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Errors in Electrical Measurements

• Systematic error every times you measuree g loading or insertion of the measuremente.g. loading or insertion of the measurement

instrument

• Meter error scaling (inaccurate marking), pointer bending, friction, no calibration

• Random error temperature effect, noises

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p ,(unwanted signals)

• Reading error parallax, read a wrong scale• Recording error for many measured values

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Background

• Electric charge, e– = 1.610–19 Coulombs

• Current, I = dq/dt Coulomb/sec = Amps

• Voltage, the difference in electrical potential between two points (Joules/Coulomb)

Power P = IV Watts

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• Power, P = IV Watts

• Energy, E = Pt Units (kWhr)• Ohm’s Law, V = IR

Background (Cont’d)

• Kirchhoff’s Current Law (KCL)I1 – I2 – I3 = 0 I A loop is any closedI1 I2 I3 0

• Kirchhoff’s Voltage Law (KVL)– V1 + I1R1 + V2 + I2R2 = 0

NodalI1

I2I3

A loop is any closed path in a circuit, in which no node is encountered more than once.

A mesh is a loop that has no other loops

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V1

V2R1

R2

I1

+

+

–

–

Mesh or Loop

pinside of it.

A supermesh occurs when a current source is contained between two essential meshes.

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Background (Cont’d)• Thévenin’s Theorem

Linear CircuitSource

A

R

A

BRLVth

Rth

Open circuit to find Vth

• Norton’s Theorem

- Source- Load B

RLEquivalent Circuit

A

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Norton s TheoremShort circuit tofind IN

B

RLIN

RN

Equivalent Circuit

Background (Cont’d)Example

No Load Equivalent Source

No Source Equivalent Load

+–

R1

R2

V1+

–Veq = R2 V1

R1+R2

+–

R1

R2

V1

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R1

R2

Sho

rted Req = R1 || R2

= R1R2R1+R2

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Background (Cont’d)• Ideal Voltage Source Vs. Ideal Current Source

V

II = Vfixed / R0

V

IV = IfixedR

• Superposition Theorem (for linear resistive network containing several sources)

V V0

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network containing several sources)Voltage source Short CircuitCurrent source Open CircuitVector summation of the individual voltage or current caused by each separate source

+ –0 V

0 A

Background (Cont’d)Example

+3V–

+

10k

Vout+6V–

5kout

+3V–

10k

5k

Vout1 = 3V/(10k+5k) 5k = 1V

i1

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+6V–

10k

5k

Vout2 = –6V/(10k+5k) 10k = –4V

i2

Vout = Vout1 + Vout2

= 1V – 4V= –3V

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Background (Cont’d)• The Maximum Power Transfer Theorem

ARs+

If Vs and Rs are fixed, when IL then VL Maximum power is at RL = Rs

BRLVs IL VL

–

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Therefore VL = Vs / 2 and IL = Vs / 2RL

PL = (IL)2RL = (Vs / 2RL)2 RL = Vs2 / 4RL

Ammeter Loading

For current measurement, open circuit to put an ammeter.

DC CircuitDC Circuit

+V–

R

I I = V/R

R

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+V–

R

IA A RAIA = V/(R+RA)

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Ammeter Loading (Cont’d)

Loading error, IA – I = V/(R+RA) – V/R

= VR – V(R+RA)( A)

R(R+RA)

= –VRA

R(R+RA)

% Loading Error = (IA – I)/I 100%

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% g ( A ) %

= –RA 100%

R+RA

It means if RA then error

Ammeter Loading (Cont’d)The ideal ammeter has zero internal

resistance, so as to drop as little voltage as possible as electrons flow through itas possible as electrons flow through it.

Example

without the ammeter,

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Ammeter Loading (Cont’d)with the ammeter,

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Ammeter Loading (Cont’d)One ingenious way to reduce the impact that a current-

measuring device has on a circuit is to use the circuit wire as part of the ammeter movement itself. p

All current-carrying wires produce a magnetic field, the strength of which is in direct proportion to the strength of the current.

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Ammeter Loading (Cont’d)By building an instrument that measures the strength

of that magnetic field, a no-contact ammeter can be produced.

S h t i bl t th t th hSuch a meter is able to measure the current through a conductor without even having to make physical contact with the circuit, much less break continuity or insert additional resistance.

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Ammeter Loading (Cont’d)More modern designs of clamp-on ammeters

utilize a small magnetic field detector device called a Hall-effect sensor to accuratelycalled a Hall-effect sensor to accurately determine field strength.

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Ammeter Loading (Cont’d)Some clamp-on meters contain electronic

amplifier circuitry to generate a small voltage proportional to the current in the wire betweenproportional to the current in the wire between the jaws, that small voltage connected to a voltmeter for convenient readout by a technician.

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Voltmeter Loading

For voltage measurement, voltmeter is placed in parallel with the circuit element.

DC CircuitDC Circuit

+V–

R

I

V

+ VV –

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+V–

R

VRV

+Vth

–

Rth

RV

Thévenin’s Ith

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Voltmeter Loading (Cont’d)Ith = Vth / ( Rth + RV )

VV = IthRV = VthRV / ( Rth + RV )

Error = VV – V hError = VV Vth

= RV – 1 Vth

Rth + RV

% Error = (VV – Vth)/Vth 100%

= R 100%

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= –Rth 100%

Rth+RV

It means if RV then error

Voltmeter Loading (Cont’d)The ideal voltmeter has infinite resistance,

so that it draws no current from the circuit under testunder test.

Example

without the voltmeter,

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Voltmeter Loading (Cont’d)with the voltmeter,

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Ohmmeter Loading

Using a circuit within the instrument

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Analog Ammeters & Voltmeters• The users have to read the meter manual to

find the basic accuracy specifications.

