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Semester II, 2017-18 Department of Physics, IIT Kanpur
PHY103A: Lecture # 7
(Text Book: Intro to Electrodynamics by Griffiths, 3rd Ed.)
Anand Kumar Jha 17-Jan-2018
Notes โข HW # 3 is uploaded on the course webpage. โข Solutions to HW#2 have also been uploaded.
โข Class this Saturday (Jan 20th).
โข Are lecture notes sufficient for exams? โข Office Hours??
2
Summary of Lecture # 6: โข Poissonโs Equation: ๐๐2V = โ ๐๐
๐๐0
โข The work required to construct a system of one point charge ๐๐:
๐๐ = QV ๐ซ๐ซ
๐๐ =12๏ฟฝ๐๐๐๐
๐๐
๐๐=1
๐๐(๐ซ๐ซ๐ข๐ข)
โข Total work required to put together ๐๐ point charges:
โข Energy of a continuous charge distribution: W =
12๏ฟฝ ๐๐ ๐๐๐๐๐๐
๐ฃ๐ฃ๐๐๐๐=๐๐02๏ฟฝ ๐ธ๐ธ2๐๐๐๐
๐๐๐๐๐๐ ๐ ๐ ๐ ๐ ๐๐๐ ๐ ๐ ๐
๐๐
V ๐๐ ๐๐ = โ๐๐V
V ๐ซ๐ซ = โ ๏ฟฝ๐๐ โ ๐๐๐ฅ๐ฅ๐ซ๐ซ
โ
3
Where is the electrostatic energy stored ?
W =12๏ฟฝ ๐๐ ๐๐๐๐๐๐
๐ฃ๐ฃ๐๐๐๐
The Energy of a Continuous Charge Distribution:
โข The first expression has a volume integral of ๐๐ ๐๐ over the localized space whereas the second one has the volume integral of ๐ธ๐ธ2over all space.
โข Just as both the integrals are mathematically correct, both the interpretations are also correct. The electrostatic energy can be interpreted as stored locally within the charge distribution or globally over all space.
โข Again, at this point, as regarding fields, we know how to calculate different physical quantities but we donโt really know what exactly the field is. 4
So, where is the electrostatic energy stored? Within the localized charge distribution or over all space?
=๐๐02๏ฟฝ ๐ธ๐ธ2๐๐๐๐
๐๐๐๐๐๐ ๐ ๐ ๐ ๐ ๐๐๐ ๐ ๐ ๐
Where is the electrostatic energy stored ?
Ex. 2.8 (Griffiths, 3rd Ed. ): Find the energy of a uniformly charged spherical shell of total charge ๐๐ and radius ๐ ๐ .
๐๐shell =12๏ฟฝ ๐๐ ๐๐๐๐๐๐
๐ฃ๐ฃ๐๐๐๐
๐๐shell =๐๐02๏ฟฝ ๐ธ๐ธ2๐๐๐๐
๐๐๐๐๐๐ ๐ ๐ ๐ ๐ ๐๐๐ ๐ ๐ ๐
=12๏ฟฝ
๐๐4๐๐ ๐ ๐ 2
ร๐๐
4๐๐๐๐0๐ ๐ ๐ ๐ 2sinฮธ ๐๐๐๐ ๐๐๐๐
=12
๐๐4๐๐ ๐ ๐ 2
ร๐๐
4๐๐๐๐0๐ ๐ ๐ ๐ 2 4๐๐ =
๐๐2
8๐๐๐๐0๐ ๐
=12๏ฟฝ๐๐ ๐๐๐๐๐๐
Alternatively:
What is ๐ธ๐ธ? ๐๐ = 0 inside and ๐๐ = ๐๐4๐๐๐๐0๐๐2
๐๐๏ฟฝ outside
๐๐shell =๐๐02๏ฟฝ
๐๐4๐๐๐๐0๐๐2
2
๐๐2sinฮธ ๐๐๐๐๐๐๐๐ ๐๐๐๐
๐๐๐๐๐๐ ๐ ๐ ๐ ๐ ๐๐๐ ๐ ๐ ๐ =
๐๐02
๐๐4๐๐๐๐0
2
4๐๐๏ฟฝ1๐๐2๐๐๐๐
โ
๐๐=๐ ๐
=๐๐2 8๐๐๐๐0
1๐ ๐
The two expressions for energy indeed give us the same information
Where is the electrostatic energy stored ?
