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7/26/2019 PearsonCorrelation (Recovered 1) (Recovered)
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bas statistics for Social Science slide 1
Pearson
Product-MomentCorrelation
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bas statistics for Social Science slide 2
Pearson Product-
Moment Correlation
Purpose determine relationship between twometric variables
Requirement:
DV - Interval/Ratio
IV - Interval/Ratio
berarti data nya parametrik: berjenis interval dan ratio
dependentvariable
independentvariable
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bas statistics for Social Science slide 3
What to Expect
Strength
DescribeDirection
Calculate r
)()( SSYSSX
SXYr=
Hypothesis Test
kekuatan magnitude/ hub
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Components ofPearson ranalysis
DirectionPearson corr.
coefficient, rStrength/
MagnitudeDescriptive
Inferential
Hypothesis Test:
HO: = 0HA: 0
> 0
< 0
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bas statistics for Social Science slide 5
1Descriptive
Calculate r using the formula
=
=
22
22 )()(
)()(
)()(
n
YY
n
XX
n
YXXY
SSYSSX
SXYr +/-
Describe the nature of relationship between the two
variables in terms of:
Direction
Strength or magnitude using Guildfords Rule
of Thumb
+ +
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bas statistics for Social Science slide 6
Scatter Plot/Scatter gram
X
X
X
Y
Y
Positive
Relationship
Negative
Relationship
No
Relationship
Y
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bas statistics for Social Science slide 7
Strength/MagnitudeCorrelation coefficient, r
r-1 1
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Guildford Rule of Thumb
r Strength of Relationship
< .2 Negligible Relationship
.2 - .4 Low relationship
.4 - .7 Moderate relationship
.7 - .9 High relationship
> .9 Very high relationship
tidak ada hub0.00
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2 InferentialSteps in Hypothesis Testing
1. State the null and alternative hypotheses
HO: = 0
HA: 0
< 0
> 0
2. Calculate the test statistic
2
2
1
=
n
r
rt
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bas statistics for Social Science slide 10
3. Determine critical valuedf = n 2
One-tailed - t, df
Two-tailed - t/2, df
4. Make your decision
Criteria Decision
|tcal| > |tcritical| Reject HO
|tcal| |tcritical| Fail to reject HO
Manual
Criteria Decision
Sig-t< Reject HOSig-t Fail to reject H
SPSS
Reject HO:
Significant relationship between the two
variables
Fail to reject HO:No significant relationship between the two
variables
5. Make conclusion
O
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Example 1:
Data were collected from a randomly selected sample to determine
relationship between average assignment and test scores in statistics.
Distribution for the data is presented in the table below. Assuming
the data are normally distributed,
Data set:
Assign Test1. Calculate an appropriate correlation
coefficient,
2. Describe the nature of relationship
between the two variables, and3. Test the hypothesis on the
relationship at .01 level of
significance.
8.5 88
6 669 94
10 98
8 87
7 72
5 456 63
7.5 85
5 77
Data: 5950 Pearson 1 Class
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Example 1 Pearson correlation
1. Calculate the correlation coefficient ID X Y1 8.5 88
2 6 66
3 9 94
4 10 985 8 87
6 7 72
7 5 45
8 6 639 7.5 85
10 5 77
Summary stat:
n 10
X 72Y 775
X2 544.5
Y2 62,441
XY 5,795.5
( )( )
865.
1563.249
5.215
5.23781.26
5.215
10)775(441,62
10)72(5.544
10
)775()72(5.795,5
)()(
)()(
22
22
22
=
==
=
=
n
Y
Yn
X
X
n
YXXY
r
2. Based on r =.865, there is apositive and high relationship
between average assignment and test scores.
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bas statistics for Social Science slide 14
Example 1 Pearson correlation
3. Test the hypothesis on the relationship between the two
variables at .01 level of significance.
1. State the null and alternative hypotheses
HO: = 0
HA: 0
2. Calculate test statistic
876.4
1774.
865.
210
865.1
0865.
21
2
2
=
=
=
=
nr
rt
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bas statistics for Social Science slide 15
Example 1 Pearson correlation
3. Determine critical value
Critical t.005, 8 = 3.355
4. Decision
Since |tcal| (4.876) is bigger than |tcritical| (3.355)
Reject the null hypothesis
5. ConclusionConclude there is a significant relationship between
average assignment and test scores at .01 level of
significance
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bas statistics for Social Science slide 16
Example 1 Pearson correlation
: Pearson Product-
Moment Correlation
Correlations
1 .865**
. .001
10 10
.865** 1
.001 .
10 10
Pearson Correlation
Sig. (2-tailed)
N
Pearson Correlation
Sig. (2-tailed)
N
Average assignment
scores
Test scores
Average
assignment
scores Test scores
Correlation is significant at the 0.01 level (2-tailed).**.
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bas statistics for Social Science slide 17
Example 2 Pearson correlation
Example 2:
Reviews of literature show that anxiety is correlated negatively with
team cohesiveness. To ascertain this relationship, Dr Irman collected
data from a randomly selected sample. Summary of the data follow:
1. Calculate an appropriate correlation
coefficient,
2. Describe the nature of relationship
between the two variables, and3. Test the hypothesis on the
relationship at .05 level of
significance.
Summary Statistics:
n 21
X 417
Y 446
X2 8,697
Y2 9,802
XY 8,566
Data: 5950 Pearson 1 Class
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bas statistics for Social Science slide 18
Example 2 Pearson correlation
1. Calculate the correlation coefficient Summary Statistics:n 21
X 417
Y 446
X2 8,697Y2 9,802
XY 8,566
( )( )
783.
6605.370
2857.290
8095.3295714.416
2857.290
21)446(802,9
21)417(697,8
21
)446()417(566,8
)()(
)()(
22
22
22
=
=
=
=
=
n
Y
Yn
X
X
n
YXY
r
2. Based on r = -.783, there is a negative and high relationship
between anxiety and team cohesiveness.
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bas statistics for Social Science slide 19
Example 2 Pearson correlation
3. Test the hypothesis on the relationship at .05 level of
significance.
1. State the null and alternative hypotheses
HO: = 0
HA: < 0
2. Calculate test statistic
487.5
1427.
783.
221
)783.(1
0783.
21
2
2
=
=
=
=
nr
rt
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Example 2 Pearson correlation
3. Determine critical value
Critical t. 05, 19 = 1.729
4. Decision
Since |tcal| (-5.487) is bigger than |tcritical| (1.729)
Reject the null hypothesis
5. ConclusionConclude there is a significant relationship between
anxiety and team cohesiveness at .05 level of
significance
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bas statistics for Social Science slide 21
Example 2 Pearson correlation
SPSS: Pearson Product-
Moment Correlation
Correlations
1 -.783**
. .000
21 21
-.783** 1
.000 .
21 21
Pearson Correlation
Sig. (1-tailed)
N
Pearson Correlation
Sig. (1-tailed)
N
Anxiety
Team cohesiveness
Anxiety
Team
cohesiveness
Correlation is significant at the 0.01 level (1-tailed).**.
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bas statistics for Social Science slide 22