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Nama = FERMAYUD NUSANTARA
DWT = 1589 Ton
LBP = 62 m
LWL = 63.5 mLOA = 7 m
B = 11 m
! = 5.9 m
T = "." m
# = 11 $no%
& = 228".96 %on
LWL = 63.55 m
KOEFISIEN KAPAL
'( = .72
'm = .987
')* = .832
'+, = .865
'+- = .73
FN = .22
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P/-0%nan Ta-anan $a+a* M%o 4*-amm/
a $+a%an
# = 11 no%
( $+a%an m :
#: = .511" ; #
= 5.63 m:
Pano/ >>00n:0? an onom0 -a*aman 193
mm(/0 >o/m*a @
Fn = #: m: 9.81 L++ .5
= .23
Ra:0o Fn n% a+a* n/a* a/o aa*a- .1" .32 .
P/maan B0an Ba:a-
mn/% ER. Mm>o/@
S = L)* ; '( ; B C 1.7 ; T
= 977.9 m2
F 'o>0:0n Ta-anan S0:a To%a*
a. o>0:0n Ta-anan S0:a
=
= 2277.2" %on
13 = 13.12 %on
L13 = 4.84
=
L B T Cm
= 0.75
$o>0:0n Ta-anan S0:a 1 3 'R
Da/0 /a>0 5.5.6. an 5.5.7 ( Ta-anan an P/o+*:0 $a+a* -a*. 121
an 122
1 3 'R n% L & 1 3 = 5
1 3 'R n%/+o*a:0 L & 1 3 ".8"
1 3 'R n% L & 1 3 = ".5
(. $o/:0 $o>0:0:n Ta-anan S0:a A0(a% Ra:0o B T
- Perbandingan antara Lebar dengan Sarat ( B/T )
B/T = 2.50
1 3 'R1 = .16 B T 2.5 C 13 'R B
= .
L)* B T '( 1."
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. $o/:0 $o>0:0:n Ta-anan S0:a A0(a% L%a L'B
Besarnya Lcb
Menurut Gulda!!er dala! bu"u #si$ design and si$ te%ry#
%le &ar'ald.P al.55
Lcb = ( -*+5 , n ) 2 , 1Lb$
= -0.* ! ( dibela"ang !idsi$ )
n = 0.2+
02 1 , Lb$
0.2 !
= -0.23 !
Bila "%re"si untu" Lcb bernilai negati4 (-) !a"a
.65
. $o/:0 A0(a% Bn% 4a0n
Baan +an :%/0m =
Baan (*aan no/ma* =
1 3 'RL'B =
. $o/:0 $o>0:0:n Ta-anan A0(a% Aan?a Ano%a Baan $a+a*
1 3 'R2 = 8 G 13 H 'R
= .2"1
>. $o/:0 Bo)
$o/:0 Bo) =
o>0:0n !am(a%an S0:a To%a* 1 3 'R%
4 Anaa R?no*
Rn = # ; L)* ,
= 3.9" ; 1 6
= 3.1 1 8
, = $o>0:0n ,0:o:0
= 1.187
! $o>0:0n Ta-anan 4:
Paa ( Ta-anan an P/o+*:0 $a+a* -a*. 119
'> = .75 Lo Rn 2 2
Lo 3.1 1 8 = 8."78
= .179
Besarnya Lcb standar!enurut 4ig. 5.5.5
Lcbstandar
=
Lcbstandar
=
Lcb = Lcb - Lcbstandar
7%re"si untu" Lcb = ( Lcb ) , ( 0+89 / Lcb )
0+89Lcb
=
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$o/:0 $o>0:0n %a-anan 4: A0(a% Aan?a Tam(a-an Paa $a+a*
Pa 13 'a = 1.2 '>
= .182
$ $o>0:0n !am(a%an An0n 'aa
1 3 'aa = .7
L $o>0:0n !am(a%an $m0 'a:
1 3 'a: = ."
M $o>0:0n !am(a%an To%a*
1 3 'T = '/% C '> C 'a C 'aa C 'a:
= ".2
N !a/a !am(a%an To%a* $a+a* RT
RT = 'T 12 I.#2.S 1
= 11.3" $N
I = 1.25 %m3
asia tenggara.
( dalam buku "Tahanan dan Propulsi Kapal" oleh Sv.A.aHarvald
hal.2!
# 2.2$ K%
# &'.& K%
O Da?a E>%0> E!P
E!P = RT ; # .7355
= 576.9"75 !P
Penambahan )Tuntuk pertimbangan servi*e *ondition di +alur
pela,aran
)T-# 2 / 0 )
T
)T# )
T1 )
T-
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= 1.8
= 1.85
= 1.88
2.5
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.1
.1
.2
13
= 3.91
%a: a0/ *a%
; 1 6
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