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Name Test 3 PHYS 0213 (Biochem) Spring 2005 1. (8 pts.) In glycolysis, ATP is formed during the conversion of phosphoenolpyruvate to pyruvate. What is the driving force for this reaction? C C OPO 3 2– H 2 C O O + ADP C C O H 3 C O O + ATP 2. In glycolysis, fructose-1,6-bisphophate is converted to dihydroxyacetonephosphate and glyceraldehyde-3-phosphate via a reverse aldol condensation. C C O H 2 C OPO 3 2- CH C OH H H 2 C OPO 3 2- O OH H H CH 2 OPO 3 2– C O C H HO C OH H C OH H CH 2 OPO 3 2– HC C OH C H HO C OH H C OH H CH 2 OPO 3 2– O H Reverse aldol condensation of fructose-1,6-bisphosphate glucose-6-phosphate a. (3 pts.) Between which C atoms is fructose cleaved. b. (3 pts.) Imagine that glucose-6-phosphate underwent a reverse aldol condensation. Between which C atoms would glucose be cleaved? c. (2 pts.) Draw the products of the reverse aldol condensation described in part b. d. (3 pts) What advantage does the reverse aldol condensation of fructose have over the reverse aldol condensation of glucose? (Hint: consider the size of the resulting product molecules.) 1. _______ 2. _______ 3. _______ 4. _______ 5. _______ 6. _______ 7. _______ 8. _______ 9. _______ 10. ______ 11. ______ 12. ______ 13. ______ 14. ______ 15. ______ 16. ______ 17. ______

Name Test 3 PHYS 0213 (Biochem) Spring 2005 1....Name Test 3 PHYS 0213 (Biochem) Spring 2005 1. (8 pts.) In glycolysis, ATP is formed during the conversion of phosphoenolpyruvate to

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Name Test 3PHYS 0213 (Biochem) Spring 2005

1. (8 pts.) In glycolysis, ATP is formed during the conversion of phosphoenolpyruvate topyruvate. What is the driving force for this reaction?

C

COPO3

2–H2C

O O

+ ADPC

COH3C

O O

+ ATP

2. In glycolysis, fructose-1,6-bisphophate is converted to dihydroxyacetonephosphate andglyceraldehyde-3-phosphate via a reverse aldol condensation.

C

C O

H2C OPO32-CH

C OHH

H2C OPO32-

O

OH

H

H

CH2OPO32–

C O

C HHO

C OHH

C OHH

CH2OPO32–

HC

C OH

C HHO

C OHH

C OHH

CH2OPO32–

O

H

Reverse aldol condensation of fructose-1,6-bisphosphate glucose-6-phosphate

a. (3 pts.) Between which C atoms is fructose cleaved.

b. (3 pts.) Imagine that glucose-6-phosphate underwent a reverse aldol condensation.Between which C atoms would glucose be cleaved?

c. (2 pts.) Draw the products of the reverse aldol condensation described in part b.

d. (3 pts) What advantage does the reverse aldol condensation of fructose have over thereverse aldol condensation of glucose? (Hint: consider the size of the resulting productmolecules.)

1. _______

2. _______

3. _______

4. _______

5. _______

6. _______

7. _______

8. _______

9. _______

10. ______

11. ______

12. ______

13. ______

14. ______

15. ______

16. ______

17. ______

3. (8 pts.) For each of the following pairs of carbon atoms indicate (circle) which carbon is the moreoxidized carbon atom.

a.

C

C

O H

CH2 OPO32–

OHH

b.

C

CCO2H

H2C CO2

CO2 c.

