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J ournal of M athematical I nequalities With Compliments of the Author JMI-09-84 1093–1114 Zagreb, Croatia Volume 9, Number 4, December 2015 A. Matkovi´ c, J. Pe ˇ cari´ c and J. Peri´ c A renement of the Jessen-Mercer inequality and a generalization on convex hulls in R k

Journal of Mathematical InequalitiesJournal of Mathematical Inequalities With Compliments of the Author JMI-09-84 1093–1114 Zagreb, Croatia Volume 9, Number 4, December 2015 A. Matkovi´c,

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  • Journal ofMathematical

    Inequalities

    With Complimentsof the Author

    JMI-09-84 1093–1114

    Zagreb, Croatia Volume 9, Number 4, December 2015

    A. Matković, J. Pečarić and J. Perić

    A refinement of the Jessen-Mercer inequality and ageneralization on convex hulls in Rk

  • JOURNAL OF MATHEMATICAL INEQUALITIES

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  • Journal ofMathematical

    Inequalities

    Volume 9, Number 4 (2015), 1093–1114 doi:10.7153/jmi-09-84

    A REFINEMENT OF THE JESSEN–MERCER INEQUALITY

    AND A GENERALIZATION ON CONVEX HULLS IN Rk

    A. MATKOVIĆ, J. PEČARIĆ AND J. PERIĆ

    (Communicated by S. Varošanec)

    Abstract. A refinement of the Jessen-Mercer inequality is obtained and shown to be an improve-ment of the upper bound for the Jessen’s difference given in [12]. Also a generalization ofthe Jessen-Mercer inequality for convex functions on convex hulls in Rk is given and demon-strated to be an improvement of the inequalities obtained in [3]. An elegant method of producingn -exponentially convex and exponentially convex functions is applied using the Jessen-Mercerdifferences. Lagrange and Cauchy mean value type theorems are proved and shown to be usefulin studying Stolarsky type means defined by using the Jessen-Mercer differences.

    1. Introduction

    Let E be a nonempty set and L be a subspace of the vector space RE over Rwhich contains 1 , that is L having following properties

    L1: f ,g ∈ L ⇒ (α f + βg) ∈ L for all α,β ∈ R ;L2: 1 ∈ L , i.e., if f (t) = 1 for t ∈ E , then f ∈ L .If L additionally has propertyL3: (∀ f ,g ∈ L) (min{ f ,g} ∈ L∧max{ f ,g} ∈ L) ,

    then it is a lattice. Obviously,(R

    E ,�)

    (with standard ordering) is a lattice. It canalso be easily verified that a subspace X ⊆ RE is a lattice if and only if x ∈ X implies|x| ∈ X . This is a simple consequence of the fact that for every x ∈ X the functions |x| ,x− and x+ can be defined by

    |x|(t) = |x(t)| , x+ (t) = max{0,x(t)} , x− (t) = −min{0,x(t)} , t ∈ E,and x+ + x− = |x| , x+− x− = x ,

    min{x,y} = 12

    (x+ y−|x− y|) , max{x,y} = 12

    (x+ y+ |x− y|) . (1.1)

    We consider positive linear functionals A : L → R , i.e., functionals having propertiesA1: A(α f + βg) = αA( f )+ βA(g) for f ,g ∈ L , α,β ∈ R (linearity);A2: f ∈ L , f (t) � 0 on E ⇒ A( f ) � 0 (positivity).Mathematics subject classification (2010): 39B62, 26D15.Keywords and phrases: Jessen-Mercer inequality, convex functions, convex hulls, n -exponential con-

    vexity, Stolarsky type means.This work has been fully supported by Croatian Science Foundation under the project 5435.

    c© � � , ZagrebPaper JMI-09-84

    1093

    http://dx.doi.org/10.7153/jmi-09-84

  • 1094 A. MATKOVIĆ, J. PEČARIĆ AND J. PERIĆ

    If A additionally satisfies the condition A(1) = 1, then it is normalized.Throughout the paper when using interval [m,M] we assume that −∞ < m < M <

    ∞.The following result is a variant of the well known Jessen’s inequality [6] (see also

    [14, p. 47]) of Mercer’s type [10] proved in [3]. We call it the Jessen-Mercer inequality.

    THEOREM A. Let L satisfy L1 , L2 on a nonempty set E , and let A be a positivenormalized linear functional. If ϕ is a continuous convex function on [m,M] , then forall f ∈ L such that ϕ ( f ) , ϕ (m+M− f ) ∈ L (so that m � f (t) � M for all t ∈ E) ,we have

    ϕ (m+M−A( f )) � ϕ (m)+ ϕ (M)−A(ϕ ( f )) . (1.2)

    REMARK 1. In fact, to be more specific, the following series of inequalities wasproved

    ϕ (m+M−A( f )) � A(ϕ (m+M− f ))

    � M−A( f )M−m ϕ(M)+

    A( f )−mM−m ϕ(m) (1.3)

    � ϕ (m)+ ϕ (M)−A(ϕ ( f )) .

    Furthermore, if the function ϕ is concave, inequalities (1.2) and (1.3) are reversed.

    The reversed Jensen inequality follows easily from Jensen’s inequality (see [14]).

    THEOREM B. Let pppp be a real n-tuple such that

    p1 > 0, pi � 0(i = 2, . . . ,n), Pn > 0

    where Pn =n

    ∑i=1

    pi . Let U be a convex set in a real vector space M , xxxxi ∈U (i = 1, . . . ,n)

    and1Pn

    n

    ∑i=1

    pixxxxi ∈U . If f : U → R is a convex function, then

    f

    (1Pn

    n

    ∑i=1

    pixxxxi

    )� 1

    Pn

    n

    ∑i=1

    pi f (xxxxi). (1.4)

    Recently, M. Klaričić Bakula et al. [8] obtained the following refinement of theconverse Jessen’s inequality [1] (see also [14, p. 98]).

    THEOREM C. Let L satisfy L1 , L2 , L3 on a nonempty set E , and let A be apositive normalized linear functional. If ϕ is a convex function on [m,M] then for allg ∈ L such that ϕ (g) ∈ L we have A(g) ∈ [m,M] and

    A(ϕ (g)) � M−A(g)M−m ϕ (m)+

    A(g)−mM−m ϕ (M)−A(g̃)δϕ , (1.5)

  • THE JESSEN-MERCER INEQUALITY AND CONVEX HULLS 1095

    where

    g̃ =12− 1

    M−m∣∣∣∣g− m+M2

    ∣∣∣∣ , δϕ = ϕ (m)+ ϕ (M)−2ϕ(m+M2)

    .

    Using inequality (1.5) and the following Lemma we will refine the series of in-equalities (1.3) .

    LEMMA 1. Let φ be a convex function on U where U is a convex set in Rk ,

    (xxxx1, . . . ,xxxxn) ∈ Un and pppp = (p1, . . . , pn) is nonnegative n-tuple such thatn

    ∑i=1

    pi = 1 .

    Then

    min{p1, . . . , pn}[

    n

    ∑i=1

    φ(xxxxi)−nφ(

    1n

    n

    ∑i=1

    xxxxi

    )]

    �n

    ∑i=1

    piφ(xxxxi)−φ(

    n

    ∑i=1

    pixxxxi

    )(1.6)

    � max{p1, . . . , pn}[

    n

    ∑i=1

    φ(xxxxi)−nφ(

    1n

    n

    ∑i=1

    xxxxi

    )]. (1.7)

    Proof. This is a simple consequence of [11, p. 717, Theorem 1]. �

    2. Refinement of the Jessen-Mercer inequality

    Next two theorems are our main results.

