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Perturbative QCD
Chul Kim
Open KIAS, Pyeong-Chang Summer Institute 2013
Seoultech
Pyeong-Chang, Alpensia Resort, July 9, 2013
Part II : Structure functions for DY One loop correction to current
Drell-Yan Process
P1
P2
N2
N1
p1
p2
q l�
l+
}p0 = p1 + p2 � q
■ Scattering Cross Section
q
q2 = Q2
q f
q f
l�
l+iM = hl+l�X|(iQ f e)q f gµq f · (ie)lgµl|N1N2i
�iq2
|M|2 =e4Q2
f
4Q4 hN1N2|J†µ|XihX|Jn|N1N2iLµn
Lµn(k1, k2) =14 Â
s,s0us(k1)g
nvs0(k2)vs0(k2)gµus(k1)
=14
Trk/1gnk/2gµ = kµ1 kn
2 � kn1kµ
2 � gµnk1 · k2
s(N1N2 ! l+l�X) =12s Â
X
Z d3k1(2p)3
d3k2(2p)3
12k0
1 · 2k02(2p)4d(P1 + P2 � q � pX)Â
f|M|2
=32p2a2
Q4s Âf
Q2f Wµn(P1, P2, q)
Z d3k1(2p)3
d3k2(2p)3
Lµn(k1, k2)
2k01 · 2k0
2
=32p2a2
Q4s Âf
Q2f
Zd4qWµn(P1, P2, q)
Z d3k1(2p)3
d3k2(2p)3
Lµn(k1, k2)
2k01 · 2k0
2d(q � k1 � k2).
s = (P1 + P2)2
Z d3k1(2p)3
d3k2(2p)3
Lµn(k1, k2)
2k01 · 2k0
2d(q � k1 � k2) = �p
6(�q2gµn + qµqn)
�!Z
dQ2d(q2 � Q2)⇣�p
6Q2gµn
⌘.
Homework:
qµWµn = qnWµn = 0
● Hadronic tensor
Wµn(P1, P2, q) = ÂX(2p)4d(P1 + P2 � q � pX)hN1N2|J†
µ|XihX|Jn|N1N2i
● Structure function ds
dQ2 = Âf
Q2f4pa2
3Q2s
Z d4q(2p)4 d(q2 � Q2)(�gµn)Wµn(P1, P2, q) =
s0s
FDY(t, Q2)
FDY(t, Q2) = �Nc ÂX
Zd4qd(q2 � Q2)d(P1 + P2 � q � pX)hN1N2|J†
µ|XihX|Jµ|N1N2i
= �Nc
Z d4q(2p)4 d(q2 � Q2)
Zd4ze�iq·zhN1N2|J†
µ(z)Jµ(0)|N1N2i
s0 = Âf
Q2f
4pa2
3NcQ2LO x-section at parton level:
will perform short distance expansion● Matching of EM current
Jµ = qgµq ! qnWngµ?W†
n qn
n/qn = O(l), n/qn = O(l)
Homework
Derivation of FT TheoremFDY(t) = �Ncd(q2 � Q2)hN1N2|qnWng
µ?W†
n qn · qnWng?µ W†
n qn|N1N2i
= �Nc
Zdy1dy2d(q2 � Q2)hN1N2|qnWng
µ?W†
n qn
⇥hqnWnd(y2 +
n · P†
n · P2)ig?
µ
hd(y1 �
n · Pn · P1
)W†n qn
i|N1N2i
● PDF projection
hN|hd(y � n · P
n · P
)Yn
ia
a
⇣Y
n
⌘b
b
|Ni = n · P
2N
c
dab⇣
n/2
⌘
ab
f
q/N
(x), Yn = W†n qn
hN|⇣
Yn
⌘a
a
hYnd(y +
n · P†
n · P)ib
b|Ni = n · P
2Ncdab
⇣n/2
⌘
abfq/N(y)
hN1N2|qnWngµ?W†
n qn ·hqnWnd(y2 +
n · P†
n · P2)ig?
