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1
Dr. Williamson’s Kinetics Notes
Chemical Kinetics or How fast do we go!
Student versionDr. Vickie M. WilliamsonDepartment of Chemistry
Texas A&M University
Thermodynamics-vs.-Kinetics2HCl(aq) + Mg(OH)2(s) --> MgCl2(aq) + 2H2O(l)
DGo = ________C(diamond) + O2(g) --> CO2(g)
DGo = _______
• Thermodynamics: Is a reaction spontaneous (favorable)?
• Kinetics: Will it actually occur within a given time period?
Thermodynamics-vs.-KineticsIs a reaction
thermodynamicallyfavored?
_____
Is a reaction kinetically favored?
____
Reaction does not
occur without
continual energyinput
____
_____
Reaction is very
slow
Reaction occurs
2
Dr. Williamson’s Kinetics Notes
Chemical Kinetics• Study of rates of chemical reactions: how
fast reactants are __________ and products are _________ in a reaction
Reaction:
Reaction rate: Change of ______________of reactant or product per unit time
Chemical Kinetics• Study of reaction mechanisms:
sequences of elementary _______ that lead to formation of product(s)
+ +
+
+
O3 + NO O2 + NO2
Reaction mechanism: Shows how reactions occur at the ________________
#1
#2
Wide Range of Reaction Rates
Copyright © Saunders College Publishing
3
Dr. Williamson’s Kinetics Notes
Measurement of Reaction Rates
Copyright © Saunders College Publishing
Dye 1 ---> Dye 2
[dye1]
Obj: Give the rate of rxn in terms of conc. variations
• For a reaction such as2N2O5(g) ---> 4NO2(g) + O2(g)
• the rate of the reaction may be written as:
Rate of _______of concentration
of reactants
Rate of _______of concentration
of products} } }
2H2O2(l) ---> 2H2O (l) + O2(g)• Rate of rxn =
• Rate of disappearance of H2O2 _______ equal to the rate of rxn
• Rate of disap of H2O2 =
• This is _________ the rate of rxn
4
Dr. Williamson’s Kinetics Notes
2HI ---> H2 + I2• Rate of rxn =
• Rate of disap of HI =
• If given rate of disappearance of HI(say 4.2 M/s) and asked for rate of rxn
or rate of appearance of I2
• Rate of rxn =
Obj: Give the rate in terms of conc. variations
For the reaction________(g) --> ______(g) + ____ (g)∆[Br2]/∆t =
(a) (1/2) ∆[BrNO]/∆t (b) 2 ∆[BrNO]/∆t (c) - (1/2) ∆[BrNO]/∆t (d) - 2 ∆[BrNO]/∆t
Obj: Give the rate in terms of conc. variations
Which of the following is _____for the reaction:____ (g) + _____ (g) --> _____(g) +
_____(g)
(a) a ∆[A]/∆t = b ∆[B]/∆t = c ∆[C]/∆t(b) a ∆[A]/∆t = b ∆[B]/∆t = -c ∆[C]/∆t(c) (1/a) ∆[A]/∆t = (1/b) ∆[B]/∆t = (1/c) ∆[C]/∆t(d) (1/a) ∆[A]/∆t = (1/b) ∆[B]/∆t = -(1/c) ∆[C]/∆t
5
Dr. Williamson’s Kinetics Notes
Obj: Calculate average rate• Average rate: The _________ of the slope of
the reactant concentration-vs.-time curve for some ____________ D t for rxn Dye1--> Dye2
--
7.04 e-6 M/min
(M x
10-6
)
Obj: Calculate average rateFor the rxn, find the aver. rate between ___ and
_____ seconds:2 BrNO (g) --> 2 NO (g) + Br2 (g)
Time (sec) [BrNO]0 0.10 M50 0.082 M100 0.070 M
(A)_________M/s (B)__________M/
(C)_________ M/s (D) _________ M/s
(E)_________ M/s
Obj: Calculate Instantaneous rate• Instantaneous rate: The ________ of the slope of
the _______to the reacant concentration-vs.-time curve at a _____________ t for rxn Dye1--> Dye2
--
4.16 e-6 M/min at t = 3 min
(M x
10-6
)
6
Dr. Williamson’s Kinetics Notes
Obj: Calculate Initial rate• Initial rate: The negative of the slope of the
_______ to the reactant concentration-vs.-time curve at ______ for rxn Dye1--> Dye2
--
1.18 e-5 M/min = initial rate
(M x
10-6
)
C4H9Cl(aq) + H2O(l) ® C4H9OH(aq) + HCl(aq)
Ave Rate 0-800=
Ave Rate =
Inst Rate 600s=
Obj: Explain the factors that affect rxnrates
An ________ in surface area ________ the rate of a reaction
Copyright © Saunders College Publishing
7
Dr. Williamson’s Kinetics Notes
Copy
right
© S
aund
ers
Colle
ge P
ublis
hing
An _______________ in reactant concentrationgenerally ____________ the rate of a reaction
