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Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

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Page 1: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Project Impact CURR 231Curriculum and Instruction in Math

Session 6

Chapters 8 & 9

Page 2: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Outcomes Number Talk – Middle School Example Share Website Reflections Text – Teaching Math 8 & 9 Video – Math Talks Make and Take – Fraction Tiles and/or Circle

Pizza Game time – student led

Page 3: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Number Talk

9.8 + 8.7Think first and estimate your answer beforeattempting to solve the problem.

Mentally solve the problem.

Share with a partner how you solved this. I will Listen and post some of your strategies for solving thismentally.

Page 4: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Share Website Reflections Each participant will share the highlights of

their favorite math related website.

Page 5: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Chapter 8: Fractions:Working with Units Smaller Than One

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Page 6: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Presentation 8a Finding and Using Equivalent Fractions

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Page 7: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

One of the most effective models for fractions is a pictorial model rather than a physical model.

The fraction square is an excellent tool for establishing mental imagery for a wide variety of fraction concepts.

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Page 8: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Begin with a unit square.

Each side of the unit square is 1.

1

1

The area of the unit square is also 1.

1

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Page 9: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

It can be subdivided vertically.

The area of the unit square can be subdivided several ways into equal parts.

Thirds

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Page 10: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

It can be subdivided horizontally.

Fourths

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Page 11: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

It can be subdivided both vertically and horizontally.

Twelfths

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Page 12: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

If parts of an equally subdivided unit square

2

3

are shaded a different color, image of a fraction is presented.

a clear visual

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Page 13: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

3

4

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Page 14: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

7

12

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Page 15: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Fraction squares can also provide clear visual images for equivalent fractions.

2

3

If we begin with a fraction using vertical subdivisions, we can visualize another name

for that fraction if we subdivide the parts horizontally.

4

6=

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Page 16: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

If we begin with a fraction using horizontal subdivisions, we can visualize another name

for that fraction if we subdivide the parts vertically.

9

12=

3

4

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Page 17: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

When enough examples have been accumulated, children can readily recognizea pattern that suggests how to find equivalent fractions.

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Page 18: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Suppose we begin with another fraction. If we cut the parts using one horizontal line,

4

6=

every part is cut into two pieces. We have 2 times as many parts.Every shaded part is also cut into two pieces. We have 2 times as many shaded parts.

X 2

X 22

3

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Page 19: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

We can find another name for the same fractional amount if we multiply both the numerator and denominator by the same number.

12

16=

X 4

X 43

4

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Page 20: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

5

10=

X 5

X 51

2

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Page 21: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

12

18=

X 6

X 62

3

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Page 22: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

There is one big idea that determines what we do procedurally when making comparisons—

People who compare unlike things are said to be “comparing apples and oranges.” Comparison of fractions is much easier when the fractional units are the same.

we compare like units.

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Page 23: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

For example, it is difficult to tell which of these fractions is greater.

2

3

3

5

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Page 24: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

2

3

3

5

If we rename the fractions using the same fractional units,

10

15= =

9

15

the comparison is easy.

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Page 25: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

2

3

3

5

10

15= =

9

15

2

3

3

5>

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Page 26: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

A similar process can be used to compare these fractions.

1

4

2

7

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Page 27: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1

4

2

7

We rename the fractions using the same fractional units.

7

28= =

8

28

1

4

2

7

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Page 28: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1

4

2

7<

1

4

2

7

7

28= =

8

28

1

4

2

7

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Page 29: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1

4

2

7

Note that the process we have been using results in our renaming the fractions using a common denominator which is the product of the two original denominators.

1 X 7

4 X 7= =

4 X 2

4 X 7=

7

28=

8

28

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Page 30: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

3

5

1

3

We can do this to compare any two fractions.

15

Multiply the denominator by 3.

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Page 31: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

3

5

1

3

15

Multiply the numerator by 3.

9

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Page 32: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Multiply the denominator by 5.

3

5

1

3

15

9

15

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Page 33: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Multiply the numerator by 5.

3

5

1

3

15

9

15

5

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Page 34: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

3

5

1

3

15

9

15

5

Both fractions have the same denominator.

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Page 35: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

3

5

1

3

15

9

15

5

So the numeratortells which

fraction is greater.

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Page 36: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

3

5

1

3

15

9

15

5

If we know the denominators will be the same

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Page 37: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

3

5

1

3

15

9

15

5

we only need tocompare thenumerators.

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Page 38: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

5

7

3

5

We will use the same procedure to compare two other fractions.

