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Review of t -test. Numerator quantifies the difference between the experimental conditions Denominator is based on a weighted average of the variances within the two groups - PowerPoint PPT Presentation
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Numerator quantifies the difference between the experimental conditions
Denominator is based on a weighted average of the variances within the two groups
You will find that the ANOVA uses the same principle, but expands the number of conditions that can be included in the numerator.
1 2
Pooled
M Mt
SE
From Chocolate Choo-choo data:◦ S2
Auditory = 4.087
◦ S2Image = 1.583
◦ F(1,5) = 4.087/1.583 = 3.987, p>.05◦ C.V. = 6.61
We are safe making the assumption about equal variances in these two samples.
The ratio of two equal variances is 1. Variances cannot be negative so the F-ratios
cannot take on a negative value. In theory, these ratios can take on infinitely
large values, but will only do so on rare occasions.
Like the t-distributions, the F-distributions are really a family of distributions that are determined by the degrees of freedom.
Notice that now we have two degrees of freedom to deal with (numerator and denominator).
At least two independent samples, but typically more than two.
The samples are drawn from approximately normal distributions.
The samples are drawn from populations with equal variances.
Sound familiar?
Within groups variance = Error + Individual Differences
Between groups variance = Error + Individual Differences + ETOH effects
If ETOH effects = 0 then Between/Within = 1 The within groups variance is simply the
average or the variances within each group. We can calculate the Between groups
variance as Σ(MGroup-GM)2/(NGroups-1)◦ We have to multiply this sum by n to convert from
SE2 to S2.
Group 1 Group 2 Group 3 Group 4
n 25 25 25 25
M 94 101 124 105
s 24 28 31 25
s^2 576 784 961 625
Grand Mean = 106 Variance Between ((94-106)2+(101-106)2+(124-
106)2+(105-106)2)/3 = ??? MSBetween = 164.67*25 = ??? MSWithin = (576+784+961+625)/4 = ??? F = 4116.667/736.5 = ??? dfBetween = 4-1 = 3 dfWithin = 24*4 = 96 C.V.alpha=.05 = 2.70 F(3,96) = 5.590, p < .05