Obj: Explain the factors that affect rxn rates
Copy
right
© S
aund
ers
Colle
ge P
ublis
hing
Obj: Explain the factors that affect rxnrates
An ________ in temperature increasesthe rate of any reaction
8
Dr. Williamson’s Kinetics Notes
Obj: Explain the factors that affect rxn rates
_________ are substances added to ________the rates of reactions
Copy
right
© S
aund
ers
Colle
ge P
ublis
hing
Obj: Explain the factors that affect rxn rates
Aggie chemists have found a reaction for flubber! But the reaction is ____________. One reactant is NaCl. In order to _______ the rxn for mass production, they should:
(a) Use rock salt instead of table salt as a reactant
(b) Decrease the amount of salt (c) Conduct the experiment at high
temperatures (d) Add the appropriate catalysis
Reaction Rates:Effect of Energy and Orientation
A
C
B
Copyright ©Saunders College Publishing
9
Dr. Williamson’s Kinetics Notes
Collision Theory of Reaction Rates
• For a chemical reaction to occur:1. Reactants (molecules, atoms, or ions) _____________ with each other
2. Collisions must be effective:✶Reactants must possess _________
_____________✶Reactants must have _________
______________at time of collision
Effect of Temperature on Ea
Obj: Explain the factors that affect rxn rates
Rate directly related to • absolute temperature– Number of ____________________ increases–More molecules _____________________
• reactant concentration–More particles = more collisions
• Surface area
• Use of a catalyst– Different mechanism with ________________
_________________
10
Dr. Williamson’s Kinetics Notes
Effect of Concentration on Reaction Rate: The Rate Law
• For a general reaction:aA + bB + .... --> cC + dD + ....
the rate law has the formRate = k[A]x[B]y.....
k = _______________________x and y = reaction orders for A & Bx + y = _________ reaction order
[A] = _______________________ of A in ________• The reaction orders x and y are not necessarily
related to a, b, c, d, ...
Reaction Orders and Rate Laws• Determined from experiment, not from the net
____________ ____________• Reaction orders are usually positive or zero,
but may be fractional or negative• e.g.: For the reaction in water:
H2O2 + 3I– + 2H+ ----> 2H2O + I3–
Rate = k[H2O2][I–] (given)________order in H2O2, ______ order in I–; _______ order in H+; _______order overall
11
Dr. Williamson’s Kinetics Notes
Other Rate Laws• Experimentally observed rate laws for some
reactions are given below. What is the overall reaction orders for each?
3NO(g) --> N2O(g) + NO2(g) (given)Rate = k______
2NO2(g) + F2(g) --> 2NO2F(g) (given) Rate = k______________
CH3COCH3 + I2 --> CH3COCH2I + I-
(given)Rate = k____________________H+
For the Rate LawMeasuring the rate of a reaction
Determine the rate law
Propose a reasonable mechanism
• For multiple reactions with different beginning conc. (Experimental data )
• For each find instantaneous rate (t = 0) • Rate Law = k [A]m[B]n
• Rate Law relates the beginning conc. of reactants to speed.
• m and n are the orders
• What is the order with respect to Ba) 0.5 b) 1.5c) -0.5 d) 2.5 e) -2
rate = k [A]___
[B]____
What is the overall order of a reaction?a) -2.5 b) 2.5c) -1.5 d) 1.5
Obj: Determine the order
12
Dr. Williamson’s Kinetics Notes
For the Rate LawMeasuring the rate of a reaction
Determine the rate law
Propose a reasonable mechanism
• For multiple reactions with different beginning conc. (Experimental data )
• For each find instantaneous rate (t = 0) • Rate Law = • Rate Law relates the ______________ of
reactants to speed.• m and n are the orders
Determination of the Rate Law• Run multiple experiments: Measure _____rate as a
function of different reactant concentrations– Concentrations of species may be monitored by
pressure, spectroscopic, conductivity, other measurements
• Find the order of each reactant by comparing _____________.