    THEOREM 1. Let L satisfy L1 , L2 , L3 on a nonempty set E , and let A be apositive normalized linear functional. If ϕ is a continuous convex function on [m,M] ,then for all f ∈ L such that ϕ ( f ) , ϕ (m+M− f ) ∈ L, we have

    ϕ (m+M−A( f )) � A(ϕ(m+M− f ))

    � M−A( f )M−m ϕ (M)+

    A( f )−mM−m ϕ (m)−A

    (12− 1

    M−m∣∣∣∣ f−m+M2

    ∣∣∣∣)δϕ� ϕ (m)+ ϕ (M)−A(ϕ ( f ))−

    [1− 2

    M−mA(∣∣∣∣ f − m+M2

    ∣∣∣∣)]δϕ� ϕ (m)+ ϕ (M)−A(ϕ ( f )) ,

    where

    δϕ = ϕ (M)+ ϕ (m)−2ϕ(

    M +m2

    ). (2.1)

  • 1096 A. MATKOVIĆ, J. PEČARIĆ AND J. PERIĆ

    Proof. Using the first inequality from the series (1.3) and applying inequality(1.5) first to the function m+M− f , and then to the function f , we obtain

    ϕ (m+M−A( f ))� A(ϕ(m+M− f ))

    � M−A( f )M−m ϕ (M)+

    A( f )−mM−m ϕ (m)−A

    (12− 1

    M−m∣∣∣∣ f − m+M2

    ∣∣∣∣)δϕ= ϕ (m)+ϕ (M)−

    [M−A( f )

    M−m ϕ (m)+A( f )−m

    M−m ϕ (M)]−A(

    12− 1

    M−m∣∣∣∣ f−m+M2

    ∣∣∣∣)δϕ� ϕ (m)+ ϕ (M)−A(ϕ ( f ))−2A

    (12− 1

    M−m∣∣∣∣ f − m+M2

    ∣∣∣∣)δϕ= ϕ (m)+ ϕ (M)−A(ϕ ( f ))−

    [1− 2

    M−mA(∣∣∣∣ f − m+M2

    ∣∣∣∣)]δϕ ,� ϕ (m)+ ϕ (M)−A(ϕ ( f )) .

    The last inequality is a simple consequence of the easily provable facts that δϕ =ϕ (M)+ ϕ (m)−2ϕ (M+m2 )� 0 and 1− 2M−mA(∣∣ f − m+M2 ∣∣)� 0. �

    THEOREM 2. Let L satisfy L1 , L2 , L3 on a nonempty set E , and let A be apositive normalized linear functional. If ϕ is a continuous convex function on [m,M] ,then for all f ∈ L such that ϕ ( f ) , ϕ (m+M− f ) ∈ L, we have

    ϕ (m+M−A( f ))

    � M−A( f )M−m ϕ (M)+

    A( f )−mM−m ϕ (m)−

    (12− 1

    M−m∣∣∣∣A( f )− m+M2

    ∣∣∣∣)δϕ� ϕ (m)+ϕ (M)−A(ϕ( f ))−

    [1− 1

    M−m(

    A

    (∣∣∣∣ f−m+M2∣∣∣∣)+ ∣∣∣∣A( f )−m+M2

    ∣∣∣∣)]δϕ� ϕ (m)+ ϕ (M)−A(ϕ( f ))−

    [1− 2

    M−mA(∣∣∣∣ f − m+M2

    ∣∣∣∣)]δϕ� ϕ (m)+ ϕ (M)−A(ϕ ( f )) ,

    where δϕ is defined as in (2.1).

    Proof. Theorem C for the function f gives us

    A(ϕ( f )) � M−A( f )M−m ϕ (m)+

    A( f )−mM−m ϕ (M)−A

    (12− 1

    M−m∣∣∣∣ f − m+M2

    ∣∣∣∣)δϕ .(2.2)

    Let the functions p,q : [m,M] → [0,1] be defined by

    p(t) =M− tM−m , q(t) =

    t−mM−m .

  • THE JESSEN-MERCER INEQUALITY AND CONVEX HULLS 1097

    For any t ∈ [m,M] we can write

    ϕ(t) = ϕ(

    M− tM−mm+

    t−mM−mM

    )= ϕ(p(t)m+q(t)M).

    By Lemma 1 for n = 2 it follows

    ϕ(t) � p(t)ϕ (m)+q(t)ϕ (M)−min{p(t) ,q(t)}δϕ ,where δϕ = ϕ (M)+ ϕ (m)−2ϕ

    (M+m

    2

    ). Using (1.1) we can write it in the form

    ϕ(t) � M− tM−mϕ (m)+

    t−mM−mϕ (M)−

    (12− 1

    M−m∣∣∣∣t− m+M2

    ∣∣∣∣)δϕ .Substituting t ↔ A(g) , where g ∈ L such that A(g) ∈ [m,M] , we get

    ϕ(A(g)) � M−A(g)M−m ϕ (m)+

    A(g)−mM−m ϕ (M)−

    (12− 1

    M−m∣∣∣∣A(g)− m+M2

    ∣∣∣∣)δϕ .(2.3)

    Now, applying inequality (2.3) on g = m+M− f (and using linearity and normalityof A), and then using inequality (2.2) , we have

    ϕ (m+M−A( f ))

    � M−A( f )M−m ϕ (M)+

    A( f )−mM−m ϕ (m)−

    (12− 1

    M−m∣∣∣∣A( f )− m+M2

    ∣∣∣∣)δϕ= ϕ (m)+ ϕ (M)−

    [M−A( f )

    M−m ϕ (m)+A( f )−mM−m ϕ (M)

    ]−(

    12− 1

    M−m∣∣∣∣A( f )− m+M2

    ∣∣∣∣)δϕ� ϕ (m)+ ϕ (M)−A(ϕ( f ))

    −A(

    12− 1

    M−m∣∣∣∣ f − m+M2

    ∣∣∣∣)δϕ −(12 − 1M−m∣∣∣∣A( f )− m+M2

    ∣∣∣∣)δϕ= ϕ (m)+ ϕ (M)

    −A(ϕ( f ))−[1− 1

    M−m(

    A

    (∣∣∣∣ f − m+M2∣∣∣∣)+ ∣∣∣∣A( f )− m+M2

    ∣∣∣∣)]δϕ� ϕ (m)+ ϕ (M)−A(ϕ( f ))−

    [1− 2

    M−mA(∣∣∣∣ f − m+M2

    ∣∣∣∣)]δϕ .The last inequality is obtained applying Jessen’s inequality to the continuous and con-vex function |x| so that∣∣∣∣A( f )− m+M2

    ∣∣∣∣= ∣∣∣∣A( f − m+M2)∣∣∣∣� A(∣∣∣∣ f − m+M2

    ∣∣∣∣) . �Using Theorem2 we can get an upper bound for the difference A(ϕ ( f ))−ϕ (A( f ))

    obtained in [12].

  • 1098 A. MATKOVIĆ, J. PEČARIĆ AND J. PERIĆ

    COROLLARY 1. Let L satisfy L1 , L2 , L3 on a nonempty set E , and let A be apositive normalized linear functional. If ϕ is a continuous convex function on [m,M] ,then for all f ∈ L such that ϕ ( f ) ,ϕ (m+M− f ) ∈ L, we have

    A(ϕ ( f ))−ϕ (A( f )) � 1M−m

    (A

    (∣∣∣∣ f − m+M2∣∣∣∣)+ ∣∣∣∣A( f )− m+M2

    ∣∣∣∣)δϕ ,where δϕ is defined as in (2.1).

