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Human genome sequence
DNA = DEOXYRIBONUCLEIC ACID
RNA = RIBONUCLEIC ACIDStrong acid hydrolyses DNA & RNA into 3 components:
• nitrogenous base (4 different ones)
• sugar
• phosphoric acid
Mild acid hydrolyses DNA & RNA into 2 components:
•Nucleoside = base—sugar
•Nucleotide = base-sugar-phosphate
DNA & RNA are polymers of nucleotides
keto (carbonyl)
amino
amino
NUCLEOTIDE structure: nitrogenous bases
PURINE1
2
3
4
5
8
9
76
N
N N
N
H
H
N
N N
N
NH2
ADENINE — A
H
H
N
N N
N
O
H2N
GUANINE — G
methyl
amino keto (carbonyl)
keto (carbonyl)
NUCLEOTIDE structure
PYRIMIDINEN
N1
3
2
4
5
6
CYTOSINE — C
H
NH2
O
N
N
THYMINE — T
H
O
O
HN
N
CH3
URACIL— U
H
O
O
HN
N
First difference between DNA and RNA:
DNA contains the bases A, G, C and T
RNA contains the bases A, G, C and U
NUCLEOTIDE structure
2. THE SUGARS — pentoses
O
OHOH
OH
H
CH2
H
HO
1
2
4
3
5
D-ribose (RNA)
O
OHOH
OH
H
CH2
H
HO
1
2
4
3
5
H
D-2-deoxyribose (DNA)
Second difference between DNA and RNA:
DNA contains 2-deoxyribose
RNA contains ribose
NUCLEOTIDE structure
3. PHOSPHORIC ACID
O
P OHHO
OH
(H3PO4)
Phosphoric acid
O
P OHO-
O-
pH 7
(HPO42-)
Phosphate ion
NUCLEOSIDE = base—sugar
N
NN
N
NH2
adenineO
OHOH
H
CH2
H
HO
ribose
DEOXYADENOSINE = adenine—deoxyribose
deoxy
H
NUCLEOTIDE structure
Base—sugar—phosphate
N
NN
N
NH2
adenineO
OHOH
H
CH2
H
HO
ribose
e.g. ADENOSINE
Adenosine 5'-monophosphate
(5'-AMP)
O
O
PO-
O-
5'
The 3' and 5' positions are very important for understanding DNA and RNA structure and function
NUCLEOSIDE numbering
O
OHOH
H
CH2
H
HO
N
N
O
NH2
5
4
3 2
1
6
5
4
3
2
1
'
'
'
'
'
"Prime" mark: '
O
OHOH
H
CH2
H
HO
ribose
N
NN
N
NH2
adenine5'
Adenosine 5'-monophosphate (5'-AMP)
O
O
PO-
O-
O
O
PO-
O-
Adenosine 5'-diphosphate (5'-ADP)
O
O
PO-
O-
Adenosine 5'-triphosphate (5'-ATP)
How are mononucleotides linked together to form the polymers DNA and
RNA?
3',5'-phosphodiester bond
N
N
O
NH2
O
OHOH
H
CH2
H
HO
5'O
3'
N
N
O
NH2
O
OHOH
H
CH2
H
HO
3'
5'O
O
P
O-
O
O
O
P
O-
N
N
O
NH2
O
OHOH
H
CH2
H
HO
5'O
O
P
O-
O
3'
N
N
O
NH2
O
OHOH
H
CH2
H
HO
3'
5'O
O
P
O-
O
O
OHOH
H
CH2
H
HO
5'O
O
P
O-
O
3'
N
NN
N
NH2 A
C
C
Single-stranded polynucleotides have one free 5' end and one free 3' end — they exhibit POLARITY
POLARITY
DNA is a double helix
•Studies of DNA hydrolysis showed that the repeating unit was a NUCLEOTIDE
• CHARGAFF's "rules"
What information did Watson and Crick use in 1953 to arrive at their "double
helix" structure for DNA?
%A = %T
%G = %C
%A = %T
%G = %C
%G = %(C + 5-MeC)
Plants have a particularly high content of 5-MeC
H
N
N N
N
NHCH3
6-methylADENINE
Note that in addition to the bases A,G, C and T there are some minor bases found in DNA
H
NH2
O
N
N
CH3
5-methylCYTOSINE
prokaryotes and eukaryotes prokaryotes
helical structure with repeats at 0.34 and 3.4 nm
2 nm wide
phosphates on outside of structure
Density of chain suggests the helix contains 2 strands
Conclusion: DNA MUST be double-stranded
X-ray diffraction patterns obtained by Wilkins, Franklin & Gosling showed:
1.08 nm
1.08 nm
N
N
N
N N
N
NH
H
O
O
H3C H
H
H
A
T
AT base pair
N
N
N
N N
N
O
H
N
N
O
H
H
H
HH
HH
C
G
GC base pair
2 H-bonds
3 H-bonds
Double helical DNA
3.4 nm:
One helical turn
0.34 nm
2 nm 2 nm
Major groove
Minor groove
sugar-phospha
te backbon
e
Base pairs "stacked" vertically in interior10 bp
per turn
Both strands coiled round a common axis
5'
3'5'
3'
Strands are ANTIPARALLEL
One runs 5' to 3'
Other runs 3' to 5'
Watson & Crick solved the structure of DNA in 1953
"...A structure this pretty just had to exist." - James Watson in The Double Helix
The implications of the ‘Double Helix’
Based on the fact that DNA is the genetic material:
Stable
Faithful replication and propagation of life– Two strands: one can form the template for DNA
replication
Faithful transmission of information to RNA– One strand acts as template
RNA then transfers information to proteins
http://science.nhmccd.edu/biol/bio1int.htm
DNA replication
Protein Structure
Amino acid structure
N C
O
OHH
HH
R
C
R is a chemical group that varies in different amino acids.
C is central “chiral” carbon.
Non-polar amino acids
Polar amino acids
Peptide bonds result
from dehydration
of A.A.s
Primary structure is the
sequence of A.A.s
Sickle-cell anemia cause
Secondary structure
Tertiary structure
Quaternary structure
If all cells come from other cells where did the first ‘life’ come from?
The Miller-Urey experiment
Water is heated in a closed apparatus containing methane (CH4), ammonia (NH3) and hydrogen (H2) and an electric discharge is passed through the mixture.
Many precursors can be produced in simple pre-biotic conditions
• Some amino acids found (building blocks for proteins)
• Some nucleic acids found e.g. adenine• Some sugars found including ribose