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Making Mountains Out of Molehills The Banach-Tarski Paradox By Bob Kronberger Jay Laporte Paul Miller Brian Sikora Aaron Sinz

Making Mountains Out of Molehills The Banach-Tarski Paradox

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Making Mountains Out of Molehills The Banach-Tarski Paradox. By Bob Kronberger Jay Laporte Paul Miller Brian Sikora Aaron Sinz. Introduction. Definitions Schroder-Bernstein Theorem Axiom of Choice Conclusion. Banach-Tarski Theorem. - PowerPoint PPT Presentation

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Page 1: Making Mountains Out of Molehills The Banach-Tarski Paradox

Making Mountains Out of MolehillsThe Banach-Tarski Paradox

By

Bob Kronberger

Jay Laporte

Paul Miller

Brian Sikora

Aaron Sinz

Page 2: Making Mountains Out of Molehills The Banach-Tarski Paradox

Introduction

Definitions

Schroder-Bernstein Theorem

Axiom of Choice

Conclusion

Page 3: Making Mountains Out of Molehills The Banach-Tarski Paradox
Page 4: Making Mountains Out of Molehills The Banach-Tarski Paradox
Page 5: Making Mountains Out of Molehills The Banach-Tarski Paradox

Banach-Tarski Theorem

If X and Y are bounded subsets of having nonempty interiors, then there exists a natural number n and partitions and of X and Y (into n pieces each) such that is congruent to for all j.

3R

njX j 1: njY j 1:

jX

jY

Page 6: Making Mountains Out of Molehills The Banach-Tarski Paradox

Definitions

Rigid Motions

Partitions of Sets

Hausdorff Paradox

Piecewise Congruence

Page 7: Making Mountains Out of Molehills The Banach-Tarski Paradox

Rigid Motions

fixed. is 3

androtation fixed a is where3

for

)()( form thehaving 33

of mappingA

RaRx

axxrRRr

Page 8: Making Mountains Out of Molehills The Banach-Tarski Paradox

Rigid Motion

333231

232221

131211

1det T-1

Page 9: Making Mountains Out of Molehills The Banach-Tarski Paradox

Partition of Sets

A partition of a set X is a family of sets whose union is X and any two members of which are identical or

disjoint.

Page 10: Making Mountains Out of Molehills The Banach-Tarski Paradox

Partition of Sets

thatmeans subsets into ofpartition a is }1:{ nXnjj

X

jiXX

XXXX

ji

n

if

and

...21

Page 11: Making Mountains Out of Molehills The Banach-Tarski Paradox

Hausdorff Rotations

100

02123

02321

cos0sin

010

sin0cos

2

1sin

2

1cos xx

Page 12: Making Mountains Out of Molehills The Banach-Tarski Paradox

Hausdorff

31

221

321

23

22

21

23

321

countable is

such that

subsetsfour into 1:

sphereunit theof ,,, partition a exists There

SSivSSiii

SSSiiPi

xxxxRxS

SSSP

Page 13: Making Mountains Out of Molehills The Banach-Tarski Paradox

Hausdorff Rotations

(2) ...

(1)

21

23

n

i

nj

n

1

1

Page 14: Making Mountains Out of Molehills The Banach-Tarski Paradox

Hausdorff Rotations

22

m

m

m

m

PPP

PPP

PPP

PPP

...

...

...

...

21

21

21

21

Page 15: Making Mountains Out of Molehills The Banach-Tarski Paradox

Piecewise Congruence

YX

njXf

njf

njX

YX

jj

j

j

~

1:

1:

1:

~

Page 16: Making Mountains Out of Molehills The Banach-Tarski Paradox

Piecewise Congruence

YXXYYXvii

YXYXvi

ZXZYYXv

YXYXiv

transitiveZXZYYXiii

symmetricXYYXii

reflexiveXXi

~~ and ~

~

~~ and ~

~~

~~ and ~

~~

~

Page 17: Making Mountains Out of Molehills The Banach-Tarski Paradox

Piecewise Congruence

YXXYandYXvii ~~~

Page 18: Making Mountains Out of Molehills The Banach-Tarski Paradox

Schröder-Bernstein Theorem

Theorem:

If |A| ≤ |B| and |B| ≤ |A|, then |A| = |B|.