    Proof. Theorem 2 gives us

    A(ϕ ( f )) �ϕ (m)+ ϕ (M)−ϕ (A( f )−m+M)

    −[1− 1

    M−m(

    A

    (∣∣∣∣ f − m+M2∣∣∣∣)+ ∣∣∣∣A( f )− m+M2

    ∣∣∣∣)]δϕ . (2.4)Since the function ϕ is convex, it follows

    ϕ (m+M−A( f ))+ ϕ (A( f )) � 2ϕ(

    M +m2

    ). (2.5)

    Combining inequalities (2.4) and (2.5) we obtain

    A(ϕ ( f ))−ϕ (A( f ))�ϕ (m)+ ϕ (M)− [ϕ (m+M−A( f ))+ ϕ (A( f ))]

    −[1− 1

    M−m(

    A

    (∣∣∣∣ f − m+M2∣∣∣∣)+ ∣∣∣∣A( f )− m+M2

    ∣∣∣∣)]δϕ�ϕ (m)+ ϕ (M)−2ϕ

    (M +m

    2

    )−[1− 1

    M−m(

    A

    (∣∣∣∣ f − m+M2∣∣∣∣)+ ∣∣∣∣A( f )− m+M2

    ∣∣∣∣)]δϕ=

    1M−m

    (A

    (∣∣∣∣ f − m+M2∣∣∣∣)+ ∣∣∣∣A( f )− m+M2

    ∣∣∣∣)δϕ . �3. Generalization on convex hulls in Rk

    We present a generalization of the Jessen-Mercer inequality for convex functionson convex hulls in Rk .

    Convex hull of vectors xxxx1, . . . ,xxxxn ∈ Rk is the set{n

    ∑i=1

    αixxxxi|αi ∈ R,αi � 0,n

    ∑i=1

    αi = 1

    }

    and it is represented by K = co({xxxx1, . . . ,xxxxn}) .

  • THE JESSEN-MERCER INEQUALITY AND CONVEX HULLS 1099

    Barycentric coordinates over K are continuous real functions λ1, . . . ,λn on K withthe following properties:

    λi(xxxx) � 0, i = 1, ...,nn

    ∑i=1

    λi(xxxx) = 1

    xxxx =n

    ∑i=1

    λi(xxxx)xxxxi. (3.1)

    If xxxx2 − xxxx1, . . . ,xxxxn − xxxx1 are linearly independent vectors, then each xxxx ∈ K can bewritten in the unique way as a convex combination of xxxx1, . . . ,xxxxn in the form (3.1) .

    We also consider k -simplex S = co({vvvv1,vvvv2, . . . ,vvvvk+1}) in Rk which is a convexhull of its vertices vvvv1, . . . ,vvvvk+1 ∈Rk , where vertices vvvv2−vvvv1, . . . ,vvvvk+1−vvvv1 ∈Rk are lin-eary independent. In this case we denote k -simplex by S = [vvvv1, . . . ,vvvvk+1] . Barycentriccoordinates λ1,λ2, . . . ,λk+1 over S are nonnegative linear polynomials on S and havea special form (see [2]).

    With Lk we denote the linear class of functions gggg : E → Rk defined bygggg(t) = (g1(t), . . . ,gk(t)), gi ∈ L (i = 1, . . . ,k).

    For a given linear functional A , we also consider linear operator à = (A, . . . ,A) : Lk →R

    k defined byÃ(gggg) = (A(g1), . . . ,A(gk)). (3.2)

    If A(1) = 1 is satisfied, then using (A1) we also haveA3: A( f (gggg)) = f (Ã(gggg)) for every linear function f on Rk .For n ∈ N we denote

    Δn−1 =

    {(μ1, . . . ,μn) : μi � 0, i ∈ {1, . . . ,n},

    n

    ∑i=1

    μi = 1

    }.

    Also, if ϕ is a function defined on a convex subset U ⊆Rk and xxxx1,xxxx2, . . . ,xxxxn ∈U ,we denote

    Snϕ(xxxx1, . . . ,xxxxn) =n

    ∑i=1

    ϕ(xxxxi)−nϕ(

    1n

    n

    ∑i=1

    xxxxi

    ).

    Let’s notice that δϕ from Theorem B is equal to S2ϕ(m,M) .Obviously, if ϕ is convex, Snϕ(xxxx1, . . . ,xxxxn) � 0.The next variant of Jensen’s inequality was proved by A. Matković and J. Pečarić

    in [9].

    THEOREM 3. Let U be a convex subset in Rk , xxxx1, . . . ,xxxxn ∈U and yyyy1, . . . ,yyyym ∈co({xxxx1, . . . ,xxxxn}) . If ϕ is a convex function on U , then the inequality

    ϕ(

    ∑ni=1 pixxxxi −∑mj=1 wjyyyy jPn−Wm

    )�

    ∑ni=1 piϕ (xxxxi)−∑mj=1 wjϕ (yyyy j)Pn−Wm (3.3)

  • 1100 A. MATKOVIĆ, J. PEČARIĆ AND J. PERIĆ

    holds for all positive real numbers p1, . . . , pn and w1, . . . ,wm satisfying the condition

    pi � Wm for all i = 1, . . . ,n,

    where Pn =n

    ∑i=1

    pi and Wm =m

    ∑j=1

    wj .

    Next theorem generalizes and improves Theorem 3.

    THEOREM 4. Let L satisfy properties L1, L2, L3 on a nonempty set E , A be apositive linear functional on L and à defined as in (3.2). Let xxxx1, . . . ,xxxxn ∈ Rk andK = co({xxxx1, . . . ,xxxxn}) . Let ϕ be a convex function on K and λ1, . . . ,λn barycentriccoordinates over K . Then for all gggg ∈ Lk such that gggg(E) ⊂ K and ϕ(gggg),λi(gggg) ∈ L,i = 1, . . . ,n and positive real numbers p1, . . . , pn , with Pn = ∑ni=1 pi, satisfying thecondition

    pi � A(1) for all i = 1, . . . ,n, (3.4)we have

    ϕ

    (∑ni=1 pixxxxi− Ã(gggg)

    Pn−A(1)

    )

    � ∑ni=1 piϕ (xxxxi)−∑ni=1 A(λi(gggg))ϕ (xxxxi)−mini {pi−A(λi(gggg))}Snϕ(xxxx1, . . . ,xxxxn)

    Pn−A(1)

    � ∑ni=1 piϕ (xxxxi)−A(ϕ(gggg))−Snϕ(xxxx1, . . . ,xxxxn) [mini {pi −A(λi(gggg))}+A(mini {λi(gggg)})]

    Pn−A(1) .

    (3.5)

    Proof. For each t ∈ E we have gggg(t) ∈ K . Using barycentric coordinates we haveλi(gggg(t)) � 0, i = 1, . . . ,n ,

    n

    ∑i=1

    λi(gggg(t)) = 1 and

    gggg(t) =n

    ∑i=1

    λi(gggg(t))xxxxi.

    Since ϕ is convex on K , then

    ϕ(gggg(t)) �n

    ∑i=1

    λi(gggg(t))ϕ(xxxxi)−mini{λi(gggg(t))}Snϕ(xxxx1, . . . ,xxxxn). (3.6)

    Applying positive linear functional A on (3.6) we get

    A(ϕ(gggg)) �n

    ∑i=1

    A(λi(gggg))ϕ(xxxxi)−A(

    mini{λi(gggg)}

    )Snϕ(xxxx1, . . . ,xxxxn),

    wheren

    ∑i=1

    A(λi(gggg)) = A

    (n

    ∑i=1

    λi(gggg)

    )= A(1)

  • THE JESSEN-MERCER INEQUALITY AND CONVEX HULLS 1101

    andA(1) � A(λi(gggg)) � 0 for all i = 1, . . . ,n.

    Also we have

    Ã(gggg) =n

    ∑i=1

    A(λi(gggg))xxxxi.

