Upload
dalmar
View
46
Download
0
Tags:
Embed Size (px)
DESCRIPTION
Recursive methods for two-dimensional risk processes with common shocks. Lan Gong – University of Toronto (joint work with Andrei L. Badescu and Eric C.K. Cheung). Summary. Introduction A recursive approach A Gerber Shiu function at claim instants Numerical illustrations Conclusions. - PowerPoint PPT Presentation
Citation preview
Recursive methods for two-dimensional risk processes with common shocks
Lan Gong – University of Toronto(joint work with Andrei L. Badescu and Eric C.K. Cheung)
Summary
•Introduction•A recursive approach•A Gerber Shiu function at claim instants•Numerical illustrations•Conclusions
Introduction• Chan et al. (2003) , Dang et al. (2009)
• - the initial capital of the i-th class of business;• - the premium rate of the i-th class of business;• - the k-th claim amount in the i-th risk process, with common cdf
and pdf ; • - the counting process for the i-th risk process. are common shock correlated Poisson processes occurring at rates respectively.
where are independent Poisson
processes with rates ;
(1) 2,1 ;0 ,)()(
1
tN
k
ikiii
i
itXtcutU
iuicikX )(iF
)(if)(tNi
)( and )( 21 tNtN21 and
)()( )( 12111 tNtNtN )()( )( 12222 tNtNtN
)( and )(),( 122211 tNtNtN
122211 and ,
Introduction
•
•
•
•
),min(}0)}(),(min{|0inf{ 2121 tUtUtTor
}0)}(),(max{|0inf{ 21 tUtUtTsim
),max( 21 andT
}0)()(|0inf{ 21 tUtUtTsum
References• Chan et al. (2003)
• Cai and Li (2005)
• Yuen et al. (2006)
• Li et al. (2007)
• Dang et al. (2009)
Introduction• Chan et al. (2003) for
• Dang et al. (2009)
(2) )()(),(),(),(),( 1 2
0 0 112222111221122
212
1
211
u uzdFzdFzuzuuu
uuuc
uuuc
1),(point startingwith
),(
(3) ),(
),({),(
210
21
])([)()(
0 21
12
])([)()(
0 21
12)()(
0 0 21221112
2112211
11222
1122
2
12
2
1222
1
22111
2211
1
12
1
2111
2
2221111 2
uu
dadaeeaa
dadaeeaa
dadaeeaacc
uu
auuaccau
c
u
uuacc
n
auuaccau
c
u
uuacc
n
uauau u
nn
02211
An alternative recursive approach
221211
21
])([)()(
0 212
111
2211
2112
12
])([)()(
0 211
222
2211
2112
12)()(
0 0 212211
2112211
where
),(
(5) ),(
),(),(
11222
1122
2
2
1222
1
22111
2211
1
1
2111
2
2221111 2
s
auuaccau
c
u
uuacc
nS
auuaccau
c
u
uuacc
nS
uauau u
nS
n
dadaeeaaccc
dadaeeaaccc
dadaeeaacc
uu
s
s
dtdxdxexfxfxtcuxtcu
dtdxexfxtcutcu
dtdxexftcuxtcuuu
dtdxdxexfxf
dtdxexfdtdxexfuu
uu
ttcu tcu
n
ttcu
n
ttcu
nn
ttcu tcu
ttcuttcu
21)(
1222110 0 0 222111
2)(
22220 0 22211
1)(
11110 0 22111211
21)(
1222110 0 0
2)(
22220 01)(
11110 0211
210
12221122 11
12221122
12221111
12221122 11
12221122
12221111
)()(),(
)(),(
(4) )(),(),(
,)()(
)()(),(
,1),(
Phase-type claims – survival probability
• Let follow independent PH distributions with parameters (α, T) and (β, Q).
21)]([)]([
))](()([1
21121221
)(
0
12)]([)]([
))](()([1
21121221
)(
0
12)]([)]([
1211212210 0211
)(
)]()()[(),(
)(
(6) )]()()[(),(
)(
)]()()[(),(),(
2211
2
222112
2
1222
1
2211
1
112112
1
2111
2
2211
1 2
dadaqte
eQcTcaa
dadaqte
eQcTcaa
dadaqte
QcTcaauu
auQauT
cuaQcTc
u
uuacc
n
auQauT
cuaQcTc
u
uuacc
n
auQauT
u u
nn
1
21
1 }{ and }{ kkkk XX
Gerber Shiu function•
• is a penalty function that depends on the surplus
levels at time Tor in both processes.
• Here are few choices of the penalty functions1. 2. 3.
4.
