larutan 55-58

Embed Size (px)

Citation preview

  • 7/26/2019 larutan 55-58

    1/5

    SOAL : 1 (Lanjutan)

    % - etanol P1g ml-1 V ml g -1

    0 0.997 1.003

    10 0.980 1.020

    20 0.966 1.035

    30 0.951 1.052

    40 0.932 1.073

    50 0.910 1.099

    60 0.887 1.127

    70 0.863 1.159

    80 0.839 1.192

    90 0.813 1.230

    100 0.785 1.274

    Alurkan tera!a" #rak$ &a$a etanol'

    e'ke&u!an tark ar$ $nun "a!a

    e

    0'5 (lat ra#k).

  • 7/26/2019 larutan 55-58

    2/5

    Larutan n - "ro"anol !an ar "a!a 25*+ :

    ("elarut n , "ro"anol)

    Xprop(= X1) Pprop(=P1) PH2O(=P2) i = i Xi

    0 0 23'76

    ek. a" !ala& tar. 0'02 5'05 23'5 1 =

    P

    P

    0'05 10'8 23'2

    0'10 13'2 22'7 2 =

    P

    K

    0'20 13'6 21'8

    0'40 14'2 21'7 K2 =lim

    X0

    P

    X

    0'60 15'5 19'9

    0'80 17'8 13'4

    0'90 19'4 8'13

    0'95 20'8 4'20

    1'/ 21'76 0'00

    !tanakan : oe#$en keakt"an n- "ro"anol' 1 ..

    oe#$en keakt"an ar'2 ..

    a!a #rak$ &ol n-"ro"anol : 0'20 0'40 0'60 0'80

    1 = 1X1 =

    P

    P 1 =

    P

    XP problema standar

    2= 2X2 =

    P

    K 2=

    P

    XP

    K = lim

    X0

    P

    X alurkanP

    K terhadap X2, kemudian ekstrapolasi hingga X2= 0 (lihat

    graik pada halaman berikut) K= !!,"

  • 7/26/2019 larutan 55-58

    3/5

    P#1 = 21,$%

    K2 = !!,"

    1=

    13.6

    0.20x 21.76 ( pd & X1 = 0&20 ) dst& 1= '&12 ( pd & X1= 0&20 )

    2=

    21.8

    0.80x 88.5 ( pd & X1 = 0&20 ) dst&

    2= 0&'0! ( pd & X2= 0&20)

    Hasil lengkap -

    SOAL : 2 (lanjutan)

    ata untuk ra#kP

    K tera!a"X2:

    X2 ( = XHO) P2( = PHO) P

    K

    0.05 4.20 84.0

    - 8.13 81.3

    0.28 - 67.0

    - - 49.8

    - - 36.2

    - 21.8 27.2

    0.90 22.7 25.2

    X1 1 2

    0&2

    0

    '&1

    2

    0&'0

    !

    0&

    0

    1&%

    '

    0&0

    *

    0&%

    0

    1&1

    *

    0&"%

    2

    0&!

    0

    1&0

    2

    0&$"

    $

  • 7/26/2019 larutan 55-58

    4/5

    Larutan $ukro$a' +1222 O11' !ala& ar :

    & (&olal) : 0'10 0'20 0'50 1'00 2'00

    1 (lar)

    *1(ar) + n

    1

    b : 0'188 0'380 0'980 2'060 4'600

    1 ($)

    *1($)

    Kb air = 1&!% e$et&. :

    1(lar)

    1($)

    !tanakan : (a) keakt"an' 1 ..(GT)T

    = H

    T

    () koe#$en keakt"an' 1 .. K =

    RT M

    1000 Hm ( "er$ 5&66 )

    1 (lar) 1($)

    1 (lar)

    *1(ar) + n

    1

    1 (ar) + n

    1 *1($) n 1 =

    1 ( s) 1(cair)RT

    = Gm

    RT

    T -

    (GmRT)T

    d

    -1

    R [ (Gm

    T )T

    ] d = HmRT d

  • 7/26/2019 larutan 55-58

    5/5

    d

    T

    THm

    RT d - n = Hm

    R (TT

    TT) =Hm

    R T b

    T

    arenaK =

    RT M

    1000 Hm, maka

    Hm

    RT =

    M

    1000K b

    Su$ttu$ :n = -M

    1000 K b T "role&a $tan!ar

    & 0'10 . 0'188 n - 0'001819 0'9982

    n = -18

    1000x1.86 0'188 & .b

    !$t. 0'10 0'188 0'9982

    0'20 0'380 0'9963

    0'50 0'980 0'9906

    1'00 2'060 0'9803

    2'00 4'600 0'9565