    Now we can write

    ∑ni=1 pixxxxi − Ã(gggg)Pn−A(1) =

    1Pn−A(1)

    (n

    ∑i=1

    pixxxxi −n

    ∑i=1

    A(λi(gggg))xxxxi

    )

    =1

    Pn−A(1)n

    ∑i=1

    (pi −A(λi(gggg)))xxxxi.

    We have1

    Pn−A(1)n

    ∑i=1

    (pi−A(λi(gggg))) = 1

    and1

    Pn−A(1) (pi−A(λi(gggg))) � 0 for all i = 1, . . . ,n,

    sincepi � A(1) � A(λi(gggg)) for all i = 1, . . . ,n.

    Therefore, expression∑ni=1 pixxxxi − Ã(gggg)

    Pn−A(1) is a convex combination of vectors xxxx1, . . . ,xxxxnand belongs to K .

    Since ϕ is convex on K , we have

    ϕ

    (∑ni=1 pixxxxi− Ã(gggg)

    Pn−A(1)

    )

    = ϕ

    (1

    Pn−A(1)n

    ∑i=1

    (pi −A(λi(gggg)))xxxxi)

    � 1Pn−A(1)

    n

    ∑i=1

    (pi −A(λi(gggg)))ϕ (xxxxi)−mini

    {pi−A(λi(gggg))

    Pn−A(1)}

    Snϕ(xxxx1, . . . ,xxxxn)

    =∑ni=1 piϕ (xxxxi)−∑ni=1 A(λi(gggg))ϕ (xxxxi)−mini {pi−A(λi(gggg))}Snϕ(xxxx1, . . . ,xxxxn)

    Pn−A(1)

    � ∑ni=1 piϕ (xxxxi)−A(ϕ(gggg))−Snϕ(xxxx1, . . . ,xxxxn) [mini {pi −A(λi(gggg))}+A(mini {λi(gggg)})]

    Pn−A(1) .

    Next Corollary shows that Theorem 4 is a generalization of Theorem 2 for convexhulls.

  • 1102 A. MATKOVIĆ, J. PEČARIĆ AND J. PERIĆ

    COROLLARY 2. Let L satisfy properties L1, L2, L3 on a nonempty set E and Abe a positive normalized linear functional on L. Let ϕ be a convex function on aninterval I = [m,M] ⊂ R . Then for all g ∈ L such that g(E)⊂ I and ϕ(g) ∈ L, we have

    ϕ (m+M−A(g))

    � A(g)−mM−m ϕ(m)+

    M−A(g)M−m ϕ(M)−

    (12− 1

    M−m∣∣∣∣A(g)− m+M2

    ∣∣∣∣)S2ϕ(m,M)� ϕ(m)+ ϕ(M)−A(ϕ(g))

    −[1− 1

    M−m(∣∣∣∣A(g)− m+M2

    ∣∣∣∣+A(∣∣∣∣g− m+M2∣∣∣∣))]S2ϕ(m,M). (3.7)

    Proof. For each t ∈ E we have g(t) ∈ I .Since interval I = [m,M] is 1-simplex with vertices m and M , then the barycentric

    coordinates have the special form:

    λ1(g(t)) =M−g(t)M−m and λ2(g(t)) =

    g(t)−mM−m .

    Applying functional A we have

    A(λ1(g)) =M−A(g)M−m and A(λ2(g)) =

    A(g)−mM−m . (3.8)

    Choosing n = 2, p1 = p2 = 1, x1 = m , x2 = M from (3.5) it follows

    ϕ (m+M−A(g))

    � ϕ(m)+ ϕ(M)−[M−A(g)M−m ϕ(m)+

    A(g)−mM−m ϕ(M)

    ]−(

    12− 1

    M−m∣∣∣∣A(g)− m+M2

    ∣∣∣∣)[ϕ(m)+ ϕ(M)−2ϕ(m+M2)]

    =A(g)−mM−m ϕ(m)+

    M−A(g)M−m ϕ(M)−

    (12− 1

    M−m∣∣∣∣A(g)− m+M2

    ∣∣∣∣)S2ϕ(m,M)� ϕ(m)+ ϕ(M)−A(ϕ(g))

    −[12− 1

    M−m∣∣∣∣A(g)− m+M2

    ∣∣∣∣+A(12 − 1M−m∣∣∣∣g− m+M2

    ∣∣∣∣)]S2ϕ(m,M)= ϕ(m)+ ϕ(M)−A(ϕ(g))

    −[1− 1

    M−m(∣∣∣∣A(g)− m+M2

    ∣∣∣∣+A(∣∣∣∣g− m+M2∣∣∣∣))]S2ϕ(m,M). �

    REMARK 2. The inequalities in (3.7) are also improvements of the inequalitiesobtained in [3].

    THEOREM 5. Let L satisfy properties L1, L2, L3 on a nonempty set E , A be apositive linear functional on L and à defined as in (3.2). Let xxxx1, . . . ,xxxxn ∈ Rk and

  • THE JESSEN-MERCER INEQUALITY AND CONVEX HULLS 1103

    K = co({xxxx1, . . . ,xxxxn}) . Let ϕ be a convex function on K and λ1, . . . ,λn barycentriccoordinates over K . Then for all gggg ∈ Lk such that gggg(E)⊂ K and ϕ(gggg),λi(gggg) ∈ L, i =1, . . . ,n and positive real numbers p1, . . . , pn satisfying the conditions Pn −A(1) > 0 ,where Pn = ∑ni=1 pi , and

    ∑ni=1 pixxxxi − Ã(gggg)Pn−A(1111) ∈ K, (3.9)

    we have

    ϕ

    (∑ni=1 pixxxxi − Ã(gggg)

    Pn−A(1)

    )�

    Pnϕ(

    1Pn ∑

    ni=1 pixxxxi

    )−A(1)ϕ

    (1

    A(1) Ã(gggg))

    Pn−A(1)

    �Pnϕ(

    1Pn ∑

    ni=1 pixxxxi

    )−∑ni=1 A(λi(gggg))ϕ (xxxxi)+mini {A(λi(gggg))}Snϕ(xxxx1, . . . ,xxxxn)

    Pn−A(1) .(3.10)

    Proof. For each t ∈ E we have gggg(t) ∈ K . Using barycentric coordinates we haveλi(gggg(t)) � 0, i = 1, . . . ,n , ∑ni=1 λi(gggg(t)) = 1 and

    gggg(t) =n

    ∑i=1

    λi(gggg(t))xxxxi.

    Also we have

    Ã(gggg) =n

    ∑i=1

    A(λi(gggg))xxxxi.

    We can easily see that

    1A(1)

    Ã(gggg) =1

    A(1)

    n

    ∑i=1

    A(λi(gggg))xxxxi ∈ K,

    since1

    A(1)

    n

    ∑i=1

    A(λi(gggg)) = 1 and1

    A(1)A(λi(gggg)) � 0, i = 1, . . . ,n.

    Since ϕ is convex on K , then using Lemma 1

    ϕ(

    1A(1)

    Ã(gggg))

    � 1A(1)

    n

    ∑i=1

    A(λi(gggg))ϕ(xxxxi)−mini

    {A(λi(gggg))

    A(1)

    }Snϕ(xxxx1, . . . ,xxxxn).