• Specific rate constant (k): Calculate from reaction-rate data for _____________ of reactant concentrations
Determination of a Rate LawReaction: A + 2B --> AB2
Expt Initial Initial Initial Rate [A, M] [B, M] (AB2, M/s)
1 0.010 0.010 1.5 x 10–4
2 0.010 0.020 1.5 x 10–4
3 0.020 0.030 6.0 x 10–4
Rate Law: Rate = k[A]x[B]yFind x, y and k
13
Dr. Williamson’s Kinetics Notes
Determination of a Rate Law• Examine how the rate of reaction varies
with beginning concentration
• Expts ___ and ___: [A] fixed, [B] is ______, reaction rate is same ->rate is independent of B -> ____ order in B (y = ____)
• The rate law reduces toRate = k = k
Determination of a Rate Law• Write the rate laws for any two sets of
experiments where the concentration of only one species is varied
rate = k [A]xExpt 1: 1.5 x 10–4 = k(.01)x
Expt 3: 6.0 x 10–4 = k(.02)x
• Divide result from 1 into 3 to obtain:3 rate = k [A]x
1 rate = k [A]x
4 = _______ so x = _____• The rate law is: Rate = k[A]___
• To find the value of k, use data from any experimentExpt 3: 6.0 x 10–4 Ms–1 = k (.02 M)2
1.5 _________ = k
• The rate law for the reaction is then:Rate = 1.5 ________[A]____
Determination of a Rate Law
14
Dr. Williamson’s Kinetics Notes
Determination of a Rate LawReaction:2A + B2 + C à A2B + BC
Expt [A]o [B2]o [C]o Rate[BC]o(M) (M) (M) (M/min)
1 0.20 0.20 0.20 2.4 x 10–6
2 0.40 0.30 0.20 9.6 x 10–6
3 0.20 0.30 0.20 2.4 x 10–6
4 0.20 0.40 0.60 7.2 x 10–6
Rate Law: Rate = k[A]x[B2]y[C]z
Find x, y, z and k
Determination of a Rate LawReaction: 3A + 2B --> 2C + D
Expt. [A]o [B]o Rate [D]o(M) (M) (M/min)
1 0.010 0.010 6.0 x 10–3
2 0.020 0.030 0.144 3 0.010 0.020 0.012
Rate Law: Rate = k[A]x[B]y
Evaluate x, y and k
15
Dr. Williamson’s Kinetics Notes
Effect of Exponent When Comparing 2 Initial Rates
exponent Effect on initial rates0 No change in rate with
changing conc.1 Rate up by amount of
change in conc.___ Conc. up by 2; rate up by _____ Conc. up by 2; rate up by _____ Conc. up by 2; rate up by __
Rate order• For A + B --> C + D
The rate of the reaction increased ___-fold when A is ______ and ___-fold when B is ________. The order of the reaction is:a) 9 in A and 2 in B b) 3 in A and 2 in B c) 2 in A and 2 in B d) 2 in A and 1 in Be) 3 in A and 1 in B
16
Dr. Williamson’s Kinetics Notes
The Rate Constant k• for a ______________________• from ___________________________ • does NOT change with changes in initial
___________________• does NOT change with _________• changes with ___________• changes with whether or not a _______ is
present• units depend on the ____________ of the
reaction
The Collision Theory says:Temperature increases, the rate ____________
Typical K’s = 10-2 to 10-8
But for:H+ + OH- -> H2Ok is _______
The Rate Constant k= a measure of rxn speed
The Rate Constant k• Its units depend on the ________________ of
the reaction– If reaction is 1st order:
rate = k [A]1M/s = units on k =
– If reaction is 2nd order:rate = k [A]2M/s = units on k =
– If reaction is zero order:rate = k [A]0 or rate = units on k =
17
Dr. Williamson’s Kinetics Notes
Summary: Kinetics to Date• From equation: can get rate in terms of changes
in reactants or products• From 1 exp. (time and [ ] data) and equation:– Can get average rate between 2 times– Can get instanteous rate for a specfic time
from tangent line• From multiple experiments using different initial
concentrations: use conc. and initial rates (initial rate from time and [ ] data)– Can get rate law (rate based on initial conc.),
order of rxn, value for rate const.