(7) )]())(),(([),( 21),(21 21
orororT
uu TITUTUweEuum or
),( w
(8) )())(),((
)())(),(()())(),(())(),((
212112
12212
21211
21
ITUTUw
ITUTUwITUTUwTUTUw
oror
orororororor
1),(),(),( 1221 www1),( and 0),(),( 0, 1221 www
zyzywzzywyzyw ),( and ),(,),( 1221
(9) )];(|)(|[)];(|)(|[ 21222),(12111),(2
21
1
21 IUeEIUeE uuuu
0),(),( and ),( 1221 wwzyzyw(10) )]())()(([ 212211),(
1
21 IUUeE uu
•
•
•
Where correspond to the cases {τ1<τ2}, {τ2<τ1} and {τ1=τ2} respectively.
(11) )]())(),(([),( 21),(21 21 norororT
uun STITUTUweEuum or
(12) ),(),( 211
21 uumuum nn
(13) ),(),(),(),( 2112121
2121
11211 uumuumuumuum
),( and ),(),,( 2112121
2121
11 uumuumuum
Gerber Shiu function for ruin at n-th claim instant
Expected discounted deficit• Considering the first case when ruin occurs at the first claim
instant in {U1(t)} only and using a conditional argument gives
• By similar method, one immediately has . Hence by adding
, we obtain the starting point of recursion.
• If , and , the three integrals reduce to
dzdydteztcufytcufzyw
dydteytcuftcuywuum
ttcu
t
s
s
)(122221110 0 0
1
)(11111220 0
121
11
)()(),(
(14) )(),(),(
22
121
21 and mm
121
21
11 and , mmm
.)()(),(
(15) ,)]()[(),(
,)]()[(),(
1)(
12111222110 021121
)(11112222220 021
21
)(22212111110 021
11
11
11
dydtdxexytcutcufxfyuum
dydtetcuFytcufyuum
dydtetcuFytcufyuum
tytcu
tcu
t
t
s
s
s
zzywyzyw ),( ,),( 21 zyw 12
Exponential claims-Expected discounted deficit•
• The idea that we use to find a computational tractable solution of (16) is based on mathematical induction.
•
• Therefore, the expected discounted deficit when ruin happens at the instant of the first claim is given by
.)11(),(
(17) ,)()(
),(
,)()(
),(
)(
2211
12
2121
121
)(
22112
12
222
122221
21
)(
22111
12
111
121121
11
2211
221122
221111
uu
s
uu
s
u
s
uu
s
u
s
ecc
uum
ecc
ec
uum
ecc
ec
uum
(18) )()(
),( 2211
222
1222
111
1211211
u
s
u
s
ec
ec
uum
dtdxdxexfxfxtcuxtcum
dtdxexfxtcutcum
dtdxexftcuxtcumuum
s
s
s
tcu tcu
n
tcu
n
tcu
nn
21)(
1222110 0 0 222111
2)(
22220 0 22211
1)(
11110 0 22111211
)()(),(
(16) )(),(
)(),(),(
22 11
22
11
Expected discounted deficit
.any for 0 assume that weNote
.0 ,)(
,)(
bygiven ispoint starting The . ,,,1,0, ;,2,1
,)(!!
!!12
)(!!!!1
)(!!!!1
))(!
!)(!
!)(0(
))(!
!)(!
!)(0(
,)(!
!)(!
!
,)(!
!)(!
!
with,,1,0for
,),(
k
ji
]0,0,1[222
1222]0,1[
111
1211]0,1[
2211
12
32211
12
112112],,[
1
)0,1max(
1
)0,1max(
22211
21
1111],,[1 1
)0,1max(
22211
121222],,[
1 1
)0,1max(
1
)0,1max(
1
12211
2],[111
2211
12],[2
1
)0,1max(
1
12211
1],[221
2211
11],[1
],,1[
1
)0,1max(
1
122
2],[111
22
12],[
22]0,1[
],1[
1
)0,1max(
1
111
1],[221
11
11],[
21]0,1[
],1[
)(21
0],,1[
02
0],1[1
0],1[211n
22112211
kj
ec
bc
a
ccwherenkjnfor
cckjccqie
kqkjqi
cckjccqie
kqkjqi
cckjccqie
jikjqi
cckicb
cckicb
jI
ccjica
ccjica
kIe
cjcib
cjcibb
b
cjcia
cjciaa
a
n
euueeubeuauum
ss
s
kjqis
kqjiqin
n
kq
n
ji
kjqis
kqjiqin
n
kq
n
ji
kjqis
kqjiqin
n
ji
n
kq
n
ki
n
jiki
s
kiin
kis
kiin
n
ji
n
jiji
s
jiin
jis
jiin
kjn
n
ji
n
jiji
s
jiin
jis
jiin
jn
n
ji
n
jiji
s
jiin
jis
jiin
jn
uukjn
jkjn
n
k
ujn
jjn
ujn
jjn
Mixture of Erlangs claims - Survival probability
•
• Using equation (4) for n=0 and λ11=λ22=0 along with the trivial condition
, we obtain
.1,,1,0,for
,)(!!!!
,)()!(!