    (3.11)Using Theorem B and (3.11) we have

    ϕ

    ⎛⎝Pn(

    1Pn ∑

    ni=1 pixxxxi

    )−A(1)

    (1

    A(1) Ã(gggg))

    Pn−A(1)

    ⎞⎠� Pnϕ(

    1Pn ∑

    ni=1 pixxxxi

    )−A(1)ϕ

    (1

    A(1) Ã(gggg))

    Pn−A(1)

    �Pnϕ(

    1Pn ∑

    ni=1 pixxxxi

    )−A(1) 1A(1) ∑ni=1 A(λi(gggg))ϕ (xxxxi)+mini {A(λi(gggg))}Snϕ(xxxx1, . . . ,xxxxn)

    Pn−A(1) .�

  • 1104 A. MATKOVIĆ, J. PEČARIĆ AND J. PERIĆ

    REMARK 3. If positive real numbers p1, . . . , pn satisfy condition (3.4) , then con-dition (3.9) is also satisfied since K is convex set. Hence (3.5) can be extended asfollows

    Pnϕ(

    1Pn ∑

    ni=1 pixxxxi

    )−∑ni=1 A(λi(gggg))ϕ (xxxxi)+mini {A(λi(gggg))}Snϕ(xxxx1, . . . ,xxxxn)

    Pn−A(1)

    �Pnϕ(

    1Pn ∑

    ni=1 pixxxxi

    )−A(1)ϕ

    (1

    A(1) Ã(gggg))

    Pn−A(1)

    � ϕ(

    ∑ni=1 pixxxxi − Ã(gggg)Pn−A(1)

    )

    �∑ni=1 piϕ (xxxxi)−∑ni=1 A(λi(gggg))ϕ (xxxxi)−mini {pi−A(λi(gggg))}Snϕ(xxxx1, . . . ,xxxxn)

    Pn−A(1)

    �∑ni=1 piϕ (xxxxi)−A(ϕ(gggg))−Snϕ(xxxx1, . . . ,xxxxn) [mini {pi −A(λi(gggg))}+A(mini {λi(gggg)})]

    Pn−A(1) .

    COROLLARY 3. Let L satisfy properties L1, L2, L3 on a nonempty set E and Abe a positive normalized linear functional on L. Let ϕ be a convex function on aninterval I = [m,M] ⊂ R. Then for all g ∈ L such that g(E)⊂ I and ϕ(g) ∈ L, we have

    ϕ (m+M−A(g)) � 2ϕ(

    m+M2

    )−ϕ (A(g))

    � 2ϕ(

    m+M2

    )−[M−A(g)M−m ϕ(m)+

    A(g)−mM−m ϕ(M)

    ]+(

    12− 1

    M−m∣∣∣∣A(g)− m+M2

    ∣∣∣∣)S2ϕ(m,M). (3.12)Proof. Choosing n = 2, x1 = m, x2 = M, p1 = p2 = 1 and using (3.8) , the

    inequalities in (3.12) easily follow from (3.10) . �

    Next we give generalizations of Corollary 2 and Corollary 3 for convex functionsdefined on k -simplices in Rk .

    Let S be a k -simplex in Rk with vertices vvvv1,vvvv2, . . . ,vvvvk+1 ∈ Rk . The barycen-tric coordinates λ1, . . .λk+1 over S are nonnegative linear polynomials which satisfyLagrange’s property

    λi(vvvv j) = δi j ={

    1, i = j0, i = j.

    It is known (see [2]) that for each xxxx∈ S barycentric coordinates λ1(xxxx), . . . ,λk+1(xxxx)have the form

    λ1(xxxx) =Volk ([xxxx,vvvv2, . . . ,vvvvk+1])

    Volk(S),

  • THE JESSEN-MERCER INEQUALITY AND CONVEX HULLS 1105

    λ2(xxxx) =Volk ([vvvv1,xxxx,vvvv3, . . . ,vvvvk+1])

    Volk(S),

    ...

    λk+1(xxxx) =Volk ([vvvv1, . . . ,vvvvk,xxxx])

    Volk(S), (3.13)

    where Volk(F) denotes the k -dimensional Lebesgue measure of a measurable set F ⊂R

    k . Here, for example, [vvvv1,xxxx, . . . ,vvvvk+1] denotes the subsimplex obtained by replacingvvvv2 by xxxx , i.e., the subsimplex opposite to vvvv2 , when adding xxxx as a new vertex.

    COROLLARY 4. Let L satisfy properties L1, L2, L3 on a nonempty set E , A bea positive normalized linear functional on L and à defined as in (3.2). Let ϕ be aconvex function on k -simplex S = [vvvv1,vvvv2, . . . ,vvvvk+1] in Rk and λ1, . . . ,λk+1 barycentriccoordinates over S . Then for all gggg ∈ Lk such that gggg(E) ⊂ S and ϕ(gggg) ∈ L we have

    (k+1)ϕ( 1

    k+1 ∑k+1i=1 vvvvi

    )−∑k+1i=1 λi(Ã(gggg))ϕ (vvvvi)+mini{λi(Ã(gggg))}Sk+1ϕ (vvvv1, . . . ,vvvvk+1)k

    �(k+1)ϕ

    (1

    k+1 ∑k+1i=1 vvvvi

    )−ϕ(Ã(gggg))k

    � ϕ(

    ∑k+1i=1 vvvvi − Ã(gggg)k

    )

    �∑k+1i=1 ϕ (vvvvi)−∑k+1i=1 λi(Ã(gggg))ϕ (vvvvi)−mini

    {1−λi(Ã(gggg))

    }Sk+1ϕ (vvvv1, . . . ,vvvvk+1)

    k

    �∑k+1i=1 ϕ (vvvvi)−A(ϕ(gggg))−Sk+1ϕ (vvvv1, . . . ,vvvvk+1)

    [mini

    {1−λi(Ã(gggg))

    }+A(mini {λi(gggg)})

    ]k

    .

    (3.14)

    Proof. Since barycentric coordinates λ1, . . . ,λk+1 over k -simplex S in Rk arenonnegative linear polynomials, then A(λi(gggg)) = λi(Ã(gggg)) for all i = 1, . . . ,k+1.

    Choosing xxxxi = vvvvi for all i = 1, . . . ,k + 1 and p1 = p2 = . . . = pk+1 = 1, the in-equalities in (3.14) easily follow from (3.5) and (3.10) . �

    REMARK 4. As a special case of Corollary 4 for k = 1 and if we take p and q

    nonnegative real numbers such that A(g) =pm+qM

    p+qwe get right hand side of the

    inequality (2.3) in [7].

    REMARK 5. Using the same technique and the same special case as in Example1 and Remark 8 in [13], from (3.14) we get the same results, that is, the k -dimensionalversion of the Hammer-Bullen inequality, namely

    1|S|∫

    Sf (t)dt − f (vvvv∗) � k

    k+1

    k+1

    ∑i=1

    f (vvvvi)− k|S|∫

    Sf (t)dt,

  • 1106 A. MATKOVIĆ, J. PEČARIĆ AND J. PERIĆ

    and, as a special case in one dimension, an improvement of classical Hermite-Hadamardinequality

    f

    (a+b

    2

    )� 1

    b−a∫ b

    af (t)dt � f (a)+ f (b)

    2− 1

    4S2f (a,b).

    4. n -exponential convexity and exponential convexity of the Jessen-Mercerdifferences, applications to Stolarsky type means

    Motivated by Theorems 1 and 2, we define two functionals Φi : Lf → R , i = 1,2,by

    Φ1(ϕ) = ϕ (m)+ ϕ (M)−ϕ (m+M−A( f ))−A(ϕ ( f ))

    −[1− 2

    M−mA(∣∣∣∣ f − m+M2

    ∣∣∣∣)]δϕ (4.1)and

    Φ2(ϕ) = ϕ (m)+ ϕ (M)−ϕ (m+M−A( f ))−A(ϕ( f ))

    −[1− 1

    M−m(

    A

    (∣∣∣∣ f − m+M2∣∣∣∣)+ ∣∣∣∣m+M2 −A( f )

    ∣∣∣∣)]δϕ , (4.2)where A, f and δϕ are as in Theorem 1, Lf = {ϕ : I → R : ϕ( f ),ϕ(m+M− f ) ∈ L} ,[m,M] ⊆ I . Obviously, Φ1 and Φ2 are linear.