• Moving-coil-based analog meters areMoving coil based analog meters are characterized by their full-scale deflection (f.s.d.) and effective resistance of the meters (few - k)

• Typical meters produce a f.s.d. current of 50 A - 1 mA(this is not the ranges of the meters)

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Percentage of FSD• The accuracy of analog ammeters and

voltmeters are quoted as a percentage of the full-scale deflection of pointer on the linear pscale for all reading on the selected range.

• e.g. an ammeter having accuracy 2% f.s.d. within the range 0-10 A,Relative error 2% of 10 AAb l t 0 2 AAbsolute error 0.2 A

• When a measured value is close to full scale, or at least above 2/3 of full scale, the published accuracy is meaningful. 24

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Percentage of Midscale

• Moving-coil-based ohmmeters is characterized by their midscale deflection ofcharacterized by their midscale deflection of the pointer on nonlinear scale.

• What figure lies exactly between infinity and zero?

• e g 3% of midscalee.g. 3% of midscaleRelative error 3% of 9 kAbsolute error 0.27 k

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Percentage of DMM Reading

• In the case of digital instruments, the accuracy is generally quoted as the percentage of theis generally quoted as the percentage of the reading 1 digit.

• e.g. 0.5% Reading 1 Digitwhen you read a voltage 1.2 V with a digit of 0.03 V (depending on the range selected)

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error = 0.5% of 1.2 V 0.03 V

= 0.036 V absolute error

= 3% of reading relative error

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Potential Meter• Before the moving coil meter, potentiometer was

used in measuring the voltage in a circuit

• Calculated from a fraction of a known voltage (on• Calculated from a fraction of a known voltage (on resistive slide wire)

• Based on voltage divider (linearly)

• By means of a galvanometer (no deflection or null-balance)

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Calibration of Potentiometer

galvanometer

• The end of a uniform resistance wire is at x1

+ –

Vs

+ – Vstd_cell

(known)

x1x2

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1

• The sliding contact or wiper is then adjusted to x2

• The standard electrochemical cell whose E.M.F. is known (e.g. 1.0183 volts for Weston cell)

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Calibration of Potentiometer (Cont’d)

• Adjust supply voltage Vs until the l t h d t t llgalvanometer shows zero or detect null

(voltage on R2 equals to the standard cell voltage or no current flows through the galvanometer)

• x2/x1 Vs = Vstd cell

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x2/x1 Vs Vstd_cell

Vs = x1/x2 Vstd_cell

Calibration of Potentiometer (Cont’d)• An extremely simple type of null detector, instead of the

galvanometer, is a set of audio headphones, the speakers within acting as a kind of meter movement.

• When a DC voltage is initially applied to a speaker theWhen a DC voltage is initially applied to a speaker, the resulting current through it will move the speaker cone and produce an audible “click.”

• Another “click” sound will be heard when the DC source is disconnected.

• The technician would repeatedly press and release the

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pushbutton switch, listening for silence to indicate that the circuit was “balanced”.

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Calibration of Potentiometer (Cont’d)• The headphone’s sensitivity may be greatly increased

by connecting it to a device called a transformer.

• A step-down transformer converts low-current pulses• A step-down transformer converts low-current pulses, created by closing and opening the pushbutton switch while connected to a small voltage source, into higher-current pulses to more efficiently drive the speaker cones inside the headphones (Np/Ns = Is/Ip).

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Measuring of Potentiometer

galvanometer

• Slide the wiper (change x3) until the

+ –

Vs

+ – Vunknown

(to be measured)

x1x3

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p ( g 3)galvanometer shows zero again

• Vunknown = x3/x1 Vs

= x3/x2 Vstd_cell

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Rheostat

• Variable resistor with two terminals

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Loading for a Potentiometer

Resistor

Fi d• Fixed

• Adjustable Potentiometer

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50 150

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Loading of a Potentiometer (Cont’d)

RLVs

px

p – x

Voltage Divider

RLVth

Rth

Thévenin’s

Vth = ( x / p ) VsI

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RLx

p – x

Superposition

1 = 1 + 1Rth (x/p)Rp ((p-x)/p)Rp

Rth = (x/p)Rp(1 – x/p)

Loading of a Potentiometer (Cont’d)Vth = I (Rth+RL)

(x/p)Vs = I [ (x/p)(1 – x/p)Rp + RL ]

I (x/p)VI = (x/p)Vs

(x/p)(1 – x/p)Rp + RL

VL = IRL = (x/p)VsRL

(x/p)(1 – x/p)Rp + RL

= (x/p)Vs

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( p) s

(Rp/RL)(x/p)(1 – x/p) + 1

It means the relationship between VL and xis nonlinear!

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Loading of a Potentiometer (Cont’d)Error,

Vth – VL = (x/p)Vs 1 – 1(Rp/RL)(x/p)(1 – x/p) +1(Rp/RL)(x/p)(1 x/p) 1

= (x/p)Vs (Rp/RL)(x/p)(1 – x/p)

(Rp/RL)(x/p)(1 – x/p) + 1

If RL >> R then R /RL 0

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If RL >> Rp then Rp/RL 0Error (x/p)Vs(Rp/RL)(x/p)(1 – x/p)

Vs(Rp/RL)[(x/p)2 – (x/p)3] , RL error % Error (Rp/RL)[(x/p) – (x/p)2] × 100%

Loading of a Potentiometer (Cont’d)

Let d(Error)/dx = Vs(Rp/RL)[2x/p2 – 3x2/p3] = 0

We get 2x/p2 = 3x2/p3

x/p = 2/3 for the maximum

Therefore,

the max error = Vs(Rp/RL)[(2/3)2 – (2/3)3]

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0.148 Vs(Rp/RL)

and the max % error 22.2 (Rp/RL) %