C

C

O OPO32–

CH2 OPO32–

OHH

d.C

C

O OPO32–

CH2 OPO32–

OHH

4. The reactions in the glycolytic pathway are summarized below.

O

OHOH

HOCH2

HOOH

ATP ADP O

OHOH

PiOCH2

HOOH

O CH2OHPiOCH2

OH

HO OHATP ADP

O CH2OPiPiOCH2

OH

HO OH

C

C

O H

CH2OPi

OHH

CH2OPi

C

CH2OH

O

C

C

O OPi

CH2OPi

OHH

NAD+ + Pi

C

C

O O

CH2OPi

OHH

ATP ADP

C

C

CH2OH

OO

OPiHC

COPiH2C

O OC

C

O O

OH3C

ATP ADP

NADH

a. (4 pts.) In which step is the sugar being oxidized?

b. (4 pts.) Which part of the sugar molecule is being oxidized?

c. (4 pts.) How many ATP molecules are synthesized for each glucose molecule that entersglycolysis?

After mannose is phosphorylated, phosphomannose isomerase performs the following conversion:

O OHOH

HOOH phosphomannose

isomerase

CH2OPO

O

OCH2OPO

O

OO CH2OH

OH

HOOH

d. (4 pts.) Phosphomannose isomerase converts mannose to what sugar?

e. (4 pts.) At what step does mannose get fed into glycolysis?

5. Gluconeogenesis is basically glycolysis run in reverse, but there are three important steps wereglycolysis cannot run in reverse. Two of those steps from the glycolytic pathway are drawnbelow.

Glycolysis Glycolysis in reverse

O

OHOH

HOCH2

HOOH

ATP ADP O

OHOH

PiOCH2

HOOH

glu glu-6-Pi

O CH2OHPiOCH2

OH

HO OHATP ADP

O CH2OPiPiOCH2

OH

HO OH

fru-6-Pi fru-1,6-bisPi

a. (2 pts.) Draw the reactions in reverse (you can use the abbreviations if you wish).

b. (4 pts.) Why don’t these reactions run in reverse?

c. (4 pts.) How does gluconeogenesis get around these two irreversible steps?

6. (2 pts. each) Which of the following molecules could be candidates for controlling glycolysis viafeedback inhibition?

a. glucose b. ADP c. ATP

d. AMP e. citrate f. pyruvate

7. (2 pts. each) Which of the following molecules could be candidates for activators of glycolysis?

a. NADH b. ADP c. ATP

d. AMP e. citrate f. pyruvate

8. A version of the citric acid cycle is drawn below.

CO2–

HC

CO2

CH

CO2–

O OC

CH2

CH2

O2C

H

C CO2

CH2

CoA

HO

CO2

C

CoA

O

S CO2–

H H

C

C

CH2

CO2–

CH2

CH2

CO2–

O

HHO

CO2–

H CO2–

C

C

CH2

CO2–

CO2–

HO

CH2

CO2–

CH2

CCO2

O

C

H2C

O2C

CoAC

O

H3C S

SH

CoA

+ H+H2O

SHCoA SH

a. (6 pts.) Identify the reactions were both CO2 and NADH are produced.

b. (4 pts.) In terms of ΔG, what is the significance of the release of CO2 in the steps in part a?

c. (4 pts.) In addition to the steps where both CO2 and NADH are produced, there are two moresteps where “reducing power” (NADH or FADH2) are produced. Identify those steps. (It is notnecessary to specify whether NADH or FADH2 is formed.)

9. In the pyruvate decarboxylase complex, an acetyl group is transferred fromthiaminepyrophosphate to lipoyl amide. One step of that reaction is drawn below.

NC

SC

C SS

O

NLYSHR'

R

H3CC

H3CO

H

SS

O

NLYSN

C

SC

C

R'

R

H3CC

H3CO

H

H+

(6 pts.) Redox wise, what is the significance of this step for the S atoms of the lipoyl amide?

10. Considering only the carbon atoms, for one crank of the citric acid cycle the overallstoichiometry of the reaction is... (One crank means start at the top and go all the way arounduntil you get back to the top.)

a. (4 pts.)

CC

CH2

C

O O

O

O

O +H3C

C

O

S CoA

Drawn below is a representation of the glyoxylate cycle. Considering only the carbon atoms, forone crank of the glyoxylate cycle the overall stoichiometry of the reaction is... (One crankmeans start at the top and go all the way around until you get back to the top.)