Concentration-vs.-Time:The Integrated Rate Equation
• The integrated rate equation relates ________________as a function of time
• It allows determination of _________ and __________ at some specified time
• It allows for the evaluation of half-life (t1/2),the time it takes for half of reactants to be converted to products
• The integrated rate equation and t1/2 depend on the overall ______________
Half-Life
18
Dr. Williamson’s Kinetics Notes
Zero-Order Reactions• The rate law for a zero-order reaction is:
Rate = k[A]0 = k(1) or Rate = _____• The integrated rate law for this reaction
is:
y = m x + b
See math
Zero-Order Reaction:[A]-vs.-Time Plot
[A]0
[A]
t
D [A]
D tSlope = D[A] = –ak
Dt
Zero Order Half-Life[A] =
MT only uses integrated rate equations where a =1. Some books, as yours, ignore �a�, but only use chemical equations where the coefficient is 1. Other books stating that it is wrapped into k. I will use �a�.
19
Dr. Williamson’s Kinetics Notes
First-Order Reactions• The rate law for a first-order reaction
(aA-->B) is:Rate = k[A]1 = k______
• The integrated rate law for this reaction is:
y = m x + b
=
See Math
First-Order Reaction:[A]-vs.-Time Plot
ln [A]0
ln [A]
t
D ln [A]
D t
Slope = D ln[A] = –akDt
Second-Order Reactions• The rate law for a second-order reaction
is:Rate = k____
• The integrated rate law for this reaction is:
y = m x + b
See math
20
Dr. Williamson’s Kinetics Notes
Second-Order Reaction:[A]-vs.-Time Plot
1/[A]0
1 [A]
t
Slope = D1/[A] = akDt
1 [A]D
D t
Summary of Relationships for Various Reaction Orders
for aA--> products (a=coeficient)
M/s or M s-1
s-1 or 1/s
s-1 M-1or 1/(s•M)
Use graphing to determine order!
-ak
-ak
ak
[A] = -akt + [A]o
a Reactant à products
RateEqu
Straight Line with
Integrated Equation
Slope k units
[A] vs t
ln[A] vs t
1 vs t[A]
k[A]0
k[A]1
k[A]2
Order
0
1
2 1 = akt + 1[A] [A]o
ln[A] = -akt + ln[A]o
Intercept?
Equations Given1 1 ln[A] = -akt + ln [A]0
[A] = akt + [A]o
[A]o = t1/2 [A] = -akt + [A]0
2ak
0.693 = t1/2 1 = t1/2
ak ak[A]o
21
Dr. Williamson’s Kinetics Notes
Order from Graphs
A B
C D
• Which is 2nd order?• Which is zero order?• Which is 1st order?
E
Using the Integrated Rate Equation• The gas-phase reaction:
2N2O5 --> 2N2O4 + O2obeys first-order kinetics with k = 0.00840s–1 at a certain temperature.
If 2.50 moles of N2O5 are placed in a 5.00-L container, we can calculate the number of moles N2O5 left after one minute
22
Dr. Williamson’s Kinetics Notes
Using the Integrated Rate Equation• Use the first-order integrated rate equation in the
form:ln [N2O5] = – akt + ln [N2O5]o
• where: [N2O5]o =______________________k = 0.00840s–1
t = ________(the units on t and k must be =)a = 2
• ln [N2O5] = – akt + ln [N2O5]o= – 2(0.00840s–1)(60s) + ln 0.500
=• [N2O5] = ____________M• mol N2O5 = 5.00 L x _________mol/L = _____ mol
• MT only uses integrated rate equations where a =1. Some books, as yours, ignore �a�, but only use chemical equations where the coefficient is 1. Other books stating that it is wrapped into k. I will use �a�.
• For practice when a = 2, 3, …. See our homepage under �frequently asked questions� and �kinetics�. There are two sets of problems with solutions for your practice.
• Read about the integrated rate laws using ‘a’ from the pdf on the protected page.
