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Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law to: • Earthquake cycles, • Earthquake depth distribution, • Earthquake nucleation, • The mechanics of aftershocks, • and more...

Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

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Page 1: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Friction

Why friction? Because slip on faults is resisted by frictional forces.

In the coming weeks we shall discuss the implications of the friction law to:

• Earthquake cycles,

• Earthquake depth distribution,

• Earthquake nucleation,

• The mechanics of aftershocks,

• and more...

Page 2: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Question: Given that all objects shown below are of equal mass and identical shape, in which case the frictional force is greater?

Question: Who sketched this figure?

Page 3: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Leonardo Da Vinci (1452-1519) showed that the friction force is independent of the geometrical area of contact.

Da Vinci law and the paradox

The paradox: Intuitively one would expect the friction force to scale proportionally to the contact area.

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Page 4: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Amontons’ laws

Amontons' first law: The frictional force is independent of the geometrical contact area.

Amontons' second law: Friction, FS, is proportional to the normal force, FN:

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FS = μFN

Page 5: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

A way out of Da Vinci’s paradox has been suggested by Bowden and Tabor, who distinguished between the real contact area and the geometric contact area. The real contact area is only a small fraction of the geometrical contact area.

Bowden and Tabor (1950, 1964)

Figure from: Scholz, 1990

Page 6: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

FN = pAr ,

where p is the penetration hardness.

where s is the shear strength.

FS = sAr ,

Thus:

μ ≡FSFN

=p

s .

Since both p and s are material constants, so is μ.

The good news is that this explains Da Vinci and Amontons’ laws.

But it does not explain Byerlee law…

Page 7: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Beyrlee law

For σ N < 200MPa : μ = 0.85

For σ N > 200MPa : μ = 0.60

Byerlee, 1978

Page 8: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Static versus kinetic friction

The force required to start the motion of one object relative to another is greater than the force required to keep that object in motion.

μstatic > μdynamicOhnaka (2003)

μstatic

μdynamic

Page 9: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

The law of Coulomb - is that so?

Friction is independent of sliding velocity.

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Page 10: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Velocity stepping - Dieterich

• A sudden increase in the piston's velocity gives rise to a sudden increase in the friction, and vice versa.

• The return of friction to steady-state occurs over a characteristic sliding distance.

• Steady-state friction is velocity dependent.

Dieterich and Kilgore, 1994

Page 11: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Slide-hold-slide - Dieterich

Static (or peak) friction increases with hold time.

Dieterich and Kilgore, 1994

Page 12: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Slide-hold-slide - Dieterich

• The increase in static friction is proportional to the logarithm of the hold duration.

Dieterich, 1972

Page 13: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Monitoring the real contact area during slip - Dieterich and Kilgore

Page 14: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Change in true contact area with hold time - Dieterich and Kilgore

• The dimensions of existing contacts are increasing.• New contacts are formed.

Dieterich and Kilgore, 1994

Page 15: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Change in true contact area with hold time - Dieterich and Kilgore

• The real contact area, and thus also the static friction increase proportionally to the logarithm of hold time.

Dieterich and Kilgore, 1994

Page 16: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Upon increasing the normal stress:• The dimensions of existing contacts are increasing.• New contacts are formed.• Real contact area is proportional to the logarithm of normal stress.

The effect of normal stress on the true contact area - Dieterich and Kilgore

Dieterich and Kilgore, 1994

Page 17: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

The effect of normal stress - Dieterich and Linker

Linker and Dieterich, 1992 Instantaneousresponse linear

response

Changes in the normal stresses affect the coefficient of friction in two ways:

• Instantaneous response, whose trend on a shear stress versus shear strain curve is linear.• Delayed response, some of which is linear and some not.

Page 18: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

• Static friction increases with the logarithm of hold time.

• True contact area increases with the logarithm of hold time.

• True contact area increases proportionally to the normal load.

• A sudden increase in the piston's velocity gives rise to a sudden increase in the friction, and vice versa.

• The return of friction to steady-state occurs over a characteristic sliding distance.

• Steady-state friction is velocity dependent.

• The coefficient of friction response to changes in the normal stresses is partly instantaneous (linear elastic), and partly delayed (linear followed by non-linear).

Summary of experimental result

Page 19: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

The constitutive law of Dieterich and Ruina

τσ=μ =μ∗+ A ln

V

V *

⎝ ⎜

⎠ ⎟+ B ln

θV *

DC

⎝ ⎜

⎠ ⎟

and

dt=1−

θV

DC−αθ

B

dσ /dt

σ ,

were:• V and are sliding speed and contact state, respectively.• A, B and are non-dimensional empirical parameters.• Dc is a characteristic sliding distance.• The * stands for a reference value.

Page 20: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

The set of constitutive equations is non-linear. Simultaneous solution of non-linear set of equations may be obtained numerically (but not analytically). Yet, analytical expressions may be derived for some special cases.

• The change in sliding speed, V, due to a stress step of τ:

• Steady-state friction:

• Static friction following hold-time, thold:

V = exp ΔτAσ( ).

μss = μ* + (A − B)lnVssV *

⎝ ⎜

⎠ ⎟= μ* + (B − A)ln

θ ssV*

Dc

⎝ ⎜

⎠ ⎟ .

μstatic ∝ (B − A)ln θ0 + Δthold( ) .

Page 21: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

τσ=μ =μ∗+ A ln

V

V *

⎝ ⎜

⎠ ⎟+ B ln

θV *

DC

⎝ ⎜

⎠ ⎟

and

dt=1−

θV

DC ,

or

dt= −θV

DClnθV

DC

⎝ ⎜

⎠ ⎟

The evolution law: Aging-versus-slip

Aging law (Dieterich law):

Slip law (Ruina law):

Page 22: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Slip law fits velocity-stepping better than aging law

Linker and Dieterich, 1992

Unpublished data by Marone and Rubin

Page 23: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

Aging law fits slide-hold-slide better than slip law

Beeler et al., 1994

Page 24: Friction Why friction? Because slip on faults is resisted by frictional forces. In the coming weeks we shall discuss the implications of the friction law

In the coming weeks we shall discuss the implications of the friction law to:

• Earthquake nucleation,

• Earthquake depth distribution,

• Earthquake cycles,

• The mechanics of aftershocks, and more.

Recommended reading:

• Marone, C., Laboratory-derived friction laws and their applications to seismic faulting, Annu. Rev. Earth Planet. Sci., 26: 643-696, 1998.• Scholz, C. H., The mechanics of earthquakes and faulting, New-York: Cambridge Univ. Press., 439 p., 1990.