CO2–

HC

CO2

CH

CO2–

O OC

CH2

CH2

O2C

H

C CO2

CH2

CoA

HO

CO2

C

CoA

O

S CO2–

H H

C

C

CH2

CO2–

CH2

CH2

CO2–

O

HHO

CO2–

H CO2–

C

C

CH2

CO2–

CO2–

HO

CH2

CO2–

CH2

CCO2

O

C

H2C

O2C

CoAC

O

H3C S

SH

CoA

+ H+H2O

SHCoA SH

OC

HC

O

O

+ CH3CO-CoA

b. (4 pts.)

CC

CH2

C

O O

O

O

O +H3C

C

O

S CoA2

c. (2 pts.) Which pathway is better suited for building molecules containing four carbon atoms fromtwo-carbon atom precursors, the citric acid cycle or the glyoxalate cycle?

d. (6 pts.) Explain why one path is better suited for the task described in part c.

11. Although it is complicated, when it comes to getting NADH from the cytosol into themitochondrial matrix the aspartate-malate shuttle has a distinct advantage over the glycerolphosphate shuttle. In the glycerol phosphate shuttle the reducing power of NADH is used toreduce dihydroxyacetone phosphate to glycerol phosphate which is then delivered to themitochondrion and used to form FADH2. However, in the aspartate-malate shuttle, thereducing power of NADH is used to convert oxaloacetate to malate, which is then delivered inthe matrix of the mitochondrion.

(8 pts.) Why would delivering malate (in the aspartate-malate shuttle) into the mitochondrialmatrix be better than converting NADH to FADH2 (in the glycerol phosphate shuttle)? (Feelfree to flip back through the test and see where malate appears in other important pathways.You may also want to flip to the last page where some supplemental information has beenattached.)

H

C

CH2

CO2

CO2HO

malate

12. (6 pts.) Describe the traits that make vitamin E an effective intramembrane antioxidant.

O

O

H

H

13. (6 pts.) Describe two strategies that cells use to deal with radicals.

14. (8 pts.) The primary goal of the electron transport chain is to do what?

15. (8 pts.) Explain why radicals are potentially so damaging to cells.

16. (10 pts.) ATP Sythase is a large molecular machine that synthesizes ATP. What provides theenergy to drive this machine.

17. A cartoon of ATP Synthase from Biochemistry by McKee and McKee is pictured below.

a.

b.

c.

d.

(4 pts.) Which subunits move (list them by letterhere)?

(4 pts.) Which subunits are stationary (list them byletter here)?

(4 pts) Which side of the drawing represents thematrix of the mitochondrion ?

(6 pts.) What is the role of the γ and ε subunits?

Supplemental information for question 11.

FMNH2

NADH + H+

mitochondrial matrix

2 H+

2 e–

2 H+

UQ

UQH2

4Fe–4Scomplex2 H+

intermembrane space

2 e–

2Fe–2Scomplex

2 H+

2 H+2 H+

UQ

UQH2

to Complex III(Cytochrome bc1Complex)

Complex I

NADH Dehydrogenase Complex

FMN

NAD+

ETC Complex II

succinateFAD–succinatedehydrogenase

Fe–Scomplexes

UQH2

UQ

mitochondrial matrix

intermembrane space

C

H2C C

H2

C O

O

O

O

C

HC C

H

C O

O

O

Ofumarate

Cytochrome bc1 complex

Complex III

UQH2 UQH•

Fe–S

cyt c1

cyt c cyt c•

H+

cyt bL

cyt bH

UQH2

UQ2 2

2

2

2

2 2

1

UQH•

H+

H+

2

2

Cytochrome OxidaseComplex IV

cyt c•CuA

cyt a

cyt a3

CuB

2 H+ + 1/2 O2H2O

Glycerol Phosphate Shuttle

mitochondrial matrix

intermembrane space

NADH + H+

FAD

CH2OH

CH2OPi

O

CH2OH

CH2OPi

HHO

CH2OH

CH2OPi

HHO

CH2OH

CH2OPi

O

cytosol

UQH2UQ

Acyl-CoAdehydrogenase complex

FAD

UQH2UQ

FADH2

NAD+

FADH2