ρ > and 2 0ρ > such that
( )( )1
1
sup , 1 1,2,3,
k
r
pm
nk v ksr k k
r k I
t xh u k M z r
ρ− −
∈
∆ ≤ =
∑
and
( )( )1
2
sup , 1 1,2,3,
k
r
pm
nk v ksr k k
r k I
t yh u k M z r
ρ− −
∈
∆ ≤ =
∑
Let 1 2ρ ρ ρ= + , then we have
( )( )
( )( )
( )( )
1
11
1 2 1
11
1 2 2
sup ,
sup ,
sup , 1.
k
r
k
r
k
r
pm
nk v k ksr k k
r k I
pm
nk v ksr k k
r k I
pm
nk v ksr k k
r k I
t x yh u k M z
t xh u k M z
t yh u k M z
ρ
ρρ ρ ρ
ρρ ρ ρ
− −
∈
− −
∈
− −
∈
∆ +
∆ ≤ +
∆ + ≤ +
∑
∑
∑
M. Aiyub
2607
Since 0ρ > , we have
( )
( )
( )
1
1
1
11 1
1inf : , 1 for some 0, 1, 2,
1inf : , 1 for some
k
r
r
k
r
r
Hpmm
nk v k kp H sk k k k
k k Ir
Hpmm
nk v kp H sk k k
k k Ir
g x y
t x yx y u k M z r
h
t xx u k M z
h
ρ ρρ
ρρ
∆
−
= ∈
−
= ∈
+
∆ + = + + ≤ > =
∆ ≤ + ≤
∑ ∑
∑ ∑
( )
1
1
2 21 2
0, 1, 2,
1inf : , 1 for some 0, 1, 2, .k
r
r
Hpmm
nk v kp H sk k k
k k Ir
r
t yy u k M z r
h
ρ
ρ ρρ
−
= ∈
> = ∆ + + ≤ > =
∑ ∑
( ) ( ) ( ).g x y g x g y∆ ∆ ∆+ ≤ +
Finally, we prove that the scalar multiplication is continuous. Let λ be a given non zero scalar in . Then the continuity of the product follows from the following expression.
( ) ( )
( ) ( )
1
1
1
1
1inf : , 1 for some 0, 1, 2,
1inf : , 1 for some 0
k
r
r
k
r
r
Hpmm
nk v kp H sk k k
k k Ir
Hpmm p H nk v ks
k k kk k Ir
t xg x x u k M z r
h
t xx u k M z
h
λλ λ ρ ρ
ρ
λ λ ζ ζζ
−∆
= ∈
−
= ∈
∆ = + ≤ > =
∆ = + ≤ >
∑ ∑
∑ ∑
, 1, 2,r =
where 0.ρζλ
= > Since ( )supmax 1, rr ppλ λ≤ ,
( ) ( )
( )
sup
1
max 1,
1inf : , 1, for some 0, 1, 2, .
r
k
r
r
p
Hpm
nk v kp H sk k
k Ir
g x
t xu k M z r
h
λ λ
ρ ρρ
∆
−
∈
=
∆ + ≤ > =
∑
This completes the proof of this theorem. Theorem 3. Let ( )kM M= be a Musielak-Orlicz function, ( )kp p= be a bounded sequence of positive
real number and ( )rkθ = be a lacunary sequence. Then
( ) ( ) ( )0, , , , , .,. , , , , , .,. , , , , , .,. .m m m
v v vM p u s M p u s M p u sθ θ θ
σ σ σω ω ω
∞ ∆ ⊂ ∆ ⊂ ∆
Proof 3. The inclusion ( ) ( )0, , , , , .,. , , , , , .,.m m
v vM p u s M p u sθ θ
σ σω ω ∆ ⊂ ∆ is obvious. Let
( ), , , , , .,. mk vx M p u sθ
σω ∈ ∆ . Then there exists some positive number 1ρ such that
( )1
1lim , 0
k
r
pm
nk v ksk kr k Ir
t x leu k M z
h ρ−
→∞ ∈
∆ − →
∑
as r →∞ , uniformly in n . Define 12ρ ρ= . Since kM is non decreasing and convex for all k ∈ , we have
M. Aiyub
2608
( )
( )
( )
1
1
1
1
1 ,
,
,
,
max 1, ,
k
r
k
r
k
r
k
r
pm
nk v ksk k
k Ir
pm
nk v ksk k
k Ir
p
kk Ir
pm
nk v kk
k Ir
t xu k M z
h
t x leD u k M zh
D leM zh
t x leD M zh
leD M z
ρ
ρ
ρ
ρ
ρ
−
∈
−
∈
∈
∈
∆
∆ − ≤
+
∆ − ≤
+
∑
∑
∑
∑
G
where ( )sup kkG p= , ( )max 1,2 1GD = − by (1). Thus ( ), , , , , .,. m
k vx M p u sθ
σω ∈ ∆ .
Theorem 4. Let ( )kM M= be a Musielak-Orlicz functions. If ( )sup kpk kM z < ∞ for all 0z > , then
( ) ( ), , , , , .,. , , , , , .,. .m mv vM p u s M p u sθ θ
σ σω ω
∞ ∆ ⊂ ∆
Proof 4. Let ( ), , , , , .,. mk vx M p u sθ
σω ∈ ∆ by using (1), we have
( )
( )
1 ,
,
, .
k
r
k
r
k
r
pm
nk v ksk k
k Ir
pm
nk v kk
k Ir
p
kk Ir
t xu k M z
h
t x leD M zh
leD M zh
ρ
ρ
ρ
−
∈
∈
∈
∆
∆ − ≤
+
∑
∑
∑
Since ( )sup kpk M z < ∞ , we can take the ( )sup kp
k M z K= . Hence we can get ( ), , , , , .,. m
k vx M p u sθ
σω ∈ ∆ .
