Prestressed Concrete - 2 Beam in Bending at Working Load

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Design of prestressed concrete in bending.

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  • 2. Prestressed Concrete:

    Beam in bending at

    working load

    Introduction

    Bending stresses in an uncracked section

    Jacking force Po, initial force Pi and

    effective force Pe.

    Two important properties of a prestressed

    section

    Stress distribution across an uncracked section

    University of Western AustraliaSchool of Civil and Resource Engineering 2004

  • INTRODUCTION

    Basic assumptions:

    Bernoulli/Navier postulate ( plane sections remain plane)

    Linear performance for concrete

    Tendon stress unaltered through range from transfer to working load

    sc

    ec

    f c

    Approx.

    linear to

    0.5 f c

    NB Demonstrating that stresses are

    acceptable at working load does not

    ensure that section has adequate

    safety. This is treated later in the

    course.

    Lecture 5

    So how to estimate the bending stresses at working load? . . .

  • BENDING STRESSES IN AN

    UNCRACKED SECTION

    Start by assuming that the section is uncracked and linear, then demonstrate

    that each is true.

    Limiting stresses:

    Concrete is linear up to about 0.5 fc where f c = current strength

    Two conditions of concern: At transfer, when f c = f cp and

    At maturity, when f c = f c

    At transfer to ensure linearity : sb = - 0.25 (f cp)0.5

    At maturity to ensure linearity : sa = - 0.25 (f c)0.5

    sc

    ec

    f c

    0.5 f cCONCRETE

    Consider this example . . .

  • centroidal

    axis

    Tendon stressed

    to force P

    applied loading

    Simple Beam - stresses in working load range

    Examine this typical section, where

    the applied bending moment = M

    This section may be anywhere along the beam,

    EXCEPT very close to the supports . . .

  • applied loading

    axis

    Examine this section, whereTendon stressed

    to force P

    centroidal

    applied moment = M.

    Simple Beam - actions at a typical section

    Stresses due to prestress only:

    e

    qP R

    Components of

    force on concrete

    Resultants at

    section

    P Pe

    Pq

    From these actions we can work out the stresses . . .

    C = Rcosq = P

    V = Rsinq= Pq

    Prestress force

  • sa

    sb

    P

    Pe

    P/A Pe / Z

    Pe / Z

    = P/A - Pe/Z

    = P/A + Pe/Z

    (Pq does not cause

    any bending at the

    section)

    So top fibre stress sa = P/A - Pe/Z and

    bottom fibre stress sb = P/A + Pe/Z

    NOTE:

    Position of neutral axis is high in the section.

    Some tension may occur high in the section.

    Stresses depend on the eccentricity of prestress at section.

    Now consider stresses due to applied loading . . .

    Simple Beam - stresses in working load range

    Stresses due to prestress only:

  • applied loading

    reaction

    MM / Z

    M / Z

    These stresses are now added

    to stresses due to prestress to

    give the total stresses . . . .

    Simple Beam - stresses in working load range

  • = P/A + Pe/Z - M/Z

    applied loading

    reaction

    P

    M

    V

    M / Z

    M / Z

    sa

    sb

    Stresses due to: Prestress Applied loading Combined

    So top fibre stress

    s

    a = P/A - Pe/Z + M/Z and

    bottom fibre stress

    s

    b

    Provided that section is not cracked in tension, AND . . .

    . . . concrete is not too highly stressed in compression.

    Simple Beam - stresses in working load range

  • JACKING FORCE PoINITIAL FORCE PiEFFECTIVE FORCE Pe Jack applies force to

    tendon at the live end.

    The maximum value

    of this force is the

    Jacking Force Po

    Immediately after jacking

    and lock-off are completed,

    tendon force at typical

    location is less than Po due to

    friction losses and anchorage

    losses. This tendon force is

    called Initial Force Pi

    Tendon force progressively

    diminishes with time due to

    shrinkage and creep of concrete, and

    relaxation of tendon. Ultimately the

    force settles at a value called the

    Effective Force Pe

    Important for

    anchorage design

    Important at transfer

    Important for maximum loads

    Pe = 0.75 - 0.85 Pi approx.

  • Now we know what were doing!

    Ok!

    Lets try an example!

  • 10.000

    Study of stresses at mid-span of beam :

    Applied working live load w = 25 kN/m (+ s/wt )

    parabolically draped

    tendon, stressed to

    Pi of 1250 kN,

    Pe 1000 kN, at mid-span.

    e = 0 e = 0e = 225

    BMD due to LL of 25 kN/m

    312.5 kNm

    400

    750

    e varies 0 to 225 mm

    Note that the maximum eccentricity e maxis governed by the need to provide

    enough space below the duct to place

    concrete, and any secondary

    reinforcement which may be needed.