Ex. 2.8 (Griffiths, 3rd Ed. ): Find the energy of a uniformly charged solid sphere of total charge ๐๐ and radius ๐ ๐ .
Wsphere =๐๐02๏ฟฝ ๐ธ๐ธ2๐๐๐๐
๐๐๐๐๐๐ ๐ ๐ ๐ ๐ ๐๐๐ ๐ ๐ ๐
HW Prob 2.5(a): ๐๐ = ๐๐๐๐3๐๐0
๐๐๏ฟฝ
Wsphere
๐๐ = ๐๐4๐๐๐๐0๐๐2
๐๐๏ฟฝ, outside
For the same charge and radius, a solid sphere has more total energy than a spherical shell.
๐๐shell =๐๐2 8๐๐๐๐0
1๐ ๐
=๐๐2
4๐๐๐๐012๐ ๐
Recall:
=๐๐
4๐๐๐ ๐ 3/3๐๐
3๐๐0 ๐๐๏ฟฝ =
๐๐๐๐ 4๐๐๐๐0๐ ๐ 3
๐๐๏ฟฝ , inside
=๐๐02
14๐๐๐๐0 2 ๐๐
2 ๏ฟฝ1๐๐44๐๐๐๐2๐๐๐๐
๐ ๐
0+ ๏ฟฝ
๐๐2
๐ ๐ 64๐๐๐๐2๐๐๐๐
โ
๐ ๐ =
๐๐2
4๐๐๐๐035๐ ๐
Electrostatic Boundary Conditions (Consequences of the fundamental laws):
1. Normal component of E is Discontinuous
๐๐ โ ๐๐ =๐๐ ๐๐0
๏ฟฝ ๐๐ โ ๐๐๐๐
๐ ๐ ๐ข๐ข๐๐๐ข๐ข=๐๐enc๐๐0
๐๐above๐ด๐ด โ ๐๐below๐ด๐ด + 0 + 0 + 0 + 0 =๐๐ ๐ด๐ด๐๐0
EaboveโEbelow =๐๐ ๐๐0
2. Parallel component of E is Continuous ๐๐ ร ๐๐ = 0 ๏ฟฝ ๐๐ โ ๐๐๐ฅ๐ฅ
๐ ๐ ๐๐๐๐๐= ๐๐
๐๐above ๐๐ โ ๐๐below๐๐ + 0 + 0 = 0
Eabove โ Ebelow = 0
๐๐aboveโ ๐๐below=๐๐ ๐๐0๐ง๐ง๏ฟฝ
7
How does electric field (๐๐) change across a boundary containing surface charge ๐๐?
The electrostatic boundary condition
How does electric potential (V) change across a boundary containing surface charge ๐๐?
V ๐๐ โ V(๐๐) = โ๏ฟฝ๐๐ โ ๐๐๐ฅ๐ฅ๐๐
๐๐
Vabove โ Vbelow = โ๏ฟฝ๐๐ โ ๐๐๐ฅ๐ฅ๐๐
๐๐
For ๐๐ โ 0,
Vabove โ Vbelow = 0
3. Potential ๐๐ is continuous across a boundary
โ๏ฟฝ๐๐ โ ๐๐๐ฅ๐ฅ๐๐
๐๐
= 0
8
Electrostatic Boundary Conditions (Consequences of the fundamental laws):
Uniformly charged spherical shell
9
Ex. 2.6 (Griffiths, 3rd Ed. ): Find the electric field and electric potential inside and outside a uniformly charged sphere of radius ๐ ๐ and total charge ๐๐.
The electric field outside the shell: ๐๐(๐ซ๐ซ) =1
4๐๐๐๐0๐๐r2
rฬ
The electric field inside the shell: The electric potential at a point outside the shell (r > ๐ ๐ ):
V ๐ซ๐ซ = โ ๏ฟฝ๐๐ โ ๐๐๐ฅ๐ฅ๐๐
โ
The electric potential for a point inside the shell (r < ๐ ๐ ):
V ๐ซ๐ซ = โ ๏ฟฝ๐๐ โ ๐๐๐ฅ๐ฅ๐ ๐
โ
โ ๏ฟฝ๐๐ โ ๐๐๐ฅ๐ฅ๐๐
๐ ๐
Check the boundary condition on Electric field at r = ๐ ๐
EaboveโEbelow =๐๐ ๐๐0
Check the boundary condition on Electric potential
Vabove โ Vbelow = 0
OK ยช
OK ยช
Eabove โ 0 =๐๐
๐๐0 4๐๐๐ ๐ 2 Eabove =
1 4๐๐๐๐0
๐๐ ๐ ๐ 2
1
4๐๐๐๐0๐๐R โ
14๐๐๐๐0
๐๐R = 0
๐๐ ๐ซ๐ซ = 0
=1
4๐๐๐๐0๐๐r = โ ๏ฟฝ
14๐๐๐๐0
๐๐rโฒ2๐๐๐๐โฒ
๐๐
โ
=1
4๐๐๐๐0๐๐R = โ ๏ฟฝ
14๐๐๐๐0
๐๐rโฒ2๐๐๐๐โฒ โ 0
๐ ๐
โ
Conductors (Materials containing unlimited supply of electrons)
10
This is true even when the conductor is placed in an external electric field ๐๐๐๐๐๐๐๐.
