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Lesson 5-3 Exponential Functions

Lesson 5-3

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Lesson 5-3. Exponential Functions. Exponential Functions:. Exponential Functions:. Any function in of the form of: f(x) = ab x where a>0, and b>0 and b≠1. Parent graphs for the general exponential functions are:. Parent graphs for the general exponential functions are:. - PowerPoint PPT Presentation

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Page 1: Lesson 5-3

Lesson 5-3

Exponential Functions

Page 2: Lesson 5-3

Exponential Functions:

Page 3: Lesson 5-3

Any function in of the form of: f(x) = abx

where a>0, and b>0 and b≠1.

Exponential Functions:

Page 4: Lesson 5-3

Parent graphs for the general exponential functions are:

Page 5: Lesson 5-3

Parent graphs for the general exponential functions are:

Page 6: Lesson 5-3

Parent graphs for the general exponential functions are:

b > 1

Page 7: Lesson 5-3

Parent graphs for the general exponential functions are:

Page 8: Lesson 5-3

Parent graphs for the general exponential functions are:

0 < b < 1

Page 9: Lesson 5-3

If f is an exponential function and f(0) = 3, f(2) = 12, find f(-2).

Page 10: Lesson 5-3

If f is an exponential function and f(0) = 3, f(2) = 12, find f(-2).

Use the general format: f(x) = abx

Page 11: Lesson 5-3

If f is an exponential function and f(0) = 3, f(2) = 12, find f(-2).

Use the general format: f(x) = abx

f(0) = 3 (0,3) 3 = ab0 3 = a

Page 12: Lesson 5-3

If f is an exponential function and f(0) = 3, f(2) = 12, find f(-2).

Use the general format: f(x) = abx

f(0) = 3 (0,3) 3 = ab0 3 = a

Page 13: Lesson 5-3

If f is an exponential function and f(0) = 3, f(2) = 12, find f(-2).

Use the general format: f(x) = abx

f(0) = 3 (0,3) 3 = ab0 3 = a

f(2) = 12 (2,12) 12 = (3)b2 4 = b2 + 2 = b

Page 14: Lesson 5-3

If f is an exponential function and f(0) = 3, f(2) = 12, find f(-2).

Use the general format: f(x) = abx

f(0) = 3 (0,3) 3 = ab0 3 = a

f(2) = 12 (2,12) 12 = (3)b2 4 = b2 + 2 = b

(b must be positive so b = 2.)

Page 15: Lesson 5-3

If f is an exponential function and f(0) = 3, f(2) = 12, find f(-2).

Use the general format: f(x) = abx

Therefore, our function is f(x) = 3(2)x.

Page 16: Lesson 5-3

If f is an exponential function and f(0) = 3, f(2) = 12, find f(-2).

Use the general format: f(x) = abx

Therefore, our function is f(x) = 3(2)x.

Thus, f(-2) = 3(2)-2.

Page 17: Lesson 5-3

If f is an exponential function and f(0) = 3, f(2) = 12, find f(-2).

Use the general format: f(x) = abx

Therefore, our function is f(x) = 3(2)x.

Thus, f(-2) = 3(2)-2.

Page 18: Lesson 5-3

When exponential functions are used to represent exponential growth and decay, the

variable t is used to represent time. Our functions can easily be written as:

Page 19: Lesson 5-3

When exponential functions are used to represent exponential growth and decay, the

variable t is used to represent time. Our functions can easily be written as:

f(t) = abt

Page 20: Lesson 5-3

When exponential functions are used to represent exponential growth and decay, the

variable t is used to represent time. Our functions can easily be written as:

f(t) = abt but we just worked with this as

Page 21: Lesson 5-3

When exponential functions are used to represent exponential growth and decay, the

variable t is used to represent time. Our functions can easily be written as:

f(t) = abt but we just worked with this as

A(t) = A0(1 + r)t

Page 22: Lesson 5-3

When exponential functions are used to represent exponential growth and decay, the

variable t is used to represent time. Our functions can easily be written as:

so, we now adjust and get

Page 23: Lesson 5-3

When exponential functions are used to represent exponential growth and decay, the

variable t is used to represent time. Our functions can easily be written as:

so, we now adjust and get

A(t) = A0b(t/k)

Page 24: Lesson 5-3

When exponential functions are used to represent exponential growth and decay, the

variable t is used to represent time. Our functions can easily be written as:

so, we now adjust and get

A(t) = A0b(t/k)

(k = time needed to multiply A0 by b)

Page 25: Lesson 5-3

A bank advertises that if you open a savings account, you can double your money in 12 years. Express A(t), the amount of money after t years, in each of the two forms previously given.

Page 26: Lesson 5-3

A bank advertises that if you open a savings account, you can double your money in 12 years. Express A(t), the amount of money after t years, in each of the two forms previously given.

Since 12 years is the time needed to multiply A0 by 2, form (2) gives:

Page 27: Lesson 5-3

A bank advertises that if you open a savings account, you can double your money in 12 years. Express A(t), the amount of money after t years, in each of the two forms previously given.

Since 12 years is the time needed to multiply A0 by 2, form (2) gives:

A(t) = A0(2t/12)

Page 28: Lesson 5-3

A bank advertises that if you open a savings account, you can double your money in 12 years. Express A(t), the amount of money after t years, in each of the two forms previously given.

Since 12 years is the time needed to multiply A0 by 2, form (2) gives:

A(t) = A0(2t/12)

To express A(t) in form (1), reason as follows.

Page 29: Lesson 5-3

A bank advertises that if you open a savings account, you can double your money in 12 years. Express A(t), the amount of money after t years, in each of the two forms previously given.

Since 12 years is the time needed to multiply A0 by 2, form (2) gives:

A(t) = A0(2t/12)

To express A(t) in form (1), reason as follows.

Page 30: Lesson 5-3

A bank advertises that if you open a savings account, you can double your money in 12 years. Express A(t), the amount of money after t years, in each of the two forms previously given.

Since 12 years is the time needed to multiply A0 by 2, form (2) gives:

A(t) = A0(2t/12)

To express A(t) in form (1), reason as follows.

Page 31: Lesson 5-3

Rule of 72: If a quantity is growing at r% per year

(or month) then the doubling time is approximately 72 / r years (or months).

Page 32: Lesson 5-3

For example, if a quantity grows at a rate of 8% per year then the quantity will double in

approximately (72 / 8) or 9 years. If a population is growing exponentially at a

rate of 2% per month then the population will double in about (72 / 2) or 36 months.

Page 33: Lesson 5-3

A radioactive isotope has a half-life of 5 days. This means that half the substance will decay in 5 days. At what rate does the substance decay each day?

Page 34: Lesson 5-3

A radioactive isotope has a half-life of 5 days. This means that half the substance will decay in 5 days. At what rate does the substance decay each day?

Page 35: Lesson 5-3

A radioactive isotope has a half-life of 5 days. This means that half the substance will decay in 5 days. At what rate does the substance decay each day?

So, the daily rate of decay is 13%.

Page 36: Lesson 5-3

Assignment:

Pgs. 183-184C.E. 1-10 all,W.E. 1-11 odd