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Layout and Design Kapitel 4 / 1(c) Prof. Richard F. Hartl
Flow shop production
Object-oriented
Assignment is derived from the item´s work plans. Uniform material flow:
Linear assignment (in most cases) Useful if (and only if) only one kind of product or a limited
amount of different kinds of products is manufactured (i.e. low variety – high volume)
Layout and Design Kapitel 4 / 2(c) Prof. Richard F. Hartl
Flow shop production
According to time-dependencies we distinguish between
Flow shop production without fixed time restriction for each workstation („Reihenfertigung“)
Flow shop prodcution with fixed time restriction for each workstation (Assemly line balancing, „Fließbandabgleich“)
Layout and Design Kapitel 4 / 3(c) Prof. Richard F. Hartl
Flow shop production
No fixed time restriction for the workload of each workstation: Intermediate inventories are needed Material flow should be similiar for all prodcuts Some workstations may be skipped, but going back to a previous department is
not possible Processing times may differ between products
Inventory Station 1 Int. inventory Station 2 ... Station m Inventory
Layout and Design Kapitel 4 / 4(c) Prof. Richard F. Hartl
Flow shop production
Fixed time restricition (for each workstation): Balancing problems Cycle time („Taktzeit“): upper bound for the workload of each workstation. Idle time: if the workload of a station is smaller than the cycle time.
Production lines, assembly lines automated system (simultaneous shifting)
Station 1 Station 2 Station 3 ...
Layout and Design Kapitel 4 / 5(c) Prof. Richard F. Hartl
Assembly line balancing
Production rate = Reciprocal of cycle time The line proceeds continuously. Workers proceed within their station parallel with their workpiece
until it reaches the end of the station; afterwards they return to the begin of the station.
Further possibilites: Line stops during processing time Intermittent transport: workpieces are transported between the stations.
Layout and Design Kapitel 4 / 6(c) Prof. Richard F. Hartl
Assembly line balancing
„Fließbandabstimmung“, „Fließbandaustaktung“, „Leistungsabstimmung“, „Bandabgleich“
The mulit-level production process is decomomposed into n operations/tasks for each product.
Processing time tj for each operation j
Restrictions due to production sequence of precedences may occur and are displayed using a precedence graph:
Directed graph witout cyles G = (V, E, t) No parallel arcs or loops Relation i < j is true for all (i, j)
Layout and Design Kapitel 4 / 7(c) Prof. Richard F. Hartl
Example
Operation j Predecessor tj
1 - 6
2 - 9
3 1 4
4 1 5
5 2 4
6 3 2
7 3, 4 3
8 6 7
9 7 3
10 5, 9 1
11 8,1 10
12 11 1
t1=61
112
1011 3
9 37
78
26
43
54
..110
t2=92
45
Precedence graph
Layout and Design Kapitel 4 / 8(c) Prof. Richard F. Hartl
Flow shop production
Machines (workstations) are assigned in a row, each station containing 1 or more operations/tasks.
Each operation is assigned to exactly 1 station I before j – (i, j) E:
i and j in same station or i in an earlier station than j
Assignment of operations to staions: Time- or cost oriented objective function Precedence conditions Optimize cycle time Simultaneous determination of number of stations and cycle time
Layout and Design Kapitel 4 / 9(c) Prof. Richard F. Hartl
Single product problems
Simple assembly line balancing problem Basic model with alternative objectives
Layout and Design Kapitel 4 / 10(c) Prof. Richard F. Hartl
Single product problems
Assumptions: 1 homogenuous product is produced by performing n operations given processing times ti for operations j = 1,...,n
Precedence graph Same cycle time for all stations fixed starting rate („Anstoßrate“) all stations are equally equipped (workers and utilities) no parallel stations closed stations workpieces are attached to the line
Layout and Design Kapitel 4 / 11(c) Prof. Richard F. Hartl
Alternative1
Minimization of number of stations m (cycle time is given):
Cycle time c: lower bound for number of stations
upper bound for number of stations