• http://chemed.tamu.edu/chem102
Transition State Theory• Chemical reactions involve the breaking
and forming of bonds; energy is needed to break bonds
• Activation energy, Ea: Minimum energy reactants must have to form the activated complex
• There is an energy of activation for both ____________ and ______________ reactions
• Reaction rates ______________ due to differences in activation energies
23
Dr. Williamson’s Kinetics Notes
ActivatedComplex
Transition State TheoryEn
ergy
Progress of a Reaction
Ea,f
Ea,r
DEreaction
ReactantsA + B2
ProductsAB + BDEreaction = Ea,f – Ea,r
A– –B– –B
Obj. Read Energy Profile
A + B
Ener
gy (J
)
Progress of a Reaction
C + D
175
100
20
Find _____ a) 80 J b) -100 Jc) -75 J d) -80 J
Find of reverse rxna) -155 J b) -75 Jc) 75 J d) 80 Je) -80J
Find Ea ________________a) 155 J b) 100 Jc) 75 J d) 80 J
Find ________________a) 155 J b) 100 Jc) 75 J d) 80 J
Obj. Read Energy Profile
A + BEner
gy (J
)
Progress of a Reaction
C + D
150
100
15
Find_________a) 150 Jb) 135 Jc) 85 Jd) 50 J
Find __________________a) 135 J b) 100 Jc) 50 J d) 85 J
24
Dr. Williamson’s Kinetics Notes
Transition State Theory
Copyright © Saunders College Publishing
Transition State Theory
Copyright © Saunders College Publishing
Transition State Theory• Magnitude of Ea cannot be predicted from
the enthalpy of reaction_________
• Increasing the ___________ increases the rate of reaction by increasing the fraction of molecules that can overcome the activation barrier
• Catalyst increases reaction rate by _______________the activation barrier
25
Dr. Williamson’s Kinetics Notes
Effect of a Catalyst on a Reaction
26
Dr. Williamson’s Kinetics Notes
Effect of a Catalyst
Decreases Activation Energy2H2O2(aq) --> 2 H2O(l) + O2(g)
.)
Catalyzed and Uncatalyzed Rxn
Ener
gy (J
)
Progress of a Reaction
C + D
150
100
15
Find_______ of the __________ ________ rxna) b) c) d) e)
Find _______of ____________________rxna) b) c) d) e)
A + B
125
The Arrhenius Equation• The Arrhenius equation is:
k = Ae–Ea/RT
wherek = specific rate constantA = frequency factor based on geometryEa = activation energyR = 8.314 J/mol.KT = absolute temperaturee–Ea/RT = fraction of molecules having min. energy to react
27
Dr. Williamson’s Kinetics Notes
Evaluation of Ea• Take an ln of both sides to get:
ln k = ln A + ln e–Ea/RT
ln k = ln A -Ea/RTFinally for the equation of a line:ln k = - Ea/R 1/T + ln A
y = Determine rate constants at two different temperaturesSolve for Ea:
Graphical Determination of Ea
ln A
ln k
1/T (K–1)
Slope = – Ea/R
ln k = - Ea/R 1/T + ln A
Obj: Determine Ea• Find Ea for the rxn V--> W if
k1 = ______ e-3 s-1T1= 700. Kk2 = ______ e-3 s-1 T2 = 900. K
a) 36.3 kJb) 5.29 e-5 Jc) 0.106 Jd) 105 kJ R = 8.314 J/mol*K
R = 0.0821 L*atm/mol*K
28
Dr. Williamson’s Kinetics Notes
Reaction Mechanism• Reaction mechanism: sequence of elementary steps that leads to formation of products
• Sum of elementary steps = ____________• Steps show bonds breaking and making to
form products• Most chemical reactions occur in a series of
elementary steps, but can be _________• If a series, one step will be slower =
______________
Elementary Steps• Elementary reaction: single event at the
molecular level• For an elementary step, reaction order equals
the number of reactant molecules (the coefficient)
• Unimolecular: one-molecule reactionBr2 --> 2Br
• Bimolecular: two-molecule reactionO3 + NO --> O2 + NO2
• Termolecular: three-molecule reaction A + B + C --> PA + A + C --> P
Guidelines in Constructing Reaction Mechanisms
• Overall equation is:2NO2Cl -->2NO2 + Cl2
• Elementary steps must add up to give overall equation:
NO2Cl --> NO2 + ClNO2Cl + Cl --> NO2 + Cl2
29
Dr. Williamson’s Kinetics Notes
Rules for Rate Laws• Rate law for an overall equation does not
include _____________, but can include products if mechanism dictates.
