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Slide on CPM and PERT for Engineering students
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AARUSH JOSEPH SONY
NETWORK SCHEDULING BY PERT/CPM
1. P.E.R.T : Programme Evaluation Review Technique
2. C.P.M : Critical Path Method
3. R.A.M.S : Resource Allocation And Multiproject Scheduling
4. P.E.P : Programme Evaluation Procedure
5. C.O.P.A.C : Critical Operating Production Allocation Control
6. M.A.P : Manpower Allocation Procedure
7. R.P.S.M : Resource Planning And Scheduling Method
8. L.C.S : Least Cost Scheduling Method
9. M.O.S.S : Multi Operation Scheduling System
10.P.C.S : Project Control System
11.G.E.R.T : Graphical Evaluation Review Technique
NETWORK TECHNIQUES
EVENT ACTIVITY CRITICAL PATH DURATION TOTAL PROJECT TIME EARLIST STARTING TIME EARLIEST FINISH TIME LATEST FINISH TIME LATEST START TIME FLOAT/SLACK NETWORK DIAGRAM/ARROW DIAGRAM
RELATED TERMS
P.E.R.T1. Probabilistic model
2. Event oriented approach
3. Network diagram, Slack, Events
4. Dummy activity required
5. Does not demarcate between critical and non critical activities
6. Finds application in projects where resources(men, material, money) are always made available as and when required
1. Deterministic model
2. Activity oriented approach
3. Arrow diagram, Nodes, Float
4. Dummy activity activity not necessary
5. Marks critical activity
6. Employed to those projects where minimum overall cost is of primary importance
DIFFERENCE BETWEEN P.E.R.T AND C.P.M
C.P.M
An event is a specific instant of time which marks the start and end of the activity. Even consumes neither time nor resources. It is represented by a circle and event number is written within the circle.
Eg. Start the motor loan approved
EVENT
Every project consists of a number of job operations or task which are called activities.
An activity is shown by an arrow and it begins and ends with an event
CLASSIFICATIONS Critical activity
Those activities which take more time Non critical activities
they have provisions (slack/ float) so if they consumes a specified time over and estimated time, the project will not be delayed.
Dummy activity
activities started at same time, they does not consumes time, joined by dotted line, may be critical or non critical
ACTIVITY
Sequence of activities which decides total project duration. It is formed by critical activities. It consumes maximum resources. It is the longest path and consumes maximum time. It has zero float. The expected completion dates cannot be met, if even one
critical activity is delayed.
CRITICAL PATH
DURATION It is the actual or estimated time required to complete the
project
TOTAL PROJECT TIME It is the time which will be taken to complete a project and
is found from the sequence of critical activities. or it is the duration of critical path.
EARLIST STARTING TIME Earliest possible time at which the activity can be started
EARLIEST FINISH TIME Earliest possible time at which the activity can be finished
EFT=EST+DURATION
LATEST FINISH TIME Calculated by moving backward from last event to first
event
LATEST START TIME Latest possible time at which the activity can be started
LST=LFT-DURATION
Float / slack Slack is with reference to an event and float is with respect to an activity.
It means spare time or extra time over and above its duration which a non critical activity can consume without delaying the project. Float is the difference between the time available for completing an activity and the time necessary to complete the same.
Total float It is the additional time which a non critical activity can consume which
increase the project duration. However, total float may affect the float in previous and subsequent activities.
Total float = (LST-EST) OR (LFT-EFT)
FREE FLOAT If all the non critical activities start as early as possible the surplus time
is the free float.
Free float = EST(tail) – EST(head) – DURATION
INDEPENDENT FLOAT It does not change the float of an activity. It can be used to
advantage if one is interested to reduce the effort on a non critical activity in order to apply the same on critical activity thereby reducing the project duration
Independent float = EST (tail) – LFT (head) – DURATION
OPTIMISTIC TIME (to )
Shortest possible time in which an activity can be completed if everything goes exceptionally well.