ctm j
n
j 1min :
11: max1
max
tctm j
n
j
Layout and Design Kapitel 4 / 12(c) Prof. Richard F. Hartl
Alternative 1
t(Sk) … workload of station k Sk, k = 1, ..., m
Integer property
Sum of inequalities
and integer property of m
max
1
111 tcmSt k
m
k
k
m
kj
n
jStt
1
11
upper bound
tmax + t(Sk) > c i.e. t(Sk) c + 1 - tmax k =1,...,m-1
Layout and Design Kapitel 4 / 13(c) Prof. Richard F. Hartl
Alternative 2
Minimization of cycle time
(i.e. maximization of prodcution rate)
lower bound for cycle time c: tmax = max {tj j = 1, ... , n} … processing time of longest operation
c tmax
Maximum production amount qmax in time horizon T is given
Given number of stations m
maxqTc
mtc j
n
j 1
Layout and Design Kapitel 4 / 14(c) Prof. Richard F. Hartl
Alternative 2
lower bound for cycle time:
upper bound for cycle time
mtqTtcc j
n
j 1maxmaxmin ,,max:
minqTc
Layout and Design Kapitel 4 / 15(c) Prof. Richard F. Hartl
Alternative 3
Maximization of efficiency („Bandwirkungsgrad“)
Determination of: Cycle time c Number of stations m
Efficiency („BG“)
BG = 1 100% efficiency (no idle time)
j
n
jt
cmBG
1
1
Layout and Design Kapitel 4 / 16(c) Prof. Richard F. Hartl
Alternative 3
Lower bound for cycle time: see Alternative 2 Upper bound for cycle time cmax is given
Lower bound for number of stations
Upper bound for number of stations
max
1min : ctm j
n
j
11: maxmin1
max
tctm j
n
j
Layout and Design Kapitel 4 / 17(c) Prof. Richard F. Hartl
ExampIe
T = 7,5 hours Minimum production amount qmin = 600 units seconds/unit 45600/3600*5,7: minmax qTc
t1=6 1
1 12
10 11 3
9 3 7
7 8
2 6
4 3
5 4
..1 10
t2=9 2
4 5
Layout and Design Kapitel 4 / 18(c) Prof. Richard F. Hartl
ExampIe
Arbeitsgang j Vorgänger tj
1 - 6
2 - 9
3 1 4
4 1 5
5 2 4
6 3 2
7 3, 4 3
8 6 7
9 7 3
10 5, 9 1
11 8,1 10
12 11 1
Summe 55
tj = 55
No maximum production amount
Minimum cycle timecmin = tmax = 10 seconds/unit
m t cj
n
jmin max:
155 45 2
Layout and Design Kapitel 4 / 19(c) Prof. Richard F. Hartl
ExampIe
0
1
2
3
4
5
6
7
10 20 30 40 50 60
m BG = 1 BG = 0.982
c Combinations of m and c leading to feasible solutions.
Layout and Design Kapitel 4 / 20(c) Prof. Richard F. Hartl
ExampIe
maximum BG = 1(is reached only with invalid values m = 1 and c = 55)
Optimal BG = 0,982(feasible values for m and c: 10 c 45 und m 2)
m = 2 stations c = 28 seconds/unit
Layout and Design Kapitel 4 / 21(c) Prof. Richard F. Hartl
# Stationen m
theoretisch min Taktzeit
minimale realisierbare Taktzeit c
Bandwirkungsgrad 55/cm
1 55 nicht möglich da c 45 -
2 28 28 0,982
3 19 19 0.965
4 14 15 0,917
5 11 12 0.917
6 10 10 0,917
Example
Possible cycle times c for varying number of stations m
m55
Increasing cycle time Reduction of BG (increasing idle time) until 1 station can be omitted. BG has a local maximum for each number of stations m with the minimum cycle time c where a feasible solution for m exists.
Layout and Design Kapitel 4 / 22(c) Prof. Richard F. Hartl
Further objectives
Maximization of BG is equivalent to Minimization of total processing time („Durchlaufzeit“): D
= m c
Minimization of sum of idle times:
Minimization of ratio of idle time: LA = = 1 – BG
Minimization of total waiting time:
j
n
jtcmL
1
mc
L
LtDW j
n
j
1
Layout and Design Kapitel 4 / 23(c) Prof. Richard F. Hartl
LP formulation
We distinguish between:
LP-Formulation for given cycle time
LP-Formulation for given number of stations
Mathematical formulation for maximization of efficiency
Layout and Design Kapitel 4 / 24(c) Prof. Richard F. Hartl
LP formulation for given cycle time
Binary variables:
= number of station, where operation j is assigned to
Assumption: Graph G has only 1 sink, which is node n
otherwise0
station toassigned is operation if1 k jx jk
j = 1, ..., n
k = 1, ..., mmax
max
1
m
kjkxk
Layout and Design Kapitel 4 / 25(c) Prof. Richard F. Hartl
LP formulation for given cycle time
Objective function:
Constraints:
nk
m
kxkxZMinimiere
max
1
1max
1
m
kjkx
ctx j
n
j=jk
1
maxmax
11
m
kjk
m
khk xkxk
10,x jk
j = 1, ... , n ... j on exactly 1 station
k = 1, ... , mmax ... Cycle time
... Precedence cond.
