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OLEH :

RIZQI PANDU SUDARMAWAN

0906557045

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Initial Pressure inside the container = Pi = 20 atm

Final Pressure inside the container = Pf = 100 kPa

Volume of the container = 0.25 liter

Mass of water = 0.225 kg

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Pi = 20 atm x 101.325 kPa = 2026.5 kPa x 1 MPa = 2.0265 MPa

1 atm 1000 kPa

Pf = 100 kPa x 1 MPa = 0.1 MPa

1000 kPa

= 0.225 kg x 1000 liter = 900 kg/m

0.25 liter 1 m

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Sumber: www.nist.gov/srd/upload/NISTIR5078-Tab3.pdf

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= 170 + 170165 x( TiT898.21)

T898.21T903.30

900 kg/m= 898.21 kg/m + 898.21 kg/m - 903.30 kg/m x (Ti170C)

170C - 165CTi = 168.242C

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Sumber: http://www.essom.com/backend/data-file/engineer/engin40_1.pdf

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Ekstrapolation at x = 99.606y = -0.635 (99.606) + 1022 =958.75019

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Sumber: http://www.essom.com/backend/data-file/engineer/engin40_1.pdf

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W = H - Q

V xP =(m x C x T) - Q0.25 liter x 1 m3x (100-2026,5) kPa = 0.225 kg x 4.1868 kJ x (99.63-168.242)oC - Q

10

3

liter kg x

o

CQ = - 64.153 kJ x 1000 J x 104J

1 kJ 104J

Q = - 6.4153 x 104J

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