ICE Lecture 2

Embed Size (px)

Citation preview

  • 8/14/2019 ICE Lecture 2

    1/6

    Ir. TRI TJAHJONO, MT/INTERNAL COMBUSTION ENGINE

    TERMODYNAMIC AND CYCLING

    1. First Law Analysis ofEngine Cycle-Energy Balance

    a). Indicated thermal efficiency ( t ).

    Indicated thermal efficiency is the ratio of energy in the indicated horse power to fuel

    energy.

    hpfuel

    ihp t =

    valuecalorificfuel/min xofmass

    4500xihp=

    b). Mechanical efficiency ( m )

    Mechanical efficiency is the ratio of brake horse power (delivered power) to the indicated

    horse power (power provided to the piston)

    ihp

    bhpm =

    and bhpihpfhp =

    7

    Fuel in System boundary

    Air in

    Engine

    Qt

    Work out

    Exhaust

    Energyin

    fuel

    ihp

    bhp

    Energy lost in exhaust, coolant, radiation etc

    Energy loss in fiction, pumping etc

    Enginebhpihp

    friction

  • 8/14/2019 ICE Lecture 2

    2/6

    Ir. TRI TJAHJONO, MT/INTERNAL COMBUSTION ENGINE

    c). Brake thermal efficiency ( tb ).

    Brake thermal efficiency is ratio of energy inbrake horse powerto the fuel energy.

    hpfuel

    bhp

    tb

    =

    valuecalorificfuel/min xofmass

    4500xbhp=

    The brake thermal equals the product of the indicated thermal efficiency t and the

    mechanical efficiency m .

    mttb x =

    d). Volumetric efficiency ( V )

    conditionpressureandretemperatuintakeatvolumecylinderbydrepresentechargeofmass

    indicatedactuallychargeofmassV =

    e). Specific fuel consumption.

    The fuel consumption characteristics of an engine are generally expressed in terms of

    specific fuel consumption in grams per horsepower-hour. Brake specific fuel

    consumptionand indicated specific fuel consumption, abbreviated as bsfc and isfc, are

    the specific fuel consumptions on the basis of bhp and ihp, respectively.

    f). Fuel-air (F/A) or air-fuel (A/F) ratio.

    The relative proportions of the fuel and air in the engine are very important from the

    standpoint of combustion and efficiency of engine. This expressed either as the ratio of the

    mass ofthe fuel to that ofthe air.

    ratioairfueltricstoichiome

    ratioairfuelactualFr

    =

    Stoichiometric = a chemically correct is mixture that contains just enough air for complete

    combustion of all fuel.

    2. Useful Thermodynamic Relations

    The following are the useful thermodynamic relations used in the analysis of air standard

    cycles.

    a). For ideal gas cycle the working fluid is a perfect gas which follows the law

    mRTpV = , or RTpv =

    where p is the pressure, V volume, v specific volume, m mass, R gas constant and Tabsolute temperature (0Kelvin).

    8

  • 8/14/2019 ICE Lecture 2

    3/6

    Ir. TRI TJAHJONO, MT/INTERNAL COMBUSTION ENGINE

    b). For perfect gas

    J

    Rcc VP =

    where cP (= 0,24) is the specific heat at constant pressure and cV (= 0.17) is the specific

    heat at constant volume. The ratio 4.1c

    c

    V

    p== will be designated by the symbol .

    c). From the perfect gas law, it can be seen that an isothermal process will follow the

    relationship

    ttanconspv =

    d). It is readily shown that for perfect gas the reversible adiabatic orisentropic process will

    follow the relationship

    ttanconspv =

    e). The definition ofenthalpy h is given by the expression

    pvuh +=

    which for a perfect gas, becomes

    RTuh +=

    f). For a perfect gas internal energy u and enthalpy h are functions of temperature only

    =2

    1

    T

    TvdTcu =

    2

    1

    T

    TpdTch

    g). In a compression process, if p1, V1, and T1 represent the initial conditions p2, V2, and T2 the

    final conditions are given by

    ( ) n/1n

    1

    2

    1n

    2

    1

    1

    2

    p

    p

    V

    V

    T

    T

    =

    =

    where n is the index of compression.

