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NTTF
CONTROL SYSTEMS
LAPLACE TRANSFORMS 1
Control Systems - Laplace transforms 1 2NTTF
Forward Transformation Procedure • Transform of an Equation
– The transform of an equation is obtained by taking the transform of the expressions on each side of the equation.
• Transform of an Expression– 1. Identify the terms, which are connected by sum
(+) or difference (-) signs. – 2. Categorize the terms and take the transform of
each term.– Constant Term: Term containing only constants
and no variables of time.
Control Systems - Laplace transforms 1 3NTTF
Example• Find the Laplace transform of 12, 256, 0.25,
and 1/40
Solution
• The transformed term is represented by the constant divided by s. The corresponding terms are
Control Systems - Laplace transforms 1 4NTTF
ExampleUndefined Variable Term without Any coefficient
• Find the Laplace transform of e, x, x(t), y, and i(t).
Solution
• The transform is represented by the capital letter representing the variable, followed by s enclosed in parentheses: E(s), X(s), x(s), y(s), I(s).
Control Systems - Laplace transforms 1 5NTTF
ExampleUndefined Variable Term with Constant
Coefficient
• Term containing an undefined variable of time multiplied or divided by a constant.
• Find the Laplace transform of 10e, 0.5x, x(t)/25, 2y(t)/3
Control Systems - Laplace transforms 1 6NTTF
Solution• The transform is represented by the constant
term (as is ) followed by the capital letter representing the variable with s enclosed in paranthesis.
• The transformed terms are 10E(s), 0.5X(s), X(s)/25, 2Y(s)/3
Control Systems - Laplace transforms 1 7NTTF
ExampleDefined Variable Term without Any Constant Coefficient
• A term that is defined as a variable of time and is not multiplied or divided by a constant.
• Find the Laplace transform of sin 1Ot, t, e-20t and sin πt.
Control Systems - Laplace transforms 1 8NTTF
Solution• The Transform is determined using the
transform table. The corresponding entries from the table of transform pairs are
2222,
20
1,
1,
100
10
ssss
Control Systems - Laplace transforms 1 9NTTF
ExampleDefined Variable Term with Constant Coefficient
• A term defined as a variable of time and multiplied and/or divided by a constant.
• Find the Laplace transform of 5 sin 1Ot, 1OOt 2.5e-20t and 6 sin πt.
Control Systems - Laplace transforms 1 10NTTF
Solution• The transform of each term is the product of
the constant term and the corresponding entry from the transform table.
or
Control Systems - Laplace transforms 1 11NTTF
Example• Find the Laplace transform of each of the
following.– a. i(t)– b. v(t)– c. a– d. x
Control Systems - Laplace transforms 1 12NTTF
Solutiona. L[i(t)] = I(s)
– The Laplace transform of a function of time is indicated simply by changing the letter to uppercase and replacing t in parentheses with s.
b. Similarly, L[v(t)] = V(s).
c. L[a] = A(s)By convention, a is a function of time and can also
be expressed as a(t).
d. L[z]=Z(s)
Control Systems - Laplace transforms 1 13NTTF
Examplea. Determine the Laplace transform of t.
b. Determine the Laplace transform of t3.
Solution
a. From the Laplace transform table ,
b. From the transform table ,
Control Systems - Laplace transforms 1 14NTTF
Examplea. Determine the Laplace transform of sin 10t.
b. Determine the Laplace transform of sin t.
c. Determine the Laplace transform of cos 0.lt.
Control Systems - Laplace transforms 1 15NTTF
Example• Determine the Laplace transform of e-2t.
Solution
2
1][ 2
seL t
Therefore
Control Systems - Laplace transforms 1 16NTTF
Inverse transformation • Inverse transformation is performed to convert
the s-domain terms back to real time (time domain).
• Inverse Transform of an Equation– Inverse transformation of an equation is done by
taking the inverse transform of the expressions on each side of the equation.
Control Systems - Laplace transforms 1 17NTTF
Inverse Transformation• Inverse Transform of an Expression
– The inverse transformation process can be as simple as the forward transformation process.