    If ϕ is additionally continuous and convex then Theorems 1 and 2 imply Φi( f ) �0, i = 1,2.

    In the following with ϕ0 we denote the function defined by ϕ0 (x) = x2 on what-ever domain we need.

    Now, we give Lagrange and Cauchy mean value type theorems for the functionalsΦi , i = 1,2.

    THEOREM 6. Let L satisfy L1 , L2 and L3 on a nonempty set E and let A be apositive normalized linear functional on L. Let f ∈ L be such that ϕ0 ∈ Lf , f (E) ∈[m,M] , [m,M] ⊆ I and let ϕ ∈ C2(I) be such that ϕ ∈ Lf . If Φ1 and Φ2 are linearfunctionals defined as in (4.1) and (4.2) then there exist ξi ∈ [m,M] , i = 1,2 such that

    Φi(ϕ) =ϕ ′′ (ξi)

    2Φi(ϕ0), i = 1,2.

    Proof. We give a proof for the functional Φ1 . Since ϕ ∈ C2(I) there exist realnumbers a = min

    x∈[m,M]ϕ ′′(x) and b = max

    x∈[m,M]ϕ ′′(x) . It is easy to show that the functions

    ϕ1,ϕ2 defined by

    ϕ1(x) =b2x2−ϕ(x), ϕ2(x) = f (x)− a2x

    2

  • THE JESSEN-MERCER INEQUALITY AND CONVEX HULLS 1107

    are continuous and convex, therefore Φ1(ϕ1) � 0, Φ1(ϕ2) � 0. This implies

    a2

    Φ1(ϕ0) � Φ1(ϕ) �b2

    Φ1(ϕ0).

    If Φ1(ϕ0) = 0, there is nothing to prove. Suppose Φ1(ϕ0) > 0. We have

    a � 2Φ1(ϕ)Φ1(ϕ0)

    � b.

    Hence, there exists ξ1 ∈ [m,M] such that

    Φ1(ϕ) =ϕ ′′(ξ1)

    2Φ1(ϕ0). �

    THEOREM 7. Let L satisfy L1 , L2 and L3 on a non-empty set E and let A be apositive normalized linear functional on L. Let f ∈ L be such that ϕ0 ∈ Lf , f (E) ∈[m,M] , [m,M] ⊆ I and ϕ1,ϕ2 ∈C2(I) such that ϕ1,ϕ2 ∈ Lf . If Φ1 and Φ2 are linearfunctionals defined as in (4.1) and (4.2) then there exist ξi ∈ [m,M] , i = 1,2 such that

    Φi(ϕ1)Φi(ϕ2)

    =ϕ ′′1 (ξi)ϕ ′′2 (ξi)

    , i = 1,2

    provided that the denominators are non-zero.

    Proof. We give a proof for the functional Φ1 . Define ϕ3 ∈C2([m,M]) byϕ3 = c1ϕ1 − c2ϕ2, where c1 = Φ1(ϕ2), c2 = Φ1(ϕ1).

    Using Theorem 6 we get that there exists ξ1 ∈ [m,M] such that(c1

    ϕ ′′1 (ξ1)2

    − c2 ϕ′′2 (ξ1)2

    )Φ1(ϕ0) = 0.

    Since Φ1(ϕ0) = 0, (otherwise we have a contradiction with Φ1(ϕ2) = 0, by Theorem6), we obtain

    Φ1(ϕ1)Φ1(ϕ2)

    =ϕ ′′1 (ξ1)ϕ ′′2 (ξ1)

    . �

    Next we introduce some function properties which are going to be explored hereand immediately after that we give some characterizations of these properties.

    DEFINITION 1. A function ψ : I → R is n -exponentially convex in the Jensensense on I if

    n

    ∑i, j=1

    ξiξ jψ(

    xi + x j2

    )� 0

    holds for all choices ξi ∈ R and xi ∈ I , i = 1, . . . ,n .A function ψ : I → R is n -exponentially convex if it is n -exponentially convex in

    the Jensen sense and continuous on I .

  • 1108 A. MATKOVIĆ, J. PEČARIĆ AND J. PERIĆ

    REMARK 6. It is clear from the definition that 1-exponentially convex functionsin the Jensen sense are in fact non-negative functions. Also, n -exponentially convexfunctions in the Jensen sense are k -exponentially convex in the Jensen sense for everyk ∈ N , k � n .

    By definition of positive semi-definite matrices and some basic linear algebra wehave the following proposition.

    PROPOSITION 1. If ψ is an n-exponentially convex in the Jensen sense, then the

    matrix

    [ψ(

    xi + x j2

    )]ki, j=1

    is positive semi-definite for all k ∈ N , k � n. Particularly,

    det

    [ψ(

    xi + x j2

    )]ki, j=1

    � 0 for all k ∈ N , k � n.

    DEFINITION 2. A function ψ : I →R is exponentially convex in the Jensen senseon I if it is n -exponentially convex in the Jensen sense for all n ∈ R .

    A function ψ : I → R is exponentially convex if it is exponentially convex in theJensen sense and continuous.

    REMARK 7. It is known (and easy to show) that a function ψ : I → R+ is log-convex in the Jensen sense if and only if

    α2ψ(x)+2αβ ψ(

    x+ y2

    )+ β 2ψ(y) � 0

    holds for every α,β ∈ R and x,y ∈ I . It follows that a positive function is log-convexin the Jensen-sense if and only if it is 2-exponentially convex in the Jensen sense. Also,using basic convexity theory, it follows that a positive function is log-convex if and onlyif it is 2-exponentially convex.

    We will also need the following result (see for example [14]).

    PROPOSITION 2. If Ψ is a convex function on I and if x1 � y1 , x2 � y2 , x1 = x2 ,y1 = y2 then the following inequality is valid

    Ψ(x2)−Ψ(x1)x2 − x1 �

    Ψ(y2)−Ψ(y1)y2− y1 . (4.3)

    If Ψ is concave on I the inequality reverses.

    When dealing with functions with different degree of smoothness divided differ-ences are found to be very useful.

    DEFINITION 3. The second order devided difference of a function f : I → R atmutually different points y0,y1,y2 ∈ I is defined recursively by

    [yi; f ] = f (yi), i = 0,1,2

  • THE JESSEN-MERCER INEQUALITY AND CONVEX HULLS 1109

    [yi,yi+1; f ] =f (yi+1)− f (yi)

    yi+1− yi , i = 0,1

    [y0,y1,y2; f ] =[y1,y2; f ]− [y0,y1; f ]

    y2− y0 . (4.4)

    REMARK 8. The value [y0,y1,y2; f ] is independent of the order of the pointsy0,y1 and y2 . This definition may be extended to include the case in which someor all the points coincide. Namely, taking the limit y1 → y0 in (4.4), we get

    limy1→y0

    [y0,y1,y2; f ] = [y0,y0,y2; f ] =f (y2)− f (y0)− f ′(y0)(y2− y0)

    (y2− y0)2 , y2 = y0

    provided that f ′ exists, and furthermore, taking the limits yi → y0 , i = 1,2 in (4.4), weget

    limy2→y0

    limy1→y0

    [y0,y1,y2; f ] = [y0,y0,y0; f ] =f ′′(y0)

    2

    provided that f ′′ exists.

    We use an idea from [5] to give an elegant method of producing an n -exponentiallyconvex and exponentially convex functions applying the functionals Φ1 and Φ2 to agiven family of functions with the same property.