• Rate law for an overall equation comes from _________________or from the __________________ NOT from _______________
• Rate Law for a step in a mechanism _____ be read from the _____________
Reaction Mechanism• Mechanism: (1) A + B --> 2C
(2) 2C + A --> D(3) D --> E + F
Net reaction:• Rate Law for a step in a mechanism CAN
be read from stoichiometry!!– So rate of step 1 = – So rate of step 2 =– So rate of step 3 =
• Substances formed, then consumed are _______________
Reaction Mechanisms
Copyright © 1995 by Saunders College Publishing
From experimentNO2(g)+ CO(g)--> NO(g)+ CO2(g)
Exp rate law = k [NO2]2Is this one-step mechanism for the reaction possible? What rate law would it give?
30
Dr. Williamson’s Kinetics Notes
Evidence for a Mechanism:Isotope Labeling
NO2(g)+ CO(g)--> NO(g)+ CO2(g)
Copyright © 1995 by Saunders College Publishing
Two-step mechanism for the reaction:
(slow)
(fast)
The Rate-Determining Step(RDS)• The slowest step in a mechanism• Reaction: NO2(g) + CO(g) --> NO(g) + CO2(g)
From experiment: Rate = k[NO2]2• Proposed two-step mechanism:
NO2(g) + NO2(g) --> NO3(g) + NO(g) (slow)NO3(g) + CO(g) --> NO2(g) + CO2(g) (fast)
would give this overall equation and rate:
Rate = k________• If first step in mechanism is rds (is slow), then
observed rate law is rate law for rds
Guidelines in Constructing Reaction Mechanisms
• Mechanism must be consistent with the experimental rate lawE.g. 2NO2 + F2 --> 2NO2F
Exp. Rate law: Rate =Is mechanismpossible?
NO2 + F2 --> NO2F + F (slow)NO2 + F --> NO2F (fast)
The rate law from the mechanism is:Rate =
31
Dr. Williamson’s Kinetics Notes
Guidelines in Constructing Reaction Mechanisms
• Elementary steps must be physically reasonable; unless evidence exists, select bimolecular over termolecular steps
• E.g.: 2NO2 + F2 --> 2NO2FExp. Rate law: Rate =k[NO][F2]
• Is a 1 step mechanism possibleNO2 + NO2 + F2 --> 2NO2F
not likely since termolecular reactions are rare. • The 1-step mechanism gives Rate = k____ _____ • SO is it possible?
Selecting a Reaction Mechanism2NO + H2 --> N2O + H2O
Expt. [NO] [H2] Initial Rate(M/s)
1 0.1 M 0.1 M ______2 0.5 M 0.5 M ______3 0.5 M 0.1 M _______
Rate law : Rate = k[NO]x[H2]y
A. Rate = k[NO]2[H2]0 B. Rate = k[NO]2[H2]1
C. Rate = k[NO]0[H2]2 D. Rate = k[NO]5[H2]1
Selecting a Reaction Mechanism2NO + H2 --> N2O + H2O obs. Rate =_____ A. NO + H2 --> H2NO slow
H2NO + NO --> N2O + H2O fastB.2NO --> N2O2 slow
N2O2 + 2H2 --> 2N2O + H2O + 2H+ fast C. 2NO --> N2O + O slow
O + H2 --> H2O fastD.2NO + H2 --> N2(OH)2 slow
N2(OH)2 --> N2 + H2O2 fast E.2NO + H2 --> N2O + OH2 slow
OH2 --> H2O fast
32
Dr. Williamson’s Kinetics Notes
Mechanism with Fast Initial Step• Reaction: 2NO + Br2 --> 2NOBr
From experiment: Rate = k[NO]2[Br]
• Proposed two-step mechanism:
NO + Br2 <--> NOBr2 (fast, eq)NOBr2 + NO --> 2NOBr (slow, rds)
• Is this mechanism consistent with observed rate law?