This complete the proof. Theorem 5. Let 1m ≥ be fixed integer. Then the following statements are equivalent: 1) ( ) ( )1, , , , , .,. , , , , , .,.m m
v vM p u s M p u sθ θ
σ σω ω
∞ ∞− ∆ ⊂ ∆ ,
2) ( ) ( )1, , , , , .,. , , , , , .,.m mv vM p u s M p u sθ θ
σ σω ω− ∆ ⊂ ∆ ,
3) ( ) ( )0 01, , , , , .,. , , , , , .,. .m mv vM p u s M p u sθ θ
σ σω ω− ∆ ⊂ ∆
Proof 5. Let ( )0 1, , , , , .,. .mk vx M p u sθ
σω − ∈ ∆ Then there exist 0ρ > such that
( )1lim , 0.
k
r
pm
nk v ksk kr k Ir
t xu k M z
h ρ−
→∞ ∈
∆ →
∑
Since kM is non decreasing and convex, we have
M. Aiyub
2609
( )
( )
( ) ( )
1 11
1 11
1 ,2
1 ,2
1 1, ,2 2
k
r
k
r
k
r r
pm
nk v ksk k
k Ir
pm m
nk v k ksk k
k Ir
pm m
nk v k nk v ks sk k k k
k I k Ir r
t xu k M z
h
t x xu k M z
h
t x t xu k M z u k M z
h h
ρ
ρ
ρ ρ
−
∈
− −+−
∈
− −+− −
∈ ∈
∆
∆ − ∆ = ∆ ∆ ≤ +
∑
∑
∑ ∑
( ) ( )1 11, , .
k
k k
r r
p
p pm m
nk v k nk v ks sk k k k
k I k Ir r
t x t xD Du k M z u k M zh hρ ρ
− −+− −
∈ ∈
∆ ∆ ≤ +
∑ ∑
Taking limr→∞ , we have
( )1 , 0,
k
r
pm
nk v ksk k
k Ir
t xu k M z
h ρ−
∈
∆ =
∑
i.e. ( )0 1, , , , , .,. .mk vx M p u sθ
σω − ∈ ∆ The rest of these cases can be proved in similar way.
Theorem 6. Let ( )kM M= and ( )kT T= be two Musielak-Orlicz functions. Then we have 1) ( ) ( ) ( ), , , , , .,. , , , , , .,. , , , , , .,. .m m m
v v vM p u s T p u s M T p u sθ θ θ
σ σ σω ω ω
∞ ∞ ∞ ∆ ∆ ⊂ + ∆
2) ( ) ( ) ( ), , , , , .,. , , , , , .,. , , , , , .,. .m m mv v vM p u s T p u s M T p u sθ θ θ
σ σ σω ω ω ∆ ∆ ⊂ + ∆
3) ( ) ( ) ( )0 0 0, , , , , .,. , , , , , .,. , , , , , .,. .m m m
v v vM p u s T p u s M T p u sθ θ θ
σ σ σω ω ω ∆ ∆ ⊂ + ∆
Proof 6. Let ( ) ( ), , , , , .,. , , , , , .,. .m mk v vx M p u s T p u sθ θ
σ σω ω
∞ ∞ ∈ ∆ ∆ Then
( ),
1sup ,
k
r
pm
nk v ksk k
r n k Ir
t xu k M z
h ρ−
∈
∆ < ∞
∑
and
( ),
1sup ,
k
r
pm
nk v ksk k
r n k Ir
t xu k T z
h ρ−
∈
∆ < ∞
∑
uniformly in n. We have
( )( ) ( ) ( )
, , ,
k k kp p pm m m
nk v k nk v k nk v kk k k k
t x t x t xM T z D M z D T z
ρ ρ ρ
∆ ∆ ∆ + ≤ +
by (1). Applying rk I∈∑ and multiplying by 1,k
r
uh
and sk − both side of this inequality, we get
( )( )
( ) ( )
1 ,
, ,
k
r
k k
r r
pm
nk v ksk k k
k Ir
p pm m
nk v k nk v ks sk k k k
k I k Ir r
t xu k M T z
h
t x t xD Du k M z u k T zh h
ρ
ρ ρ
−
∈
− −
∈ ∈
∆ +
∆ ∆ ≤ +
∑
∑ ∑
M. Aiyub
2610
uniformly in n. This completes the proof 2) and 3) can be proved similar to 1). Theorem 7. 1) The sequence spaces , , , , , .,.M p u sθ
σω
∞ and
0, , , , , .,.M p u sθ
σω are solid and hence
they are monotone. 2) The space , , , , , .,.M p u sθ
σω is not monotone and neither solid nor perfect.
Proof 7. We give the proof for 0
, , , , , .,.M p u sθ
σω . Let
0, , , , , .,.kx M p u sθ
σω ∈ and ( )kα be a
sequence of scalars such that 1kα ≤ for all k ∈ . Then we have
( ) ( )1 1, , 0k k
r r
p p
nk k k nk ks sk k k k
k I k Ir r
t x t xu k M z u k M z
h hαρ ρ
− −
∈ ∈
≤ →
∑ ∑
( )r →∞ , uniformly in n. Hence ( )0
, , , , , .,.k kx M p u sθ
σα ω ∈ for all sequence of scalars ( )kα with
1kα ≤ for all k ∈ , whenever 0
, , , , , .,.kx M p u sθ
σω ∈ . The spaces are monotone follows from the re-
mark (1).
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