(2) The charge density ๐๐ = 0 inside a conductor.
(3) Any net charge resides on the surface.
This is because ๐๐ = 0.
(5) ๐๐ is perpendicular to the surface, just outside the conductor.
> Wsphere =๐๐2
4๐๐๐๐035๐ ๐
๐๐shell =๐๐2
4๐๐๐๐012๐ ๐
To minimize the energy Why?
This is because ๐๐ = 0 inside a conductor
(1) The electric field ๐๐ = 0 inside a conductor
(4) A conductor is an equipotential.
and therefore ๐๐ = ๐๐0๐๐ โ ๐๐ = 0.
V ๐๐ โ V ๐๐
So, for any two points ๐๐ and ๐๐,
This means V ๐๐ = V ๐๐ . = 0. = โ๏ฟฝ ๐๐ โ ๐๐๐ฅ๐ฅ๐๐
๐๐
Induced Charges
11
Charge inside the cavity
No charge inside the cavity
No charge inside the cavity, Conductor in an external field
Induced Charges
12
Prob. 2.36 (Griffiths, 3rd Ed. ):
- Surface charge ๐๐๐๐? ๐๐๐๐ = โ๐๐๐๐4๐๐๐๐2
- Surface charge ๐๐๐๐? ๐๐๐๐ = โ๐๐๐๐4๐๐๐๐2
- Surface charge ๐๐๐ ๐ ? ๐๐๐ ๐ =๐๐๐๐ + ๐๐๐๐4๐๐๐ ๐ 2
- Force on ๐๐๐๐ ? 0
- Force on ๐๐๐๐ ? 0
- ๐๐out(๐ซ๐ซ) ? ๐๐out =1
4๐๐๐๐0๐๐๐๐ + ๐๐๐๐๐๐2
๐ซ๐ซ๏ฟฝ
- ๐๐(๐ซ๐ซ๐๐) ? ๐๐out =1
4๐๐๐๐0๐๐๐๐๐๐๐๐2
๐ซ๐ซ๐๐๏ฟฝ
- ๐๐(๐ซ๐ซ๐๐) ? ๐๐out =1
4๐๐๐๐0๐๐๐๐๐๐๐๐2
๐ซ๐ซ๐๐๏ฟฝ
Induced Charges
13
Prob. 2.36 (Griffiths, 3rd Ed. ):
- Surface charge ๐๐๐๐? ๐๐๐๐ = โ๐๐๐๐4๐๐๐๐2
- Surface charge ๐๐๐๐? ๐๐๐๐ = โ๐๐๐๐4๐๐๐๐2
- Surface charge ๐๐๐ ๐ ? ๐๐๐ ๐ =๐๐๐๐ + ๐๐๐๐4๐๐๐ ๐ 2
- Force on ๐๐๐๐ ? 0
- Force on ๐๐๐๐ ? 0
Same ยช
Same ยช
Changes ๏ฟฝ
Same ยช
Same ยช
Same ยช
Same ยช
Changes ๏ฟฝ - ๐๐out(๐ซ๐ซ) ? ๐๐out =
14๐๐๐๐0
๐๐๐๐ + ๐๐๐๐๐๐2
๐ซ๐ซ๏ฟฝ
- ๐๐(๐ซ๐ซ๐๐) ? ๐๐out =1
4๐๐๐๐0๐๐๐๐๐๐๐๐2
๐ซ๐ซ๐๐๏ฟฝ
- ๐๐(๐ซ๐ซ๐๐) ? ๐๐out =1
4๐๐๐๐0๐๐๐๐๐๐๐๐2
๐ซ๐ซ๐๐๏ฟฝ
Bring in a third charge ๐๐๐ ๐