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Project Job ref Part of structure Calc sheet no r / 0 Drawing ref. Calc by Date Check by Date Jul-22 Nov-09 Ref Calculations Output Design of pile cap - PC4 Line of critical sh Dia. Of pile = 450 mm B Offest from pile = 150 mm Column width = 600 mm Pile spacing (2L) = 1350 mm Depth of pile cap = 750 mm Width of pile cap (B) = 750 mm 2L Bottom cover = 75 mm Side cover = 50 mm Ultimate axial load (N) = 1800 kN Materials = 35 = 500 = 1.25 (partial saftey factor for concrete - shear) = 1.15 (partial saftey factor for steel) Design for main reinforcement: Effective depth of pile cap (d) = 653 mm According to Truss theory: Tension to be resisted by main reinforce = (N x L) / (2 x d) = 1800 x 675 / (2 x 653) = ### kN According to Flexural theory: Moment parallel to X axis = 608 kNm K = = 0.054 Z = d(0.5 + √(0.25 - K / = 611.14 mm Therefore Tx = ### kN Area of steel required = T / (0.87 x fy) = 994040 / (0.87 x 500) = 2286 Dia. Of bars using for main reinforcemen = 20 mm No. of bars required = 7.28 Provide No. of bars = 9 Nos Area of steel provided = 2827 OK BS 8110 Spacing of main bars = 78.3 mm Table 3.25 Percentage of steel = 0.5 % > 0.13 % OK Φ/5 fcu N/mm 2 fy N/mm 2 Gm Gm M / fcu b d 2 mm 2 mm 2

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TwoProjectJob refPart of structureCalc sheet no rev/0Drawing ref.Calc byDateCheck byDateJan-10Nov-09RefCalculationsOutputDesign of pile cap - PC4Line of critical shearDia. Of pile=450mmBOffest from pile=150mmColumn width=600mmPile spacing (2L)=1350mm/5Depth of pile cap=750mmWidth of pile cap (B)=750mm2LBottom cover=75mmSide cover=50mmUltimate axial load (N)=1800kNMaterialsfcu=35N/mm2fy=500N/mm2Gm=1.25(partial saftey factor for concrete - shear)Gm=1.15(partial saftey factor for steel)Design for main reinforcement:Secondary steel diaEffective depth of pile cap (d)=653mm12According to Truss theory:Tension to be resisted by main reinforcement, T=(N x L) / (2 x d)=1800 x 675 / (2 x 653)=930.3kNAccording to Flexural theory:Moment parallel to X axis=607.5kNmK=M / fcu b d2=0.054Z=d(0.5 + (0.25 - K / 0.9))=611.14mmTherefore Tx=994.0kNArea of steel required=T / (0.87 x fy)=994040 / (0.87 x 500)=2286.292mm2Dia. Of bars using for main reinforcement=20mmNo. of bars required=7.277493463Provide No. of bars=9NosArea of steel provided=2827.4333882308mm2OKBS 8110Spacing of main bars=78.25mmTable 3.25Percentage of steel=0.5026548246%> 0.13 % OKProjectJob refNewport Station Regeneration5074908Part of structureCalc sheet no revCar Park - Design of Pile Caps for Columns9/ 9/0Drawing ref.Calc byDateCheck byDateSJJun 08CMNJun-08RefCalculationsOutputCheck for shear:Shear stress along critical section (v)=(N / 2) / (B x d)=(1800 / 2) / (750 x 653)3.4.5.2=1.8376722818N/mm21.8376722818OKHence, shear links are not required. However provide nominal T12 links @ 200 c/c.Side face reinforcement:3.12.5.4Dia. Of bar used for side face reinforcement=16mmSpacing of bar=( 2 x fy ) / b=256mmHence, provide side face reinforcement - 2 nos. T16 bars

ThreeProjectJob refPart of structureCalc sheet no rev/0Drawing ref.Calc byDateCheck byDateBVRJan-10Nov-09RefCalculationsOutputDesign of pile cap - PC2 (For 750x300 column)Yav/5Dia. Of pile ( )=450mmavOffest from pile=150mmColumn width in X-direction=600mmColumn width in Y-direction=600mmEffective length of pile cap (2 Lx)=1350mm21002Ly750Effective length of pile cap (2 Ly)=1350mmDepth of pile cap=750mmBottom cover=75mmSide cover=50mmUltimate axial load (N)=3500kN2LxXReaction of each pile (N/3)=1166.6666666667kN2100Materialsfcu=35N/mm2Gm=1.25(partial saftey factor for concrete - shear)fy=500N/mm2Gm=1.15(partial saftey factor for steel)Design for main reinforcement:Effective depth of pile cap (d)=637.5mmAccording to Truss theory:Effective length of pile cap (2 Lxy)=1509.35mmTension to be resisted by main reinforcement, Txy=(2N x Lxy) / (9 x d)=2 x 3500 x 754.675 / (9 x 637.5)=920.74kNTension to be resisted by main reinforcement, Ty=(2N x Ly) / (9 x d)=2 x 3500 x 675 / (9 x 637.5)=823.53kNNet tension to be resisted by main reinforcement, Tx=2 x Txy cos 26.57=2 x 920.74 x cos 26.57=1647.1kNNet tension to be resisted by main reinforcement, Ty=2 x Txy sin 26.57 + 823.53=1647.1kNAccording to Flexural theory:Moment parallel to X axis=700kNmK=M / fcu b d2=0.023Z=d(0.5 + (0.25 - K / 0.9))=605.63mmMoment parallel to Y axis=437.5kNmK=M / fcu b d2=0.015Z=d(0.5 + (0.25 - K / 0.9))=605.63mmTherefore Tx=1155.8kNTherefore Ty=722.39kNIn X-directionArea of steel required in X-direction=Tx / (0.87 x fy)=1647100 / (0.87 x 500)=3786.4367816092mm2Dia. Of bars using for main reinforcement=25mmNo. of bars required=7.7136656704Provide No. of bars=14NosArea of steel provided=6872.2339297277mm2OKProvideBS 8110-1Spacing of main bars=153.8mm14 Nos. T25 barsTable 3.25Percentage of steel=0.44%> 0.13 % OKProjectJob refNewport Station Regeneration5074908Part of structureCalc sheet no revCar Park - Design of Pile Caps for Columns5/ 9/0Drawing ref.Calc byDateCheck byDateSJJun 08CMNJun-08RefCalculationsOutputIn Y-directionArea of steel required in Y-direction=Ty / (0.87 x fy)=1647100 / (0.87 x 500)=3786.4367816092mm2Dia. Of bars using for main reinforcement=25mmNo. of bars required=7.7136656704Provide No. of bars=14NosArea of steel provided=6872.2339297277mm2OKProvideSpacing of main bars=150mm14 Nos. T25 barsPercentage of steel=0.44%> 0.13 % OKCheck for shear:Shear stress along critical section (v)=(2 N/3) / (B x d)=2 (3500000 / 3) / (2100 x 637.5)3.4.5.2=1.74N/mm2