We know that 35 will be the denominator of both fractions.

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Page 39: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

5

7

3

5

We will use the same procedure to compare two other fractions.

So all we need to compute are the two numerators.

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Page 40: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

5

7

3

5

We will use the same procedure to compare two other fractions.

The numerators will tell us which fraction is greater.

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Page 41: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

5

7

3

5

25 21

This numerator is greater.

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Page 42: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

5

7

3

5

25 21

So this is the greater of the two original fractions.

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Page 43: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1615 3

8

2

5

This is the greater of the two original fractions.

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Page 44: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

The notion of equivalent fractions is also used when we add unlike fractions.

Remember that we always add like units.

2

3

3

5+

Suppose we want to add fractions with unlike fractional units.

We need to rename those fractions so the units will be the same.

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Page 45: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

2

3

3

5

10

15= =

9

15

2

3

3

5+

10

15= +

9

15

19

15=

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Page 46: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Suppose we want to add these fractions:

2

7

1

4+

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Page 47: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1

4

2

7

7

28= =

8

28

1

4

2

7

2

7

1

4+

7

28= +

8

28=

15

28

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Page 48: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

So it turns out that when we have unlike fractions to add,

1

8

2

3+

product of the two denominators as the common denominator.

we can always use the

We can use 24 as the common denominator.

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Page 49: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1

8

2

3+

We multiply this numerator and denominator by 8.

=16

24

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Page 50: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

We multiply this numerator and denominator by 3.

1

8

2

3+ =

16

24+

3

24=

19

24

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Page 51: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Chapter 8: Fractions:Working with Units Smaller Than One

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Page 52: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Presentation 8b ModelingFraction Multiplication

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Page 53: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

In the literature, you can find two different approaches for modeling multiplication of fractions that are supported by research:

A Fraction of a Fraction

Length X Length = Area

We will examine each of these two methods.

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Page 54: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

We will begin by thinking of fraction multiplication as finding a fraction of a fraction.

We will think of2

3X

3

4

as meaning the same as2

3of .

3

4

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Page 55: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

In order to find2

3of ,

3

4

we will start with 3

4

and find of it. 2

3

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Page 56: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

A Fraction of a Fraction

34

23

of

23

34X = 6

12

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Page 57: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

23

12

of

12

23X = 2

6

12

23X

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Page 58: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

34

of

34

25X = 6

20

34

25X

25

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Page 59: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Now, we will think of fraction multiplication as multiplying lengths of the sides of a rectangle to find its area.

to get this area.We multiply this length times this length

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Page 60: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Let’s examine how this approach works with fraction multiplication.

34This length is

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Page 61: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

23This length is

34

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Page 62: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

23

34

This area is X34

23

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Page 63: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

23

34

This area is X34

23

It is also612

34

23X =

612

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Page 64: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

12This length is

45This length is

12

45X

This area is12

45X

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Page 65: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

12This length is

45This length is

12

45X

This area is12

45X

12

45X 4

10=

It is also equal to4

10

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Page 66: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Either of these approaches to the modeling of fraction multiplication works well with children.

Both methods do an effective job of building mental imagery for the process.

Both methods do a good job of convincing children that the answers make sense—that they must be correct.

And, consequently, both methods produce results that can be used as the basis for generalizing the fraction multiplication algorithm.

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Page 67: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Chapter 9: Decimals and Percents:Working with Base-Ten Units Smaller Than One and Using Hundredths as a Common Denominator

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Page 68: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Presentation 9 Fraction Comparison and theMeaning of Percent

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Page 69: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Recall that there is one big idea for comparison—compare like units.

We have already applied this big idea in the comparison of two fractions. We renamed the fractions with the same denominator (the fractional unit) and then the comparison was easy.

If we want to compare more than two fractions, we need to rename them so that all of them have the same denominator.

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Page 70: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

For example, suppose we have these three fractions:

1 2

23

25

We can rename the fractions using 30 ( that is, 2 X 3 X 5) as the denominator.

= 1530

= 2030

= 1230

Now it is easy to compare any two of the fractions or arrange the fractions in order.

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Page 71: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

These same three fractions can be renamed using any number as the denominator.

1 2

23

25

To accomplish this, we begin by multiplying the numerator and the denominator by 17.

= 1734

= 3451

= 3485

For example, we could use 17 as the denominator.

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Page 72: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

These same three fractions can be renamed using any number as the denominator.

1 2

23

25

Then we divide the numerator and the denominator by the original denominator.

= 1734

= 3451

= 3485

For example, we could use 17 as the denominator.