    For reversible adiabatic or isentropic compression n = .

    h). Forisothermal process of a perfect gas, the change in u and h is zero. Therefore, for both

    flow and non-flow process

    1

    2isothermal

    v

    vlogmRTWQ ==

    where Q is the heat interchange and W the work done

    i). The work done in a non-flowpolytrophic process is given by

    ( )

    1n

    TTmR

    1n

    VpVpW 212211

    =

    =

    9

    u + pv

  • 8/14/2019 ICE Lecture 2

    4/6

    Ir. TRI TJAHJONO, MT/INTERNAL COMBUSTION ENGINE

    where m = mass of gas

    The work transfer during flow process is given by

    ( )

    1n

    TTmRn xW 21

    =

    j). The heat transferto any fluid can be evaluated from

    == dTcTdsQ nrevwhere cn = specific heat of the fluid in which subscript n refers to the property which

    remains constant during the process.

    k). For any general process, according to the first law of thermodynamics,

    fornon-flow process UWQ =

    and forflow process HWQ =

    l). For any cycling process

    addedtrejectedadded QxQQQW ===

    Where the symbol refers to over the cycle and t is the thermal efficiency.

    added

    tQ

    W=

    THE CARNOT CYCLE

    (Carnot is a French Engineer)

    10

  • 8/14/2019 ICE Lecture 2

    5/6

    Ir. TRI TJAHJONO, MT/INTERNAL COMBUSTION ENGINE

    During the isentropic process bc and da the heat transfer form or to the working

    substance is zero. Therefore, heat transfer takes place during isothermal process ab and cd

    only.

    Let r= ratio ofexpansion Vb/Va during process ab

    = ratio ofcompression Vc/Vd during process cd

    If the ratio of expansion and compression are not equal it would be a closed cycle.

    Now, consider 1 kg of working substance:

    Heat supplied during process ab, rlogRTrlogvpq e1eaac =

    Heat rejected during process cd, rlogRTrlogvpq e2eccd =

    Work done = heat supplied heat rejected

    = rlogRTrlogRT e2e1

    Thermal efficiency of the Carnot cycle,

    pliedsupheat

    workdonecarnot =

    rlogRT

    rlogRTrlogRT

    e1

    e2e1 =

    1

    2

    1

    21

    T

    T1

    T

    TT=

    =

    peraturHigher tem

    T=

    Carnot cycle on T-s diagram.

    On T-s diagram the two isothermal processes ab and cdare represented by horizontal lines

    and two isentropic processes bc and adby vertical lines.

    The heat supplied during the isothermal process ab is given by

    )s(sTssbaareaq 121211 ==

    Similarly, the heat rejected during the isothermal process cd is given by

    )s(sTssdcareaq 122212 ==

    Hence we have thermal efficiency of Carnot cycle

    ( ) ( )

    ( )121

    122121carnot

    ssT

    ssTssT

    =

    1

    2

    1

    21

    T

    T1

    T

    TT=

    =

    11

  • 8/14/2019 ICE Lecture 2

    6/6

    Ir. TRI TJAHJONO, MT/INTERNAL COMBUSTION ENGINE

    Net work output = (T1 T2)(s2 s1)

    Gross workof expansion = work done during process ab + work done during process bc.

    For isothermal process Q = W

    i.e., Wab = Qab = area under line ab on T-s diagram

    = T1(s2-s1)

    Forisentropic process from b and c

    Wbc = ub - uc

    Therefore, for a perfect gas

    ( )21vbc TTcW =

    ( )( )

    ( ) ( )21v121

    1221

    TTcssT

    ssTTratioWork

    +

    =

    Relative work outputs of various piston engine cycles is given by mean effective

    pressure (mep or pm), which is defined as the constant pressure producing the same net work

    output whilst causing the piston to move through the same swept volume as in the actual cycle

    Let pm = mean effective pressure

    Vs = swept volume

    W = net work output per cycle

    Then,volumestroke

    cycleperdoneworkpm =

    ss V

    pdV

    V

    W ==

    Also,diagramtheoflength

    diagramindicatortheofareapm =

    12