– Ideally, an entry can be found in transform table that matches the problem at hand.
– It then becomes a simple matter of substitution of the terms.
– Unfortunately, it is rare to find an exact match, and some manipulation of terms is needed.
Control Systems - Laplace transforms 1 18NTTF
Inverse Transform Process• In general, the following approach is
recommended. • Identify the terms, which are connected by
sum (+) or difference (- ) signs. • Categorize the terms as follows and take the
inverse transform of each term– Constant Term: A term containing only constants
and no s term (variables of time). A purely constant term represents an impulse function in time.
Control Systems - Laplace transforms 1 19NTTF
Example• Determine the inverse Laplace transform of
1,2.5, and 10.
Solution
• The corresponding time-domain term (inverse transformation) is a product of a constant with the delta function. (See Chapter 6 for the delta/impulse function.)
• The inverse transformed terms are δ(t), 2.5δ(t), and 10δ(t).
Control Systems - Laplace transforms 1 20NTTF
Inverse Transform• In the following discussions, multiplication or
division by a constant is not considered.
• A constant coefficient does not change the forward or inverse transformation process and can be considered transparent to both.
• The only time a constant term is treated differently is when it appears on its own and not as a coefficient to another term.
Control Systems - Laplace transforms 1 21NTTF
Inverse Transform• Term Containing Division by s
– It relates to a constant term in the time domain.
Example• Determine the inverse Laplace transform of
Solution• The corresponding time-domain term in each
case is expressed by simply removing the s term from the expression: 1,256,0.25, and 1/40
Control Systems - Laplace transforms 1 22NTTF
Inverse Transform• Undefined Variable Term
– A term containing a capital letter representing an undefined variable followed by s enclosed in parentheses.
Example
• Determine the inverse Laplace transform of
Control Systems - Laplace transforms 1 23NTTF
Solution• The time-domain term is expressed as the
lowercase letter representing the variable.
• To explicitly indicate that the inverse quantity is in the time domain, it can be expressed as the lowercase variable followed by t enclosed in parentheses.
Control Systems - Laplace transforms 1 24NTTF
Inverse Transform• Other Terms Containing s
1. Find an entry in the transform table similar to the s-domain term under consideration. The entry should have identical s terms in both the numerator and denominator but can differ in the numerical constant term.
2. If no match can be found, use partial fractions to factor the s-domain term into simpler terms.
3. Manipulate the s term so that the coefficient of the s term is the same as in' a suitable entry in transform pair table. This can be done by dividing and/or multiplying both numerator and denominator by a suitable constant.
4. If necessary, take the constant terms outside the transformation (rule 1)
5. Using one-to-one correspondence with the table entry, convert the s-domain term into time domain.
Control Systems - Laplace transforms 1 25NTTF
Example• Find the inverse Laplace transform of the
following.– a. M(s)– b. P(s)– c. X(s)
Control Systems - Laplace transforms 1 26NTTF
Solution• a. L-1[M(s)] = m(t)
– Simply changing the uppercase letter to lowercase and replacing s in parentheses with t indicate the inverse Laplace transform of a function.
• b. Similarly, L-1[P(S)] = p(t).
• c. L-1[X(s)] = x(t)
Control Systems - Laplace transforms 1 27NTTF
Example• Determine the inverse Laplace transform of
Solution
• On checking the entries in Table, entry 14 is found to be a close match
Therefore, the answer is cos 10t
NTTF
Laplace Transform Pairs
Control Systems - Laplace transforms 1 29NTTF
Control Systems - Laplace transforms 1 30NTTF
Control Systems - Laplace transforms 1 31NTTF
Example• Find the inverse Laplace transform of the
following.
A. 2
B. sI(s)
C. s2X(s)+Y(s)
D. 4X(s)/s
Control Systems - Laplace transforms 1 32NTTF
Solution• A f (t) = L-1 [2]
= 2L-1 [l ]
= 2δ(t) [δ(t) is the impulse function ]
• B f (t) = L-1 [sI(s)]
= di(t)/dt
• C
D