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Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

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Page 1: Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

Lecture No. 46Chapter 14

Contemporary Engineering EconomicsCopyright © 2010

Contemporary Engineering Economics, 5th edition, © 2010

Page 2: Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

Chapter Opening Story Issue: United Airlines (UAL) is in the process of replacing many of its 111-airplane wide-body fleet, as well as some of its 97 aging Boeing 757 narrow-body planes. What basis do they make the fleet-replacement decisions?

Contemporary Engineering Economics, 5th edition, © 2010

Page 3: Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

Replacement TerminologyDefender: an old

machine Challenger: a new

machineCurrent market value:

selling price of the defender in the market place

Sunk cost: any past cost unaffected by any future decisions

Trade-in allowance: value offered by the vendor to reduce the price of a new equipment

Contemporary Engineering Economics, 5th edition, © 2010

Page 4: Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

Sunk Cost associated with an Asset’s Disposal Given: Original investment = $20,000, current market value = $10,000, repair cost made in the past = $5,000

Find: Relevant cost for replacement analysis

Lost investment value, $10,000 Repair cost made, $5,000 Total sunk cost = $15,000 Relevant cost for replacement analysis = current market value = $10,000

Contemporary Engineering Economics, 5th edition, © 2010

Page 5: Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

Example 14.2 -Opportunity Cost Approach

Basic Principle: Treat the proceeds from sale of the old machine as the investment required to keep the old machine.

Defender:Market price: $10,000Remaining useful life: 3 yearsSalvage value: $2,500O&M cost: $8,000

Challenger:Cost: $15,000Useful life: 3 yearsSalvage value: $5,500O&M cost: $6,000

Decision: Replace the defender now

Contemporary Engineering Economics, 5th edition, © 2010

Page 6: Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

Definition: Economic service life is the remaining useful life of an asset that results in the minimum annual equivalent cost. Annual Equivalent Cost (AEC) = Capital Cost + Operating Cost

Contemporary Engineering Economics, 5th edition, © 2010

Page 7: Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

Mathematical RelationshipCapital Cost:

Operating Cost:

Total Cost:

Objective: Find n* that minimizes AEC(i)

Contemporary Engineering Economics, 5th edition, © 2010

n*

Page 8: Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

Example 14.3 Economic Service Life for a Lift Truck

Given: I = $18,000, i = 12%, Salvage value = -20% over the previous year, O&M = $3,000 during the first year, and 15% increase over the previous year thereafter

Find: Economic Service Life

Contemporary Engineering Economics, 5th edition, © 2010

n = 1:

n = 2:

$18,000

$14,400

$3,000

01

$18,000

$3,000

$11,520

$3,450

0 1 2

Page 9: Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

AEC Calculation If you Kept the Truck for 2 Years

Ownership Cost:

Operating Cost:

Annual Equivalent Cost:

Contemporary Engineering Economics, 5th edition, © 2010

CR(12%) ($18,000 $11,520)( / ,12%,2)(0.12)($11,520)$5,760

A P

OR(12%) $3,000( / ,12%,1) $3,450( / ,12%,2)

( / ,12%,2)$3,212

P F P F

A P

2AEC(12%) $5,760 $3,212$8,429

n

Page 10: Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

Conversion of an Infinite Number of Replacement Cycles to Infinite AEC Streams

Contemporary Engineering Economics, 5th edition, © 2010

Page 11: Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

Economic Service Life Calculation Using Excel Economic Service Life = 6 Years with AEC(12%) = $7,977

What It Really Means? You purchase a brand new lift truck for every 6 years, assuming that the future replacement cost as well as operating costs remain constant. Then the equivalent annual cost of owning and operating the truck is $7,977.

Contemporary Engineering Economics, 5th edition, © 2010

Page 12: Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5th edition, © 2010

For an asset with non-increasing operating cost, keep

the asset as long as it lasts.If everything remains the same, a higher interest rate

will tend to extend the economic service life (or defer the replacement decision).

Contemporary Engineering Economics, 5th edition, © 2010

Sensitivity of Economic Service Life