Mole Island DiagramMole Island Diagram

How Big is a Mole?How Big is a Mole?

One mole of marbles would cover the entire Earth (oceans included) for a depth of two miles.

One mole of $1 bills stacked one on top of another would reach from the Sun to Pluto and back 7.5 million times.

It would take light 9500 years to travel from the bottom to the top of a stack of 1 mole of $1 bills.

AmedeoAmedeo Avogadro Avogadro

1 mole = 602213673600000000000000

or 6.022 x 1023

thousandsmillionsbillionstrillions

quadrillions?

Welcome to Mole Island

1 mole = 22.4 L @ STP

1 mol = molar mass

1 mol = 6.02 x 1023 particles

Stoichiometry Island DiagramStoichiometry Island Diagram

Mass

Particles

Volume Mole Mole

Mass

Known UnknownSubstance A Substance B

Stoichiometry Island Diagram

Volume

Particles

M

V

P

Mass Mountain

Liter Lagoon

Particle Place

Mole Island

Stoichiometry Mole Island DiagramStoichiometry Mole Island DiagramWhen in doubt…convert to moles!When in doubt…convert to moles!

Mass

Particles

Volume Mole Mole

Mass

Volume

Particles

Known Unknown

Substance A Substance B

1 mole = molar mass (g) Use coefficientsfrom balanced

chemical equation1 mole = 22.4 L @ STP

1 mole =

6.022 x

1023 partic

les

(atoms o

r molecu

les)

1 mole = 22.4 L @ STP

1 mole = 6.022 x 10 23 particles

(atoms or molecules)

1 mole =

molar m

ass (g

)

(gases) (gases)

Stoichiometry Island DiagramStoichiometry Island Diagram

Mass

Particles

Volume Mole Mole

Mass

Known UnknownSubstance A Substance B

Stoichiometry Island Diagram

Volume

Particles

M

V

P

Mass Mountain

Liter Lagoon

Particle Place

Mass, Volume, Mole RelationshipMass, Volume, Mole Relationship

A. Using Mole IslandA. Using Mole IslandA. Using Mole IslandA. Using Mole Island

79.1g Zn

1 molZn

65.39g Zn

= 27.1 L H2

1 molH2

1 molZn

22.4 LH2

1 molH2

Zn + 2HCl ZnCl2 + H2 79.1 g ? L

Just watch, don’t write: If you have 79.1 g of Zn to react with excess HCl (enough HCl to keep reacting as long as you need), how many Liters of H2 gas will be produced?

79.1g HCl

1 molHCl

36.5g HCl

= 24.3 L H2

1 molH2

2 molHCl

22.4 LH2

1 molH2

Zn + 2HCl ZnCl2 + H2 79.1 g ? L

B. Using Mole IslandB. Using Mole IslandB. Using Mole IslandB. Using Mole IslandNow write this one for practice: If you instead have 79.1 g of HCl to react with excess Zinc (enough Zinc to keep reacting as long as you need), how many Liters of H2 gas will be produced?

Other possibilities: Still starting with 79.1 grams of HCl, how many molecules of H2 gas are produced? Or what mass of H2 gas is produced?

How would these questions change your calculations?

79.1g HCl

1 molHCl

36.5g Zn

= 6.5 x 1023 mc H2

1 molH2

2 molHCl

6.02 x 1023 mc H2

1 molH2

Zn + 2HCl ZnCl2 + H2 79.1 g ? mc

Or ? g

= 2.17 g H2

Same conversion to moles, same mole to mole ratio, different last conversions…