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20 40 60 80 100 120 t 20 40 60 80 100 120 y FIGURE 3.1 A population with limited resources cannot grow exponentially forever.

FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

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Page 1: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

20 40 60 80 100 120t

20

40

60

80

100

120

y

FIGURE 3.1 Apopulation with limited resources cannot grow exponentially forever.

To protect the rights of the author(s) and publisher we inform you that this PDF is an uncorrected proof for internal business use only by the author(s), editor(s),reviewer(s), Elsevier and typesetter SPi. It is not allowed to publish this proof online or in print. This proof copy is the copyright property of the publisher and isconfidential until formal publication.

Page 2: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

50 100 150 200 250t

50

100

150

200

250

y

FIGURE 3.2 With these parameter values, the upper limit on the population of the United States is approximately300 million.

To protect the rights of the author(s) and publisher we inform you that this PDF is an uncorrected proof for internal business use only by the author(s), editor(s),reviewer(s), Elsevier and typesetter SPi. It is not allowed to publish this proof online or in print. This proof copy is the copyright property of the publisher and isconfidential until formal publication.

Page 3: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

y B

y A

y 0

(a) 5(b) 10 15 20 25t

1

2

3

4

5y

FIGURE 3.3 (a) Phase line for dy/dt = −r(1 − (1/A)y)(1 − (1/B)y)y. (b) Several solutions together with the slope field for dy/dt = −0.25(1 − y)(1 − y/3)y. The phaseportrait shows that all nontrivial solutions other than if y0 = 1, y(t) = 1. If y0 < 1, then limt→∞ y(t) = 0. If y0 > 1, thenlimt→∞ y(t) = 3.

To protect the rights of the author(s) and publisher we inform you that this PDF is an uncorrected proof for internal business use only by the author(s), editor(s),reviewer(s), Elsevier and typesetter SPi. It is not allowed to publish this proof online or in print. This proof copy is the copyright property of the publisher and isconfidential until formal publication.

Page 4: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

-2 -1 1 2 3 4t

20

40

60

80

100

120

T

FIGURE 3.4 Graph of T(t) = 17(7/17)t/2 + 65.

To protect the rights of the author(s) and publisher we inform you that this PDF is an uncorrected proof for internal business use only by the author(s), editor(s),reviewer(s), Elsevier and typesetter SPi. It is not allowed to publish this proof online or in print. This proof copy is the copyright property of the publisher and isconfidential until formal publication.

Page 5: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

5 10 15 20t

62.5

65

67.5

70

72.5

75

u

FIGURE 3.5 Modeling the temperature in a building over the course of a 24-h day.

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Page 6: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

Negative direction

Positive direction

Object

FR

mg

FIGURE 3.6 Force diagram.

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Page 7: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

10 20 30 40 50 60 70t

500

1000

1500

2000

s

FIGURE 3.7 Graph of s(t) = 32t+ 30e−t − 30.

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Page 8: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

0.5 1 1.5 2 2.5 3t

5

10

15

20

25

30

v

FIGURE 3.8 The velocity functions from Example ?? (dashed) and Example ??. Notice how the different forces due to airresistance affect the velocity of the object.

To protect the rights of the author(s) and publisher we inform you that this PDF is an uncorrected proof for internal business use only by the author(s), editor(s),reviewer(s), Elsevier and typesetter SPi. It is not allowed to publish this proof online or in print. This proof copy is the copyright property of the publisher and isconfidential until formal publication.

Page 9: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

Negative direction

Positive direction

Object

Motion

FRg

FIGURE 3.9 By drawing a force diagram, we see that g and FR are in the negative direction.

To protect the rights of the author(s) and publisher we inform you that this PDF is an uncorrected proof for internal business use only by the author(s), editor(s),reviewer(s), Elsevier and typesetter SPi. It is not allowed to publish this proof online or in print. This proof copy is the copyright property of the publisher and isconfidential until formal publication.

Page 10: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

0.5

(a)

1 1.5 2 2.5 3t

-20

20

40

v

0.5

(b)

1 1.5 2 2.5 3 t

-20

20

40

{v, s}

FIGURE 3.10 (a) Graph of v(t) = 88e−4t/5 − 40. (b) Graph of v(t) together with s(t) = 110 − 40t− 110e−4t/5 (dashed).

To protect the rights of the author(s) and publisher we inform you that this PDF is an uncorrected proof for internal business use only by the author(s), editor(s),reviewer(s), Elsevier and typesetter SPi. It is not allowed to publish this proof online or in print. This proof copy is the copyright property of the publisher and isconfidential until formal publication.

Page 11: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

1 2(a)

3 4 5t

20

40

60

80

100

120

s

1 2 3 4 5t

5

10

15

20

25

30

s

(b)

FIGURE 3.11 (a) Graph of s(t) = 32e−t + 32t − 32. (b) Graph of s(t) = 3.99722 − 3.9972e−6t + 163 t.