    Example 2.1

  • 400

    750

    Stresses due to prestress only :

    sa = P/A - Pe/Z

    -3.33

    sb = P/A + Pe/Z +11.67

    NOTE:

    Neutral

    axis . . .

    Pi = 1250 kN

    . . . does not coincide

    with centroidal axis

    This is fictitious case, since self-weight of beam is engaged

    when the beam is stressed and curves upwards . . .

    So . . . .

  • Stresses due to p/s + s/wt of beam :

    sa = P/A - Pe/Z + Mswt / Z400

    750

    -0.83

    sb = P/A + Pe/Z - Mswt / Z

    +9.17

    NOTE:

    both top and bottom fibre stresses are reduced by self-weight.

    neutral axis is even higher.

    Now what about stresses due to applied load? . . . .

    Bending stresses

    prestress

    only

  • Stresses due to p/s, s/wt and applied load :

    Mtot = Mswt + Mapplied = 93.75 + 312.5 = 406.25 kNm

    sa = P/A - Pe/Z + Mtot /Z+8.16

    sb = P/A + Pe/Z - Mtot /Z

    -1.50

    400

    750

    NOTE:

    stress reversals at extreme fibres, so

    movement of neutral axis.

    Now check stresses to ensure our assumptions are o.k. . .

    Bending stresses

    prestress only

    p/s and s/wt

  • Our stress estimates will not be valid if, at any time j,

    Compressive stress anywhere exceeds 0.5 f cj , since above that stress the stress /strain curve for concrete is not linear, or

    Tensile stress anywhere exceeds 0.25 (fcj ) 0.5, since above that tensile

    stress the section may crack.

    where fcj is compressive strength at that time j.

    So we must check stresses at

    Time of transfer, when f cp is probably less than f c, and

    At full load, when concrete strength = f c.

    If excessive stress is indicated anywhere,

    then a different approach will be required

    Lecture 4

    Now consider stresses across the entire section . . .

    Bending stresses Checking of stresses :

  • STRESS DISTRIBUTION ACROSS

    AN UNCRACKED SECTION

    Consider again Example 2.1. The applied load is all live load, (except for the

    self-weight). Remember that live load may or may not be present. So in the

    mature life of the beam, there are a range of extreme fibre stresses to be

    considered.

    The bending stress at any distance y below the

    centroidal axis is:

    sy = P/A + Pey/I - My/I

    So the stress varies linearly with depth y

    The range of stresses to be considered (for a simply

    supported beam) is:

    From MQ = 0 to MQ = MQ max

  • 400

    750

    -0.17 +8.16

    -1.50 +6.83

    Life-time range of stresses :

    Live load may, or may not, be present. So stresses will vary

    throughout the beams life. The full range is displayed by a

    diagram which pivots about the centroidal axis.

    Note that there is a particular value of w, somewhere

    between 0 and 25 kN/m for which the stress will be

    uniformly compressive. More on this next lecture.

    Example 2.1

    total

    p/s + s/wt

  • TWO IMPORTANT PROPERTIES

    OF A PRESTRESSED SECTION

    Decompression moment Mo or Mdec :

    The total moment which is just enough to

    eliminate tension in the bottom fibre:

    sa

    sb = 0

    sb = 0 so P/A + Pe/Z - Mdec/Z = 0

    then M dec = Z [P/A + Pe/Z]

    Cracking moment Mcr :

    The total moment which is just enough to

    cause tensile cracking in the bottom fibre

    sa

    sb = - f cf

    sb = - f cf so P/A + Pe/Z - Mcr/Z = - f cf

    then Mcr = Z [P/A + Pe/Z + f cf ]

  • Rectangular section T section

    I sectionBox section

    Some Typical Prestressed Beam Sections :

    y

    Top fibre stress : sa = P/A - Pe/Ztop + M/Ztop , and

    Bottom fibre stress : sb = P/A + Pe/Zbott - M/Zbott

    Z is section modulus.

    For sections which

    are not symmetrical

    about the horizontal

    axis, Z is different

    for top and bottom.

    Z top = I / y top, and

    Z bott = I / y bott.

    Also, stress at any level y below centroidal axis :

    sy = P/A + Pey/I - My/I

    Enough for

    today !

    Bending stresses

    y

    y

  • Bending stresses must be checked for the transfer condition, and the maximum load condition.

    Stresses must be checked to ensure assumptions of linearity and non-cracking are valid.

    Simple beam theory is appropriate, noting that the action caused by prestress may be modelled in terms

    of an axial load applied at the centroidal axis, and a

    bending action.

    Mdec and Mcr are important properties of a prestessed section.

    This theory may be applied to any prismatic member.

    SUMMARY