Page 19: Making Mountains Out of Molehills The Banach-Tarski Paradox

Cardinality

Questions that need to be answered:What is cardinality of sets?How do you compare cardinalities of different sets?

Page 20: Making Mountains Out of Molehills The Banach-Tarski Paradox

Cardinality

Definition: Number of elements in a set. Relationship between two cardinalities determined by:

•existence of an injection function•existence of a bijection function

Page 21: Making Mountains Out of Molehills The Banach-Tarski Paradox

Cardinality

Bijection functionOne-to-oneOnto

Page 22: Making Mountains Out of Molehills The Banach-Tarski Paradox

Cardinality

Bijection functionOne-to-oneOnto

Injection functionOne-to-one

Page 23: Making Mountains Out of Molehills The Banach-Tarski Paradox

Cardinality

B? &A between function bijection

B intoA fromfunction injection |B| |A| If

B intoA fromfunction injection |B| |A| If

B &A between function bijection |B| |A| If

Page 24: Making Mountains Out of Molehills The Banach-Tarski Paradox

Cardinality

Comparing cardinalities of two finite setsBoth cardinalities are integers

• If integers are = Bijection exists

• If integers are No Bijection exists Injection exists

Page 25: Making Mountains Out of Molehills The Banach-Tarski Paradox

Cardinality

Comparing cardinalities of two infinite setsCardinality =Cardinality

Page 26: Making Mountains Out of Molehills The Banach-Tarski Paradox

Cardinality

Comparing cardinalities of two infinite setsCardinality =CardinalityNot always clear

• Z • Z• Bijection function

2

2

xxf 2

Page 27: Making Mountains Out of Molehills The Banach-Tarski Paradox

Cardinality

Comparing cardinalities of a finite and an infinite Infinite cardinality > finite cardinality

Page 28: Making Mountains Out of Molehills The Banach-Tarski Paradox

Schröder-Bernstein Theorem

Four cases for sets A & BCase I: A finite & B finiteCase II: A infinite & B infiniteCase III: A finite & B infiniteCase IV: A infinite & B finite

Schröder-Bernstein Theorem:If |A| ≤ |B| and |B| ≤ |A|, then |A| = |B|

Page 29: Making Mountains Out of Molehills The Banach-Tarski Paradox

Schröder-Bernstein Theorem

Four cases for sets A & BCase I: A finite & B finiteCase II: A infinite & B infiniteCase III: A finite & B infiniteCase IV: A infinite & B finite

Schröder-Bernstein Theorem:If |A| ≤ |B| and |B| ≤ |A|, then |A| = |B|

Page 30: Making Mountains Out of Molehills The Banach-Tarski Paradox

Schröder-Bernstein Theorem

Two cases for sets A & BCase I: A finite & B finiteCase II: A infinite & B infinite

Schröder-Bernstein Theorem:If |A| ≤ |B| and |B| ≤ |A|, then |A| = |B|

Page 31: Making Mountains Out of Molehills The Banach-Tarski Paradox

Schröder-Bernstein Theorem

Case I: A finite & B finite |A| & |B| are integersLet |A| = r, |B| = s

• Given conditions |A| ≤ |B| & |B| ≤ |A|,• Given conditions r ≤ s & s ≤ r , then r = s |A| = |B|

Schröder-Bernstein Theorem :If |A| ≤ |B| and |B| ≤ |A|, then |A| = |B|

Page 32: Making Mountains Out of Molehills The Banach-Tarski Paradox

Schröder-Bernstein Theorem

Case II: A infinite & B infinite

First condition Schröder-Bernstein Theorem: If |A| ≤ |B| and |B| ≤ |A|, then |A| = |B|

• Injection function f from A into a subset of B, B

Page 33: Making Mountains Out of Molehills The Banach-Tarski Paradox

Schröder-Bernstein Theorem

Case II: A infinite & B infinite

Second condition Schröder-Bernstein Theorem: If |A| ≤ |B| and |B| ≤ |A|, then |A| = |B|