,)()!(!
where
,1),(
1
1
12211
2121
1
1
],,1[
1
1
122
22],1[
1
1
111
11],1[
1
0
)(21
1
0],,1[
1
02],1[
1
01],1[211
22112211
mvscclkvs
ccqpsk
vslke
cskscp
b
cskscqa
euueeubeuauu
m
si
i
skvslk
lkvlskij
m
vj
j
vlvs
m
sj
j
sksk
kskj
s
m
si
i
sksk
kski
s
m
s
uuvsm
vvs
m
s
uss
m
s
uss
,)!1(
)(111
11
111
i
exqxfxiim
ii
)!1(
)(221
22
122
j
expxfxjjm
ij
1),( 210 uu
.1)1(,,1,0,,2,1for
,)(!!)!1()!1(
)!()!()1(
))((
))((!!)!1()!()1(
)10(
))((!!)!1()!()1(
)10(
)10,10(
,))((!)!(!)!1(
!)!()1(
)10(
,))((!)!(!)!1(
!)!()1(
)10( with,,1,0for
,1),(
)u,(ulim),(
12211
2121
)1,1max(
1
)0,max( 0 )1,1max(
1
)0,max( 0
],,[
12211
2121
)1,1max(
1
)0,max( 0],[
1
1
12211
2121
)1,1max(
1
)0,max( 0],[
1
1
],,1[],,1[
)1,1max(1
22
221
)0,max( 0],[
],1[],1[
)1,1max(1
11
111
)0,max( 0],[
],1[],1[
)(21
1)1(
0],,1[
1)1(
02
1)1(
0],1[1
1)1(
0],1[211n
21n21
22112211
mnymccywji
jviscczv
vgs
swis
ywjvis
zjvgiseqpccjgsywj
jsccgs
syjs
ywkjs
bqpmwI
ccigsywiiscc
gss
wisywkis
bqpmyI
mymwIeecjgswgsgjsjscbp
mwIbbcigswgsgisiscaq
mwIaan
euueeubeuauu
uu
ywjivs
jiyjvwiszgvs
m
mnwi
nm
iws
s
g
m
mnyj
nm
jyv
v
z
vsnij
ywsjk
jkyjswkgs
m
mnwi
nm
iws
s
gsnij
m
wi
i
wk
ywlis
jkylwisgs
m
mnwi
nm
iws
s
gsnij
m
wi
i
wk
ywywn
m
mnwjwjs
wjsjgsnm
jws
s
gsnj
wwn
m
mnwiwis
wisigsnm
iws
s
gsni
wwn
uuywmn
yywn
mn
w
uwmn
wwn
uwmn
wwn
n
Survival probability for Tand
• We denote the survival probability associated to the time of ruin Tand, by .
•
•
21212121 ,|or ,|),( uuPuuTPuu andand
. ),()()(),( 2122
11
21 uuuuuu ornnn
andn
dtetcudtdxexfxtcuu t
n
ttcu
nnss
2211
1
011211111110 0
11
11 )())(()()( 11
. ispoint starting The .,,1,0;,2,1for
,)(!
!)(!
!)0(
with,0,1,nfor
,1)(
tionrepresenta theadmits eventsclaimth -1)(n theincluding and toup )(y probabilit survival univariate The
11
12111]0,1[
1
111
1221
],[1
)0,1max(2
11
11
1],[1
1]0,1[1
]0,1[1
],1[
10
1],1[1
11n
11
1n
11
canjn
cjica
cjicaa
jIaa
euau
u
s
n
jiji
s
jiin
n
jiji
s
jiin
jn
ujn
jjn
Numerical illustrations
• u1=2 ,u2=10, c1=3.2, c2=30, 1/µ1=1 and 1/µ2=10.
• Case 1: Independent model — λ11=λ22=2; λ12=0. Case 2: Three-states common shock model — λ11=λ22=1.5;
λ12=0.5. Case 3: Three-states common shock model — λ11=λ22=0.5;
λ12=1.5. Case 4: One-state common shock model — λ11 = λ22 = 0;
λ12 = 2.
• Note that λ1 = λ2 = 2, and θ1 = 0.6 and θ2 = 0.5.
Numerical illustrations
• In Case 1, after 100 iterations we obtain a ruin probability of 0.6306428 that is very close to the exact value of 0.6318894.
•
)()(
)()(
),(} )(),(max{
22
11
22
11
21
22
11
uu
uu
uuuu
or
Numerical illustrations
• Cai and Li (2005, 2007) provided simple bounds for Ψand(u1, u2) given by
)}(),(min{
),()()(
22
11
21
22
11
uu
uuuu
and
Numerical illustrations
• δ = 0.05
Numerical illustrations
• This quantity is achieved by letting w1(y, z) = y+z and w2(.,. ) = w12(.,.) =0
Numerical illustrations
• This quantity is achieved by letting w2(y, z) = y+z and w1(.,. ) = w12(.,.) =0
Conclusions
• Several extensions:
1. Correlated claims
2. Correlated inter-arrival times and the resulting claims
3. Renewal type risk models