    THEOREM 8. Let Φi , i = 1,2, be linear functionals defined as in (4.1) and (4.2).Let ϒ = {ϕs : s ∈ J} , where J is an interval in R , be a family of functions definedon an open interval I such that ϒ ⊆ Lf and that the function s → [y0,y1,y2;ϕs] is n-exponentially convex in the Jensen sense on J for every three mutually different pointsy0,y1,y2 ∈ I . Then s → Φi(ϕs) is an n-exponentially convex function in the Jensensense on J . If the function s →Φi(ϕs) is also continuous on J then it is n-exponentiallyconvex on J .

    Proof. For ξi ∈ R , i = 1, . . . ,n and si ∈ J , i = 1, . . . ,n , we define the functionχ : I → R by

    χ(y) =n

    ∑i, j=1

    ξiξ jϕ si+s j2

    (y).

    Using the assumption that the function s → [y0,y1,y2;ϕs] is n -exponentially convex inthe Jensen sense we obtain

    [y0,y1,y2;χ ] =n

    ∑i, j=1

    ξiξ j[y0,y1,y2;ϕ si+s j2

    ] � 0,

    which in turn implies that χ is a convex (and continuous) function on I , thereforeΦi(χ) � 0, i = 1,2. Hence

    n

    ∑i, j=1

    ξiξ jΦi(ϕ si+s j2

    ) � 0.

  • 1110 A. MATKOVIĆ, J. PEČARIĆ AND J. PERIĆ

    We conclude that the function s →Φi(ϕs) is n -exponentially convex on J in the Jensensense. If the function s → Φi(ϕs) is also continuous on J , then s → Φi(ϕs) is n -exponentially convex by definition. �

    The following corollary is an immediate consequence of Theorem 8.

    COROLLARY 5. Let Φi , i = 1,2, be linear functionals defined as in (4.1) and(4.2). Let ϒ = {ϕs : s ∈ J} , where J is an interval in R , be a family of functionsdefined on an open interval I such that ϒ ⊆ Lf and that the function s → [y0,y1,y2;ϕs]is exponentially convex in the Jensen sense on J for every three mutually different pointsy0,y1,y2 ∈ I . Then s → Φi(ϕs) is an exponentially convex function in the Jensen senseon J . If the function s → Φi(ϕs) is continuous on J then it is exponentially convex onJ .

    COROLLARY 6. Let Φi , i = 1,2, be linear functionals defined as in (4.1) and(4.2). Let Ω = {ϕs : s ∈ J} , where J is an interval in R , be a family of functionsdefined on an open interval I such that Ω ⊆ Lf and that the function s → [y0,y1,y2;ϕs]is 2 -exponentially convex in the Jensen sense on J for every three mutually differentpoints y0,y1,y2 ∈ I . Then the following statements hold:

    (i) If the function s → Φi(ϕs) is continuous on J then it is 2 -exponentially convexfunction on J . If s → Φi(ϕs) is additionally strictly positive than it is also log-convex on J .

    (ii) If the function s → Φi(ϕs) is strictly positive and differentiable on J then forevery s,q,u,v ∈ J , such that s � u and q � v, we have

    μs,q(Φi,Ω) � μu,v(Φi,Ω), i = 1,2, (4.5)

    where

    μs,q(Φi,Ω) =

    ⎧⎪⎪⎨⎪⎪⎩(

    Φi(ϕs)Φi(ϕq)

    ) 1s−q

    , s = q,

    exp

    (dds Φi(ϕs)Φi(ϕs)

    ), s = q.

    (4.6)

    for ϕs,ϕq ∈ Ω (μs,q(Φi,Ω), i = 1,2 are the Stolarsky type means).

    Proof. (i) This is an immediate consequence of Theorem 8 and Remark 7.(ii) Since by (i) the function s → Φi(ϕs) is log-convex on J , that is, the function

    s → logΦi(ϕs) is convex on J . Applying Proposition 2 we getlogΦi(ϕs)− logΦi(ϕq)

    s−q �logΦi(ϕu)− logΦi(ϕv)

    u− v (4.7)

    for s � u,q � v,s = q,u = v , and therefrom conclude thatμs,q(Φi,Ω) � μu,v(Φi,Ω), i = 1,2.

    Cases s = q and u = v follow from (4.7) as limit cases. �

  • THE JESSEN-MERCER INEQUALITY AND CONVEX HULLS 1111

    REMARK 9. Note that the results from Theorem 8, Corollary 5, Corollary 6 stillhold when two of the points y0,y1,y2 ∈ I coincide, say y1 = y0 , for a family of dif-ferentiable functions ϕs such that the function s → [y0,y1,y2;ϕs] is n -exponentiallyconvex in the Jensen sense (exponentially convex in the Jensen sense, log-convex in theJensen sense), and furthermore, they still hold when all three points coincide for a fam-ily of twice differentiable functions with the same property. The proofs are obtained byrecalling Remark 8 and suitable characterization of convexity.

    Now, we present several families of functions which fulfil the conditions of The-orem 8, Corollary 5 and Corollary 6 (and Remark 9). This enables us to construct alarge family of functions which are exponentially convex. For a discussion related tothis problem see [4].

    In the rest of the section we consider only Φ1 and Φ2 defined as in (4.1) and (4.2)with A which is continuous and f such that compositions with any function from thechosen familly Ωi as well as with other functions which appear as arguments of Φ1and Φ2 remain in L .

    EXAMPLE 1. Consider a family of functions

    Ω1 = {gs : R → [0,∞) : s ∈ R}defined by

    gs(x) =

    {1s2

    esx, s = 0,12 x

    2, s = 0.

    We have d2gs

    dx2(x) = esx > 0 which shows that gs is convex on R for every s ∈ R

    and s → d2gsdx2

    (x) is exponentially convex by definition. Using analogous arguing as inthe proof of Theorem 8 we also have that s → [y0,y1,y2;gs] is exponentially convex(and so exponentially convex in the Jensen sense). Using Theorem 5 we conclude thats → Φi(gs) , i = 1,2, are exponentially convex in the Jensen sense. It is easy to verifythat these mappings are continuous (although mapping s → gs is not continuous fors = 0), so they are exponentially convex.

    For this family of functions, μs,q(Φi,Ω1) , i = 1,2, from (4.6) become

    μs,q(Φi,Ω1) =

    ⎧⎪⎪⎪⎪⎨⎪⎪⎪⎪⎩

    (Φi(gs)Φi(gq)

    ) 1s−q

    , s = q,exp(

    Φi(id·gs)Φi(gs)

    − 2s)

    , s = q = 0,exp(

    Φi(id·g0)3Φi(g0)

    ), s = q = 0,

    and using (4.5) they are monotonous functions in parameters s and q .Using Theorem 7 it follows that for i = 1,2

    Ms,q(Φi,Ω1) = logμs,q(Φi,Ω1)

    satisfy m � Ms,q(Φi,Ω1) � M , which shows that Ms,q(Φi,Ω1) are means (of a functiong ). Notice that by (4.5) they are monotonous.

  • 1112 A. MATKOVIĆ, J. PEČARIĆ AND J. PERIĆ

    EXAMPLE 2. Consider a family of functions

    Ω2 = { fs : (0,∞) → R : s ∈ R}defined by

    fs(x) =

    ⎧⎪⎨⎪⎩xs

    s(s−1) , s = 0,1,− logx, s = 0,x logx, s = 1.

