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1 MAE 5540 – Propulsion Systems II Homework 1.2 Solution Assignment 1.2 Date Assigned: Wednesday September 4, 2019 Date Due: Friday September 20, 2019 Title: 2-D Method of Characteristics (M.O.C.) Grid Solver Development Num. of Points: 10 Ø Code and Verify subroutines or scripts for Initial Data Line along Expansion Section Wall Internal Flow Unit Process Centerline Intercept Unit Process (C- characteristic line) Wall Intercept Unit Process (C+ chracteristic line) Minimum Length Nozzle Maximum Turning Angle Ø Link and Sequence Unit Process Modules to Calculate M.O.C Grid

Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

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Page 1: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

1MAE 5540 – Propulsion Systems II

Homework 1.2 SolutionAssignment 1.2 Date Assigned: Wednesday September 4, 2019Date Due: Friday September 20, 2019Title: 2-D Method of Characteristics (M.O.C.) Grid Solver Development Num. of Points: 10 Ø Code and Verify subroutines or scripts for

• Initial Data Line along Expansion Section Wall • Internal Flow Unit Process• Centerline Intercept Unit Process (C- characteristic line)• Wall Intercept Unit Process (C+ chracteristic line)• Minimum Length Nozzle Maximum Turning Angle

Ø Link and Sequence Unit Process Modules to Calculate M.O.C Grid

Page 2: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

2MAE 5540 – Propulsion Systems II

Homework 1.2 Solution (2)

Solve Problem 11.1 in Anderson, page 429. (See Section 1.1 Notes for Example)... Minimum Length Nozzle with Maximum Turning Angle -- infinitesimal expansion section... Mexit = 2.0... D* = 2.0 cm

... Assume Gamma = 1.4

... Repeat with Gamma = 1.2Solve Problem 11.2 in Anderson, Page 430 but with ...

... Finite expansion section radius of Curvature equal to 1.5 x throat radius

... Mexit = 2.0

... D* = 2.0 cm ... Assume Gamma = 1.4... Repeat with Gamma = 1.2

for all parts Plot nozzle half-contoursPlot nozzle Mach number profile along upper wall and along centerlineCompare to Mach number profile calculated using A/A* equation

Page 3: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

3MAE 5540 – Propulsion Systems II

Homework 1.2 Solution (3)

For each of the 4 Nozzle Contours above à• Use the approximate Mapping technique to solve for P,Q,S, and T of the Parabolic

Contour• Plot Contours against the derived M.O.C contours, compare shapes• Use M.O.C. values for qmax, Nozzle length LN, and Radius of Curvature Rc of the

expansion section for these calculations• Be sure to show Calculations for Xn, Yn, P, Q, S, T, etc. • Assume Nozzle exit angle is zero for each case

Page 4: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

4MAE 5540 – Propulsion Systems II

Solution1.2, part 1• Minimum Length Nozzle … g = 1.4• Let N=6

180π

1.4 1+1.4 1−# $% &

0.5 1.4 1−1.4 1+# $% & 2.02 1−( )# $% &

0.5

# $' (% &

atan 2.02 1−( )( )0.5

( )atan−# $' (% &

Mexit = 2.0→ν(Mexit ) =γ +1γ −1

tan−1 γ −1γ +1

2.02 −1( )%&'

('

)*'

+'− tan−1 2.02 −1 =

= 26.3798o

θw Max=νexit2

== 13.1899o

Page 5: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

5MAE 5540 – Propulsion Systems II

Solution 1.2, part 1 (2)

Minimum Length à Rc expansion = 0

θw Max=νexit2

== 13.1899o

Page 6: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

6MAE 5540 – Propulsion Systems II

Solution 1.2, part 1 (3)

Page 7: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

7MAE 5540 – Propulsion Systems II

Solution 1.2, part 1 (4)

• Minimum Length Nozzle … g = 1.2• Let N=6

Mexit = 2.0→ν(Mexit ) =γ +1γ −1

tan−1 γ −1γ +1

2.02 −1( )%&'

('

)*'

+'− tan−1 2.02 −1 =

= 31.46o

θw Max=νexit2

= 15.731o

Maximium Turning Angle changes!

Page 8: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

8MAE 5540 – Propulsion Systems II

Solution 1.2, part 1 (5)

Minimum Length à Rc expansion = 0

θw Max=νexit2

== 15.731o

Page 9: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

9MAE 5540 – Propulsion Systems II

Solution 1.2, part 1 (6)

Page 10: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

10MAE 5540 – Propulsion Systems II

Solution 1.2, Part 1 comparisonsθw Max

=νexit2

== 13.1899o

θw Max=νexit2

=15.731o

Page 11: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

11MAE 5540 – Propulsion Systems II

Solution 1.2, part 2 (1)

Rc expansion = 1.5 x Rthroat = 1.5 cm

θw Max=νexit2

== 13.189o

Page 12: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

12MAE 5540 – Propulsion Systems II

Solution 1.2, part 2 (2)

Page 13: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

13MAE 5540 – Propulsion Systems II

Solution 1.2, part 2 (3)

Rc expansion = 1.5 x Rthroat = 1.5 cm

θw Max=νexit2

== 15.732o

Page 14: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

14MAE 5540 – Propulsion Systems II

Solution 1.2, part 2 (4)

Page 15: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

15MAE 5540 – Propulsion Systems II

Solution 1.2, Part 2 comparisons

θw Max=νexit2

=

θw Max=νexit2

== 15.731o

= 13.189o

Page 16: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

16MAE 5540 – Propulsion Systems II

Part 3, Approximate Contour Mappinga) Minimum Length à Rc expansion = 0, g=1.4, A/A* = 1.6875

M.O.C Nozzle Spline Fit Nozzle

θw Max=νexit2

== 13.1899o

Page 17: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

17MAE 5540 – Propulsion Systems II

Part 3, Approximate Contour Mapping (2)

b) Non-Minimum Length à Rc expansion = 1.5 cm, g=1.4, A/A* = 1.6875

M.O.C Nozzle Spline Fit Nozzle

θw Max=νexit2

== 13.1899o

Page 18: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

18MAE 5540 – Propulsion Systems II

Part 2, Approximate Contour Mapping (3)

c) Minimum Length à Rc expansion = 0, g=1.2, A/A* = 1.884

M.O.C Nozzle Spline Fit Nozzle

θw Max=νexit2

== 15.732o

Page 19: Homework 1.2 Solutionmae-nas.eng.usu.edu/MAE_6530_Web/subpages/Assignments/... · 2019-09-20 · 2 MAE 5540 – Propulsion Systems II Homework 1.2 Solution (2) Solve Problem 11.1

19MAE 5540 – Propulsion Systems II

Part 2, Approximate Contour Mapping (3)

b) Non-Minimum Length à Rc expansion = 1.5 cm, g=1.2, A/A* = 1.884

M.O.C Nozzle Spline Fit Nozzle

θw Max=νexit2

== 15.732o