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Page 73: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

These same three fractions can be renamed using any number as the denominator.

1 2

23

25

= 1734

= 3451

= 3485

For example, we could use 17 as the denominator.

Divide this numerator Divide this numerator and denominator by 2.and denominator by 2.

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Page 74: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

These same three fractions can be renamed using any number as the denominator.

1 2

23

25

= 8.50 = 3451

= 3485

For example, we could use 17 as the denominator.

17

Divide this numerator Divide this numerator and denominator by 2.and denominator by 2.

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Page 75: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

These same three fractions can be renamed using any number as the denominator.

1 2

23

25

= 8.50 = 3451

= 3485

For example, we could use 17 as the denominator.

17

Divide this numerator Divide this numerator and denominator by 3.and denominator by 3.

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Page 76: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

These same three fractions can be renamed using any number as the denominator.

1 2

23

25

= 8.50 = 3485

For example, we could use 17 as the denominator.

17= 11.33

17

Divide this numerator Divide this numerator and denominator by 3.and denominator by 3.

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Page 77: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

These same three fractions can be renamed using any number as the denominator.

1 2

23

25

= 8.50 = 3485

For example, we could use 17 as the denominator.

17= 11.33

17

Divide this numerator Divide this numerator and denominator by 5.and denominator by 5.

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 78: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

These same three fractions can be renamed using any number as the denominator.

1 2

23

25

= 8.50 =

For example, we could use 17 as the denominator.

17= 11.33

176.8017

Divide this numerator Divide this numerator and denominator by 5.and denominator by 5.

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 79: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

These same three fractions can be renamed using any number as the denominator.

1 2

23

25

= 8.50 =

For example, we could use 17 as the denominator.

17= 11.33

176.8017

Now it is easy to compare any two of the fractions or arrange the fractions in order.

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 80: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Or, we could use 100 as the denominator.

1 2

23

25

To accomplish this, we begin by multiplying the numerator and the denominator by 100.

= 100200

= 200300

= 200500

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

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All rights reserved.

Page 81: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1 2

23

25

Then we divide the numerator and the denominator by the original denominator.

= 100200

= 200300

= 200500

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

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All rights reserved.

Page 82: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1 2

23

25

= 100200

= 200300

= 200500

Divide this numerator Divide this numerator and denominator by 2.and denominator by 2.

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 83: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1 2

23

25

= 50 100

= 200300

= 200500

Divide this numerator Divide this numerator and denominator by 2.and denominator by 2.

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 84: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1 2

23

25

= 50 100

= 200300

= 200500

Divide this numerator Divide this numerator and denominator by 3.and denominator by 3.

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 85: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1 2

23

25

= 50 100

= 66.67 = 200500100

Divide this numerator Divide this numerator and denominator by 3.and denominator by 3.

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 86: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1 2

23

25

= 50 100

= 66.67 = 200500100

Divide this numerator Divide this numerator and denominator by 5.and denominator by 5.

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 87: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1 2

23

25

= 50 100

= 66.67 = 40 100100

Divide this numerator Divide this numerator and denominator by 5.and denominator by 5.

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 88: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

1 2

23

25

= 50 100

= 66.67 = 40 100100

Now it is easy to compare any two of the fractions or arrange the fractions in order.

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 89: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

When the denominator is 100, the numerator is called the percent. The symbol for percent is %.

23

25

1 2

= 50 100

= 66.67

= 40 100

100

= 50% (One half equals 50 percent.)

= 66.67% (Two thirds equals 66.67 percent.)

= 40% (Two fifths equals 40 percent.)

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 90: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

The term percent literally means “per hundred”

1 2

= 50 100

= 50%

or “out of one hundred.”

50 out 50 out of one of one hundredhundred

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 91: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

The term percent literally means “per hundred”

1 2

= 50 100

= 50%

or “out of one hundred.”

50 per 50 per hundredhundred

50 percent50 percent

Tucker/Singleton/WeaverTeaching Mathematics to ALL Children, Second Edition

Copyright ©2006 by Pearson Education, Inc.Upper Saddle River, New Jersey 07458

All rights reserved.

Page 92: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Video – Math Talks Catherine Pieck 6th Number Talk

Page 93: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Make and Take Activity Fraction Tiles

Page 94: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Activity

GAME TIME!!!

Each week, students will take turns leading the class in a math game.

Page 95: Project Impact CURR 231 Curriculum and Instruction in Math Session 6 Chapters 8 & 9

Closing Final thoughts, comments? Making connections – Anything to add to

your reflection?