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Page 12: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

y

x(a)

l1

l2

q

y

x(b)

l1

l2

l2�q

q

FIGURE 3.12 (a) Calculating the angle of intersection of two non-parallel lines. (b) Drawing the parallel can help computethe angle.

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Page 13: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

Arterial blood line

Blood pump

Dialyzing(bathing)solution

Venousblood line

Bubble trap

Compressed airFreshdialyzingsolution

Constant-temperaturebath

Used dialyzingsolution

Cellophane membrane(tubing containing blood)

FIGURE 3.13 Diagram of a kidney dialysis machine.

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Page 14: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

TABLE 3.1 Half-Lives of Various Nuclides

Element Nuclide Half-Life Element Nuclide Half-Life

Aluminum 26Al 7.4 × 105 years Polonium 209Po 100 years

Beryllium 10Be 1.51 × 106 years Polonium 210Po 138 days

Carbon 14C 5730 years Radon 222Rn 3.82 days

Chlorine 36Cl 3.01 × 105 years Radium 226Ra 1700 years

Iodine 131I 8.05 days Thorium 230Th 75,000 years

Potassium 40K 1.2 × 109 years Uranium 238U 4.51 × 109 years

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Page 15: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

TABLE 3.2 U.S. Population and Values of y(t)

Actual Population Value of y(t) = Actual Population Value of y(t) =Year (t) (in millions) 5.3 e0.03t Year (t) (in millions) 5.3 e0.03t

1800 (0) 5.30 5.30 1870 (70) 38.56 43.28

1810 (10) 7.24 7.15 1880 (80) 50.19 58.42

1820 (20) 9.64 9.66 1890 (90) 62.98 78.86

1830 (30) 12.68 13.04 1900 (100) 76.21 106.45

1840 (40) 17.06 17.60 1910 (110) 92.23 143.70

1850 (50) 23.19 23.75 1920 (120) 106.02 193.97

1860 (60) 31.44 32.06 1930 (130) 123.20 261.83

To protect the rights of the author(s) and publisher we inform you that this PDF is an uncorrected proof for internal business use only by the author(s), editor(s),reviewer(s), Elsevier and typesetter SPi. It is not allowed to publish this proof online or in print. This proof copy is the copyright property of the publisher and isconfidential until formal publication.

Page 16: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

TABLE 3.3 U.S. Population and Values of y(t)

Actual Population Actual PopulationYear (t) (in millions) Value of y(t) Year (t) (in millions) Value of y(t)

1800 (0) 5.30 5.30 1900 (100) 76.21 79.61

1810 (10) 7.24 7.11 1910 (110) 92.23 98.33

1820 (20) 9.64 9.52 1920 (120) 106.02 119.08

1830 (30) 12.68 12.71 1930 (130) 123.20 141.14

1840 (40) 17.06 16.90 1940 (140) 132.16 163.59

1850 (50) 23.19 22.38 1950 (150) 151.33 185.45

1860 (60) 31.44 29.44 1960 (160) 179.32 205.82

1870 (70) 38.56 38.42 1970 (170) 203.30 224.05

1880 (80) 50.19 49.63 1980 (180) 226.54 239.78

1890 (90) 62.98 63.33 1990 (190) 248.71 252.94

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Page 17: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

TABLE 3.4 Units Useful in Solving Problems Associated with Newton’s SecondLaw of Motion

English International

Mass Slug (1b s2/ft.) Kilogram (kg)

Force Pound (1b) Newton (mkg/s2)

Distance Foot (ft.) Meter (m)

Time Second (s) Second (s)

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Page 18: FIGURE 3.1 ......1 1.5 2 2.5 3 t-20 40 { ,s} FIGURE 3.10 (a)Graphofv(t) = 88e−4t/5 −40.(b)Graphofv(t) togetherwiths(t) = 110 −40t−110e−4t/5 (dashed). To protect the rights

210Po Concentration 226Ra ConcentrationPainting (dpm/g of Pb) (dpm/g of Pb) 1−Ra

Po

Washing of Feet 12.6 0.26 0.98Woman Reading Music 10.3

0.300.97

Woman Playing Mandolin 8.2 0.17 0.98Woman Drinking 8.3 0.1 0.99Disciples of Emmaus 0.8 0.91Boy Smoking 4.8 0.31 0.94Lace Maker 1.5 1.4 0.07Laughing Girl 5.2 6.0 −0.15

To protect the rights of the author(s) and publisher we inform you that this PDF is an uncorrected proof for internal business use only by the author(s), editor(s),reviewer(s), Elsevier and typesetter SPi. It is not allowed to publish this proof online or in print. This proof copy is the copyright property of the publisher and isconfidential until formal publication.