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Lecture 2 Kjemisk reaksjonsteknikk. Review of Lecture 1 and 2 (chapter 1 and 2) Rate Laws Reaction Orders Arrhenius Equation Activation Energy Effect of Temperature. General Mole Balance. General Mole Balance on System Volume V. System Volume, V. F A0. F A. G A. 2. - PowerPoint PPT Presentation
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1 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Lecture 2
Kjemisk reaksjonsteknikk
Review of Lecture 1 and 2 (chapter 1 and 2) Rate Laws Reaction Orders Arrhenius Equation Activation Energy Effect of Temperature
2 - 04/21/23
Departm
ent of Chem
ical E
ngineering
General Mole Balance
General Mole Balance on System Volume V
In Out Generation Accumulation
FA 0 FA rA dV dNA
dt
FA
0
FAGA
System Volume, V
2
3 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Reactor Mole Balance Summary
Reactor Differential Algebraic Integral
The GMBE applied to the four major reactor types (and the general reaction AB)
V FA 0 FA
rA
CSTR
Vrdt
dNA
A 0
A
A
N
N A
A
Vr
dNtBatch
NA
t
dFA
dVrA
A
A
F
F A
A
dr
dFV
0
PFRFA
V
dFA
dW r A
A
A
F
F A
A
r
dFW
0
PBRFA
W3
4 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Reactor Mole Balances in terms of conversion
Reactor Differential Algebraic Integral
A
0A
r
XFV
CSTR
A0A rdV
dXF
X
0 A0A r
dXFVPFR
Vrdt
dXN A0A
Vr
dXNt
X
0 A0A
Batch
X
t
A0A rdW
dXF
X
0 A0A r
dXFWPBR
X
W4
FA=FA0-FA0X=FA0(1-X)
X
5 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Reactor Mole Balances in terms of residence time and conversion
X
t
5
FA=CAΦV , CA=CA0(1-X), τ=V/ ΦV
X
Batch reactor dt
dxC
dt
dCr A
AA 0
CSTR
xCr A
A0
PFR d
dxC
FVd
dxr A
AA 0
0 )/(
X
τ
6 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Two types of problems Design problem: Design a reactor to achieve certain conversion
Operating problem: in a existing reactor to find conversion or the residence time to reach the certain conversion
A
x
AA r
dxC
FVd
dx
0
00 )/(
PFR
Levenspiel Plots
A
A
r
xC
0
CSTR
7 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Reactors in Series
2,
1202
)(
xA
A
r
xxFV
1,
101
xA
A
r
xFV
1
0
01
x
AA r
dxFV
1,
101
xA
A
r
xFV
2
1
02
x
x AA r
dxFV
8 - 04/21/23
Departm
ent of Chem
ical E
ngineering
PFR vs CSTR in series
…..
A
A
r
F
0
x
Is the PFR always better than the CSTR in terms of reactor size to achieve a identical conversion?
i
iAA V
xFr 0
9 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Reactors in Series
9
reactorfirst tofedA of moles
ipoint toup reactedA of molesX i
Only valid if there are no side streams
10 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Reactors in Series
10
Exothermic reaction in an adiabatic reactor
How can we minimize the reaction size?
11 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Basic Definitions
Homogeneous reactions involve only one phase Heterogeneous reactions involve more than one phase, and
reactions occur at interfaces of two phases Irreversible reactions occur at only one direction Reversible reactions occur at both directions, depending one the
approach to equilibrium Molecularity of the reaction is the number of the atoms, ions or
molecules involved in a reaction step. Unimolecular, bimolecular and termolecular refer to reactions involving one, two and three atoms or molecules in one reaction step, respectively
Elementary reaction involves only one bond breaking or formation Non-elementary reaction could involve multi elementary reaction
steps
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Departm
ent of Chem
ical E
ngineering
Kinetics
13 - 04/21/23
Departm
ent of Chem
ical E
ngineering
BAA CkCr
βα
β
α
OrderRection Overall
Bin order
Ain order
Kinetics - Power Law Model
13
C3BA2 A reactor follows an elementary rate law if the reaction orders just happens to agree with the stoichiometric coefficients for the reaction as written.e.g. If the above reaction follows an elementary rate law
2nd order in A, 1st order in B, overall third order
B2AAA CCkr
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Departm
ent of Chem
ical E
ngineering
"Everyone has Problems -
but Chemists have Solutions"
Chemical Engineers have Simple Solutions !!!
