> read.csv("C:/komstat/latihan.csv",header=T,sep=",") Nama
IPK usia berat jk1 A 3.0 18 60 L2 B 2.5 18 58 P3 C 3.6 19 63 P4 D
4.0 20 55 P5 E 2.1 21 64 L6 F 3.3 22 67 L7 G 3.5 20 58 P8 H 2.2 19
65 L9 I 2.2 20 60 P10 J 2.9 19 61 P11 K 3.1 21 56 L> dataku =
read.csv("C:/komstat/latihan.csv",header=T,sep=",")> dataku Nama
IPK usia berat jk1 A 3.0 18 60 L2 B 2.5 18 58 P3 C 3.6 19 63 P4 D
4.0 20 55 P5 E 2.1 21 64 L6 F 3.3 22 67 L7 G 3.5 20 58 P8 H 2.2 19
65 L9 I 2.2 20 60 P10 J 2.9 19 61 P11 K 3.1 21 56 L> b = dataku
[,1:3]> b Nama IPK usia1 A 3.0 182 B 2.5 183 C 3.6 194 D 4.0 205
E 2.1 216 F 3.3 227 G 3.5 208 H 2.2 199 I 2.2 2010 J 2.9 1911 K 3.1
21> b = dataku [,1;3]Error: unexpected ';' in "b = dataku
[,1;"> b = dataku [,1&3]> b Nama IPK usia berat jk1 A 3.0
18 60 L2 B 2.5 18 58 P3 C 3.6 19 63 P4 D 4.0 20 55 P5 E 2.1 21 64
L6 F 3.3 22 67 L7 G 3.5 20 58 P8 H 2.2 19 65 L9 I 2.2 20 60 P10 J
2.9 19 61 P11 K 3.1 21 56 L> b = dataku [1&3,]> b Nama
IPK usia berat jk1 A 3.0 18 60 L2 B 2.5 18 58 P3 C 3.6 19 63 P4 D
4.0 20 55 P5 E 2.1 21 64 L6 F 3.3 22 67 L7 G 3.5 20 58 P8 H 2.2 19
65 L9 I 2.2 20 60 P10 J 2.9 19 61 P11 K 3.1 21 56 L> b = dataku
[,1,3]> b [1] A B C D E F G H I J KLevels: A B C D E F G H I J
K> b = dataku [1,3]> b[1] 18> b = dataku [,3]> b [1] 18
18 19 20 21 22 20 19 20 19 21> b = dataku [,1]> b [1] A B C D
E F G H I J KLevels: A B C D E F G H I J K> b = dataku
[,1,&,3]Error: unexpected '&' in "b = dataku [,1,&">
b = dataku [,1&3] # memanggil data 1 & 3> b Nama IPK
usia berat jk1 A 3.0 18 60 L2 B 2.5 18 58 P3 C 3.6 19 63 P4 D 4.0
20 55 P5 E 2.1 21 64 L6 F 3.3 22 67 L7 G 3.5 20 58 P8 H 2.2 19 65
L9 I 2.2 20 60 P10 J 2.9 19 61 P11 K 3.1 21 56 L> b = dataku
[,1:3] # memanggil data 1 & 3> b Nama IPK usia1 A 3.0 182 B
2.5 183 C 3.6 194 D 4.0 205 E 2.1 216 F 3.3 227 G 3.5 208 H 2.2 199
I 2.2 2010 J 2.9 1911 K 3.1 21> b = dataku [,1|3] > b Nama
IPK usia berat jk1 A 3.0 18 60 L2 B 2.5 18 58 P3 C 3.6 19 63 P4 D
4.0 20 55 P5 E 2.1 21 64 L6 F 3.3 22 67 L7 G 3.5 20 58 P8 H 2.2 19
65 L9 I 2.2 20 60 P10 J 2.9 19 61 P11 K 3.1 21 56 L> b =
dataku[dataku(1,3)]Error in `[.data.frame`(dataku, dataku(1, 3)) :
could not find function "dataku"> b = dataku[c(1,3)]> b Nama
usia1 A 182 B 183 C 194 D 205 E 216 F 227 G 208 H 199 I 2010 J 1911
K 21> c=which(dataku$jk==L)Error in which(dataku$jk == L) :
object 'L' not found> c=which(dataku$jk=="L")> c[1] 1 5 6 8
11> cP=which(dataku$jk=="P")> cP[1] 2 3 4 7 9 10>
d=if(dataku$jk=="L")&(dataku$ipk>3)Error: unexpected '&'
in "d=if(dataku$jk=="L")&">
d=if(dataku$jk=="L"&dataku$ipk>3)+ dError in if (dataku$jk
== "L" & dataku$ipk > 3) d : argument is of length zero>
d=if(dataku$jk=="L"&$ipk>3)Error: unexpected '$' in
"d=if(dataku$jk=="L"&$"> d=if(dataku$jk=="L"&ipk>3)+
dError: object 'ipk' not found>
d=which(dataku$jk=="L"&ipk>3)Error in which(dataku$jk == "L"
& ipk > 3) : object 'ipk' not found>
d=if(dataku$jk=="L"&IPK>3)+ dError: object 'IPK' not
found> d=which(dataku$jk=="L"&IPK>3)Error in
which(dataku$jk == "L" & IPK > 3) : object 'IPK' not
found> e = mean(IPK,usia,berat)Error in mean(IPK, usia, berat) :
object 'IPK' not found> e1 = mean(IPK)Error in mean(IPK) :
object 'IPK' not found> c=which(dataku$jk=="L")>
cP=which(dataku$jk=="P")> dataku[c,];dataku[cP,] Nama IPK usia
berat jk1 A 3.0 18 60 L5 E 2.1 21 64 L6 F 3.3 22 67 L8 H 2.2 19 65
L11 K 3.1 21 56 L Nama IPK usia berat jk2 B 2.5 18 58 P3 C 3.6 19
63 P4 D 4.0 20 55 P7 G 3.5 20 58 P9 I 2.2 20 60 P10 J 2.9 19 61
P> d=which(dataku$jk=="L" & dataku$ipk>3)>
dinteger(0)> d[d,]Error in d[d, ] : incorrect number of
dimensions> dataku[d,][1] Nama IPK usia berat jk (or 0-length
row.names)> d=which(dataku$jk=="L" & dataku$IPK>3)>
dataku[d,] Nama IPK usia berat jk6 F 3.3 22 67 L11 K 3.1 21 56
L> stat = dataku[,2;4]Error: unexpected ';' in "stat =
dataku[,2;"> stat = dataku[,2:4]> stat IPK usia berat1 3.0 18
602 2.5 18 583 3.6 19 634 4.0 20 555 2.1 21 646 3.3 22 677 3.5 20
588 2.2 19 659 2.2 20 6010 2.9 19 6111 3.1 21 56> data =
as.matrix(stat)> data IPK usia berat [1,] 3.0 18 60 [2,] 2.5 18
58 [3,] 3.6 19 63 [4,] 4.0 20 55 [5,] 2.1 21 64 [6,] 3.3 22 67 [7,]
3.5 20 58 [8,] 2.2 19 65 [9,] 2.2 20 60[10,] 2.9 19 61[11,] 3.1 21
56> t(data)%*%data IPK usia beratIPK 99.46 640.1 1955.8usia
640.10 4297.0 13169.0berat 1955.80 13169.0 40589.0
