HSC March_2014 Chemistry Detailed Key_English Medium to Kalvisolai

7/21/2019 HSC March_2014 Chemistry Detailed Key_English Medium to Kalvisolai

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*Detailed Chemistry Key answer HSC March - 2014.*

Collected By: x+ V.CHANDRASEKARANM.Sc., M.Ed.,(Mysore), M.Phil., Ph.D.*,(Che), PG Teacher in Chemistry,Government Higher Secondary School, Athanur636 301, Namakkal District.

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PART - IQ. No. Correct Answer

1 ( d ) = h / mv

2 ( d ) sp3d3

3 ( a ) Z* = Z S

4 ( c ) PH3

5 ( d ) Cu+

6 ( b ) 3d54S1

7 ( d) + 4

8 ( b ) Lu

9 ( a ) Magnesium - Porphyrin

10 ( c ) 6 , 4

11 ( c ) Unit cell

12 ( b ) q = 0

13 ( b ) are state functions

14 ( b) K1 = 1 / K2

15 ( b ) deactivates the catalyst

16 ( b ) mol litre-1 sec-1

17 ( a ) Protein

18 ( b ) Glycerine

19 ( c ) Dialysis

20 ( c) 13

21( a) CH3MgI reacts with alcoholgiving methane.

22 ( d ) Comparatively inert.

23 ( b ) Williamson synthesis

24 ( c ) Ammonical silver nitrate

25( b ) Acid chloride > Acid

anhydride > Ester > Amide

26 ( c ) Functional

27 ( c ) Di methyl amine28 ( b ) Diphenyl amine

29 ( d ) Waxes

30 ( b ) Cellulose

CHEMISTRY

Note :The key answer published for paper

evaluation by the Directorate of GovernmentExaminations Chennai- 6 is the foremost one.

It is only a guidance material to theteachers as well as students for betterunderstanding of distribution of mark to the keypoints.

If the teacher highlight the key pointsand make a note on distribution of marks in redink in this detailed key answer material from thekey answer given by DGE, then the evaluationshould beCORRECTION FREE EVALUATION.

The students are advised to understand

the key answer and not to miss the key pointswhile writing the examination in the upcomingyears.

If you find any inconsistencies kindlycorrect it in accordance with DGE Key.

x+YOU CAN WIN+xOur life is what our thoughts makeit.

Marcus Aurelius.

Success is a journey its not a destination.

Rick Hawkins

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PART - II

31.Significance of negative electron

energy

32.IE Boron is less than that of

Berllium

33.P2O5powerful dehydrating agent

34.Three uses of Helium

35.The reason for transition elements

form complexes

36.Gold reaction with auqaregia

37.Half-life period calculation

1/2

0.693

t

0.693

2.31min

10.3min

38.Vitreous state

39.Calculation of Entropy

540 /18

( ) 373

vap

vap

b

H cal moleS X

T k K

v p

26.05898 = 26.06 1 1calk mole

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40.Reaction Quotient (Q)

41.Consecutive reaction-example

42.Activation energy

43.Tyndall effect

44. Common ion effect - example

45.Recemisation

46.Victor Meyers test for tertiary

alchohol

47.Picric acid preparation from phenol

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48.Urotropine and its use.

49.Trans-esterification reaction

50.

Compound Molecularformula

Name

A C6H7N Aniline

B C6H5N2ClBenzene diazoniumchloride

C C6H5OH Phenol

51.Antiacids and Example

PART III

Section -A

52.Formation of N2Molecule by MOT.

53. The extraction of Zinc

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54. Extraction of lanthanides.

55.Write for the Coordination compound

[ Cr (en)3] Cl3

(a IUPAC NAME

Tris (ethylenediamine) Chromium (III) Chloride

(b Name of the central metal ion-Cr3+

(c Ligand en - Ethylene diamine

(d Coordination Number 6

(e Structure of [ Cr (en)3] Cl3

chandrachemistry Octahedral

56. Characteristics of Free energy G

57. Relationship between Kp and Kc.

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58. Rate constant for first order equation.

59. Half cell emf Calculation.

60.The isomerism in ethers.

61. Mechanism of aldol condensation.

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62. Preparation of Oxalic acid.

63.

PART IV 4x10 = 40

64.a.Ionic radii determination.

64. b.Uses of silicones.

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65 a.

65. b.Difference between chemical

bbbb reactions and nuclear reactions.

66 . a.Braggs spectrometer method.

66 . b. Repeated M 2012, M 2013

The preparation of colloides by

chemical methods.

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67 .a.

67. b .

68.a. Difference between enantiomers

chanand diastereomers

5. Example d or l tartaric acid

d, l tartaric acid and meso tartaric acid.

68.b.Benzoic acid preparation from

1.Toluene

2.Phenyl cyanide

3.Carbon dioxide

69. a.Reduction of nitrobenzene in

chanalkaline medium.

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69. b. The structure of Glucose.

70.a.Hydroxy derivatives.

2 4. /440

2 5 2 2 22

Con H SO K C H OH CH CH H O

2 2 2 2 2( )CH CH H O O CH OH CH OH

CompoundMolecularformula

Name Structure

A C2H6O Ethanol CH3CH2OH

B C2H4 Ethylene CH2=CH2

C C2H6O2EthyleneGlycol

CH2OH

CH2OH

70.b. d- block elements.

CompoundChemicalformula

Name

A Ag Silver Metal

B AgNO3 Silver Nitrate

C AgNO2 Silver Nitrite

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70.c. Carbonyl compounds.

Compound Molecularformula Name Structure

A C7H6O Benzaldehyde C6H5CHO

BAldimine /Shiffs base C6H5CH=NC6H5

CBenzoylchloride

70 . d.Electro chemistryI

The Ka of propionic acid is 1.34 x 10-5

.What is the PHof a solution containing 0.5 M

propionic acid and 0.5 M sodium

propionate?

Solution :

Ka = 1.34 x 105

PKa = log Ka

= log (1.34 x 105)

= 5 log1010 log 1.34

= 4.87

PH = PKa + log acidsalt

= 4.87 + log 5.0

5.0

PH = 4.87

Space for rough work

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HSC March_2014 Chemistry Detailed Key_English Medium to Kalvisolai