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Leontief Input-Output Model. Becky Siegel Carson Finkle April 23 2008. What is the model about?. Used to describe the relationship of industries within a sector International National Regional Within a business. Assumptions of the Model. Fixed proportions of inputs - PowerPoint PPT Presentation
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Leontief Input-Output Model
Becky Siegel
Carson Finkle
April 23 2008
What is the model about?
Used to describe the relationship of industries within a sectorInternationalNationalRegionalWithin a business
Assumptions of the Model
Fixed proportions of inputs Demand is met fully without a surplus
or shortage Internally for closed modelInternally + external demand for open
model
The Equation (closed) Let C be a consumption matrix such that and X be
the production vector such that
Economic Activities
Inputs to Energy
Inputs to Manufacturing
Inputs to Services
Total Production
Energy .2 .3 .2 ?
Manufacturing .5 .2 .3 ?
Services .3 .5 .5 ?
C X⏐ →⏐
= X⏐ →⏐
Closed Model
Energy Manufact-uring
Services
Ener. Manuf . Services
C =.2 .3 .2.5 .2 .3.3 .5 .5
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
EnergyManufacturingServices
= consumption matrix
Want to Find C x⏐ →⏐
= x⏐ →⏐so need to find eigenvector associated
with an eigenvalue of 1 (if it exists)
Characteristic polynomial: x3 −.9x2 −.12x+ .02λ =1,−.2,.1, want to find eigenvector for E1
C −λI =C−I =−.8 .3 .2 0.5 −.8 .3 0.3 .5 −.5 0
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
RREF =−.8 .3 .2 0.5 −.8 .3 0.3 .5 −.5 0
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥~
1 0−2549
0
0 1−3449
0
0 0 0 0
⎡
⎣
⎢⎢⎢⎢⎢⎢⎢
⎤
⎦
⎥⎥⎥⎥⎥⎥⎥
x1 =2549x3
x2 =3449x3
E1 =span
254934491
⎡
⎣
⎢⎢⎢⎢⎢⎢⎢
⎤
⎦
⎥⎥⎥⎥⎥⎥⎥
⎧
⎨
⎪⎪⎪
⎩
⎪⎪⎪
⎫
⎬
⎪⎪⎪
⎭
⎪⎪⎪
=span.51.691
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
⎧
⎨⎪
⎩⎪
⎫
⎬⎪
⎭⎪
The Equation (open) Let C be a consumption matrix such that and X be
the production vector such that
C X⏐ →⏐
+ D⏐ →⏐
= X⏐ →⏐
Economic
Activities
Inputs to
Labor
Inputs to
Transportation
Inputs to
Food
External
Demand
Total
Production
Labor 0 .5 .5 10,000 ?
Transportation .4 .3 .05 20,000 ?
Food .2 0 .35 10,000 ?
Open Model
Labor Transportation
FoodExternal
Demand
X⏐ →⏐
=C X⏐ →⏐
+ D⏐ →⏐
X⏐ →⏐
−C X⏐ →⏐
= D⏐ →⏐
(I −C) X⏐ →⏐
= D⏐ →⏐
X⏐ →⏐
=(I −C)−1 D⏐ →⏐
Solving for x vector
Labor Trans Food
C =0 .5 .5.4 .3 .05.2 0 .35
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
LaborTransportation
Food= consumption matrix
D=10,00020,00010,000
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥ = external demand function
I −C =1 0 00 1 00 0 1
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥−
0 .5 .5.4 .3 .05.2 0 .35
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥=
1 −.5 −.5−.4 −.7 −.05−.2 0 .65
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
I −C−1 =1 −.5 −.5 1 0 0−.4 −.7 −.05 0 1 0−.2 0 .65 0 0 1
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥~
1 0 0 1.82 1.3 1.50 1 0 1.08 2.2 10 0 1 .56 .4 2
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
X⏐ →⏐
=(1−C)−1D=1.82 1.3 1.51.08 2.2 1.56 .4 2
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
10,00020,00010,000
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥ =
59,20064,80033,600
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
Just for fun…
Economic
Activities
Inputs to
Labor
Inputs to
Transportation
Inputs to
Food
External
Demand
Total
Production
Labor .5 .0 .25 10,000 ?
Transportation .2 .8 .8 20,000 ?
Food 1 .4 0 10,000 ?
Labor Trans Food
C =.5 0 .25.2 .8 .81 .4 0
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
LaborTransportation
Food= consumption matrix
D=10,00020,00010,000
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥ = external demand function
I −C =1 0 00 1 00 0 1
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥−
.5 0 .25
.2 .8 .81 .4 0
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥=
.5 0 .25
.2 .2 .81 .4 1
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
I −C−1 =.92 −.8 −.38−7.69 −1.92 −3.46−2.15 −1.54 .8
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
X⏐ →⏐
−C X⏐ →⏐
= D⏐ →⏐
⏐ →⏐ (I −C) X⏐ →⏐
= D⏐ →⏐
⏐ →⏐ X=(I −C)−1 D⏐ →⏐
(I −C)−1D=.92 −.8 −.38−7.69 −1.92 −3.46−2.15 −1.54 .8
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
10,00020,00010,000
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥ =
-75,300-152,200-44,300
⎡
⎣
⎢⎢⎢
⎤
⎦
⎥⎥⎥
Wrap Up
ContributionsLimitationsConclusions