    Here, d2 fs

    dx2(x) = xs−2 = e(s−2) lnx > 0 which shows that fs is convex for x > 0 and

    s → d2 fsdx2

    (x) is exponentially convex by definition. Arguing as in Example 1 we get thatthe mappings s → Φi(gs) , i = 1,2 are exponentially convex. Functions (4.6) in thiscase are equal to:

    μs,q(Φi,Ω2) =

    ⎧⎪⎪⎪⎪⎪⎪⎪⎪⎨⎪⎪⎪⎪⎪⎪⎪⎪⎩

    (Φi( fs)Φi( fq)

    ) 1s−q

    , s = q,exp(

    1−2ss(s−1) − Φi( fs f0)Φi( fs)

    ), s = q = 0,1,

    exp(1− Φi( f 20 )2Φi( f0)

    ), s = q = 0,

    exp(−1− Φi( f0 f1)2Φi( f1)

    ), s = q = 1.

    If Φi is positive, then Theorem 7 applied for f = fs ∈ Ω2 and g = fq ∈ Ω2 yields thatthere exists ξ ∈ [m,M] such that

    ξ s−q =Φi( fs)Φi( fq)

    .

    Since the function ξ → ξ s−q is invertible for s = q , we then have

    m �(

    Φi( fs)Φi( fq)

    ) 1s−q

    � M, (4.8)

    which together with the fact that μs,q(Φi,Ω2) is continuous, symmetric and monotonous(by (4.5)), shows that μs,q(Φi,Ω2) is a mean (of a function f ).

    EXAMPLE 3. Consider a family of functions

    Ω3 = {hs : (0,∞) → (0,∞) : s ∈ (0,∞)}defined by

    hs(x) =

    ⎧⎨⎩s−xln2 s

    , s = 1,x22 , s = 1.

    Since s → d2hsdx2

    (x) = s−x is the Laplace transform of a non-negative function (see [15])it is exponentially convex. Obviously hs are convex functions for every s > 0.

  • THE JESSEN-MERCER INEQUALITY AND CONVEX HULLS 1113

    For this family of functions, μs,q(Φi,Ω3) , from (4.6) becomes

    μs,q(Φi,Ω3) =

    ⎧⎪⎪⎪⎪⎨⎪⎪⎪⎪⎩

    (Φi(hs)Φi(hq)

    ) 1s−q

    , s = q,exp(−Φi(id·hs)sΦi(hs) −

    2s lns

    ), s = q = 1,

    exp(− 2Φi(id·h1)3Φi(h1)

    ), s = q = 1,

    and it is monotonous in parameters s and q by (4.5).Using Theorem 7, it follows that

    Ms,q (Φi,Ω3) = −L(s,q) logμs,q(Φi,Ω3),satisfies m � Ms,q(Φi,Ω3) � M , which shows that Ms,q(Φi,Ω3) is a mean (of a functionh ). L(s,q) is the logarithmic mean defined by L(s,q) = s−qlog s−logq , s = q , L(s,s) = s .

    EXAMPLE 4. Consider a family of functions

    Ω4 = {ks : (0,∞) → (0,∞) : s ∈ (0,∞)}defined by

    ks(x) =e−x

    √s

    s.

    Since s → d2ksdx2

    (x) = e−x√

    s is the Laplace transform of a non-negative function (see[15]) it is exponentially convex. Obviously ks are convex functions for every s > 0.

    For this family of functions, μs,q(Φi,Ω4) from (4.6) becomes

    μs,q(Φi,Ω4) =

    ⎧⎪⎨⎪⎩(

    Φi(ks)Φi(kq)

    ) 1s−q

    , s = q,exp(− Φi(id·ks)2√sΦi(ks) −

    1s

    ), s = q,

    and it is monotonous function in parameters s and q by (4.5).Using Theorem 7, it follows that

    Ms,q(Φi,Ω4) = −(√

    s+√

    q)logμs,q(Φi,Ω4)

    satisfies m � Ms,q(Φi,Ω4) � M , which shows that Ms,q(Φi,Ω4) is a mean (of a functionk ).

    RE F ER EN C ES

    [1] PAUL R. BEESACK, JOSIP E. PEČARIĆ, On Jessen’s inequality for convex functions, J. Math. Anal.Appl. 110 (1985), no. 2, 536–552.

    [2] M. BESSENYEI, The Hermite-Hadamard inequality on Simplices, Amer. Math. Monthly 115 (4)(2008) 339–345.

    [3] W. S. CHEUNG, A. MATKOVIĆ, J. PEČARIĆ, A variant of Jessen’s inequality and generalized means,JIPAM. J. Inequal. Pure Appl. Math. 7 (2006), no. 1, Article 10, 8 pp.

  • 1114 A. MATKOVIĆ, J. PEČARIĆ AND J. PERIĆ

    [4] W. EHM, MARC G. GENTON, T. GNEITING, Stationary covariances associated with exponentiallyconvex functions, Bernoulli 9 (2003), no. 4, 607–615.

    [5] J. JAKŠETIĆ, JOSIP E. PEČARIĆ, Exponential convexity method, J. Convex Anal. 20 (2013), no. 1,181–197.

    [6] B. JESSEN, Bemaerkinger om konvekse Funktioner og Uligheder imellem Middelvaerdier I, Mat.Tidsskrift B (1931), 17–29.

    [7] M. KLARIČIĆ BAKULA, J. PEČARIĆ, J. PERIĆ, Extensions of the Hermite-Hadamard inequality withApplications, Math. Inequal. Appl. 12 (2012), no. 4, 899–921.

    [8] M. KLARIČIĆ BAKULA, J. PEČARIĆ, J. PERIĆ, On the converse Jensen inequality, Appl. Math.Comput. 218 (2012), no. 11, 6566–6575.

    [9] A. MATKOVIĆ, J. PEČARIĆ, A variant of Jensen’s inequality for convex functions of several variables,J. Math. Ineq. 1 (1) (2007) 45–51.

    [10] A. MCD. MERCER, A variant of Jensen’s inequality, JIPAM. J. Inequal. Pure Appl. Math. 4 (2003),no. 4, Article 73, 2 pp.

    [11] D. S. MITRINOVIĆ, J. E. PEČARIĆ, A. M. FINK, Classical and new inequalities in analysis. Mathe-matics and its Applications, East European Series, 61. Kluwer Academic Publishers Group, Dordrecht,1993.

    [12] J. PEČARIĆ, J. PERIĆ, Remarks on the paper “Jensen’s inequality and new entropy bounds” by S.Simic, Math. Inequal. Appl. 6 (2012), no. 4, 631–636.

    [13] J. PEČARIĆ, J. PERIĆ, Generalizations and improvements of converse Jensen’s inequality for convexhulls in Rk , submitted to Math. Inequal. Appl.

    [14] J. E. PEČARIĆ, F. PROSCHAN, Y. L. TONG, Convex functions, partial orderings, and statisticalapplications, Mathematics in Science and Engineering, 187. Academic Press, Inc., Boston, MA, 1992.

    [15] D. V. WIDDER, The Laplace Transform, Princeton Mathematical Series, v. 6. Princeton UniversityPress, Princeton, N. J., 1941.

    (Received October 13, 2014) A. MatkovićFaculty of Electrical Engineering, Mechanical Engineering

    and Naval ArchitectureUniversity of Split

    Ru -dera Boškovića 32, 21 000 Split, Croatiae-mail: [email protected]

    J. PečarićFaculty of Textile Technology

    University of ZagrebPrilaz baruna Filipovića 30, 10 000 Zagreb, Croatia

    e-mail: [email protected]

    J. PerićFaculty of Science, Department of Mathematics

    University of SplitTeslina 12, 21 000 Split, Croatia

    e-mail: [email protected]

    Journal of Mathematical [email protected]

    IntroductionRefinement of the Jessen-Mercer inequalityGeneralization on convex hulls in Rkn-exponential convexity and exponential convexity of the Jessen-Mercer differences, applications to Stolarsky type means

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