• Injection function g from B to a subset of A, A

Page 34: Making Mountains Out of Molehills The Banach-Tarski Paradox

Case II: A infinite & B infinite

Result Schröder-Bernstein Theorem: If |A| ≤ |B| and |B| ≤ |A|, then |A| = |B|

• Bijection function h between A and B

Page 35: Making Mountains Out of Molehills The Banach-Tarski Paradox

Schröder-Bernstein Theorem

Case II: A infinite & B infinite

To get resulting bijection function h:Combine the two given conditions

• Remove some of the mappings of g• Reverse some of the mappings of g

-1g

Page 36: Making Mountains Out of Molehills The Banach-Tarski Paradox

Schröder-Bernstein Theorem

Resulting bijection function h |A| = |B|

Af\Bg\A

Af\B1

xxf

xxgxh

Page 37: Making Mountains Out of Molehills The Banach-Tarski Paradox

The Axiom of Choice

For every collection A of nonempty sets there is a function f such that, for every B in A, f(B) B. Such a function is called a choice function for A.

Page 38: Making Mountains Out of Molehills The Banach-Tarski Paradox

Galaxy O’ Shoes

Page 39: Making Mountains Out of Molehills The Banach-Tarski Paradox

Questions That Surround the Axiom of Choice

1. Can It Be Derived From Other Axioms?

2. Is It Consistent With Other Axioms?

3. Should We Accept It As an Axiom?

Page 40: Making Mountains Out of Molehills The Banach-Tarski Paradox

The First Six AxiomsAxiom 1 Two sets are equal if they contain the same

members.Axiom 2 For any two different objects a, b there exists the set

{a,b} which contains just a and b.Axiom 3 For a set s and a “definite” predicate P, there exists

the set Sp which contains just those x in s which satisfy P.Axiom 4 For any set s, there exists the union of the members

of s-that is, the set containing just the members of the members of s.

Axiom 5 For any set s, there exists the power set of s-that is, the set whose members are just all the subsets of s.

Axiom 6 There exists a set Z with the properties (a) is in Z and (b) if x is in Z, the {x} is in Z.

Page 41: Making Mountains Out of Molehills The Banach-Tarski Paradox

Can It Be Derived From Other Axioms?

Page 42: Making Mountains Out of Molehills The Banach-Tarski Paradox

Is It Consistent With Other Axioms?

Page 43: Making Mountains Out of Molehills The Banach-Tarski Paradox

Major schools of thought concerning the use of the Axiom of Choice

A. Accept it as an axiom and use it without hesitation.

B. Accept it as an axiom but use it only when you can not find a proof without it.

C. Axiom of Choice is unacceptable.

Page 44: Making Mountains Out of Molehills The Banach-Tarski Paradox

Three major views are:

PlatonismConstructionismFormalism

Page 45: Making Mountains Out of Molehills The Banach-Tarski Paradox

Platonism:

A Platonist believes that mathematical objects exist independent of the human mind and a mathematical statement, such as the Axiom of Choice is objectively true or false.

Page 46: Making Mountains Out of Molehills The Banach-Tarski Paradox

Constructivism:A Constructivist believes that the only

acceptable mathematical objects are ones that can be constructed by the human mind, and the only acceptable proofs are constructive proofs

Page 47: Making Mountains Out of Molehills The Banach-Tarski Paradox

Formalism:A Formalist believes that mathematics

is strictly symbol manipulation and any consistent theory is reasonable to study.

Page 48: Making Mountains Out of Molehills The Banach-Tarski Paradox

Against:Its not as simple, aesthetically pleasing, and intuitive as the other axioms.With it you can derive non-intuitive results such as the Banach-Tarski Paradox.It is nonconstructive

Page 49: Making Mountains Out of Molehills The Banach-Tarski Paradox

For:Every vector space has a basisTricotomy of Cardinals: For any cardinals k and l, either k<1 or k=1 or k>1.The union of countably many countable sets is countable.Every infinite set has a denumerable subset.

Page 50: Making Mountains Out of Molehills The Banach-Tarski Paradox

What is a mathematical model?

Page 51: Making Mountains Out of Molehills The Banach-Tarski Paradox

What does the Banach-Tarski Paradox show?

?

Page 52: Making Mountains Out of Molehills The Banach-Tarski Paradox

Conclusion

Page 53: Making Mountains Out of Molehills The Banach-Tarski Paradox

References

Dr. Steve Deckelman“The Banach-Tarski Paradox”

By Karl Stromberg

“The Axiom of Choice”By Alex Lopez-Ortiz

“ Proof, Logic and Cojecture: The Mathematicians’”By Robert S. Wolf