Upload
saifadamzs
View
217
Download
0
Embed Size (px)
Citation preview
8/19/2019 Lecture Notes (Chapter 4.5 Gauss and Stokes Theorem )
http://slidepdf.com/reader/full/lecture-notes-chapter-45-gauss-and-stokes-theorem- 1/5
1 Chapter 4: Vector Calculus
Example 1
Evaluate surface integral of ( , , ) 2 x y z x y z F i j k over all the surfaces of the cube
0, 1, 0, 1, 0, x x y y z and 1 z , with the oriented outward unit normal vector.
Solution
2 x y z x y z
F i j k i j k
1 1 2
4
S G
dS dV F n F
11 1
0 0 0
11
0 0
1
0
4
4
4
4
y z x
z y x
y z
z y
z
z
dxdydz
dydz
dz
Gauss’s Theorem / Divergence Theorem
Gauss’s Theorem / Divergence Theorem
Let G be a simple and closed solid region and let S be the surface of G given with positive
(outwards) orientation.
Let ( , , ) ( , , ) ( , , ) ( , , ) x y z u x y z v x y z w x y z F i j k be a vector field whose component
functions have continuous partial derivatives on an open region that contains G.
Hence, the surface integrals of the vector field F is given by:
S G
dS dV
F n F
8/19/2019 Lecture Notes (Chapter 4.5 Gauss and Stokes Theorem )
http://slidepdf.com/reader/full/lecture-notes-chapter-45-gauss-and-stokes-theorem- 2/5
2 Chapter 4: Vector Calculus
Example 2
Use Gauss’s Theorem to evaluateS
dS F n , where ( , , ) x y z y xy z F i j k and S is the
surfaces enclosed by cylinder 2 2 4 x y , plane 0 z , and paraboloid 2 2. z x y
Solution
y xy z x y z
F i j k i j k
0 1
1
x
x
By Gauss’s Theorem,
S G
dS dV F n F
( 1)G
x dV
By cylindrical coordinates,
22 2
0 0 0
( cos 1)r z r
S r z
dS r dzrdrd
F n
22 2
2
0 0 0
2 2
2 2
0 0
2 2
4 3
0 0
22 5 4
0 0
2
0
2
0
( cos )
( cos )
( cos )
cos
5 4
32cos4
5
32sin 4
5
8
r z r
r z
r
r
r
r
r r dzdrd
r r r drd
r r drd
r r d
d
It’s projection on xy-plane
8/19/2019 Lecture Notes (Chapter 4.5 Gauss and Stokes Theorem )
http://slidepdf.com/reader/full/lecture-notes-chapter-45-gauss-and-stokes-theorem- 3/5
3 Chapter 4: Vector Calculus
Example 3
Let S be the surfaces of the solid G enclosed by upper hemisphere 2 21 z x y , and
plane 0 z , and oriented outward. Use Gauss’s Theorem to find the surface integrals of the
vector field 3 3 3( , , ) x y z x y z F i j k over the surface S .
Solution
3 3 3 x y z x y z
F i j k i j k
2 2 2
2 2 2
3 3 3
3( )
x y z
x y z
By Gauss’s Theorem,
S G
dS dV F n F
2 2 23( )G
x y z dV
By spherical coordinates,
/2 12
2 2
0 0 0
3 sinS
dS d d d
F n
/2 2
0 0
/2
0
/2
0
3sin
5
6sin
5
6 cos5
6
5
d d
d
It’s projection on xy-plane
8/19/2019 Lecture Notes (Chapter 4.5 Gauss and Stokes Theorem )
http://slidepdf.com/reader/full/lecture-notes-chapter-45-gauss-and-stokes-theorem- 4/5
4 Chapter 4: Vector Calculus
Stoke’s Theorem can be regarded as an extension of Green’s Theorem. Stoke’sTheorem relates a surface integral over a surface S to a line integral around the
boundary curve of S .
Example 4
EvaluateS
d F r by using Stoke’s Theorem for 2 32 z x y F i j k with C is the circle
2 2 1 x y in the xy-plane with counterclockwise orientation looking down the positive z -axis.
Solution
2
2 3
3 2 2
2
y z x y z
z x y
i j k
F i j k
For plane 0 ( , , ) z f x y z z
2
2
1 1
( 3 2 2 ) 2
f f f f
x y z
f
f
f
y z
i j k k
|| ||
n k || ||
F n i j k k
Stoke’s Theorem
Stoke’s Theorem
Let S be an orientable piecewise smooth surface, which is bounded by a simple, closed,
piecewise smooth boundatu curve C with positive orientation.
Let ( , , ) ( , , ) ( , , ) ( , , ) x y z u x y z v x y z w x y z F i j k be a vector field whose component
functions have continuous partial derivatives on an open region that contains S .
Hence,
S S
d dS F r F n
8/19/2019 Lecture Notes (Chapter 4.5 Gauss and Stokes Theorem )
http://slidepdf.com/reader/full/lecture-notes-chapter-45-gauss-and-stokes-theorem- 5/5
5 Chapter 4: Vector Calculus
By Stoke’s Theorem,
S S
d dS F r F n
2 1
0 0
2
0
2
2
1
2
S
r
r
dA
rdrd
d