Determination of the rate constant, the time of half-life and the activation energy of a chemical reaction GROUP B. Temperature of bath: - 298K Initial concentration of S 2 O 8 2- in the reaction mixture – 0.025 mol dm -3 Titration results: Time (min) Vt(Cm 3 ) (V ∞ - Vt) (cm 3 ) Vt/ (V ∞ - Vt) 5.17 0.3 86.8 0.003 10.1 1.1 86 0.013 15.08 0.6 86.5 0.007 20.1 0.7 86.4 0.008 30.07 1.2 85.9 0.014 40.16 1.5 85.6 0.018 50.21 1.8 85.3 0.021 Infinity 87.1
Determination of the rate constant, the time of half-life and the activation energy of a chemical reaction
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Determination of the rate constant, the time of half-life and
the activation energy of a chemical reactionGroup B.
Temperature of bath: - 298K
Initial concentration of S2O82- in the reaction mixture 0.025
mol dm-3Titration results:
Time (min)Vt(Cm3)(V - Vt) (cm3)Vt/ (V - Vt)
5.170.386.80.003
10.11.1860.013
15.080.686.50.007
20.10.786.40.008
30.071.285.90.014
40.161.585.60.018
50.211.885.30.021
Infinity87.1
Correlation Coefficient obtained by Excel 0.896139
Excel calculations of k and t :
slope3.38E-004
k6.76E-003
T1/2 s2956.48
lnk-5.00E+000
Temp298
Discussion
The plot shows a fairly linear relationship between the two
variables (Vt/ (V - Vt), time (min)). With the exception of an
outlier at t=10.1m, which may have been an experimental error
during titration. From the other student groups, it was found that
as the reaction temperature increased, the slope of the graph
increased and k decreased._1495151164.unknown