µ
hd(y1 �
n · Pn · P1
)W†n qn
i|N1N2i
=s
4N2c
Nc fq/N1(y1) fq/N2(y2)Trn/2
gµ?
n/2
g?µ = � s
Ncfq/N1(y1) fq/N2(y2)
q = P1 + P2 � pX = (P1 � pXn) + (P2 � pXn) + pXH = p1 + p2 � pXH
■ LO factorization theorem FDY(t) = s
Zdy1dy2 fq/N1(y1) fq/N2(y2)d(q2 � Q2)
=Z dy1
y1
dy2y2
fq/N1(y1) fq/N2(y2)d(1 � z) =Z 1
t
dzz
d(1 � z)Lqq(t
z)
Lqq(t) =Z 1
t
dy1y1
fq/N1(y) fq/N2(t
zy1)
● Kinematic variables
s = (p1 + p2)2 = n · p1n · p2 = y1y2s
P1
P2
N2
N1
p1
p2
q l�
l+
}p0 = p1 + p2 � q
q2 � Q2 = s � 2pXH · (p1 + p2) + p2XH
� Q2
pXn
pXn
pXH
z ⌘ Q2
s, t ⌘ Q2
s
At LO,
pXH = 0 ! q2 � Q2 = s(1 � z)
■ Factorization theorem
FDY(t) =Z 1
t
dzz
HDY(z, Q2, µ)Lqq(t
z, µ)
F(0)DY(t) = d(1 � t)
※ LO structure function at parton level
H(0)DY = d(1 � z)
f (0)q/q(y) = f (0)q/q(y) = d(1 � y)
● At the higher order - The hard function should be IR-finite- All the IR divergence should reside in PDFs- Structure fn should be scale invariant
µ ⇠ Q
µ ⇠ LQCD
RG evolution
HDY(z, Q2, µ)
fq/N1 , fq/N2
One loop virtual computation in full QCD
p
p0
k
p+ k
p0 + k
MVqgµq = �ig2CFµ2#MS
Z dDk(2p)D
1k2(k + 2p · k)(k + 2p0 · k)
qgn(k/ + p/0)gµ(k/ + p/)gnq
Z dDk(2p)D
1k2(k + 2p · k)(k + 2p0 · k)
= 2Z 1
0da
Z 1
1�adb
Z dDl(2p)D
1(l2 � D)3
■ One loop correction to current
l = k + ap + bp0
D = abM2, M2 ⌘ 2p · p0 = 2p · q
qgn(k/ + p/0)gµ(k/ + p/)gnq =h (D � 2)2
Dl2 + 2M2(1 � a � b + (1 � #)ab)
iqgµq
● Numerator
● Loop integrals
gµgµ = D, gµgagµ = (2 � D)ga, gµg5gµ = �Dg5,
gµgagbgµ = 4gab + (D � 4)gagb,
gµgagbgdgµ = �2gdgbga + (4 � D)gagbgd.
In D-dimension, after Wick rotation such as l0 = il0
E, l2 = �l2
E, we have
Z dDlE(2p)D =
Z dWD(2p)D
Z •
0
dlElD�1
E ,
ZdWD =
2pD/2
G(D/2). (1)
Therefore Feynman integrals becomes
Z dDlE(2p)D
l2mE
(l2
E + D)n =1
(4p)D/2
G(m + D/2)G(D/2)
G(n � m � D/2)G(n)
⇣1
D
⌘n�D/2�m.
(2)
Usually D = 4� 2e, and Gamma function can be expanded in powers of e such
as
G(1 + e) = eG(e) = 1 � gEe +1
2
(g2
E +p2
6
)e2 + · · · . (3)
● Result at one loop
MV =asCF4p
⇣µ2eg
M2
⌘# Z 1
0da
Z 1
1�adb
h2(1 � 2#)G(#)D0�#
� 2G(1 + #)D0�1�#(1 � a � b + (1 � #)ab)i
=asCF2p
h 12 #UV
� 1#2
IR� 1
#IR(2 + ln
µ2
M2 )� 4 +p2
12� 3
2ln
µ2
M2 � 12
ln2 µ2
M2
i.
Cancelled by field strength renormalization of quark fields
- Double pole (logarithm) results from Sudakov effect
- For totally inclusive process, all the IR divergences cancel, but....
D0 = D/M2 = ab
- Can be matched onto EFT (SCET), Remaining finite terms gives the hard corrections