Mechanism: Consistency CheckNO + Br2 <--> NOBr2 (fast, eq)NOBr2 + NO --> 2NOBr (slow, rds)
• Rate law from slow step:Rate2 = k2[NOBr2][NO] BUT it contains an intermediate, which can�t be in the overall rate
• For equilibrium step(initial fast step): ratef = rater
kf[NO][Br2] =[NOBr2] =
• Now sub into slow step for [NOBr2] Rate2 = k2 [NO]
Rateo = k
Sample Problem• The proposed mechanism for the
reaction between H2 and CO is:H2 <--> 2H (fast, eq)H + CO --> HCO (slow)H + HCO --> HCHO (fast)
• Write the balanced overall equation• The observed rate-dependence is
_____order in H2 and ___ order in CO. Is this mechanism plausible?A. Yes B. No
33
Dr. Williamson’s Kinetics Notes
Catalyst• Substance added to __________ the
reaction rate without being _____________in reaction (does not appear in the balanced equation)
• ________________ both forward and reverse reactions
• Is part of the ___________• Lowers the __________________ by
providing a different reaction ________________
Homogeneous Catalysis• Catalyst exists in same phase as reactants
(solid, liquid, gas, aqueous)• Oxidation of Ce4+ catalyzed by Mn2+ -all
substances are aqueous :Net: 2 Ce4+ + Tl+ --> 2Ce3+ + Tl3+
Steps: Ce4+ + Mn2+ --> Ce3+ + Mn3+
Ce4+ + Mn3+ --> Ce3+ + Mn4+
Tl+ + Mn4+ --> Tl3+ + Mn2+
A catalysts is first a ________, then a ___________in the mechanism steps
Recognizing Various Speciesin a Reaction Mechanism
• ___________: More consumed than formed• ____________: More formed than consumed• _________: Formed in an early step and entirely
consumed in later step(s)• _____________: Consumed in an early step
(reactant )and entirely regenerated as a ____________ in later step(s)
Ce4+ + Mn2+ --> Ce3+ + Mn3+Ce4+ + Mn3+ --> Ce3+ + Mn4+
Tl+ + Mn4+ --> Tl3+ + Mn2+
34
Dr. Williamson’s Kinetics Notes
Heterogeneous Catalysis• Catalyst present in _____________ from
reactants
• Usually _______; provide surfaces on which reactions occur
• The larger the surface area, the more _____________the catalyst
• When solid catalyst employed, reactions usually follow ____-order kinetics
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Heterogeneous Catalysts at WorkCatalytic Converters
Heterogeneous Catalysis at Work• The catalytic converter in automobile exhaust
systems uses noble metals and transition metal oxides (Pt/NiO) to catalyze the following reactions:2C8H18(g) + 25O2(g) --> 16CO2(g) + 18H2O(g)2CO(g) + O2(g) --> 2CO2(g)2NO(g) --> N2(g) + O2(g)
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Dr. Williamson’s Kinetics Notes
Catalytic NO à N2 + O2 Conversion
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• Proteins in living systems that catalyze veryspecific biochemical reactions
• Function as both homogeneous and heterogeneous catalyst
• Increase rates by 108 to 1020 times• Mechanism of enzyme catalysis:
E + S --> ES (fast, reversible)ES --> E + P (slow, rds)
E = enzyme (catalysis); S = substrate (reactant)
Enzymes: Biological Catalysts
Mechanism of Enzyme Action
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Dr. Williamson’s Kinetics Notes
• In the presence of Enzyme, the reaction:Substrate --> Product
occurs by 3 stepsE + S --> ES (fast, reversible)
ES --> EP (slow)EP --> E + P (fast)
The ______________for this reaction is:(a) (b) (c) (d)
Enzymes: Biological Catalysts
Reaction Mechanisms:A Closer Look
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What is the Rate Law?Elementary Steps:
1. O3 <---> O2 + O ________2. O + O3 ---> 2O2 ________
Rate = ? RXN 2O3 ---> 3O2
(A) k (B) k (C) k (D) k (E) k
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Dr. Williamson’s Kinetics Notes
Kinetics Equations1 1 ln[A] = -akt + ln [A]0[A] = akt + [A]o
[A]o = t1/2 [A] = -akt + [A]0 0.693 = t1/22ak ak1 = t1/2
ak[A]o lnk = -Ea/R (1/T) + ln A
ln k1 = Ea [ 1 - 1 ]k2 R [ T2 T1 ]