15 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Example : Ammonia decomposition
2NH3=3H2+N2 11 kJ/mol
The kinetic study was performed in a fixed bed reactor (6 mm diameter) on Fe/Al2O3 catalysts at atmospheric pressure and total flow of 100 ml/min with Ar as the balance. 100 mg catalysts mixed with 1 g SiC were loaded in the reactor.
FNH3.s (ml/min) 20 40 80
FAr,s (ml/min) 80 60 20
XNH3 0.050 0.051 0.050
1) Can we determine the reactor order? (n=0,1,2 ? ) 2) How can we reduce the conversion from 5.0 % to 2.5 %
16 - 04/21/23
Departm
ent of Chem
ical E
ngineering
dDcCbBaA
d
r
c
r
b
r
a
r DCBA
Da
dC
a
cB
a
bA
Relative Rates of Reaction
16
17 - 04/21/23
Departm
ent of Chem
ical E
ngineering
3
r
1
r
2
r CBA
Relative Rates of Reaction
C3BA2
sdm
mol10r
3A
sdm
mol5
2
rr
3A
B
sdm
mol15r
2
3r
3AC
17
18 - 04/21/23
Departm
ent of Chem
ical E
ngineering
If2AA kCr
›Second Order in A›Zero Order in B›Overall Second Order
2A+B3C
BAAA CCkr 2
BABB CCkr 2
2
1
BACC CCkr 2
2
3
18
19 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Reversible Reaction
Elementary
e
3C2
BAA
AA
3C2
BAA
3CA
2BAAA
K
CCCk
kk
CCCk
CkCCkr
19
C3BA2
This equation is thermodynamically consistent.
20 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Reversible Reaction
A+2B3C
kA
k-AReaction is: First Order in A
Second Order in BOverall third Order
sm
molesrA 3
3m
molesCA
smole
m
mmolemmole
smmole
CC
rk
BA
A2
6
233
3
2
20
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Departm
ent of Chem
ical E
ngineering
21
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Departm
ent of Chem
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ngineering
Arrhenius Equation
k Ae E RT
k is the specific reaction rate (constant) and is given by the Arrhenius Equation.
where:
T k A
T 0 k 0
A 1013
k
T22
Svante August Arrhenius was a Swedish scientist, received the Nobel Prize for Chemistry in 1903
23 - 04/21/23
Departm
ent of Chem
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ngineering
Arrhenius Equation
where:E = Activation energy (cal/mol)R = Gas constant (cal/mol*K)T = Temperature (K)A = Frequency factor (same units as rate constant k)(units of A, and k, depend on overall reaction order)
23
24 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Reaction Coordinate
The activation energy can be thought of as a barrier to the reaction. One way to view the barrier to a reaction is through the reaction coordinates. These coordinates denote the energy of the system as a function of progress along the reaction path. For the reaction:
A BC A ::: B ::: C AB CThe reaction coordinate is
24
Transition state theory
25 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Why is there an Activation Energy?
We see that for the reaction to occur, the reactants must overcome an energy barrier or activation energy EA. The energy to overcome their barrier comes from the transfer to the kinetic energy from molecular collisions and internal energy (e.g. Vibrational Energy).1.The molecules need energy to disort or
stretch their bonds in order to break them and thus form new bonds
2.As the reacting molecules come close together they must overcome both stearic and electron repulsion forces in order to react.25
26 - 04/21/23
Departm
ent of Chem
ical E
ngineering
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Departm
ent of Chem
ical E
ngineering
28 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Collision probability
29 - 04/21/23
Departm
ent of Chem
ical E
ngineering
One such distribution of energies is in the following figure:
f(E,T)dE=fraction of molecules with energies between E+dE
29
30 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Rate expression – Gas phase reaction
A+B = 2C
31 - 04/21/23
Departm
ent of Chem
ical E
ngineering
Rate expression – Catalysed reaction