... Binary variables
Eh,j
j and k
Layout and Design Kapitel 4 / 26(c) Prof. Richard F. Hartl
Notes
Possible extensions: Assignment restrictions (for utilities or positions)
elimination of variables or fix them to 0
Restrictions according to operations Operations h and j with (h, j) are not allowed to be assigned
to the same station.
E(h,j)xkxkm
k
m
kjkhk with 1
1 1
Layout and Design Kapitel 4 / 27(c) Prof. Richard F. Hartl
LP formulation for given number of stations
Replace mmax by the given number of stations m
c becomes an additional variable
Layout and Design Kapitel 4 / 28(c) Prof. Richard F. Hartl
LP formulation for given number of stations
Objective function: Minimize Z(x, c) = c … cycle time
Constraints:
j = 1, ... , n ... j on exactly 1 station
k = 1, ... , m ... cycle time
... precedence cond.
j und k ... binary variables
Eh,j
11
m
kjkx
ctx j
n
j=jk
1
m
kjk
m
khk xkxk
11
10,x jk
c 0 integer
Layout and Design Kapitel 4 / 29(c) Prof. Richard F. Hartl
LP formulation for maximization of BG
If neither cycle time c nor number of stations m is given take the formulation for given cycle time.
Objective function (nonlinear):
Additional constraints:c cmax
c cmin
nk
m
kxkccxZ
max
1, Minimize
Layout and Design Kapitel 4 / 30(c) Prof. Richard F. Hartl
LP formulation for maximization of BG
Derive a LP again Weight cycle time and number of stations with factors w1 and w2
Objective function (linear):
Minimize Z(x,c) = w1(kxnk) + w2c
Large Lp-models!
Many binary variables!
Layout and Design Kapitel 4 / 31(c) Prof. Richard F. Hartl
Heuristic methods in case of given cycle time
Many heuristic methods(mostly priorityrule methods)
Shortened exact methods
Enumerative methods
Layout and Design Kapitel 4 / 32(c) Prof. Richard F. Hartl
Priorityrule methods
Determine a priortity value PVj for each operations j
Prioritiy list
A non-assigned operation j can be assigned to station k if all his precedessors are already assigned to a station 1,..k and the remaining idle time in station k is equal or larger than the
processing time of operation j.
Layout and Design Kapitel 4 / 33(c) Prof. Richard F. Hartl
Priorityrule methods
Requirements: Cycle time c Operations j=1,...,n with processing times tj c
Precedence graph, defined by a sets of precedessors.
Variables k number of current station idle time of current station Lp set of already assigned operations
Ls sorted list of n operations in respect to priority value
c
Layout and Design Kapitel 4 / 34(c) Prof. Richard F. Hartl
Priorityrule methods
Operation j Lp can be assigned, if tj and h Lp is true for all h V(j)
Start with station 1 and fill one station after the other
From the list of operations ready to be assigned to the current station the highest prioritized is taken
Open a new station if the current station is filled to the maximum
c
Layout and Design Kapitel 4 / 35(c) Prof. Richard F. Hartl
Priorityrule methods
Start: determine list Ls by applying a prioritiy rule; k := 0; LP := <]; ... No operations assigned so far
Iteration:
repeat
k := k+1; := c;
while there is an operation in list Ls that can be assigned to station k do
begin
select and delete the first operation j (that can be assigned to) from list Ls;
Lp:= < Lp,j]; :=- tj
end;
until Ls = <];
Result: Lp contains a valid sorted list of operations with m = k stations.
Single-pass- vs. multi-pass-heuristics (procedure is performed once or several times)
Layout and Design Kapitel 4 / 36(c) Prof. Richard F. Hartl
Priorityrule methods
Rule 1: Random choice of operations
Rule 2: Choose operations due to monotonuously decreasing (or increasing) processing time: PVj: = tj
Rule 3: Choose operations due to monotonuously decreasing (or increasing) number of direct followers:
PVj : = (j)
Rule 4: Choose operations due to monotonuously increasing depths of operations in G:PVj : = number of arcs in the longest way from a source of the graph to j
Layout and Design Kapitel 4 / 37(c) Prof. Richard F. Hartl
Priorityrule methods
Rule 5 Choose operations due to monotonuously decreasing positional weight („Positionswert“):
Rule 6: Choose operations due to monotonuously increasing upper bound for the minimum number of stations needed for j and all it´s predecessors::
Rule 7: Choose operations due to monotonuously increasing upper bound for the latest possible station of j:
mjNh
hj tt:PVj
cttmjVh
hjjj E:PV
cttmLmjNh
hjj 1:RW j