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Section 3: Dilutions Dilutions Calculatio ns

Section 3: Dilutions Dilutions Calculations. DDilutions llowers concentration, or molarity but… ttotal moles of solute does not change A. Dilutions

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Page 1: Section 3: Dilutions Dilutions Calculations. DDilutions llowers concentration, or molarity but… ttotal moles of solute does not change A. Dilutions

Section 3: Dilutions

• Dilutions• Calculations

Page 2: Section 3: Dilutions Dilutions Calculations. DDilutions llowers concentration, or molarity but… ttotal moles of solute does not change A. Dilutions

Dilutions

lowers concentration, or molarity

but…

total moles of solute does not change

A. Dilutions

mol L

M = mol

LM =

Page 3: Section 3: Dilutions Dilutions Calculations. DDilutions llowers concentration, or molarity but… ttotal moles of solute does not change A. Dilutions

A. Dilutions

6 molin 100 mL

6 molin 200 mL

same# of mol

Page 4: Section 3: Dilutions Dilutions Calculations. DDilutions llowers concentration, or molarity but… ttotal moles of solute does not change A. Dilutions

A. Dilutions

Page 5: Section 3: Dilutions Dilutions Calculations. DDilutions llowers concentration, or molarity but… ttotal moles of solute does not change A. Dilutions

Dilutions

A. Dilutions

initial Molarity

initial Volume

Molarity of dilute solution

Volume of dilute solution

Page 6: Section 3: Dilutions Dilutions Calculations. DDilutions llowers concentration, or molarity but… ttotal moles of solute does not change A. Dilutions

How many mL of 2.00 M MgSO4 must be diluted to prepare 100 mL of 0.400 M MgSO4?

V1 = (0.400 M) x (100 mL) = (2.00 M)

B. Calculations

Finding Volume (V1)

20.0 mL

M1

V2 M2

V1

(2.00 M) x V1 = (0.400 M) x (100 mL)

Page 7: Section 3: Dilutions Dilutions Calculations. DDilutions llowers concentration, or molarity but… ttotal moles of solute does not change A. Dilutions

200 mL of 10.0 M NaOH is diluted to 500 mL, what is the molarity of the dilute solution?

M2 = (10.0 M) x (200 mL) = (500 mL)

B. Calculations

Finding Molarity (M2)

4.00 M

M1 V2

M2

V1

(10.0 M) x (200 mL) = M2 x (500 mL)