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S. S 10. Secretion. Reabsorption. Filtration. Test # 3 on Monday. Covers only Cardiovascular and Respiratory. Some short answer questions and draw and label questions. Lab next week: Urinalysis!. Drink Test Beverage in 5 minutes or less. Urinalysis Lab. 800 ml tap water or - PowerPoint PPT Presentation
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Test # 3 on Monday
Covers only Cardiovascular and Respiratory.
Some short answer questions and draw and label questions.
Lab next week: Urinalysis!
1 Hrbefore LabEmpty bladder; note time
Beginning of Lab:Collect Urine, measure Volume and titrate [NaCl]
Drink Test Beverage in 5 minutes or less
At 30 min intervals, collect urinemeasure V and [NaCl]
30 min 30 min30 min30 min30 min
Drink plenty of water the day of lab;Avoid coffee, caffeine, salty foods
60 min
800 ml tap water or800 ml tap water + 7 g NaCl or 80 ml tap water + 7 g NaCl
Urinalysis Lab
During intervals, diagram the negative feedback loops.
Renal Physiology
• Structures of the kidney• Four fundamental renal mechanisms
– Filtration– Reabsorption– Secretion– Metabolism
• Functions of the kidneys– Homeostasis
• Fluid balance (blood pressure)• Electrolyte balance (blood pressure, membrane excitability)• Acid-base balance (in concert with lungs)
S 11
Special terms• Filtration: movement of fluid from blood into
the lumen of the nephron (renal tubule)
• Reabsorption: the movement of specific compounds from the tubular lumen back into the blood (peritubular capillaries)
• Secretion: the transport of specific compounds from blood into the tubular lumen
• Excretion: elimination from the body in urine
Glomerular Filtration Rate = 120 ml/ min
Lab: Extra 800 ml intake!
Sidebar: some desert animals never drink and must obtain all their water in the diet.
Kidneys are source of 3 hormones: Renin, EPO, and Vit D.Kidneys are targets of 3 hormones: ADH, Aldosterone, ANH
Topics discussed: cortex, medulla, kidney stones, micturition (detrussor, internal and external urethra sphincters and innervation), incidence of bladder infections by gender, urethral sphincters
Tubular fluid vs urine
Nephron = tubule
S 15
Fig. 14.02a
Renalcorpuscle
Juxtamedullary and Cortical Nephrons
Peritubular Capillaraies and branch thereof called vasa recta
S 19
A Portal System
Fig. 14.05Glomerular Filtration Rate is 120 ml/min = 180 L/day
Three stimuli for secretion of renin from JGC
Figure 14.03Ultrafiltrate of plasma enters Bowman’s space
Composition same as plasma except no formed elements and no proteins and no substances bound to proteins
Fig. 14.09
Ways to alter GFR
What happens during hemorrhage?
What substances can cause this constriction?
Figure 14.10
Membrane proteins are segregated into apical (luminal) and basolateral membranes.
reabsorption
S e c r e t i o n
metabolismAmino acid glucose
Reabsorption and secretion in proximal tubule is NOT under hormonal control.Primary active transport of Na+ establishes a gradient for reabsorption of glucose, amino acids, etc.
Reabsorption and secretion in DCT & CCD is under hormonal control.Hormones that act here: ANH, ADH, Aldosterone.
Here, reabsorption of Na+ is linked to the secretion of K+.
Figure 14.10
Membrane proteins are segregated into apical (luminal) and basolateral membranes.
reabsorption
secretionmetabolism
Amino acid glucose
Consider a substance that in filtered only, no reabsorption, no secretion.
Excretion of this substance = GFRClearance of this substance = GFR
• Clearance = volume of plasma from which a substance is completely removed (cleared) by the kidneys per unit time.
• Clearance of Inulin is 120 ml/min
• Cinulin or Ccreatinine = Glomerular Filtration Rate
Filtration + complete Secretion
Ex: Para AminoHippurate (PAH)
Measure Renal Plasma Flow
Filtration + partial reabsorption
Ex: SodiumEx: Water
Filtration + 100 Reabsorption
Ex: GlucoseEx: Amino Acids
Renal Handling of Substances
• Clearance = volume of plasma from which a substance is completely removed (cleared) by the kidneys per unit time.
• Clearance of Inulin is 120 ml/min
• Cinulin or Ccreatinine = Glomerular Filtration Rate
• If C x is greater than GFR ( which is Cinulin) then that substance undergoes NET TUBULAR SECRETION
• If C x is less than GFR ( which is Cinulin) then that substance undergoes NET TUBULAR REABSORPTION
A little more on Clearance:
Clearance of glucose = 0 ml/min which means….
Clearance of X = 120 ml/min which means….
Clearance of antibiotic XXX = 500 ml/min which means…
Calculating clearanceClearance of s = Urine concentration of s X Urine Volume
Plasma concentration of s
Special cases: Clearance of
•Inulin and creatinine (filtered only; use to measure Glomerular Filtration Rate.)
•Para Amino Hippurate (filtered and completelysecreted, use to measure Renal Plasma Flow)
“24 hour urine catch” + blood sample