MOST LIKELY TIME (tm)
Time in which activity is normally expected to complete under normal contingencies
PESSIMISTIC TIME (tp)
It is the time which an activity will take to complete in case of difficulty i.e. is if mostly the things go wrong. it is the longest of all the three time estimates
Estimation of variability of activity times the purpose is to find how reliable te is
if te = tm
St = Tp-To
6 Vt = [Tp-To]2 = St
2
62
Z=D-Ts
St
where,
Ts is the total project duration
St is the standard deviation
D is the due date or scheduled days (time)
Z is the number of standard deviations by which D exceeds Te
Each activity is represented by only one and only arrow Each activity must be identified by its starting and end node
which implies that
(a) Two activities should not be identified by the same completion events, and
(b) Activities must be represented either by their symbols or by corresponding ordered pair of starting completion events
Nodes are numbered to identify an activity uniquely. Tail node (starting point) should be lower than the head node (end point) of an activity
Between any pair so node there should be one and only one activity; however more than one activity may be emanate from and terminate to a node.
Arrow should be kept straight and not curved or bend. The logical sequence must follow
an event cannot occur until previous is completed
dummy activity should only be introduced if only it is necessary
Rules for network construction
ACTIVITY TO TM TP
1-2 2 5 14
1-6 2 5 8
2-3 5 11 29
2-4 1 4 7
3-5 5 11 17
4-5 2 5 14
6-7 3 9 27
5-8 2 2 8
7-8 7 13 31
Q1: The following are the details of estimated time of activities of a certain project. Explain in detail pert technique
1. Find the critical path and the expected time of the project
2. Find the estimated time, standard deviation and variance
3. Find the total stack
ACTIVITY
TO (A)
TM
(B)TP
(C)TE= (A+4B+C)/6
EST
EFT=EST+D
LST=LFT-D
LFT TOTAL SLACK
ST
= (CA)/6
VT=ST
2
1-2 2 5 14 6 0 6 0 6 0 2 4
1-6 2 5 8 5 0 5 2 7 2 1 1
2-3 5 11 29 13 6 19 6 19 0 4 16
2-4 1 4 7 4 6 10 20 24 14 1 1
3-5 5 11 17 11 19 30 19 30 0 2 4
4-5 2 5 14 6 10 16 24 30 14 2 4
6-7 3 9 27 11 5 16 7 18 2 4 16
5-8 2 2 8 3 30 33 30 33 0 1 1
7-8 7 13 31 15 16 21 18 33 2 4 16
Q2: The following are the details of estimated times of activities of a certain project.
ACTIVITY IMMEDEATE PREDECESSORS
NORMAL TIME (DAYS)
A 16
B 20
C A 8
D A 10
E B,C 6
F D,E 12
1. Find the critical path and the expected time of the project
2. Find the total and free-float of the project
ACTIVITY
ACTIVITY
DAYS (D)
EST EFT=EST+D
LST=LFT-D
LFT TOTAL FLOAT
FREE FLOAT
A 1-2 16 0 16 0 16 0 0
B 1-3 20 0 20 4 24 4 4
C 2-3 8 16 24 16 24 0 0
D 2-4 10 16 26 20 30 4 4
E 3-5 6 24 30 24 30 0 0
F 5-6 12 30 42 30 42 0 0
Q3: Tasks A, B, C,..., H, I constitute a project . The notation X<Y means that the task X must be finished before Y can begin. With this notation
A<D, A<E, B<F, D<F, C<G, C<H, F<I, G<I
Draw a graph to represent the sequence of tasks and find the minimum time of completion of each task is as follows.TAS
KA B C D E F G H I
TIME 8 10 8 10 16 17 18 14 9
Q4: Given the following information
(i) Draw the arrow diagram(ii) Identify critical path and find the total
project duration(iii)Determine total, free and independent
floats
Activ
0-1 1-2 1-3 2-4 2-5 3-4 3-6 4-7 5-7 6-7
Time 2 8 10 6 3 3 7 5 2 8
Q5: Consider the data of the project , find its critical path and project duration:
AITY
A B C D E F G H I
PRE A B C,D B E E F,G
TIME
4 7 2 9 6 5 2 10 4
OPERATION RESEARCH by
KANTI SWARUP P.K. GUPTA MAN MOHANINDUSTRIAL ENGINEERING AND
MANAGEMENT by Dr. O.P. KHANNA
REFERENCES